In this lesson, we will look at additional features and different grouping types.
Backreferences
We have a group of symbols from which we choose either ta or tu:
/(ta|tu)/
ta-tu ta-ta tu-tu
Suppose we want to find only those substrings in which the left and right parts match: ta - ta and tu - tu.
Let us try to add another "or" condition to our expression. That way, we will see that we have not got what we wanted:
/(ta|tu)-(ta|tu)/
ta-tu ta-ta tu-tu
It is the case when backreferencing helps. It works as follows. We use the special notation \1, which shows that we should substitute the characters from the first group for \1.
Thus, we will find substrings with the same left and right parts:
/(ta|tu)-\1/
ta-tu ta-ta tu-tu
By default, we create all character groups, write them to a specific memory area, and label them with characters from \1 to \9.
When we use quantification, it does not affect the result. The quantification is not involved in the backreference, so we take only the first occurrence in the memory area:
/(ta|tu)+-\1/
ta-tu ta-ta tu-tu
Named groups
When programmers have multiple groups, they do not find it very convenient to remember them by number. It is much easier to use names. To do this, you must add ?<name> after opening the bracket:
/(?<group1>ta|tu)-\k<group1>/
ta-tu ta-ta tu-tu
Now you can refer to the group using the name group1 to perform operations on the group1 in your code.
Disabling backreferencing
We can turn off backreferencing by putting a ?: inside our group:
/(?:ta|tu)-\1/
ta-tu ta-ta tu-tu
After that, we do not save the group to the memory area. An error can occur when calling it since the group does not exist in the memory.
If you use this approach, the regular expression will get very difficult to read, but it will work faster. This method works 100% of the time if:
- You have a lot of groups and do not need them
- You want to avoid using them to save up space and avoid interference with further grouping
Atomic grouping
Another interesting kind of grouping without backreferencing is atomic grouping.
JavaScript, Python, and other popular programming languages do not support atomic grouping. But you can google solutions to emulate them with existing constructions.
For atomic grouping, we use : instead of >:
/a(?>bc|b|x)cc/
abccaxcc
If we remove ?>, the regex will find two substrings — abcc and axcc:
/a(bc|b|x)cc/
abccaxcc
When we add the atomic grouping characters, ?>, the following happens: we find first a, then bc, then cc. Usually, in the example above, the search would have rolled back to a and continued checking from b since the alternation character | is present. Then, we would get to cc, and the check would work.
But with atomic grouping, the return along the string back to a is disabled. It continues moving along the alternatives bc -> b -> x. After x we find cc.
Once we find the first match from the atomic group (?>bc|b|x), other variants from this group do not get considered. Then the next character of the analyzed string is searched from the first character of the regular expression.
We would only be able to find a match for the whole string with atomic grouping if we added another c to it:
/a(?>bc|b|x)cc/
abcccaxcc
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Backreferences"},"units":[{"id":7690,"name":"theory","url":"/courses/regexp/lessons/backreferences/theory_unit"},{"id":7701,"name":"exercise","url":"/courses/regexp/lessons/backreferences/exercise_unit"}],"links":[],"ordered_units":[{"id":7690,"name":"theory","url":"/courses/regexp/lessons/backreferences/theory_unit"},{"id":7701,"name":"exercise","url":"/courses/regexp/lessons/backreferences/exercise_unit"}],"id":3421,"slug":"backreferences","state":"approved","name":"Grouping. Backreferences","course_order":700,"goal":"Learn how to reuse groups in regular expressions","self_study":null,"theory_video_provider":"vimeo","theory_video_uid":"132323839","theory":"In this lesson, we will look at additional features and different grouping types.\n\n### Backreferences\n\nWe have a group of symbols from which we choose either `ta` or `tu`:\n\n---\n\n/`(ta|tu)`/\n\n`ta`-`tu` `ta`-`ta` `tu`-`tu`\n\n---\n\nSuppose we want to find only those substrings in which the left and right parts match: `ta - ta` and `tu - tu`.\n\nLet us try to add another \"or\" condition to our expression. That way, we will see that we have not got what we wanted:\n\n---\n\n/`(ta|tu)-(ta|tu)`/\n\n`ta-tu` `ta-ta` `tu-tu`\n\n---\n\nIt is the case when **backreferencing** helps. It works as follows. We use the special notation `\\1`, which shows that we should substitute the characters from the first group for `\\1`.\n\nThus, we will find substrings with the same left and right parts:\n\n---\n\n/`(ta|tu)-\\1`/\n\nta-tu `ta-ta` `tu-tu`\n\n---\n\nBy default, we create all character groups, write them to a specific memory area, and label them with characters from `\\1` to `\\9`.\n\nWhen we use quantification, it does not affect the result. The quantification is not involved in the backreference, so we take only the first occurrence in the memory area:\n\n---\n\n/`(ta|tu)+-\\1`/\n\nta-tu `ta-ta` `tu-tu`\n\n---\n\n### Named groups\n\nWhen programmers have multiple groups, they do not find it very convenient to remember them by number. It is much easier to use names. To do this, you must add `?<name>` after opening the bracket:\n\n---\n\n/`(?<group1>ta|tu)-\\k<group1>`/\n\nta-tu `ta-ta` `tu-tu`\n\n---\n\nNow you can refer to the group using the name group1 to perform operations on the `group1` in your code.\n\n### Disabling backreferencing\n\nWe can turn off backreferencing by putting a `?:` inside our group:\n\n---\n\n/`(?:ta|tu)-\\1`/\n\nta-tu ta-ta tu-tu\n\n---\n\nAfter that, we do not save the group to the memory area. An error can occur when calling it since the group does not exist in the memory.