Yuk, siap hadapi Penilaian Tengah Semester dengan latihan soal dan pembahasan PTS kelas 6 Semester Genap tahun 2025 berikut ini!
—
MATEMATIKA
Topik: Luas dan Volume Bangun Ruang
Subtopik: Limas
1. Perhatikan gambar berikut!
Gambar di atas merupakan jaring-jaring dari ….
- limas segitiga
- limas segi empat
- prisma segitiga
- prisma segi empat
Jawaban: A
Pembahasan:
Apabila jaring-jaring tersebut dirangkai, maka akan membentuk bangun seperti gambar berikut.
Gambar bangun di atas adalah limas segitiga.
Dengan demikian, gambar jaring-jaring pada soal adalah jaring-jaring limas segitiga.
Jadi, jawaban yang tepat adalah A.
Topik: Luas dan Volume Bangun Ruang (II)
Subtopik: Kerucut
2. Sebuah kerucut memiliki volume . Jika panjang jari-jari kerucut tersebut 14 cm, tinggi kerucut tersebut adalah … cm.
- 18
- 21
- 24
- 35
Jawaban: C
Pembahasan:
Diketahui volume kerucut adalah dan jari-jarinya 14 cm.
Tinggi kerucut (t) dapat dihitung sebagai berikut.
Dengan demikian, tinggi kerucut tersebut adalah 24 cm.
Jadi, jawaban yang tepat adalah C.
Topik: Luas dan Volume Bangun Ruang (II)
Subtopik: Bola
3. Andi memiliki bola bervolume . Luas permukaan bola milik Andi adalah … . (π = 3,14)
- 706
- 1.560,5
- 2.826
- 3.215,36
Jawaban: C
Pembahasan:
Pertama, hitung jari-jari bola dengan menggunakan rumus volume bola sebagai berikut.
Setelah diperoleh jari-jari bola, yaitu 15 cm, maka luas permukaan bola dapat diperoleh dengan perhitungan berikut.
Jadi, jawaban yang tepat adalah C.
Topik: Aplikasi Luas dan Volume Bangun Ruang
Subtopik: Volume Bangun Ruang Gabungan
4. Perhatikan gambar berikut!
Jika perbandingan tinggi tabung dan tinggi kerucut adalah 7:5, volume bangun tersebut adalah …
- 9.856
- 21.354,67
- 22.176
- 29.568,67
Jawaban: B
Pembahasan:
Diketahui diameter alas kerucut dan tabung tersebut adalah 28 cm, maka jari-jarinya adalah r = 14 cm.
Karena perbandingan tinggi tabung dan tinggi kerucut adalah 7:5, maka didapat tinggi tabung dan tinggi kerucut sebagai berikut.
Berdasarkan keterangan di atas, volume gabungan dari kedua bangun tersebut dapat dihitung sebagai berikut.
Jadi, jawaban yang tepat adalah B.
Topik: Aplikasi Luas dan Volume Bangun Ruang
Subtopik: Luas Permukaan Bangun Ruang Gabungan
5. Perhatikan gambar berikut!
Luas permukaan bangun ruang di atas adalah … . (π = 3,14)
- 3.271
- 3.140
- 3.107
- 3.082
Jawaban: B
Pembahasan:
Perhatikan gambar berikut!
Bangun ruang gabungan di atas, terdiri dari dua buah setengah bola atau dapat digabungkan menjadi dan satu buah tabung tanpa alas dan tutup.
Untuk menghitung luas permukaan seluruh bangun, hitung luas permukaan masing-masing bangun.
Dari gambar, diperoleh informasi seperti berikut.
Diameter bola = diameter tabung = 20 cm, maka jari-jari bola = jari-jari tabung =
Panjang seluruh bangun ruang = 50 cm, maka tinggi tabung adalah
Selanjutnya, tentukan luas permukaaan bola!
Perhatikan perhitungan berikut!
Kemudian, hitung luas permukaan tabung tanpa alas dan tutup.
Dengan demikian, luas permukaan gabungan bangun ruang tersebut adalah sebagai berikut.
Jadi, jawaban yang tepat adalah B.
TEMATIK
Topik: Menuju Masyarakat Sehat
Subtopik: Lingkungan Sehat, Masyarakat Sehat
1. Contoh zat yang tidak berbahaya bagi kesehatan manusia adalah ….
- formalin
- boraks
- alkohol
- protein
Jawaban: D
Pembahasan:
Protein berguna untuk membantu pembentukan sel jaringan tubuh yang baru. Dengan demikian, jawaban yang tepat adalah D.
Adapun formalin, boraks, dan alkohol merupakan zat yang berbahaya bagi kesehatan manusia. Formalin berbahaya karena menyebabkan gangguan persyarafan berupa susah tidur, mudah lupa, dan sulit berkonsentrasi. Boraks berbahaya karena dapat menyebabkan gangguan otak, hati, dan ginjal. Sedangkan alkohol dapat merusak fungsi hati/liver.
Jadi, jawaban yang tepat adalah D.
Topik: Menuju Masyarakat Sehat
Subtopik: Masyarakat Sehat, Negara Kuat
2. Bacalah teks laporan investigasi di bawah ini dengan saksama!
Selamat pagi para pemirsa!
Museum Karst Dunia, Pracimantoro, Wonogiri, yang merupakan museum karst terbesar di Asia Tenggara mengalami kebanjiran. Hampir setengah gedung direndam air hasil luapan sungai yang berada di sebelah barat museum. Tidak ada korban dalam kejadian ini, tetapi kerugian ditaksir ratusan juta rupiah.
Isi berita di atas adalah …
- Museum Karst Dunia di Pracimantoro adalah museum karst terbesar di Asia Tenggara.
- Kerugian yang dialami pengelola Museum Karst Dunia di Pracimantoro.
