Pada artikel Matematika kelas 7 kali ini, kamu akan mempelajari tentang macam-macam hubungan antar himpunan dalam Matematika. Ada himpunan bagian, himpunan kuasa, himpunan yang sama, dan himpunan ekuivalen.
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Hai! Siapa di antara kamu yang ikut kegiatan ekstrakurikuler di sekolahnya, nih? Bagi kamu yang aktif, mungkin hanya mengikuti satu kegiatan ekstrakurikuler saja tidak akan cukup ya untuk mengisi waktu luang kamu saat pulang sekolah atau akhir pekan.
Sama kayak Rogu, Gita, dan Iqbal, nih! Saking aktifnya, mereka sampai ikut lebih dari satu kegiatan ekstrakurikuler, lho! Untungnya, jadwal latihan ekstrakurikuler Rogu, Gita, dan Iqbal nggak bentrok. Coba kalau iya, bisa-bisa mereka jadi seperti amuba deh yang harus membelah diri.
Kebetulan, Rogu dan Gita sama-sama mengikuti dua kegiatan ekstrakurikuler. Rogu mengikuti futsal dan pencak silat, sedangkan Gita mengikuti PMR dan paskibra. Sementara itu, Iqbal mengikuti tiga kegiatan ekstrakurikuler, yaitu futsal, paskibra, dan basket. Hmm, kurang aktif apa coba si Iqbal ini. Kalau kamu perhatikan, ternyata Iqbal mengikuti ekstrakurikuler yang sama dengan Rogu dan Gita, yaitu futsal dan paskibra.
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Eh, tapi kamu tahu nggak sih, masalah ekstrakurikuler di atas, ternyata bisa dikaitkan dengan materi himpunan yang mau kita bahas kali ini, lho. Kok bisa?
Coba kamu ingat kembali materi himpunan yang sudah kamu pelajari sebelumnya. Berdasarkan definisinya, himpunan merupakan kumpulan objek yang dapat didefinisikan dengan jelas dan terukur. Sama halnya kayak ekstrakurikuler, kalau ekstrakurikuler ibarat himpunan, maka anggota dari ekstrakurikuler itu merupakan sekumpulan objeknya yang dapat kita hitung dan juga jelas bentuknya.
Nah, kalau masalah Rogu, Gita, dan Iqbal tadi kita ilustrasikan dengan gambar, maka bentuknya akan seperti ini.
Berdasarkan gambar di atas, dapat kamu perhatikan kalau Rogu berada pada lingkaran A dan B yang menyatakan kalau ia tergabung dalam kumpulan atau himpunan siswa ekstrakurikuler futsal dan pencak silat. Begitupun dengan Gita, ia berada pada lingkaran C dan D yang menyatakan kalau ia tergabung dalam himpunan siswa ekstrakurikuler PMR dan paskibra. Sementara itu, Iqbal berada pada tiga lingkaran, yaitu A, D, dan E yang menyatakan kalau ia tergabung dalam tiga himpunan, yaitu himpunan siswa ekstrakurikuler futsal, paskibra, dan basket.
Nah, gambar di atas juga menandakan kalau antara himpunan yang satu dengan himpunan yang lainnya dapat terjadi suatu hubungan. Hubungan apakah itu? Untuk penjelasan lebih rincinya bisa kamu baca pada artikel di bawah ini. Let’s check this out!
Terdapat beberapa istilah yang dipakai dalam menjelaskan hubungan antar himpunan, yaitu:
1. Himpunan Bagian
Himpunan bagian atau subset adalah himpunan yang semua anggotanya terdapat di dalam himpunan lainnya. Himpunan bagian biasanya disimbolkan dengan “⊂” yang artinya “himpunan bagian dari”, sedangkan simbol “⊄” memiliki arti “bukan himpunan bagian dari”. Nah, supaya kamu nggak bingung, yuk, perhatikan contoh di bawah ini.