\n\nIf you use this approach, the regular expression will get very difficult to read, but it will work faster. This method works 100% of the time if:\n\n* You have a lot of groups and do not need them\n* You want to avoid using them to save up space and avoid interference with further grouping\n\n### Atomic grouping\n\nAnother interesting kind of grouping without backreferencing is **atomic grouping**.\n\nJavaScript, Python, and other popular programming languages do not support atomic grouping. But you can google solutions to emulate them with existing constructions.\n\nFor atomic grouping, we use `:` instead of `>`:\n\n---\n\n/`a(?>bc|b|x)cc`/\n\nabcc`axcc`\n\n---\n\nIf we remove `?>`, the regex will find two substrings — `abcc` and `axcc`:\n\n---\n\n/`a(bc|b|x)cc`/\n\n`abccaxcc`\n\n---\n\nWhen we add the atomic grouping characters, `?>`, the following happens: we find first `a`, then `bc`, then `cc`. Usually, in the example above, the search would have rolled back to `a` and continued checking from `b` since the alternation character `|` is present. Then, we would get to `cc`, and the check would work.\n\nBut with atomic grouping, the return along the string back to `a` is disabled. It continues moving along the alternatives `bc` -> `b` -> `x`. After `x` we find `cc`.\n\nOnce we find the first match from the atomic group (?>bc|b|x), other variants from this group do not get considered. Then the next character of the analyzed string is searched from the first character of the regular expression.\n\nWe would only be able to find a match for the whole string with atomic grouping if we added another `c` to it:\n\n---\n\n/`a(?>bc|b|x)cc`/\n\n`abcccaxcc`\n"},"lessonMember":null,"courseMember":null,"course":{"start_lesson":{"exercise":{"id":2251,"slug":"regexp_symbols_exercise","name":null,"state":"active","kind":"exercise","language":"shell","locale":"en","has_web_view":false,"has_test_view":false,"reviewable":true,"readme":"## solution\n\nBuild a regular expression `ruby1.*`, where the `*` can be any character. \n","prepared_readme":"## solution\n\nBuild a regular expression `ruby1.*`, where the `*` can be any character. \n","has_solution":true,"entity_name":"Character representation. Metacharacter."},"units":[{"id":7684,"name":"theory","url":"/courses/regexp/lessons/symbols/theory_unit"},{"id":7998,"name":"quiz","url":"/courses/regexp/lessons/symbols/quiz_unit"},{"id":7695,"name":"exercise","url":"/courses/regexp/lessons/symbols/exercise_unit"}],"links":[{"id":423882,"name":"Regular Expressions","url":"https://en.wikipedia.org/wiki/Regular_expression"},{"id":423883,"name":"Regular Expressions Cheat Sheet","url":"https://www.cheatography.com/davechild/cheat-sheets/regular-expressions/"},{"id":423884,"name":"Online regular expression editor","url":"https://regex101.com/"}],"ordered_units":[{"id":7684,"name":"theory","url":"/courses/regexp/lessons/symbols/theory_unit"},{"id":7998,"name":"quiz","url":"/courses/regexp/lessons/symbols/quiz_unit"},{"id":7695,"name":"exercise","url":"/courses/regexp/lessons/symbols/exercise_unit"}],"id":3415,"slug":"symbols","state":"approved","name":"Character representation. Metacharacter.","course_order":120,"goal":"Learn basic regular expressions","self_study":null,"theory_video_provider":"vimeo","theory_video_uid":"132322923","theory":"Regular expressions are the formal language used to look for characters and manipulate substrings. It is a powerful tool that allows you to work efficiently with text.\n\nRegular expressions are text strings that set a search `pattern` using the characters you want to find and special characters.\n\nFor clarity, in the examples in this course, we will put the string pattern with regular expressions at the top and the strings we are searching for at the bottom.\n\nWe recommend running all the examples yourself, using online regular expression editors such as [regex101](https://regex101.com/), [regexr](https://regexr.com/), or others. Choose a JavaScript or PCRE engine for examples that do not support JS.\n\nNow, let us set a pattern with the characters we want to find in the text line:\n\n---\n/`java`/\n\n`java` \\ python ruby1.9 `java`script c#\n\n---\n\nWe can see two matches from the string with the `java` text. 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Let us try to find combinations of any characters with `y`.\n\nSeems like there are two matches:\n\n---\n/`.y`/\n\njava \\ `py`thon ru`by`1.9 javascript c#\n\n---\n\nCombining special and ordinary characters, we need to remember that special characters have particular behavior. Notice the example below, where we have written the characters `1.9`. 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Backreferences</h1><script type="application/ld+json">{"@context":"https://schema.org","@type":"LearningResource","name":"Grouping. 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<h3 id="heading-3-1">Backreferences</h3>
<p>We have a group of symbols from which we choose either <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta</code> or <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu</code>:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">(ta|tu)</code>/</p>
<p><code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta</code>-<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu</code> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta</code>-<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta</code> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu</code>-<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu</code></p>
<hr/>
<p>Suppose we want to find only those substrings in which the left and right parts match: <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta - ta</code> and <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu - tu</code>.</p>
<p>Let us try to add another "or" condition to our expression. That way, we will see that we have not got what we wanted:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">(ta|tu)-(ta|tu)</code>/</p>
<p><code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta-tu</code> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta-ta</code> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu-tu</code></p>