- Museum Karst Dunia di Pracimantoro mengalami kebanjiran.
- Kebanjiran di Museum Karst Dunia menyebabkan kerugian.
Jawaban: C
Pembahasan:
Berita dari teks laporan investigasi di atas membicarakan Museum Karst Dunia di Pracimantoro yang mengalami kebanjiran sehingga mengakibatkan kerugian yang dialami oleh pihak pengelola. Hal yang dibicarakan itulah yang menjadi isi berita dalam teks tersebut.
Jadi, jawaban yang tepat adalah C.
Topik: Menuju Masyarakat Sehat
Subtopik: Masyarakat Sehat, Negara Kuat
3. Perhatikan teks di bawah ini!
Anisa berjalan-jalan di kampung halamannya di Desa Sukajaya. Ternyata masyarakat di desa sedang melakukan kegiatan pengolahan pupuk. Pupuk di sana terdiri dari dua jenis, yaitu pupuk organik dan pupuk kandang. Pupuk organik biasanya dikenal sebagai pupuk kompos yang dibuat dari sampah-sampah dedaunan. Biasanya masyarakat akan menyapu dedaunan kering, kemudian membuangnya ke pembuangan akhir di tempat pengolahan pupuk. Berbeda dengan pupuk kandang yang terbuat dari kotoran-kotoran hewan.
Berdasarkan teks tersebut, manfaat yang dapat dirasakan oleh masyarakat di Desa Sukajaya dengan adanya pembuatan pupuk tersebut adalah ….
- mencegah timbulnya tanah longsor
- tubuh menjadi lebih sehat dan bugar
- lingkungan menjadi bersih dan subur
- mencegah balita terserang penyakit polio
Jawaban: C
Pembahasan:
Setelah melihat pengolahan pupuk di Desa Sukajaya, Anisa menyadari bahwa pembuatan pupuk dapat memberi banyak manfaat. Sebelum mengolah pupuk organik, masyarakat akan menyapu dedaunan-dedaunan kering sehingga lingkungan menjadi bersih. Setelah dedaunan kering dikumpulkan, dedaunan tersebut kemudian diolah menjadi pupuk organik. Pupuk organik yang sudah jadi digunakan untuk menyuburkan tanah sehingga tanaman bisa tumbuh sehat.
Jadi, jawaban yang tepat adalah C.
Topik: Kepemimpinan
Subtopik: Ayo, Memimpin!
4. Benda berikut ini yang memanfaatkan sifat konduktor dan isolator adalah ….
- setrika
- ketel
- panci alumunium
- cangkir
Jawaban: A
Pembahasan:
Setrika merupakan benda yang memanfaatkan sifat konduktor dan isolator. Bagian setrika yang memanfaatkan isolator yaitu bagian pegangan setrika yang bertujuan agar panas tidak mudah terkena oleh tangan. Sementara bagian setrika yang memanfaatkan konduktor yaitu bagian bawah setrika yang digunakan untuk menyetrika pakaian sehingga harus menggunakan bahan material yang mudah untuk menghantarkan panas.
Jadi, jawaban yang tepat adalah A.
Topik: Kepemimpinan
Subtopik: Kepemimpinan di Sekitarku
5. Bacalah potongan teks pidato di berikut ini dengan saksama!
- Bapak dan Ibu Guru yang saya cintai, kami mengucapkan terima kasih atas bimbingan Bapak dan Ibu Guru sehingga acara ini berjalan dengan lancar.
- Teman-teman yang saya kasihi, saya ingin mengucapkan terima kasih atas waktu yang sudah teman-teman sisihkan selama ini, terutama untuk mewujudkan terselenggaranya acara ini.
- Bapak dan Ibu Guru yang saya hormati, kami mohon maaf yang sebesar-besarnya jika selama kami dididik oleh Bapak dan Ibu Guru ada kata dan perilaku kami yang kurang berkenan.
- Adik-adik kelas yang saya banggakan, acara ini sungguh bermanfaat bagi kita semua agar kalian semua bisa saling menghargai sehingga bisa menambah sahabat.
Cuplikan pidato yang tepat digunakan untuk acara perpisahan sekolah adalah nomor ….
- 1
- 2
- 3
- 4
Jawaban: C
Pembahasan:
Cuplikan pidato nomor 3 tepat diucapkan dalam perpisahan karena cuplikan pidato itu berisi ucapan terima kasih atas didikan Bapak/Ibu Guru selama di sekolah. Ucapan terima kasih kepada Bapak/Ibu Guru biasanya disampaikan saat pidato perpisahan di sekolah.
Jadi, jawaban yang tepat adalah C.
Mudah dipahami kan? Itulah tadi berbagai soal dan pembahasan yang bisa kamu pakai sebagai latihan untuk menghadapi PTS (Penilaian Tengah Semester). Semoga berguna! Mau belajar lebih banyak dengan mengerjakan latihan soal? Kamu bisa cek ruanguji untuk mendapatkan try out yang bisa bantu nge-boost nilai PTS kamu!