Contoh:
Misalkan, terdapat tiga buah himpunan, yaitu himpunan A, himpunan B, dan himpunan C dengan masing-masing anggotanya adalah sebagai berikut:
A = {1, 2, 3}, B = {1, 2, 3, 4, 6}, C = {8, 9, 10}
Sekarang, kita coba bahas bersama-sama, ya. Ternyata, setiap anggota dari himpunan A merupakan anggota dari himpunan B juga, lho. Oleh karena itu, dapat kita katakan himpunan A merupakan himpunan bagian atau subset dari himpunan B.
Kita bisa menulisnya dengan simbol (A ⊂ B). Sementara itu, karena semua anggota himpunan A merupakan anggota dari himpunan B juga, jadi himpunan B merupakan super himpunan atau superset dari himpunan A, bisa kita tulis dengan simbol (B ⊃ A).
Lalu, bagaimana dengan himpunan C, nih? Yap, benar! Karena setiap anggota dari himpunan C tidak terdapat di dalam himpunan A maupun himpunan B, maka dapat dikatakan himpunan C bukan merupakan himpunan bagian dari himpunan A (C ⊄ A) maupun himpunan B (C ⊄ B). Jika ketiga himpunan itu kita sajikan ke dalam gambar, maka akan seperti ini:
Bagaimana, paham sampai di sini?
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Oke, selanjutnya, perlu kamu ketahui juga, nih. Apabila terdapat suatu himpunan, maka kita dapat menghitung banyak kemungkinan himpunan bagian yang dapat terbentuk. Bagaimana caranya? Caranya, dapat menggunakan rumus 2n, dengan n adalah banyaknya anggota himpunan. Bingung? Tenang, nggak perlu khawatir! Langsung saja kita simak bersama-sama contoh soal di bawah ini, ya.
Contoh:
Misalkan, terdapat sebuah himpunan A yang terdiri dari tiga buah anggota, yaitu a, b, dan c sebagai berikut:
A = {a,b,c}
Maka, banyaknya kemungkinan-kemungkinan himpunan bagian yang dapat terbentuk dari himpunan A adalah = 23 = 8 buah. Kemungkinan-kemungkinan himpunan bagian tersebut terdiri dari { }, {a}, {b}, {c}, {a,b}, {a,c}, {b,c}, dan {a,b,c}.
Selain dengan menggunakan rumus di atas, kita juga dapat menggunakan cara lain untuk mencari banyak kemungkinan himpunan bagian dari suatu himpunan lho, yaitu dengan menggunakan segitiga Pascal.
Apa itu segitiga Pascal? Segitiga Pascal adalah pola bilangan yang membentuk bangun segitiga, diawali dan diakhiri dengan angka satu, serta bilangan-bilangan selain angka satu itu diperoleh dari penjumlahan dua bilangan yang terletak di atasnya dan saling berdekatan. Wuaduh! Pusing, kan? Daripada pusing-pusing, cus, langsung simak gambar berikut!
Mau kamu pakai cara pertama atau cara kedua, hasilnya akan sama saja, nih. Jadi, pilih saja cara yang menurutmu lebih mudah, ya.
2. Himpunan Kuasa
Selanjutnya adalah himpunan kuasa. Himpunan kuasa atau power set adalah himpunan yang seluruh anggotanya merupakan kumpulan dari himpunan-himpunan bagian.
Misalnya, kita ambil contoh himpunan kuasa dari A, maka dapat ditulis dengan notasi P(A) dengan anggota-anggotanya merupakan himpunan bagian dari himpunan A. Banyak anggota himpunan kuasa dapat dihitung menggunakan rumus n(P(A))= 2n(A), dengan n(A) adalah banyak anggota dari himpunan A.
Gimana, bingung nggak? Kalau bingung, kita perhatikan contoh soal di bawah ini dulu, yuk.
Contoh:
Misalkan, terdapat suatu himpunan A yang anggotanya merupakan bilangan-bilangan ganjil ≤ 5. Maka, banyak anggota A adalah sebanyak 3 buah, yaitu A = {1, 3, 5}. P(A) merupakan himpunan kuasa dari A dengan semua anggotanya merupakan himpunan bagian dari A. Jadi, banyak anggota P(A) adalah n(P(A)) = 2n(A) = 23 = 8, yang terdiri dari { }, {1}, {3}, {5}, {1, 3}, {1, 5}, {3, 5}, {1, 3, 5}.