<hr/>
<p>It is the case when <strong>backreferencing</strong> helps. It works as follows. We use the special notation <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">\1</code>, which shows that we should substitute the characters from the first group for <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">\1</code>.</p>
<p>Thus, we will find substrings with the same left and right parts:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">(ta|tu)-\1</code>/</p>
<p>ta-tu <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta-ta</code> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu-tu</code></p>
<hr/>
<p>By default, we create all character groups, write them to a specific memory area, and label them with characters from <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">\1</code> to <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">\9</code>.</p>
<p>When we use quantification, it does not affect the result. The quantification is not involved in the backreference, so we take only the first occurrence in the memory area:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">(ta|tu)+-\1</code>/</p>
<p>ta-tu <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta-ta</code> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu-tu</code></p>
<hr/>
<h3 id="heading-3-2">Named groups</h3>
<p>When programmers have multiple groups, they do not find it very convenient to remember them by number. It is much easier to use names. To do this, you must add <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">?<name></code> after opening the bracket:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">(?<group1>ta|tu)-\k<group1></code>/</p>
<p>ta-tu <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">ta-ta</code> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">tu-tu</code></p>
<hr/>
<p>Now you can refer to the group using the name group1 to perform operations on the <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">group1</code> in your code.</p>
<h3 id="heading-3-3">Disabling backreferencing</h3>
<p>We can turn off backreferencing by putting a <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">?:</code> inside our group:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">(?:ta|tu)-\1</code>/</p>
<p>ta-tu ta-ta tu-tu</p>
<hr/>
<p>After that, we do not save the group to the memory area. An error can occur when calling it since the group does not exist in the memory.</p>
<p>If you use this approach, the regular expression will get very difficult to read, but it will work faster. This method works 100% of the time if:</p>
<ul>
<li>You have a lot of groups and do not need them</li>
<li>You want to avoid using them to save up space and avoid interference with further grouping</li>
</ul>
<h3 id="heading-3-4">Atomic grouping</h3>
<p>Another interesting kind of grouping without backreferencing is <strong>atomic grouping</strong>.</p>
<p>JavaScript, Python, and other popular programming languages do not support atomic grouping. But you can google solutions to emulate them with existing constructions.</p>
<p>For atomic grouping, we use <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">:</code> instead of <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">></code>:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">a(?>bc|b|x)cc</code>/</p>
<p>abcc<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">axcc</code></p>
<hr/>
<p>If we remove <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">?></code>, the regex will find two substrings — <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">abcc</code> and <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">axcc</code>:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">a(bc|b|x)cc</code>/</p>
<p><code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">abccaxcc</code></p>
<hr/>
<p>When we add the atomic grouping characters, <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">?></code>, the following happens: we find first <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">a</code>, then <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">bc</code>, then <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">cc</code>. Usually, in the example above, the search would have rolled back to <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">a</code> and continued checking from <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">b</code> since the alternation character <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">|</code> is present. Then, we would get to <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">cc</code>, and the check would work.</p>
<p>But with atomic grouping, the return along the string back to <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">a</code> is disabled. It continues moving along the alternatives <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">bc</code> -> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">b</code> -> <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">x</code>. After <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">x</code> we find <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">cc</code>.</p>
<p>Once we find the first match from the atomic group (?>bc|b|x), other variants from this group do not get considered. Then the next character of the analyzed string is searched from the first character of the regular expression.</p>
<p>We would only be able to find a match for the whole string with atomic grouping if we added another <code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">c</code> to it:</p>
<hr/>
<p>/<code style="margin-bottom:var(--mantine-spacing-lg)" class="m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight m_e597c321 mantine-CodeHighlight-codeHighlight m_dfe9c588 mantine-InlineCodeHighlight-inlineCodeHighlight">a(?>bc|b|x)cc</code>/</p>
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