Di artikel Fisika kelas 12 kali ini, kita akan mempelajari tentang rangkaian arus bolak-balik, penjelasan resistor, induktor, dan kapasitor secara lengkap, disertai dengan rumus serta latihan soal!
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Tahukah kamu, generator pembangkit listrik yang biasa digunakan kalau listrik di rumahmu sedang mati merupakan salah satu aplikasi dari rangkaian arus bolak-balik?
Ternyata rangkaian arus bolak-balik terdiri dari beberapa jenis yaitu rangkaian resistor, induktor, dan kapasitor. Lalu, bagaimana keadaan rangkaian-rangkaian tersebut saat dialiri arus bolak-balik? Yuk kita bahas secara detail ya!
Arus bolak-balik atau alternating current (AC) merupakan arus dan tegangan listrik yang besarnya berubah terhadap waktu dan mengalir dalam dua arah. Arus bolak-balik biasanya dimanfaatkan untuk peralatan elektronik.
Pada prinsipnya, sumber arus bolak-balik bekerja melalui perputaran kumparan dengan kecepatan sudut tertentu yang berada dalam medan magnetik. Jenis-jenis rangkaian dalam rangkaian AC adalah rangkaian resistor, rangkaian induktor, dan rangkaian kapasitor. Sudah pernah belajar tentang hal tersebut? kita bahas dulu satu persatu ya!
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Rangkaian Resistor
Sebuah resistor akan dialiri arus bolak-balik ketika dihubungkan dengan sumber tegangan bolak-balik. Fungsi rangkaian resistor dalam arus bolak-balik ialah untuk menurunkan potensial listrik dalam rangkaian, atau sebagai pembatas arus listrik yang masuk.
Nah jika sudah dibatasi, arus dan tegangan dalam rangkaian resistor mempunyai fase yang sama saat terhubung dengan sumber tegangan bolak-balik.
Rangkaian resistor pada arus bolak-balik.
Grafik hubungan tegangan dan arus terhadap waktu pada resistor.
Berdasarkan grafik terlihat bahwa tegangan dan arus berada pada keadaan sefase, yang artinya mencapai nilai maksimum pada saat yang sama. Sebuah resistor dihubungkan dengan sumber tegangan bolak-balik, besarnya tegangan pada resistor sama dengan tegangan sumber.
Rumus Tegangan pada Resistor
Di bawah ini merupakan rumus tegangan resistor dan arus yang mengalir melalui resistor.
Nah, supaya kamu nggak bingung sama rumus-rumus di atas, kita coba kerjakan contoh soal di bawah ini, kuy!
Contoh Soal Tegangan Resistor
Sebuah sumber arus sinusoidal AC memiliki frekuensi sudut 100 rad/s dan mempunyai arus maksimum sebesar 10 mA, maka arus yang terjadi pada selang waktu adalah…
- 10 mA
- 5 mA
- 5 √3 mA
- 10 √3 mA
- 5 √2 mA
Jawaban:
Pertama, kita tulis dulu apa aja yang diketahui di soal.
Diketahui:
ω = 100 rad/s
Im = 10 mA
t =
Ditanya: i …?
Jadi, arus yang terjadi pada selang waktu adalah 5mA. Jawaban yang tepat B.
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Rangkaian Induktor
Sebuah induktor mempunyai hambatan yang disebut reaktansi induktif saat dihubungkan dengan sumber tegangan bolak-balik. Hambatan atau reaktansi induktif ini bergantung pada frekuensi sudut arus, dan induktansi diri induktor. Secara singkat, dapat dirumuskan sebagai:
Keterangan:
XL = Reaktansi Induktif (Ω)
ω = Kecepatan sudut (rad/s)
L = Induktansi induktor (H)
Rangkaian induktor pada arus bolak-balik.
Grafik hubungan tegangan dan arus terhadap waktu pada induktor.
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Berdasarkan grafik, terlihat bahwa besar tegangan pada induktor adalah nol saat arus induktornya maksimum, begitupun sebaliknya. Artinya tegangan pada induktor mencapai nilai maksimum lebih cepat seperempat periode daripada saat arus mencapai maksimumnya.
Rumus Tegangan pada Induktor
Rumus tegangan dan arus yang mengalir pada induktor seperti berikut:
Wah, kelihatannya rumit banget tuh rumus. Eits, tenang, guys! Kalo kamu sering berlatih soal, pasti lama-lama jadi hapal di luar kepala.
Contoh Soal Tegangan Induktor
Sebuah hambatan sebesar 50 Ω, dihubungkan dengan sumber tegangan AC yang memenuhi persamaan V = 200 Sin (200t), kuat arus rata-rata yang mengalir pada rangkaian tersebut adalah…
- 5,55 A
- 4,55 A
- 3,55 A
- 2,55 A
- 1,55 A
Jawaban:
Diketahui pada soal:
R = 50 Ω
V = 200 sin (200t)
Persamaan tegangan tiap saat diberikan oleh
- V = Vmaks sin ωt
-
V = 200 sin (200t)
Sehingga,
Maka arus maksimum pada rangkaian yaitu:
Dengan demikian arus rata-rata dalam rangkaiannya yaitu:
Jadi, kuat arus rata-rata yang mengalir pada rangkaian tersebut adalah 2,55 A. Jawaban yang tepat adalah D.
Rangkaian Kapasitor
Sebuah kapasitor memiliki karakteristik yang dapat menyimpan energi dalam bentuk muatan listrik ketika dihubungkan dengan sumber tegangan bolak-balik maupun tegangan searah.