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3. Himpunan yang Sama
Dua buah himpunan dikatakan sama apabila kedua himpunan tersebut memiliki anggota yang sama walaupun urutannya dapat berbeda.
Contoh:
Misalkan, terdapat dua buah himpunan, yaitu himpunan A dan himpunan B dengan masing-masing anggota sebagai berikut:
A = {a, s, r, i} dan B = {r, i, a, s}
Nah, sekarang, coba kamu perhatikan! Himpunan A ternyata memiliki anggota-anggota yang sama dengan himpunan B, yaitu a, s, r, dan i. Meskipun urutan anggota dari himpunan B berbeda dengan himpunan A, tapi kedua himpunan memiliki anggota yang sama. Jadi, dapat dikatakan himpunan A sama dengan himpunan B.
4. Himpunan yang Ekuivalen
Oke, kita masuk ke materi terakhir untuk pembahasan kali ini, ya. Terakhir adalah himpunan yang ekuivalen. Dua buah himpunan dikatakan ekuivalen apabila banyak anggota dari kedua himpunan bernilai sama.
Contoh:
Misalkan, terdapat dua buah himpunan, yaitu himpunan A dan himpunan B dengan masing-masing anggota sebagai berikut:
A = {1, 2, 3, 4, 5} dan B = {a, b, c, d, e}
Bisa kamu lihat dari kedua himpunan di atas, himpunan A memiliki jumlah anggota, yaitu n(A) = 5 dan himpunan B memiliki jumlah anggota, yaitu n(B) = 5. Jadi, (n(A) = n(B) = 5). Oleh karena itu, dapat dikatakan kalau himpunan A ekuivalen dengan himpunan B.
Bagaimana, sejauh ini kamu paham, ya? Nah, di bawah ini ada latihan soal yang bisa kamu kerjakan, nih. Mudah, kok! Nanti, jangan lupa tulis jawabanmu di kolom komentar, ya. Ditunggu, lho!
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Wah, sekarang, kamu sudah tahu deh apa saja macam-macam hubungan antarhimpunan di dalam Matematika itu. Ternyata, nggak sesulit yang kamu kira, ya? Kalau berdasarkan cerita Rogu, Gita, dan Iqbal sebelumnya, masalah hubungan antarhimpunan ini juga ada di sekitar, ya.
Nah, bagi kamu yang masih belum paham dengan materi ini, jangan khawatir! Kamu bisa gunakan aplikasi ruangbelajar untuk pahami materi pelajaran menjadi lebih mudah lewat video animasi yang menarik bersama Master Teacher yang nggak kalah asik. Penasaran? Yuk, gabung sekarang!
Referensi:
As’ari A. R., dkk. (2017). Matematika SMP/MTs Kelas VII Semester I. Jakarta: Pusat Kurikulum dan Perbukuan, Balitbang, Kemendikbud.
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<h1 class="content-title">
Hubungan Antar Himpunan Matematika & Contohnya | Matematika Kelas 7 </h1>
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<p class="content-author"><a href="https://www.ruangguru.com/blog/author/hani-ammariah" class="">Hani Ammariah</a> </p>
<p class="content-info"><span>October 28, 2025 • </span> <span>7 minutes read</span></p>
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<p><img decoding="async" style="width: 820px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/Macam-Macam%20Hubungan%20Antar%20Himpunan.jpg" alt="Macam-Macam Hubungan Antar Himpunan & Contohnya" width="820" /></p>
<blockquote>
<p style="font-size: 16px; text-align: center;"><em>Pada artikel </em><a style="font-weight: bold; font-style: italic;" href="https://www.ruangguru.com/blog/c/matematika/matematika-smp-kelas-7" rel="noopener">Matematika kelas 7</a><em> kali ini, kamu akan mempelajari tentang macam-macam hubungan antar himpunan dalam Matematika. Ada himpunan bagian, himpunan kuasa, himpunan yang sama, dan himpunan ekuivalen.</em></p>
<p style="text-align: center; font-size: 16px;"><em>—</em></p>