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<h1 class="content-title">
Contoh Soal & Jawaban PTS Kelas 6 SD Semester Genap 2025 </h1>
<div class="content-meta">
<p class="content-author"><a href="https://www.ruangguru.com/blog/author/shabrina-alfari" class="">Shabrina Alfari</a> </p>
<p class="content-info"><span>March 3, 2025 • </span> <span>6 minutes read</span></p>
<br />
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<p><img decoding="async" class="aligncenter" style="width: 820px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Latihan%20soal%20-%20Latihan%20Soal%20PTS%20kelas%206%20SD-01.jpg" alt="Latihan Soal PTS kelas 6 SD" /></p>
<blockquote>
<p style="text-align: center;"><em>Yuk, siap hadapi Penilaian Tengah Semester dengan latihan soal dan pembahasan PTS kelas 6 Semester Genap tahun 2025 berikut ini!</em></p>
</blockquote>
<p style="text-align: center;">—</p>
<p> </p>
<p style="text-align: center;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<h2 style="text-align: center;"><span style="font-size: 18pt;">MATEMATIKA</span></h2>
<p> </p>
<p style="text-align: justify;"><strong>Topik: <a href="/blog/kedudukan-titik-garis-dan-bidang-pada-bangun-ruang" target="_blank" rel="noopener">Luas dan Volume Bangun Ruang</a></strong></p>
<p style="text-align: justify;"><strong>Subtopik: Limas</strong></p>
<p> </p>
<p style="text-align: justify;"><strong style="background-color: transparent;">1. Perhatikan gambar berikut!</strong></p>
<p style="text-align: justify;"><img decoding="async" style="width: 222px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/1-Feb-09-2022-04-18-01-74-AM.png" alt="1-Feb-09-2022-04-18-01-74-AM" width="222" /></p>
<p style="text-align: justify;">Gambar di atas merupakan jaring-jaring dari ….<img decoding="async" src="https://lh4.googleusercontent.com/Xh_s9qceI_enWy2Dn6aPbf36j07Vwdw91FSpT2Le43KPQPU-r5t-7B2NbjfCnn6OvuQRRQEWOXRScixkH85xR-9wAPEdJeE6sQ9vYFn8fNb7V4M97B5PWtjNluWqTLBhImsnnSvq" width="4" height="4" /></p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="1">limas segitiga</li>
<li aria-level="1">limas segi empat</li>
<li aria-level="1">prisma segitiga</li>
<li aria-level="1">prisma segi empat</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban: A<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan:</strong></p>
<p style="text-align: justify;">Apabila jaring-jaring tersebut dirangkai, maka akan membentuk bangun seperti gambar berikut.</p>
<p style="text-align: center;"><img decoding="async" style="width: 192px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/2-Feb-09-2022-04-18-01-78-AM.png" alt="2-Feb-09-2022-04-18-01-78-AM" width="192" /></p>
<p style="text-align: justify;">Gambar bangun di atas adalah limas segitiga.</p>
<p style="text-align: justify;">Dengan demikian, gambar jaring-jaring pada soal adalah jaring-jaring <strong>limas segitiga</strong>.</p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah A.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Luas dan Volume Bangun Ruang (II)</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Kerucut</strong></p>
<p> </p>
<p style="text-align: justify;"><span style="background-color: transparent;">2. Sebuah kerucut memiliki volume <img decoding="async" style="width: 77px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/3-Feb-09-2022-04-19-54-00-AM.png" alt="3-Feb-09-2022-04-19-54-00-AM" width="77" />. Jika panjang jari-jari kerucut tersebut 14 cm, tinggi kerucut tersebut adalah … cm. <img decoding="async" style="width: 72px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/5-Feb-09-2022-04-20-25-50-AM.png" alt="5-Feb-09-2022-04-20-25-50-AM" width="72" /></span></p>
<ol style="list-style-type: upper-alpha;">
<li>18</li>
<li>21</li>
<li>24</li>
<li>35<strong><br />
</strong></li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban: C<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan:</strong></p>
<p style="text-align: justify;">Diketahui volume kerucut adalah <span style="background-color: transparent;"><img decoding="async" style="width: 77px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/3-Feb-09-2022-04-19-54-00-AM.png" alt="3-Feb-09-2022-04-19-54-00-AM" width="77" /></span> dan jari-jarinya 14 cm.</p>
<p style="text-align: justify;">Tinggi kerucut (t) dapat dihitung sebagai berikut.</p>
<p style="text-align: justify;"><img decoding="async" style="width: 225px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/4-Feb-09-2022-04-19-54-06-AM.png" alt="4-Feb-09-2022-04-19-54-06-AM" width="225" /></p>
<p style="text-align: justify;">Dengan demikian, tinggi kerucut tersebut adalah 24 cm.</p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah C.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Luas dan Volume Bangun Ruang (II)</strong></p>
<p style="text-align: justify;"><strong>Subtopik: <a href="/blog/volume-dan-luas-permukaan-bola" target="_blank" rel="noopener">Bola</a></strong></p>
<p> </p>
<p style="text-align: justify;"><span style="background-color: transparent;">3. Andi memiliki bola bervolume <img decoding="async" style="width: 84px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/6-Feb-09-2022-04-22-42-69-AM.png" alt="6-Feb-09-2022-04-22-42-69-AM" width="84" /></span><span style="font-size: 11px;">.</span><span style="background-color: transparent;"> Luas permukaan bola milik Andi adalah … <img decoding="async" style="width: 29px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/7-Feb-09-2022-04-22-42-74-AM.png" alt="7-Feb-09-2022-04-22-42-74-AM" width="29" />. (π = 3,14) </span></p>