Kapasitor yang dialiri arus bolak-balik akan timbul resistansi semu atau biasa disebut dengan reaktansi kapasitif. Besar nilai reaktansi kapasitif bergantung pada besarnya nilai kapasitansi kapasitor dan frekuensi sudut arus atau dapat dirumuskan sebagai:
Keterangan:
Xc = Reaktansi kapasitif (Ω)
ω = Kecepatan sudut (rad/s)
L = Induktansi induktor (H)
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Rangkaian kapasitor pada arus bolak-balik.
Grafik hubungan tegangan dan arus terhadap waktu pada kapasitor.
Berdasarkan grafik, terlihat bahwa arus pada kapasitor maksimum saat tegangan kapasitor bernilai nol, begitupun sebaliknya. Artinya, arus mencapai nilai maksimumnya seperempat periode lebih cepat daripada saat tegangan mencapai nilai maksimumnya.
Rumus Tegangan pada Kapasitor
Rumus tegangan dan arus yang mengalir pada kapasitor seperti berikut:
Daripada bingung, kuy kita kerjakan contoh soal di bawah ini bersama-sama!
Contoh Soal Tegangan Kapasitor
Kapasitas pengganti susunan kapasitor di atas adalah…
- 1,2F
- 3,0F
- 6,0F
- 9,0F
- 12,0F
Jawaban:
Diketahui:
C1 = 6F
C2 = 3F
C3 = 3F
Ditanya: Cp = …
Kapasitor di atas disusun secara paralel, maka kapasitas pengganti memenuhi:
- Cp = C1 + C2 + C3
- Cp = 6F + 3F + 3F
- Cp = 12F
Jadi, jawaban yang tepat adalah E. Mudah, bukan?
Gimana, sekarang kamu sudah lebih paham kan jenis-jenis rangkaian pada rangkaian arus bolak-balik? Yup, rangkaian resistor, induktor dan kapasitor memiliki besar tegangan dan arus yang berbeda ketika dialiri dengan sumber tegangan bolak-balik seperti rumus yang sudah dibahas di atas.
Tapi masih bingung ngga? Kalau iya, yuk langsung aja tanyain secara privat ke Ruangguru Privat Fisika. Akan ada tutor yang membantumu untuk memahami rumus serta memberikan penjelasannya. Buatlah belajar jadi praktis dari sekarang!
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<h1 class="content-title">
Rangkaian Arus Bolak-Balik: Resistor, Induktor & Kapasitor | Fisika Kelas 12 </h1>
<div class="content-meta">
<p class="content-author"><a href="https://www.ruangguru.com/blog/author/karina-dwi-adistiana" class="">Karina Dwi Adistiana</a> </p>
<p class="content-info"><span>August 14, 2025 • </span> <span>5 minutes read</span></p>
<br />
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<p><img decoding="async" style="width: 850px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Konsep%20Pelajaran%20-%20Resistor%2c%20Induktor%2c%20dan%20Kapasitor%20-%20Fisika%20Kelas%2012-02.jpg" alt="Rangkaian Arus Bolak-Balik: Resistor, Induktor, dan Kapasitor | Fisika Kelas 12" width="850" /></p>
<blockquote>
<p style="text-align: center; font-size: 16px;"><em>Di artikel <a href="https://www.ruangguru.com/blog/c/fisika/fisika-sma-kelas-12" rel="noopener"><span style="font-weight: bold;">Fisika kelas 12</span></a> kali ini, kita akan mempelajari tentang rangkaian arus bolak-balik, penjelasan resistor, induktor, dan kapasitor secara lengkap, disertai dengan rumus serta latihan soal!</em></p>
<p style="text-align: center; font-size: 16px;"><em>—</em></p>
<p> </p></blockquote>
<p style="text-align: justify;">Tahukah kamu, generator pembangkit listrik yang biasa digunakan kalau listrik di rumahmu sedang mati merupakan salah satu aplikasi dari rangkaian arus bolak-balik?</p>
<p style="text-align: justify;">Ternyata rangkaian arus bolak-balik terdiri dari beberapa jenis yaitu rangkaian resistor, induktor, dan kapasitor. Lalu, bagaimana keadaan rangkaian-rangkaian tersebut saat dialiri arus bolak-balik? Yuk kita bahas secara detail ya!</p>
<p style="text-align: justify;"><strong>Arus bolak-balik atau </strong><strong><em>alternating current</em></strong><strong> (AC) merupakan arus dan tegangan listrik yang besarnya berubah terhadap waktu dan mengalir dalam dua arah.</strong> Arus bolak-balik biasanya dimanfaatkan untuk peralatan elektronik.</p>
<p style="text-align: justify;">Pada prinsipnya, sumber arus bolak-balik bekerja melalui perputaran kumparan dengan kecepatan sudut tertentu yang berada dalam medan magnetik. Jenis-jenis rangkaian dalam rangkaian AC adalah rangkaian resistor, rangkaian induktor, dan rangkaian kapasitor. Sudah pernah belajar tentang hal tersebut? kita bahas dulu satu persatu ya!</p>
<p><strong>Baca Juga: <a href="/blog/ultraviolet" rel="noopener">Kenapa Pulang dari Pantai Kulit Menjadi Belang?</a></strong></p>
<p> </p>
<h2><span style="font-size: 18pt;">Rangkaian Resistor</span></h2>
<p style="text-align: justify;">Sebuah resistor akan dialiri arus bolak-balik ketika dihubungkan dengan <strong>sumber tegangan bolak-balik</strong>. Fungsi rangkaian resistor dalam arus bolak-balik ialah untuk menurunkan potensial listrik dalam rangkaian, atau sebagai pembatas arus listrik yang masuk.</p>
<p style="text-align: justify;">Nah jika sudah dibatasi, arus dan tegangan dalam rangkaian resistor mempunyai fase yang sama saat terhubung dengan sumber tegangan bolak-balik.</p>