</blockquote>
<p> </p>
<p style="font-size: 16px; text-align: justify;">Hai! Siapa di antara kamu yang ikut kegiatan ekstrakurikuler di sekolahnya, nih? Bagi kamu yang aktif, mungkin hanya mengikuti satu kegiatan ekstrakurikuler saja tidak akan cukup ya untuk mengisi waktu luang kamu saat pulang sekolah atau akhir pekan.</p>
<p style="font-size: 16px; text-align: justify;">Sama kayak Rogu, Gita, dan Iqbal, nih! Saking aktifnya, mereka sampai ikut lebih dari satu kegiatan ekstrakurikuler, lho! Untungnya, jadwal latihan ekstrakurikuler Rogu, Gita, dan Iqbal nggak bentrok. Coba kalau iya, bisa-bisa mereka jadi seperti amuba deh yang harus membelah diri.</p>
<p style="text-align: justify;">Kebetulan, Rogu dan Gita sama-sama mengikuti dua kegiatan ekstrakurikuler. Rogu mengikuti futsal dan pencak silat, sedangkan Gita mengikuti PMR dan paskibra. Sementara itu, Iqbal mengikuti tiga kegiatan ekstrakurikuler, yaitu futsal, paskibra, dan basket. Hmm, kurang aktif apa coba si Iqbal ini. Kalau kamu perhatikan, ternyata Iqbal mengikuti ekstrakurikuler yang sama dengan Rogu dan Gita, yaitu futsal dan paskibra.</p>
<p><strong>Baca Juga: <a href="/blog/pengertian-dan-contoh-bilangan-bulat" rel="noopener">Yuk, Pahami Pengertian dan Contoh Bilangan Bulat</a></strong></p>
<p style="text-align: justify;">Eh, tapi kamu tahu nggak sih, masalah ekstrakurikuler di atas, ternyata bisa dikaitkan dengan materi himpunan yang mau kita bahas kali ini, lho. Kok bisa?</p>
<p style="text-align: justify;">Coba kamu ingat kembali materi <strong><a href="/blog/matematika-kelas-7-pengertian-dan-istilah-istilah-dalam-himpunan" rel="noopener">himpunan</a></strong> yang sudah kamu pelajari sebelumnya. Berdasarkan definisinya, <strong>himpunan merupakan kumpulan objek yang dapat didefinisikan dengan jelas dan terukur</strong>. Sama halnya kayak ekstrakurikuler, kalau ekstrakurikuler ibarat himpunan, maka anggota dari ekstrakurikuler itu merupakan sekumpulan objeknya yang dapat kita hitung dan juga jelas bentuknya.</p>
<p style="text-align: justify;">Nah, kalau masalah Rogu, Gita, dan Iqbal tadi kita ilustrasikan dengan gambar, maka bentuknya akan seperti ini.</p>
<p style="text-align: justify;"><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/ilustrasi%20gambar%20himpunan%20bagian.jpg" alt="ilustrasi gambar himpunan bagian" width="600" /></p>
<p> </p>
<p style="text-align: justify;">Berdasarkan gambar di atas, dapat kamu perhatikan kalau Rogu berada pada lingkaran A dan B yang menyatakan kalau ia tergabung dalam kumpulan atau himpunan siswa ekstrakurikuler futsal dan pencak silat. Begitupun dengan Gita, ia berada pada lingkaran C dan D yang menyatakan kalau ia tergabung dalam himpunan siswa ekstrakurikuler PMR dan paskibra. Sementara itu, Iqbal berada pada tiga lingkaran, yaitu A, D, dan E yang menyatakan kalau ia tergabung dalam tiga himpunan, yaitu himpunan siswa ekstrakurikuler futsal, paskibra, dan basket.</p>
<p style="text-align: justify;">Nah, gambar di atas juga menandakan kalau antara himpunan yang satu dengan himpunan yang lainnya dapat terjadi suatu hubungan. Hubungan apakah itu? Untuk penjelasan lebih rincinya bisa kamu baca pada artikel di bawah ini. <em>Let’s check this out</em>!</p>
<p style="text-align: justify;">Terdapat beberapa istilah yang dipakai dalam menjelaskan hubungan antar himpunan, yaitu:</p>
<p> </p>