<ol style="list-style-type: upper-alpha;">
<li>706</li>
<li>1.560,5</li>
<li>2.826</li>
<li>3.215,36</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban: C<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan:</strong></p>
<p style="text-align: justify;">Pertama, hitung jari-jari bola dengan menggunakan rumus volume bola sebagai berikut.</p>
<p style="text-align: center;"><img decoding="async" style="width: 239px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/8-Feb-09-2022-04-22-42-73-AM.png" alt="8-Feb-09-2022-04-22-42-73-AM" width="239" /></p>
<p style="text-align: justify;">Setelah diperoleh jari-jari bola, yaitu 15 cm, maka luas permukaan bola dapat diperoleh dengan perhitungan berikut.</p>
<p style="text-align: center;"><img decoding="async" style="width: 264px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/9-Feb-09-2022-04-22-42-77-AM.png" alt="9-Feb-09-2022-04-22-42-77-AM" width="264" /></p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah C.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Aplikasi Luas dan Volume Bangun Ruang</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Volume <a href="/blog/rumus-kubus-dan-balok" target="_blank" rel="noopener">Bangun Ruang Gabungan</a></strong></p>
<p> </p>
<p style="text-align: justify;"><strong style="background-color: transparent;">4. Perhatikan gambar berikut!</strong></p>
<p style="text-align: center;"><strong style="background-color: transparent;"><img decoding="async" style="width: 201px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/10-Feb-09-2022-04-25-48-79-AM.png" alt="10-Feb-09-2022-04-25-48-79-AM" width="201" /></strong></p>
<p style="text-align: justify;">Jika perbandingan tinggi tabung dan tinggi kerucut adalah 7:5, volume bangun tersebut adalah … <img decoding="async" style="width: 103px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/11-Feb-09-2022-04-25-48-72-AM.png" alt="11-Feb-09-2022-04-25-48-72-AM" width="103" /></p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="1">9.856</li>
<li aria-level="1">21.354,67</li>
<li aria-level="1">22.176</li>
<li aria-level="1">29.568,67</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban: B</strong></p>
<p style="text-align: justify;"><strong>Pembahasan:</strong></p>
<p style="text-align: justify;">Diketahui diameter alas kerucut dan tabung tersebut adalah 28 cm, maka jari-jarinya adalah r = 14 cm.</p>
<p style="text-align: justify;">Karena perbandingan tinggi tabung dan tinggi kerucut adalah 7:5, maka didapat tinggi tabung dan tinggi kerucut sebagai berikut.</p>
<p style="text-align: justify;"><img decoding="async" style="width: 297px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/12-Feb-09-2022-04-25-48-77-AM.png" alt="12-Feb-09-2022-04-25-48-77-AM" width="297" /></p>
<p style="text-align: justify;">Berdasarkan keterangan di atas, volume gabungan dari kedua bangun tersebut dapat dihitung sebagai berikut.</p>
<p style="text-align: center;"><strong> <img decoding="async" style="width: 284px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/13-Feb-09-2022-04-25-49-64-AM.png" alt="13-Feb-09-2022-04-25-49-64-AM" width="284" /></strong></p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah B.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Aplikasi Luas dan Volume Bangun Ruang</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Luas Permukaan Bangun Ruang Gabungan</strong></p>
<p> </p>
<p style="text-align: justify;"><strong style="background-color: transparent;">5. Perhatikan gambar berikut!</strong></p>
<p style="text-align: center;"><img decoding="async" style="width: 315px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/14-Feb-09-2022-04-30-16-17-AM.png" alt="14-Feb-09-2022-04-30-16-17-AM" width="315" /></p>
<p style="text-align: justify;">Luas permukaan bangun ruang di atas adalah … <img decoding="async" style="width: 29px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/7-Feb-09-2022-04-22-42-74-AM.png" alt="7-Feb-09-2022-04-22-42-74-AM" width="29" />. (<span style="background-color: transparent;">π</span> = 3,14)</p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="2">3.271</li>
<li aria-level="2">3.140</li>
<li aria-level="2">3.107</li>
<li aria-level="2">3.082</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban: B<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan:</strong></p>
<p style="text-align: justify;">Perhatikan gambar berikut!</p>
<p style="text-align: center;"><img decoding="async" style="width: 363px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/15-Feb-09-2022-04-30-16-21-AM.png" alt="15-Feb-09-2022-04-30-16-21-AM" width="363" /></p>
<p style="text-align: justify;">Bangun ruang gabungan di atas, terdiri dari dua buah setengah bola atau dapat digabungkan menjadi <img decoding="async" style="width: 222px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/16-Feb-09-2022-04-30-16-54-AM.png" alt="16-Feb-09-2022-04-30-16-54-AM" width="222" /> dan satu buah tabung tanpa alas dan tutup.</p>
<p style="text-align: justify;">Untuk menghitung luas permukaan seluruh bangun, hitung luas permukaan masing-masing bangun.</p>
<p style="text-align: justify;">Dari gambar, diperoleh informasi seperti berikut.</p>
<p style="text-align: justify;">Diameter bola = diameter tabung = 20 cm, maka jari-jari bola = jari-jari tabung = <img decoding="async" style="width: 111px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/17-Feb-09-2022-04-30-16-16-AM.png" alt="17-Feb-09-2022-04-30-16-16-AM" width="111" /></p>