<p style="text-align: center;"><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Konsep%20Pelajaran%20-%20Resistor%2c%20Induktor%2c%20dan%20Kapasitor%20-%20Fisika%20Kelas%2012-03.jpg" alt="Rangkaian resistor pada arus bolak-balik" width="600" /></p>
<p style="text-align: center;"><em>Rangkaian resistor pada arus bolak-balik.</em></p>
<p> </p>
<p style="text-align: justify;"><img fetchpriority="high" decoding="async" style="height: auto; max-width: 100%; width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Grafik%20hubungan%20tegangan%20dan%20arus%20terhadap%20waktu%20pada%20resistor.jpg" alt="Grafik hubungan tegangan dan arus terhadap waktu pada resistor" width="600" height="600" /></p>
<p style="text-align: center;"><em>Grafik hubungan tegangan dan arus terhadap waktu pada resistor.</em></p>
<p> </p>
<p style="text-align: justify;">Berdasarkan grafik terlihat bahwa tegangan dan arus berada pada keadaan sefase, yang artinya mencapai nilai maksimum pada saat yang sama. Sebuah resistor dihubungkan dengan sumber tegangan bolak-balik, besarnya tegangan pada resistor sama dengan tegangan sumber.</p>
<p> </p>
<h3><span style="font-size: 14pt;">Rumus Tegangan pada Resistor</span></h3>
<p style="text-align: justify;">Di bawah ini merupakan rumus tegangan resistor dan arus yang mengalir melalui resistor.</p>
<p><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Konsep%20Pelajaran%20-%20Resistor%2c%20Induktor%2c%20dan%20Kapasitor%20-%20Fisika%20Kelas%2012-04%20(4).jpg" alt="Rumus tegangan dan arus yang mengalir pada resistor" width="600" /></p>
<p> </p>
<p>Nah, supaya kamu nggak bingung sama rumus-rumus di atas, kita coba kerjakan contoh soal di bawah ini, kuy!</p>
<p> </p>
<h3 style="font-weight: bold; font-size: 16px;"><span style="font-size: 14pt;">Contoh Soal Tegangan Resistor</span></h3>
<p style="font-weight: bold; text-align: justify;"><span style="font-weight: normal;">Sebuah sumber arus sinusoidal AC memiliki frekuensi sudut 100 rad/s dan mempunyai arus maksimum sebesar 10 mA, maka arus yang terjadi pada selang waktu <span style="text-decoration: line-through;"><img decoding="async" style="width: 40px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/WhatsApp%20Image%202021-10-15%20at%2014.22.52.jpeg" alt="WhatsApp Image 2021-10-15 at 14.22.52" width="40" /></span> adalah… </span></p>
<ol style="list-style-type: upper-alpha;">
<li>10 mA</li>
<li>5 mA</li>
<li>5 √3 mA</li>
<li>10 √3 mA</li>
<li>5 √2 mA</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="font-weight: bold;">Jawaban:</p>
<p style="font-weight: normal;">Pertama, kita tulis dulu apa aja yang diketahui di soal.</p>
<p style="font-weight: normal;">Diketahui:</p>
<p style="font-weight: normal;"><em>ω</em> = 100 <em>rad/s</em></p>
<p style="font-weight: normal;"><em>I<sub>m</sub> = </em>10 <em>mA</em></p>
<p style="font-weight: normal;"><em>t = <span style="font-weight: normal;"><span style="text-decoration: line-through;"><img decoding="async" style="width: 40px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/WhatsApp%20Image%202021-10-15%20at%2014.22.52.jpeg" alt="WhatsApp Image 2021-10-15 at 14.22.52" width="40" /></span></span></em></p>
<p> </p>
<p style="font-weight: normal;">Ditanya:<em> i …? </em></p>
<p style="font-weight: normal;"><em><img decoding="async" style="width: 200px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/WhatsApp%20Image%202021-10-15%20at%2014.30.02.jpeg" alt="WhatsApp Image 2021-10-15 at 14.30.02" width="200" /></em></p>
<p style="font-weight: normal;">Jadi, arus yang terjadi pada selang waktu <em><span style="font-weight: normal;"><span style="text-decoration: line-through;"><img decoding="async" style="width: 40px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/WhatsApp%20Image%202021-10-15%20at%2014.22.52.jpeg" alt="WhatsApp Image 2021-10-15 at 14.22.52" width="40" /></span></span></em> adalah 5mA. Jawaban yang tepat B.</p>
<p><strong>Baca Juga: <a href="/blog/sinar-inframerah" rel="noopener">Berbagai Manfaat Sinar Inframerah di Kehidupan Sehari-hari dan Karakteristiknya</a></strong></p>
<p> </p>
<h2><span style="font-size: 18pt;">Rangkaian Induktor</span></h2>
<p style="text-align: justify;">Sebuah induktor mempunyai hambatan yang disebut reaktansi induktif saat dihubungkan dengan sumber tegangan bolak-balik. Hambatan atau reaktansi induktif ini bergantung pada frekuensi sudut arus, dan induktansi diri induktor. Secara singkat, dapat dirumuskan sebagai:</p>
<p style="text-align: justify;"><img decoding="async" style="margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/xl.png" alt="xl.png" /></p>
<p> </p>
<div>
<p style="text-align: justify; font-weight: bold;">Keterangan:</p>
<p style="text-align: justify;">XL = Reaktansi Induktif (Ω)</p>
<p style="text-align: justify;">ω = Kecepatan sudut (rad/s)</p>
<p style="text-align: justify;">L = Induktansi induktor (H)</p>