<h2><span style="font-size: 18pt;">1. Himpunan Bagian</span></h2>
<p style="text-align: justify;">Himpunan bagian atau subset adalah <strong>himpunan yang semua anggotanya terdapat di dalam himpunan lainnya</strong>. Himpunan bagian biasanya disimbolkan dengan <strong>“⊂”</strong> yang artinya <strong>“himpunan bagian dari”</strong>, sedangkan simbol <strong>“⊄”</strong> memiliki arti<strong> “bukan himpunan bagian dari”</strong>. Nah, supaya kamu nggak bingung, yuk, perhatikan contoh di bawah ini.</p>
<p style="text-align: justify;"><strong>Contoh:</strong></p>
<p style="text-align: justify;">Misalkan, terdapat tiga buah himpunan, yaitu himpunan A, himpunan B, dan himpunan C dengan masing-masing anggotanya adalah sebagai berikut:</p>
<p style="text-align: center;">A = {1, 2, 3}, B = {1, 2, 3, 4, 6}, C = {8, 9, 10}</p>
<p> </p>
<p style="text-align: justify;">Sekarang, kita coba bahas bersama-sama, ya. Ternyata, setiap anggota dari himpunan A merupakan anggota dari himpunan B juga, lho. Oleh karena itu, dapat kita katakan<strong> himpunan A merupakan himpunan bagian atau subset dari himpunan</strong> <span style="font-weight: bold;">B</span><span style="font-weight: normal;">. </span></p>
<p style="text-align: justify;"><span style="font-weight: normal;">Kita bisa menulisnya dengan simbol</span><strong> (A ⊂ B)</strong>. Sementara itu, karena semua anggota himpunan A merupakan anggota dari himpunan B juga, jadi <strong>himpunan B merupakan super himpunan atau superset dari himpunan A</strong><span style="font-weight: normal;">, bisa kita tulis dengan simbol</span><strong> (B ⊃ A)</strong>.</p>
<p style="text-align: justify;">Lalu, bagaimana dengan himpunan C, nih? Yap, benar! Karena setiap anggota dari himpunan C tidak terdapat di dalam himpunan A maupun himpunan B, maka dapat dikatakan <strong>himpunan C bukan merupakan himpunan bagian dari himpunan A (C ⊄ A) maupun himpunan B (C ⊄ B)</strong>. Jika ketiga himpunan itu kita sajikan ke dalam gambar, maka akan seperti ini:</p>
<p><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/ilustrasi%20himpunan%20bagian.jpg" alt="ilustrasi himpunan bagian" width="600" /></p>
<p> </p>
<p>Bagaimana, paham sampai di sini?</p>
<p><strong>Baca Juga: <a href="/blog/matematika-kelas-7-mengenal-operasi-hitung-pada-pecahan" rel="noopener">Mengenal Operasi Hitung pada Pecahan, Apa Saja Ya?</a></strong></p>
<p style="text-align: justify;">Oke, selanjutnya, perlu kamu ketahui juga, nih. <strong>Apabila terdapat suatu himpunan</strong><span style="font-weight: bold;">, maka kita dapat menghitung banyak kemungkinan himpunan bagian yang dapat terbentuk</span>. Bagaimana caranya? Caranya, dapat menggunakan <strong>rumus 2<sup>n</sup></strong>, dengan n adalah banyaknya anggota himpunan. Bingung? Tenang, nggak perlu khawatir! Langsung saja kita simak bersama-sama contoh soal di bawah ini, ya.</p>
<p style="text-align: justify;"><strong>Contoh:</strong></p>
<p style="text-align: justify;">Misalkan, terdapat sebuah himpunan A yang terdiri dari tiga buah anggota, yaitu a, b, dan c sebagai berikut:</p>
<p style="text-align: justify;">A = {a,b,c}</p>
<p style="text-align: justify;">Maka, banyaknya kemungkinan-kemungkinan himpunan bagian yang dapat terbentuk dari himpunan A adalah = 2<sup>3</sup> = 8 buah. Kemungkinan-kemungkinan himpunan bagian tersebut terdiri dari <span style="font-weight: bold;">{ }, {a}, {b}, {c}, {a,b}, {a,c}, {b,c}, dan {a,b,c}</span>.</p>