<p style="text-align: justify;">Panjang seluruh bangun ruang = 50 cm, maka tinggi tabung adalah <img decoding="async" style="width: 229px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/18-Feb-09-2022-04-30-16-18-AM.png" alt="18-Feb-09-2022-04-30-16-18-AM" width="229" /></p>
<p style="text-align: justify;">Selanjutnya, tentukan luas permukaaan bola!</p>
<p style="text-align: justify;">Perhatikan perhitungan berikut!</p>
<p style="text-align: center;"> <img decoding="async" style="width: 210px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/19-Feb-09-2022-04-30-16-23-AM.png" alt="19-Feb-09-2022-04-30-16-23-AM" width="210" /></p>
<p style="text-align: justify;">Kemudian, hitung luas permukaan tabung tanpa alas dan tutup.</p>
<p style="text-align: center;"> <img decoding="async" style="width: 348px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/20-Feb-09-2022-04-30-16-30-AM.png" alt="20-Feb-09-2022-04-30-16-30-AM" width="348" /></p>
<p style="text-align: justify;">Dengan demikian, luas permukaan gabungan bangun ruang tersebut adalah sebagai berikut.</p>
<p style="text-align: center;"><img decoding="async" style="width: 238px;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/21-Feb-09-2022-04-30-16-52-AM.png" alt="21-Feb-09-2022-04-30-16-52-AM" width="238" /></p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah B.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<h2 style="text-align: center;"><span style="font-size: 18pt;"><strong>TEMATIK</strong></span></h2>
<p> </p>
<p style="text-align: justify;"><strong>Topik: Menuju Masyarakat Sehat</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Lingkungan Sehat, Masyarakat Sehat</strong></p>
<p> </p>
<p style="text-align: justify;">1. Contoh zat yang tidak berbahaya bagi kesehatan manusia adalah ….</p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="1">formalin</li>
<li aria-level="1">boraks</li>
<li aria-level="1">alkohol</li>
<li aria-level="1">protein</li>
</ol>
<p style="text-align: justify;"><strong> </strong></p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban</strong><strong>: D</strong></p>
<p style="text-align: justify;"><strong>Pembahasan</strong><strong>:</strong></p>
<p style="text-align: justify;">Protein berguna untuk membantu pembentukan sel jaringan tubuh yang baru. <strong>Dengan demikian, jawaban yang tepat adalah D. </strong></p>
<p style="text-align: justify;">Adapun formalin, boraks, dan alkohol merupakan zat yang berbahaya bagi kesehatan manusia. Formalin berbahaya karena menyebabkan gangguan persyarafan berupa susah tidur, mudah lupa, dan sulit berkonsentrasi. Boraks berbahaya karena dapat menyebabkan gangguan otak, hati, dan ginjal. Sedangkan alkohol dapat merusak fungsi hati/liver.</p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah D.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Menuju Masyarakat Sehat</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Masyarakat Sehat, Negara Kuat</strong></p>
<p> </p>
<p style="text-align: justify;"><strong>2. Bacalah teks laporan investigasi di bawah ini dengan saksama!</strong><strong><img decoding="async" src="https://lh3.googleusercontent.com/AsQkNqsT_l_OU-2DVFJJDFug5qlSd9PRXpK4CQG8aITjXfMiB4aXH0GOPySdpgb9mP-lYaGirOA1bk1W_S2tqC4_MgPYbhj1DCveMmqR7Zy6YK1ukQaSaGPZhE1NaqvK1g_pUkJd" width="4" height="5" /></strong><strong> </strong></p>
<p style="text-align: justify;">Selamat pagi para pemirsa!</p>
<p style="text-align: justify;">Museum Karst Dunia, Pracimantoro, Wonogiri, yang merupakan museum karst terbesar di Asia Tenggara mengalami kebanjiran. Hampir setengah gedung direndam air hasil luapan sungai yang berada di sebelah barat museum. Tidak ada korban dalam kejadian ini, tetapi kerugian ditaksir ratusan juta rupiah.<img decoding="async" src="https://lh5.googleusercontent.com/IT9p3RWIH58fsI9ORw8dzMj-Cc2RMYaRqK9i2kfgjMPw581_cE6C7uldbAZX3Emip78S4z3nbX3CJmrHTi3lqaG7-Hcgr0eitti9-D4JSMScDhgjVumlSjXED8XONIlYRvUKEd2_" width="4" height="5" /><strong> </strong></p>
<p style="text-align: justify;">Isi berita di atas adalah …</p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="1">Museum Karst Dunia di Pracimantoro adalah museum karst terbesar di Asia Tenggara.</li>
<li aria-level="1">Kerugian yang dialami pengelola Museum Karst Dunia di Pracimantoro.</li>
<li aria-level="1">Museum Karst Dunia di Pracimantoro mengalami kebanjiran.</li>
<li aria-level="1">Kebanjiran di Museum Karst Dunia menyebabkan kerugian.</li>
</ol>
<p> </p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban</strong><strong>: C<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan</strong><strong>:</strong></p>
<p style="text-align: justify;">Berita dari teks laporan investigasi di atas membicarakan Museum Karst Dunia di Pracimantoro yang mengalami kebanjiran sehingga mengakibatkan kerugian yang dialami oleh pihak pengelola. Hal yang dibicarakan itulah yang menjadi isi berita dalam teks tersebut.</p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah C.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Menuju Masyarakat Sehat</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Masyarakat Sehat, Negara Kuat</strong></p>
<p> </p>
<p style="text-align: justify;"><strong>3. Perhatikan teks di bawah ini!</strong></p>