<p style="text-align: justify;"><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Konsep%20Pelajaran%20-%20Resistor%2c%20Induktor%2c%20dan%20Kapasitor%20-%20Fisika%20Kelas%2012-07.jpg" alt=" Rangkaian induktor pada arus bolak-balik" width="600" /></p>
</div>
<p style="text-align: center;"><em>Rangkaian induktor pada arus bolak-balik.</em></p>
<p> </p>
<p style="text-align: center;"><img decoding="async" style="height: auto; max-width: 100%; width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Grafik%20hubungan%20tegangan%20dan%20arus%20terhadap%20waktu%20pada%20induktor.jpg" alt="Grafik hubungan tegangan dan arus terhadap waktu pada induktor" width="600" height="600" /></p>
<p style="text-align: center;"><em>Grafik hubungan tegangan dan arus terhadap waktu pada induktor.</em></p>
<p><strong>Baca Juga: <a href="/blog/transistor" rel="noopener">Mengenal Transistor, Si Kecil Pendobrak Zaman</a></strong></p>
<p> </p>
<p style="text-align: justify;">Berdasarkan grafik, terlihat bahwa besar tegangan pada induktor adalah nol saat arus induktornya maksimum, begitupun sebaliknya. Artinya tegangan pada induktor mencapai nilai maksimum lebih cepat seperempat periode daripada saat arus mencapai maksimumnya.</p>
<p> </p>
<h3><span style="font-size: 14pt;">Rumus Tegangan pada Induktor</span></h3>
<p style="text-align: justify;">Rumus tegangan dan arus yang mengalir pada induktor seperti berikut:</p>
<p><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Konsep%20Pelajaran%20-%20Resistor%2c%20Induktor%2c%20dan%20Kapasitor%20-%20Fisika%20Kelas%2012-08%20(2).jpg" alt="Rumus tegangan dan arus yang mengalir pada induktor" width="600" /></p>
<p> </p>
<p style="text-align: justify;">Wah, kelihatannya rumit banget tuh rumus. Eits, tenang, guys! Kalo kamu sering berlatih soal, pasti lama-lama jadi hapal di luar kepala.</p>
<p> </p>
<h3 style="font-size: 16px;"><span style="font-size: 14pt;"><strong>Contoh Soal Tegangan Induktor</strong></span></h3>
<p style="text-align: justify;">Sebuah hambatan sebesar 50 Ω, dihubungkan dengan sumber tegangan AC yang memenuhi persamaan <em>V = </em>200 Sin (200t), kuat arus rata-rata yang mengalir pada rangkaian tersebut adalah…</p>
<ol style="list-style-type: upper-alpha;">
<li>5,55 A</li>
<li>4,55 A</li>
<li>3,55 A</li>
<li>2,55 A</li>
<li>1,55 A</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p><span style="font-weight: bold;">Jawaban: </span></p>
<p style="font-weight: normal;">Diketahui pada soal:</p>
<p style="font-weight: normal;">R = 50 Ω</p>
<p style="font-weight: normal;">V = 200 sin (200t)</p>
<p style="font-weight: normal;">Persamaan tegangan tiap saat diberikan oleh</p>
<ul>
<li style="font-weight: normal;"><em> V = V<sub>maks</sub> sin ωt</em></li>
<li style="font-weight: normal;"><em>V = </em>200 sin (200t)</li>
</ul>
<p> </p>
<p>Sehingga,</p>
<ul>
<li><em>V<sub>maks </sub>= </em>200 V</li>
</ul>
<p> </p>
<p>Maka arus maksimum pada rangkaian yaitu:</p>
<p><img decoding="async" style="width: 200px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/WhatsApp%20Image%202021-10-15%20at%2014.14.31.jpeg" alt="WhatsApp Image 2021-10-15 at 14.14.31" width="200" /></p>
<p>Dengan demikian arus rata-rata dalam rangkaiannya yaitu:</p>
<p><img decoding="async" style="width: 200px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/WhatsApp%20Image%202021-10-15%20at%2014.15.34.jpeg" alt="WhatsApp Image 2021-10-15 at 14.15.34" width="200" /></p>
<p>Jadi, kuat arus rata-rata yang mengalir pada rangkaian tersebut adalah 2,55 A. Jawaban yang tepat adalah D.</p>
<p> </p>
<h2><span style="font-size: 18pt;">Rangkaian Kapasitor</span></h2>
<p style="text-align: justify;">Sebuah kapasitor memiliki karakteristik yang dapat menyimpan energi dalam bentuk muatan listrik ketika dihubungkan dengan sumber tegangan bolak-balik maupun tegangan searah.</p>
<p style="text-align: justify;"><span style="text-align: justify; background-color: transparent; font-size: 1rem;">Kapasitor yang dialiri arus bolak-balik akan timbul <strong>resistansi semu</strong> atau biasa disebut dengan <strong>reaktansi kapasitif</strong>. Besar nilai reaktansi kapasitif bergantung pada besarnya nilai kapasitansi kapasitor dan frekuensi sudut arus atau dapat dirumuskan sebagai:</span></p>
<p><img decoding="async" style="text-align: justify; background-color: transparent; font-size: 1rem; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/xc-2.png" alt="xc-2.png" /></p>
<p> </p>
<p style="text-align: justify;">Keterangan:</p>
<p style="text-align: justify;">Xc = Reaktansi kapasitif (Ω)</p>
<p style="text-align: justify;">ω = Kecepatan sudut (rad/s)</p>
<p style="text-align: justify;">L = Induktansi induktor (H)</p>
<p><strong>Baca Juga: <a href="/blog/peran-sinar-x-di-berbagai-bidang-kehidupan" rel="noopener">Peran Sinar-X di Berbagai Bidang Kehidupan</a></strong></p>