<p style="text-align: justify;">Anisa berjalan-jalan di kampung halamannya di Desa Sukajaya. Ternyata masyarakat di desa sedang melakukan kegiatan pengolahan pupuk. Pupuk di sana terdiri dari dua jenis, yaitu pupuk organik dan pupuk kandang. Pupuk organik biasanya dikenal sebagai pupuk kompos yang dibuat dari sampah-sampah dedaunan. Biasanya masyarakat akan menyapu dedaunan kering, kemudian membuangnya ke pembuangan akhir di tempat pengolahan pupuk. Berbeda dengan pupuk kandang yang terbuat dari kotoran-kotoran hewan.</p>
<p style="text-align: justify;">Berdasarkan teks tersebut, manfaat yang dapat dirasakan oleh masyarakat di Desa Sukajaya dengan adanya pembuatan pupuk tersebut adalah ….</p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="1">mencegah timbulnya tanah longsor</li>
<li aria-level="1">tubuh menjadi lebih sehat dan bugar</li>
<li aria-level="1">lingkungan menjadi bersih dan subur</li>
<li aria-level="1">mencegah balita terserang penyakit polio</li>
</ol>
<p style="text-align: justify;"><strong> </strong></p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban</strong><strong>: C<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan</strong><strong>:</strong></p>
<p style="text-align: justify;">Setelah melihat pengolahan pupuk di Desa Sukajaya, Anisa menyadari bahwa pembuatan pupuk dapat memberi banyak manfaat. Sebelum mengolah pupuk organik, masyarakat akan menyapu dedaunan-dedaunan kering sehingga<strong> lingkungan menjadi bersih.</strong> Setelah dedaunan kering dikumpulkan, dedaunan tersebut kemudian diolah menjadi pupuk organik. Pupuk organik yang sudah jadi digunakan untuk<strong> menyuburkan tanah</strong> sehingga tanaman bisa tumbuh sehat.<img loading="lazy" decoding="async" src="https://lh6.googleusercontent.com/KMVsDJ2d-o4n8tefzHf8RQ_Cq2mSuQV_VKIPpPh0fuQpcIVf7X1liM-03VCUrJxaXPUd758qvnIXCTN1Sc-TJaSzjuqpefsfjAahuHbpjRf7-Dq8VGr-I98SAys4B3Z5BxO-xHv6" width="4" height="5" /></p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah C.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Kepemimpinan</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Ayo, Memimpin!</strong></p>
<p> </p>
<p style="text-align: justify;">4. Benda berikut ini yang memanfaatkan sifat konduktor dan isolator adalah ….</p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="1">setrika</li>
<li aria-level="1">ketel</li>
<li aria-level="1">panci alumunium</li>
<li aria-level="1">cangkir</li>
</ol>
<p style="text-align: justify;"><strong> </strong></p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban</strong><strong>: A<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan</strong><strong>:</strong></p>
<p style="text-align: justify;">Setrika merupakan benda yang memanfaatkan sifat konduktor dan isolator. Bagian setrika yang memanfaatkan isolator yaitu bagian pegangan setrika yang bertujuan agar panas tidak mudah terkena oleh tangan. Sementara bagian setrika yang memanfaatkan konduktor yaitu bagian bawah setrika yang digunakan untuk menyetrika pakaian sehingga harus menggunakan bahan material yang mudah untuk menghantarkan panas.</p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah A.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;"><strong>Topik: Kepemimpinan</strong></p>
<p style="text-align: justify;"><strong>Subtopik: Kepemimpinan di Sekitarku</strong></p>
<p> </p>
<p style="text-align: justify;"><strong>5. Bacalah potongan teks pidato di berikut ini dengan saksama!</strong></p>
<ol>
<li aria-level="1">Bapak dan Ibu Guru yang saya cintai, kami mengucapkan terima kasih atas bimbingan Bapak dan Ibu Guru sehingga acara ini berjalan dengan lancar.<img loading="lazy" decoding="async" src="https://lh6.googleusercontent.com/bqP2iUmCYRUeqD3vLpF4KENfOARvpBOAQy_ILFe99UP1gU8YogIxTzBs6qrurmTG1obRV5WThqg2hBPWYTeG7m03olELz0J_mJrwA7QYq0Ox3QiL5GpeimKgnpmsh6qqa4gXqSUI" width="4" height="5" /></li>
<li aria-level="1">Teman-teman yang saya kasihi, saya ingin mengucapkan terima kasih atas waktu yang sudah teman-teman sisihkan selama ini, terutama untuk mewujudkan terselenggaranya acara ini. <img loading="lazy" decoding="async" src="https://lh5.googleusercontent.com/YUDXi-Fr8oXUA_69RtotlHSRh4-yFAya9yzfm1z7Gsdx5b0h24S9ahx8vSxkN5msSNoYgOJi67zmVIVl6Y2686By68Wgo4Qh9mw5JCw6QZsreRV9rCx79eJ895GbcWNk7gj5JuYX" width="4" height="5" /></li>
<li aria-level="1">Bapak dan Ibu Guru yang saya hormati, kami mohon maaf yang sebesar-besarnya jika selama kami dididik oleh Bapak dan Ibu Guru ada kata dan perilaku kami yang kurang berkenan.<img loading="lazy" decoding="async" src="https://lh6.googleusercontent.com/706ekJjmpF9bi0NzV0nx7CziDfUX749A4IjVhQHFEQF_BbmS-hdmiMVJ4x7GF7lBGFqwXdOnWO-ZxR7cosdfcfsH85DzgYhL7RfKKHl4JvAkq7z-35MMoSE02r3EQkv15GFgYv7N" width="4" height="5" /></li>
<li aria-level="1">Adik-adik kelas yang saya banggakan, acara ini sungguh bermanfaat bagi kita semua agar kalian semua bisa saling menghargai sehingga bisa menambah sahabat.<img loading="lazy" decoding="async" src="https://lh4.googleusercontent.com/VSnIEHJUE6zRc1zJledb8LnN3nVJjof-bddkuB9hspXcfciIqiMCGzatl0g5UIf-CIMUO92eJ7nwR9nUB43_IZZgEfNJ1F7JKhs3NlDyDaaGpsSvO1sEB5keFqC7lNaQV4Gcylpt" width="4" height="5" /></li>
</ol>
<p style="text-align: justify;">Cuplikan pidato yang tepat digunakan untuk acara perpisahan sekolah adalah nomor ….</p>
<ol style="list-style-type: upper-alpha;">
<li aria-level="1">1</li>
<li aria-level="1">2</li>
<li aria-level="1">3</li>
<li aria-level="1">4</li>
</ol>
<p style="text-align: justify;"><strong> </strong></p>
<p> </p>
<p> </p>