<p><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Konsep%20Pelajaran%20-%20Resistor%2c%20Induktor%2c%20dan%20Kapasitor%20-%20Fisika%20Kelas%2012-09.jpg" alt="Rangkaian kapasitor pada arus bolak-balik" width="600" /></p>
<p style="text-align: center;"><em>Rangkaian kapasitor pada arus bolak-balik.</em></p>
<p> </p>
<p style="text-align: justify;"><em><img decoding="async" style="height: auto; max-width: 100%; width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Grafik%20hubungan%20tegangan%20dan%20arus%20terhadap%20waktu%20pada%20kapasitor.jpg" alt="Grafik hubungan tegangan dan arus terhadap waktu pada kapasitor" width="600" height="600" /></em></p>
<p style="text-align: center;"><em>Grafik hubungan tegangan dan arus terhadap waktu pada kapasitor.</em></p>
<p> </p>
<p style="text-align: justify;">Berdasarkan grafik, terlihat bahwa arus pada kapasitor maksimum saat tegangan kapasitor bernilai nol, begitupun sebaliknya. Artinya, arus mencapai nilai maksimumnya seperempat periode lebih cepat daripada saat tegangan mencapai nilai maksimumnya.</p>
<p> </p>
<h3><span style="font-size: 14pt;">Rumus Tegangan pada Kapasitor</span></h3>
<p style="text-align: justify;">Rumus tegangan dan arus yang mengalir pada kapasitor seperti berikut:</p>
<p><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Konsep%20Pelajaran%20-%20Resistor%2c%20Induktor%2c%20dan%20Kapasitor%20-%20Fisika%20Kelas%2012-10%20(3).jpg" alt="Rumus tegangan dan arus yang mengalir pada kapasitor" width="600" /></p>
<p> </p>
<p>Daripada bingung, kuy kita kerjakan contoh soal di bawah ini bersama-sama!</p>
<p> </p>
<h3 style="text-align: justify; font-weight: bold; font-size: 16px;"><span style="font-size: 14pt;">Contoh Soal Tegangan Kapasitor</span></h3>
<p style="text-align: justify;"><img decoding="async" class="aligncenter" style="width: 200px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/WhatsApp%20Image%202021-10-15%20at%2013.50.06.jpeg" alt="WhatsApp Image 2021-10-15 at 13.50.06" width="200" /></p>
<p style="text-align: justify;">Kapasitas pengganti susunan kapasitor di atas adalah…</p>
<ol style="list-style-type: upper-alpha;">
<li>1,2F</li>
<li>3,0F</li>
<li>6,0F</li>
<li>9,0F</li>
<li>12,0F</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="font-weight: bold;">Jawaban:</p>
<p style="font-weight: normal;">Diketahui:</p>
<p style="font-weight: normal;">C<sub>1 </sub>= 6F</p>
<p style="font-weight: normal;">C<sub>2 </sub>= 3F</p>
<p style="font-weight: normal;">C<sub>3 </sub>= 3F</p>
<p> </p>
<p style="font-weight: normal;">Ditanya: C<sub>p</sub> = …</p>
<p style="font-weight: normal;">Kapasitor di atas disusun secara paralel, maka kapasitas pengganti memenuhi:</p>
<ul>
<li style="font-weight: normal;">C<sub>p </sub>= C1 + C2 + C3</li>
<li style="font-weight: normal;">C<sub>p </sub>= 6F + 3F + 3F</li>
<li style="font-weight: normal;"><strong>C<sub>p </sub>= 12F</strong></li>
</ul>
<p> </p>
<p style="text-align: justify;">Jadi, jawaban yang tepat adalah E. Mudah, bukan?</p>
<p style="text-align: justify;">Gimana, sekarang kamu sudah lebih paham <em>kan</em> jenis-jenis rangkaian pada rangkaian arus bolak-balik? <em>Yup</em>, rangkaian resistor, induktor dan kapasitor memiliki besar tegangan dan arus yang berbeda ketika dialiri dengan sumber tegangan bolak-balik seperti rumus yang sudah dibahas di atas.</p>
<p style="text-align: justify;">Tapi masih bingung ngga? Kalau iya, yuk langsung aja tanyain secara privat ke <strong><a href="https://www.ruangguru.com/privat/fisika">Ruangguru Privat Fisika</a></strong>. Akan ada tutor yang membantumu untuk memahami rumus serta memberikan penjelasannya. Buatlah belajar jadi praktis dari sekarang!</p>
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<li><a href="https://www.ruangguru.com/beasiswa">Beasiswa Ruangguru</a></li>
<li><a href="https://www.ruangguru.com/cicilan">Cicilan Ruangguru</a></li>
<li><a href="https://www.ruangguru.com/promo">Promo Ruangguru</a></li>
<li><a href="https://ticketing.ruangguru.com/help?request_type_id=459" target="_blank">Vulnerability Report</a></li>
<li><a href="https://www.ruangguru.com/bantuan#layanan">Layanan Pengaduan</a></li>
<li><a href="https://www.ruangguru.com/terms-conditions">Syarat & Ketentuan</a></li>
<li><a href="https://www.ruangguru.com/privacy-policy">Kebijakan Privasi</a></li>
<li><a href="https://www.ruangguru.com/about-us">Tentang Kami</a></li>
<li><a href="https://www.ruangguru.com/contact-us">Kontak Kami</a></li>
<li><a href="https://www.ruangguru.com/press">Press Kit</a></li>
<li><a href="https://www.ruangguru.com/bantuan">Bantuan</a></li>
<li><a href="https://career.ruangguru.com/">Karier</a></li>
</ul>
</nav>
</div>
<div class="col-6 col-md-3">
<nav class="footer-menu">
<p class="title">Produk Lainnya</p>
<ul type="none">
<li><a href="https://www.brainacademy.id/" target="_blank">Brain Academy</a></li>
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<li><a href="https://skillacademy.com/" target="_blank">Skill Academy</a></li>
<li><a href="https://www.ruangkerja.id/" target="_blank">Ruangkerja</a></li>
<li><a href="https://www.schoters.com/id/" target="_blank">Schoters</a></li>
<li><a href="https://www.kalananti.id/" target="_blank">Kalananti</a></li>
</ul>
</nav>
</div>
<div class="col-6 col-md-3">
<nav class="footer-menu">
<p class="title"> Coba GRATIS Aplikasi Ruangguru</p>
<div class="download-list">
<ul>
<li>
<a target="_blank" rel="nofollow" href="https://apps.apple.com/id/app/ruangguru-solusi-belajar/id1099742206?l=id">
<img src="https://cdn-web-2.ruangguru.com/static/appstore.png" loading="lazy" alt="Button App Store Footer " />
</a>
</li>
<li>
<a target="_blank" rel="nofollow" href="https://play.google.com/store/apps/details?id=com.ruangguru.livestudents&hl=in">
<img src="https://cdn-web-2.ruangguru.com/static/googleplay.png" loading="lazy" alt="Button Google Play Footer " />
</a>
</li>
<li>
<a target="_blank" rel="nofollow" href="https://appgallery.huawei.com/#/app/C102352375">
<img src="https://cdn-web-2.ruangguru.com/static/huawei.png" loading="lazy" alt="Button AppGallery Footer " />
</a>
</li>
</ul>
</div>
</nav>
</div>
</div>
</div>
</div>
<div class="d-lg-none text-center">
<nav class="footer-menu social">
<p class="title">Ikuti Kami</p>
<a target="_blank" href="https://www.instagram.com/ruangguru/">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/instagram.png?height=60&convert=webp" type="image/webp">
<source srcset="https://cdn-web-2.ruangguru.com/static/instagram.png?height=60" type="image/png">
<img src="https://cdn-web-2.ruangguru.com/static/instagram.png" loading="lazy" alt="Logo Instagram Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.facebook.com/ruanggurucom/">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/facebook.png?height=60&convert=webp" type="image/webp">
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<img src="https://cdn-web-2.ruangguru.com/static/facebook.png" loading="lazy" alt="Logo Facebook Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://twitter.com/ruangguru/">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/twitter.png?height=60&convert=webp" type="image/webp">
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<img src="https://cdn-web-2.ruangguru.com/static/twitter.png" loading=" lazy" alt="Logo Twitter Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.youtube.com/ruangguru">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/youtube.png?height=60&convert=webp" type="image/webp">
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<img src="https://cdn-web-2.ruangguru.com/static/youtube.png" loading=" lazy" alt="Logo Youtube Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.linkedin.com/company/ruangguru-com">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/linkedin.png?height=60&convert=webp" type="image/webp">
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<img src="https://cdn-web-2.ruangguru.com/static/linkedin.png" loading=" lazy" alt="Logo LinkedIn Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.tiktok.com/@ruangguru">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/tiktok.png?height=60&convert=webp" type="image/webp">
<source srcset="https://cdn-web-2.ruangguru.com/static/tiktok.png?height=60" type="image/png">
<img src="https://cdn-web-2.ruangguru.com/static/tiktok.png" loading=" lazy" alt="Logo TikTok Footer" width="32px" height="32px" />
</picture>
</a>
</nav>
</div>
<p class="footer-copyright">
© 2026 All Rights Reserved PT. Ruang Raya Indonesia
</p>
</div>
<style>
.bantuan-container {
position: relative;
}
.bantuan-element {
position: fixed;
z-index: 999;
display: flex;
align-items: flex-end;
justify-content: flex-end;
cursor: pointer;
transition: all 0.6s ease;
}
.bantuan-top {
bottom: 11rem;
right: 2rem;
}
.bantuan-bottom {
bottom: 2rem;
right: 2rem;
}
.bantuan-top-2 {
bottom: 15rem;
right: 2rem;
}
.bantuan-top-3 {
bottom: 19rem;
right: 2rem;
}
.bantuan-bottom-2 {
bottom: 5rem;
right: 2rem;
}
.bantuan-bottom-3 {
bottom: 8rem;
right: 2rem;
}
@media (min-width: 768px) {
.bantuan-element img {
width: auto;
transition: all 0.4s ease;
}
.bantuan-top img {
width: 140px;
}
.bantuan-bottom img {
width: 140px;
}
.bantuan-top-2 img,
.bantuan-top-3 img {
width: 140px;
}
.bantuan-bottom-2 img,
.bantuan-bottom-3 img {
width: 140px;
}
.bantuan-element.clicked {
bottom: 9rem;
right: 2.5rem;
}
.bantuan-element.clicked img {
width: auto;
height: 64px;
}
}
@media (max-width: 767px) {
.bantuan-top {
bottom: 8rem;
right: 1rem;
align-items: center;
}
.bantuan-bottom {
bottom: 2rem;
right: 1.25rem;
align-items: center;
}
.bantuan-top-2 {
bottom: 12rem;
right: 1rem;
align-items: center;
}
.bantuan-top-3 {
bottom: 16rem;
right: 1rem;
align-items: center;
}
.bantuan-bottom-2 {
bottom: 5rem;
right: 1.25rem;
align-items: center;
}
.bantuan-bottom-3 {
bottom: 8rem;