<p style="text-align: justify;"><strong>Jawaban</strong><strong>: C<br />
</strong></p>
<p style="text-align: justify;"><strong>Pembahasan</strong><strong>:</strong></p>
<p style="text-align: justify;">Cuplikan pidato nomor 3 tepat diucapkan dalam perpisahan karena cuplikan pidato itu berisi ucapan terima kasih atas didikan Bapak/Ibu Guru selama di sekolah. Ucapan terima kasih kepada Bapak/Ibu Guru biasanya disampaikan saat pidato perpisahan di sekolah. <img loading="lazy" decoding="async" src="https://lh3.googleusercontent.com/cihX2Irdnn9ixmEYE3Q_oxub8O0kmDnxJmQeDpLsjpA1QeIbOZFVOnI9txKQ_UDP6quvN2_j7GZ700obH6u3IPwWO0tWb27_HDaXdat5Ijd5Icn2d8P1yDXWmbbyAFPcYp8YLo1v" width="12" height="5" /></p>
<p style="text-align: justify;"><strong><span style="text-decoration: underline;">Jadi, jawaban yang tepat adalah C.</span></strong></p>
<p style="text-align: justify;"><img decoding="async" class="alignnone size-medium" src="https://cdn-web-2.ruangguru.com/landing-pages/assets/3b726299-9d49-4441-b770-18442e96fd7e.png" alt="Separator Latihan Soal SD" /></p>
<p style="text-align: justify;">Mudah dipahami kan? Itulah tadi berbagai soal dan pembahasan yang bisa kamu pakai sebagai latihan untuk menghadapi PTS (Penilaian Tengah Semester). Semoga berguna! Mau belajar lebih banyak dengan mengerjakan latihan soal? <strong><a href="https://www.ruangguru.com/ruanguji" target="_blank" rel="noopener">Kamu bisa cek ruanguji</a></strong> untuk mendapatkan try out yang bisa bantu nge-<em>boost </em>nilai PTS kamu!</p>
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<h5 class="author-title">Shabrina Alfari</h5>
<p class="author-description">Content Writer and Content Performance at Ruangguru. Hope my writing finds you well and help you learn a thing or two! :D</p>
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// Configuration
this.config = {
baseApiUrl: 'https://gw.ruangguru.com/api/v3/rdb/p_ddgy8hjx5dxsqx/rg_banner/views/',
apiKey: 'vLyK3dJrDBRmOwueX2OJXibMkgsUbBk0WS4ua2p1',
maxElements: 2,
zIndexBase: 100,
};
// Build dynamic API URL based on table parameter
this.config.apiUrl = this.buildApiUrl();
this.init();
}
buildApiUrl() {
const baseUrl = this.config.baseApiUrl;
const tableName = this.table || 'rg_floating_icon';
const queryParams =
'offset=0&limit=99999&sort=rankPosition&where=(type,eq,floating)~and(showIn,anyof,blog)~and(hide,is,false)~and(product,eq,' +
this.product +
')&nested%5Bcta%5D%5Bfields%5D=Id,name,ctaId,imageUrl,ctaLink,targetUrl';
return `${baseUrl}${tableName}?${queryParams}`;
}
async init() {
try {
await this.fetchFloatingElements();
this.renderFloatingElements();
} catch (error) {
console.error('Failed to initialize floating divs component:', error);
}
}
async fetchFloatingElements() {
try {
const options = {
method: 'GET',
headers: {
'xc-token': this.config.apiKey || 'vLyK3dJrDBRmOwueX2OJXibMkgsUbBk0WS4ua2p1',
},
};
const urlNoco = this.config.apiUrl;
const response = await fetch(urlNoco, options);
if (!response.ok) {
throw new Error(`HTTP error! status: ${response.status}`);
}
const data = await response.json();
this.floatingElements = this.processApiResponse(data);
} catch (error) {
console.error('Error fetching floating elements:', error);
throw error;
}
}
processApiResponse(data) {
if (!data || !data.list || !Array.isArray(data.list)) {
return [];
}
console.log(data.list);
// Ensure we only get maximum 2 elements
const limitedElements = data.list.slice(0, this.config.maxElements);
return limitedElements;
}
renderFloatingElements() {
if (!this.container || this.floatingElements.length === 0) {
return;
}
// Additional safeguard: ensure we never render more than maxElements
const elementsToRender = this.floatingElements.slice(0, this.config.maxElements);
// Clean up existing elements and their event listeners
this.cleanupExistingElements();
// Clear existing content
this.container.innerHTML = '';
elementsToRender.forEach((element, index) => {
const floatingDiv = this.createFloatingDiv(element, index);
this.container.appendChild(floatingDiv);
});
}
cleanupExistingElements() {
// Clear existing elements (no need for event listener cleanup with CSS approach)
const existingElements = this.container.querySelectorAll('[data-floating-element]');
existingElements.forEach(element => {
element.remove();
});
}
createFloatingDiv(element, index) {
const div = document.createElement('div');
const cta = element.cta[0]; // Use the first CTA
// Add data attribute for cleanup tracking
div.setAttribute('data-floating-element', 'true');
// Apply CSS classes based on rankPosition
const positionClass = this.getPositionClass(element.rankPosition, index);
div.className = `bantuan-element ${positionClass}`;
div.style.zIndex = this.config.zIndexBase + index;
// Create the link and image
const link = document.createElement('a');
link.href = 'https://cta.ruangguru.com/' + cta.ctaId || '#';
link.target = '_blank';
// Add tracking attributes
link.setAttribute('data-tracking-event-type', 'landing_page__core__item_click');
link.setAttribute(
'data-tracking-context',
JSON.stringify({
product_name: this.product,
cta_action: 'redirection',
cta_action_detail: link.href,
item_type: 'floating',
item_name: element.name || 'Floating element',
item_category: 'payment',
item_position: index,
item_serial: null,
section_type: 'floating_item',
section_position: 'body',
section_name: 'floating_item',
})
);
const img = document.createElement('img');
img.src = element.imageUrl + '?h=200&convert=webp';
img.alt = element.name || 'Floating element';