right: 1.25rem;
align-items: center;
}
.bantuan-element img {
width: auto;
}
.bantuan-top img,
.bantuan-top-2 img,
.bantuan-top-3 img {
width: 96px;
}
.bantuan-bottom img,
.bantuan-bottom-2 img,
.bantuan-bottom-3 img {
width: 96px;
}
}
.bantuan-element:hover {
transform: scale(1.05);
}
.bantuan-element img {
max-width: 100%;
height: auto;
}
</style>
<div id="bantuan-divs-container" style="position: relative" data-product="ruangguru" data-table="rg_floating_icon"></div>
<script>
class FloatingDivsComponent {
constructor(product = 'ruangguru', table = 'rg_floating_icon') {
this.container = document.getElementById('bantuan-divs-container');
this.floatingElements = [];
this.product = product;
this.table = table;
// Configuration
this.config = {
baseApiUrl: 'https://gw.ruangguru.com/api/v3/rdb/p_ddgy8hjx5dxsqx/rg_banner/views/',
apiKey: 'vLyK3dJrDBRmOwueX2OJXibMkgsUbBk0WS4ua2p1',
maxElements: 2,
zIndexBase: 100,
};
// Build dynamic API URL based on table parameter
this.config.apiUrl = this.buildApiUrl();
this.init();
}
buildApiUrl() {
const baseUrl = this.config.baseApiUrl;
const tableName = this.table || 'rg_floating_icon';
const queryParams =
'offset=0&limit=99999&sort=rankPosition&where=(type,eq,floating)~and(showIn,anyof,blog)~and(hide,is,false)~and(product,eq,' +
this.product +
')&nested%5Bcta%5D%5Bfields%5D=Id,name,ctaId,imageUrl,ctaLink,targetUrl';
return `${baseUrl}${tableName}?${queryParams}`;
}
async init() {
try {
await this.fetchFloatingElements();
this.renderFloatingElements();
} catch (error) {
console.error('Failed to initialize floating divs component:', error);
}
}
async fetchFloatingElements() {
try {
const options = {
method: 'GET',
headers: {
'xc-token': this.config.apiKey || 'vLyK3dJrDBRmOwueX2OJXibMkgsUbBk0WS4ua2p1',
},
};
const urlNoco = this.config.apiUrl;
const response = await fetch(urlNoco, options);
if (!response.ok) {
throw new Error(`HTTP error! status: ${response.status}`);
}
const data = await response.json();
this.floatingElements = this.processApiResponse(data);
} catch (error) {
console.error('Error fetching floating elements:', error);
throw error;
}
}
processApiResponse(data) {
if (!data || !data.list || !Array.isArray(data.list)) {
return [];
}
console.log(data.list);
// Ensure we only get maximum 2 elements
const limitedElements = data.list.slice(0, this.config.maxElements);
return limitedElements;
}
renderFloatingElements() {
if (!this.container || this.floatingElements.length === 0) {
return;
}
// Additional safeguard: ensure we never render more than maxElements
const elementsToRender = this.floatingElements.slice(0, this.config.maxElements);
// Clean up existing elements and their event listeners
this.cleanupExistingElements();
// Clear existing content
this.container.innerHTML = '';
elementsToRender.forEach((element, index) => {
const floatingDiv = this.createFloatingDiv(element, index);
this.container.appendChild(floatingDiv);
});
}
cleanupExistingElements() {
// Clear existing elements (no need for event listener cleanup with CSS approach)
const existingElements = this.container.querySelectorAll('[data-floating-element]');
existingElements.forEach(element => {
element.remove();
});
}
createFloatingDiv(element, index) {
const div = document.createElement('div');
const cta = element.cta[0]; // Use the first CTA
// Add data attribute for cleanup tracking
div.setAttribute('data-floating-element', 'true');
// Apply CSS classes based on rankPosition
const positionClass = this.getPositionClass(element.rankPosition, index);
div.className = `bantuan-element ${positionClass}`;
div.style.zIndex = this.config.zIndexBase + index;
// Create the link and image
const link = document.createElement('a');
link.href = 'https://cta.ruangguru.com/' + cta.ctaId || '#';
link.target = '_blank';
// Add tracking attributes
link.setAttribute('data-tracking-event-type', 'landing_page__core__item_click');
link.setAttribute(
'data-tracking-context',
JSON.stringify({
product_name: this.product,
cta_action: 'redirection',
cta_action_detail: link.href,
item_type: 'floating',
item_name: element.name || 'Floating element',
item_category: 'payment',
item_position: index,
item_serial: null,
section_type: 'floating_item',
section_position: 'body',
section_name: 'floating_item',
})
);
const img = document.createElement('img');
img.src = element.imageUrl + '?h=200&convert=webp';
img.alt = element.name || 'Floating element';
img.loading = 'lazy';
// Add click tracking
link.addEventListener('click', () => {
this.trackClick(element, cta);
});
link.appendChild(img);
div.appendChild(link);
return div;
}
getPositionClass(rankPosition, index) {
// Define positioning classes based on rankPosition
if (rankPosition === 1) {
return 'bantuan-top'; // Top position
} else if (rankPosition === 2) {
return 'bantuan-bottom'; // Bottom position
} else {
// For additional elements, distribute them evenly
return `bantuan-${index % 2 === 0 ? 'top' : 'bottom'}-${Math.floor(index / 2) + 1}`;
}
}
trackClick(element, cta) {
// Implement click tracking logic here
console.log('Floating element clicked:', {
elementId: element.Id,
elementName: cta.name,
ctaId: cta.ctaId,
targetUrl: cta.targetUrl,
});
}
// Public method to manually refresh
async refresh() {
try {
await this.fetchFloatingElements();
this.renderFloatingElements();
} catch (error) {
console.error('Failed to refresh floating elements:', error);
throw error;
}
}
// Public method to get current floating elements
getFloatingElements() {
return [...this.floatingElements];
}
}
// Initialize the component when DOM is ready
document.addEventListener('DOMContentLoaded', () => {
// Get product and table parameters from data attributes
const container = document.getElementById('bantuan-divs-container');
const product = container.getAttribute('data-product') || 'ruangguru';
const table = container.getAttribute('data-table') || 'rg_floating_icon';
new FloatingDivsComponent(product, table);
});
// Export for use in other modules if needed
if (typeof module !== 'undefined' && module.exports) {
module.exports = FloatingDivsComponent;
}
</script> <div id="wp-install-nudge" style="
position: fixed;
bottom: 0rem;
right: 0;
z-index: 999;
cursor: pointer;
"></div>
<script>
(function (w, d, s, o, f, js, fjs) {
w['Sales-Nudge-Widget'] = o; w[o] = w[o] || function () { (w[o].q = w[o].q || []).push(arguments) };
js = d.createElement(s), fjs = d.getElementsByTagName(s)[0];
js.id = o; js.src = f; js.async = 1; fjs.parentNode.insertBefore(js, fjs);
}(window, document, 'script', 'wpInstallNudge', 'https://cdn-web-2.ruangguru.com/sales-nudge/6198a95130/dist/widget.js'));
wpInstallNudge('init', { targetElementId: 'wp-install-nudge', clientTarget: 'ruangguru_blog' });
</script>
<script>
// note: disabled due to auto reload page
// var lastScrollTop = 0;
// $(window).scroll(function(event){
// var st = $(this).scrollTop();
// if (st > lastScrollTop){
// $('#wp-install-nudge').slideDown( "slow", function() {});
// } else {
// $('#wp-install-nudge').slideUp( "slow", function() {});
// }
// lastScrollTop = st;
// });
// $(document).ready(function () {
// $("#wp-install-nudge").hide();
// });
$('#wp-install-nudge').click(function(){
Analytics.track("promotion__install_nudge__click",
{
user_email: "ruangguru@blog.com",
cta_link: widgetData.dataConfig.target_link
}).catch((err) => {
console.log("tracker error", err);
});
});
</script>
</footer>
<div id="__next"></div>
<script type="speculationrules">
{"prefetch":[{"source":"document","where":{"and":[{"href_matches":"\/blog\/*"},{"not":{"href_matches":["\/blog\/wp-*.php","\/blog\/wp-admin\/*","\/blog\/wp-content\/uploads\/*","\/blog\/wp-content\/*","\/blog\/wp-content\/plugins\/*","\/blog\/wp-content\/themes\/ruangguru\/*","\/blog\/*\\?(.+)"]}},{"not":{"selector_matches":"a[rel~=\"nofollow\"]"}},{"not":{"selector_matches":".no-prefetch, .no-prefetch a"}}]},"eagerness":"conservative"}]}
</script>
<script>
async function getCtaDetails(ctaIds) {
const endpoint =
" https://gw.ruangguru.com/api/v3/rdb/p_ddgy8hjx5dxsqx/CTA/views/CTA?offset=0&limit=10&where=(ctaId,in," + ctaIds.toString() + ")";
try {
const response = await fetch(endpoint, {
headers: {
"xc-token": "-hG2nBDJzSj0agSgNtcJx97M4F02y54nUMoY6plJ",
},
});
const data = await response.json();
const ctaList = data?.list || [];
const ctaMap = new Map();
for (const ctaData of ctaList) {
ctaMap.set(ctaData.ctaId, ctaData);
}
return ctaMap;
} catch (error) {
console.error("Error fetching CTA details:", error);
return new Map();
}
}
async function replaceCTA() {
const regex = /{{cta\((‘(.*?)’|“(.*?)”)\)}}/g;
const bodyHTML = document.body.innerHTML;
const matches = Array.from(bodyHTML.matchAll(regex));
const ctaIds = matches.map((match) => {
let ctaId = match[2] ?? match[3];
return ctaId;
});
const ctaMap = await getCtaDetails(ctaIds);
const replacedHTML = bodyHTML.replace(regex, (match, _inner, ctaId1, ctaId2) => {
const ctaId = ctaId1 ?? ctaId2;
const ctaData = ctaMap.get(ctaId);
if (ctaData) {
return `<a href="https://cta.ruangguru.com/${ctaData.ctaId}" target="_${ctaData.targetType}" style="position:relative;display:inline-block;">
<img src="${ctaData.imageUrl}" loading="lazy" alt="${ctaData.altText}" />
</a>`;
} else {
return match;
}
});
document.body.innerHTML = replacedHTML;
}
</script>
<meta name="author" content="Ruangguru Tech Team">
<!-- Google Tag Manager (noscript) -->
<noscript><iframe src="https://www.googletagmanager.com/ns.html?id=GTM-PVNLZFT" height="0" width="0" style="display:none;visibility:hidden"></iframe></noscript>
<!-- Tracker -->
<script type="text/javascript" src="https://cdn-web-2.ruangguru.com/landing-page-web/public/staticpages/global-assets/js/cta.js"></script>
<script src="https://unpkg.com/@dotlottie/player-component@latest/dist/dotlottie-player.mjs" type="module"></script>
</body>
</html>