img.loading = 'lazy';
// Add click tracking
link.addEventListener('click', () => {
this.trackClick(element, cta);
});
link.appendChild(img);
div.appendChild(link);
return div;
}
getPositionClass(rankPosition, index) {
// Define positioning classes based on rankPosition
if (rankPosition === 1) {
return 'bantuan-top'; // Top position
} else if (rankPosition === 2) {
return 'bantuan-bottom'; // Bottom position
} else {
// For additional elements, distribute them evenly
return `bantuan-${index % 2 === 0 ? 'top' : 'bottom'}-${Math.floor(index / 2) + 1}`;
}
}
trackClick(element, cta) {
// Implement click tracking logic here
console.log('Floating element clicked:', {
elementId: element.Id,
elementName: cta.name,
ctaId: cta.ctaId,
targetUrl: cta.targetUrl,
});
}
// Public method to manually refresh
async refresh() {
try {
await this.fetchFloatingElements();
this.renderFloatingElements();
} catch (error) {
console.error('Failed to refresh floating elements:', error);
throw error;
}
}
// Public method to get current floating elements
getFloatingElements() {
return [...this.floatingElements];
}
}
// Initialize the component when DOM is ready
document.addEventListener('DOMContentLoaded', () => {
// Get product and table parameters from data attributes
const container = document.getElementById('bantuan-divs-container');
const product = container.getAttribute('data-product') || 'ruangguru';
const table = container.getAttribute('data-table') || 'rg_floating_icon';
new FloatingDivsComponent(product, table);
});
// Export for use in other modules if needed
if (typeof module !== 'undefined' && module.exports) {
module.exports = FloatingDivsComponent;
}
</script> <div id="wp-install-nudge" style="
position: fixed;
bottom: 0rem;
right: 0;
z-index: 999;
cursor: pointer;
"></div>
<script>
(function (w, d, s, o, f, js, fjs) {
w['Sales-Nudge-Widget'] = o; w[o] = w[o] || function () { (w[o].q = w[o].q || []).push(arguments) };
js = d.createElement(s), fjs = d.getElementsByTagName(s)[0];
js.id = o; js.src = f; js.async = 1; fjs.parentNode.insertBefore(js, fjs);
}(window, document, 'script', 'wpInstallNudge', 'https://cdn-web-2.ruangguru.com/sales-nudge/6198a95130/dist/widget.js'));
wpInstallNudge('init', { targetElementId: 'wp-install-nudge', clientTarget: 'ruangguru_blog' });
</script>
<script>
// note: disabled due to auto reload page
// var lastScrollTop = 0;
// $(window).scroll(function(event){
// var st = $(this).scrollTop();
// if (st > lastScrollTop){
// $('#wp-install-nudge').slideDown( "slow", function() {});
// } else {
// $('#wp-install-nudge').slideUp( "slow", function() {});
// }
// lastScrollTop = st;
// });
// $(document).ready(function () {
// $("#wp-install-nudge").hide();
// });
$('#wp-install-nudge').click(function(){
Analytics.track("promotion__install_nudge__click",
{
user_email: "ruangguru@blog.com",
cta_link: widgetData.dataConfig.target_link
}).catch((err) => {
console.log("tracker error", err);
});
});
</script>
</footer>
<div id="__next"></div>
<script type="speculationrules">
{"prefetch":[{"source":"document","where":{"and":[{"href_matches":"\/blog\/*"},{"not":{"href_matches":["\/blog\/wp-*.php","\/blog\/wp-admin\/*","\/blog\/wp-content\/uploads\/*","\/blog\/wp-content\/*","\/blog\/wp-content\/plugins\/*","\/blog\/wp-content\/themes\/ruangguru\/*","\/blog\/*\\?(.+)"]}},{"not":{"selector_matches":"a[rel~=\"nofollow\"]"}},{"not":{"selector_matches":".no-prefetch, .no-prefetch a"}}]},"eagerness":"conservative"}]}
</script>
<script>
async function getCtaDetails(ctaIds) {
const endpoint =
" https://gw.ruangguru.com/api/v3/rdb/p_ddgy8hjx5dxsqx/CTA/views/CTA?offset=0&limit=10&where=(ctaId,in," + ctaIds.toString() + ")";
try {
const response = await fetch(endpoint, {
headers: {
"xc-token": "-hG2nBDJzSj0agSgNtcJx97M4F02y54nUMoY6plJ",
},
});
const data = await response.json();
const ctaList = data?.list || [];
const ctaMap = new Map();
for (const ctaData of ctaList) {
ctaMap.set(ctaData.ctaId, ctaData);
}
return ctaMap;
} catch (error) {
console.error("Error fetching CTA details:", error);
return new Map();
}
}
async function replaceCTA() {
const regex = /{{cta\((‘(.*?)’|“(.*?)”)\)}}/g;
const bodyHTML = document.body.innerHTML;
const matches = Array.from(bodyHTML.matchAll(regex));
const ctaIds = matches.map((match) => {
let ctaId = match[2] ?? match[3];
return ctaId;
});
const ctaMap = await getCtaDetails(ctaIds);
const replacedHTML = bodyHTML.replace(regex, (match, _inner, ctaId1, ctaId2) => {
const ctaId = ctaId1 ?? ctaId2;
const ctaData = ctaMap.get(ctaId);
if (ctaData) {
return `<a href="https://cta.ruangguru.com/${ctaData.ctaId}" target="_${ctaData.targetType}" style="position:relative;display:inline-block;">
<img src="${ctaData.imageUrl}" loading="lazy" alt="${ctaData.altText}" />
</a>`;
} else {
return match;
}
});
document.body.innerHTML = replacedHTML;
}
</script>
<meta name="author" content="Ruangguru Tech Team">
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<noscript><iframe src="https://www.googletagmanager.com/ns.html?id=GTM-PVNLZFT" height="0" width="0" style="display:none;visibility:hidden"></iframe></noscript>
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<script type="text/javascript" src="https://cdn-web-2.ruangguru.com/landing-page-web/public/staticpages/global-assets/js/cta.js"></script>
<script src="https://unpkg.com/@dotlottie/player-component@latest/dist/dotlottie-player.mjs" type="module"></script>
</body>
</html>