<p style="text-align: justify;">Selain dengan menggunakan rumus di atas, kita juga dapat menggunakan cara lain untuk mencari banyak kemungkinan himpunan bagian dari suatu himpunan lho, yaitu dengan menggunakan <strong>segitiga Pascal</strong>.</p>
<p style="text-align: justify;">Apa itu segitiga Pascal? Segitiga Pascal adalah pola bilangan yang membentuk bangun segitiga, diawali dan diakhiri dengan angka satu, serta bilangan-bilangan selain angka satu itu diperoleh dari penjumlahan dua bilangan yang terletak di atasnya dan saling berdekatan. Wuaduh! Pusing, kan? Daripada pusing-pusing, cus, langsung simak gambar berikut!</p>
<p><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/cara%20mencari%20banyak%20kemungkinan%20himpunan%20bagian%20menggunakan%20segitiga%20pascal.jpg" alt="cara mencari banyak kemungkinan himpunan bagian menggunakan segitiga pascal" width="600" /></p>
<p> </p>
<p style="text-align: justify;">Mau kamu pakai cara pertama atau cara kedua, hasilnya akan sama saja, nih. Jadi, pilih saja cara yang menurutmu lebih mudah, ya.</p>
<p> </p>
<h2><span style="font-size: 18pt;">2. Himpunan Kuasa</span></h2>
<p style="text-align: justify;">Selanjutnya adalah himpunan kuasa. <span style="font-weight: bold;">Himpunan kuasa atau <em>power set</em> adalah</span> <strong>himpunan yang seluruh anggotanya merupakan kumpulan dari himpunan-himpunan bagian</strong>.</p>
<p style="text-align: justify;">Misalnya, kita ambil contoh <strong>himpunan kuasa dari A</strong>, maka dapat ditulis dengan <strong>notasi P(A)</strong> dengan <strong>anggota-anggotanya merupakan himpunan bagian dari himpunan A</strong>. <strong>Banyak anggota himpunan kuasa</strong> dapat dihitung menggunakan <strong>rumus n(P(A))= 2<sup>n(A)</sup></strong>, dengan n(A) adalah banyak anggota dari himpunan A.</p>
<p style="text-align: justify;">Gimana, bingung nggak? Kalau bingung, kita perhatikan contoh soal di bawah ini dulu, yuk.</p>
<p style="text-align: justify;"><strong>Contoh:</strong></p>
<p style="text-align: justify;">Misalkan, terdapat suatu himpunan A yang anggotanya merupakan bilangan-bilangan ganjil ≤ 5. Maka, banyak anggota A adalah sebanyak 3 buah, yaitu A = {1, 3, 5}. P(A) merupakan himpunan kuasa dari A dengan semua anggotanya merupakan himpunan bagian dari A. Jadi, banyak anggota P(A) adalah n(P(A)) = 2<sup>n(A)</sup> = 2<sup>3</sup> = 8, yang terdiri dari <span style="font-weight: bold;">{ }, {1}, {3}, {5}, {1, 3}, {1, 5}, {3, 5}, {1, 3, 5}</span>.</p>
<p><strong>Baca Juga: <a href="/blog/penyajian-data-dalam-tabel-dan-diagram" rel="noopener">Begini Cara Menyajikan Data pada Tabel dan Diagram!</a></strong></p>
<p> </p>
<h2><span style="font-size: 18pt;">3. Himpunan yang Sama</span></h2>
<p style="text-align: justify;"><strong>Dua buah himpunan dikatakan sama apabila kedua himpunan tersebut memiliki anggota yang sama walaupun urutannya dapat berbeda.</strong></p>
<p style="text-align: justify;"><strong>Contoh:</strong></p>
<p style="text-align: justify;">Misalkan, terdapat dua buah himpunan, yaitu himpunan A dan himpunan B dengan masing-masing anggota sebagai berikut:</p>
<p style="text-align: center;">A = {a, s, r, i} dan B = {r, i, a, s}</p>
<p> </p>
<p style="text-align: justify;">Nah, sekarang, coba kamu perhatikan! Himpunan A ternyata memiliki anggota-anggota yang sama dengan himpunan B, yaitu a, s, r, dan i. Meskipun urutan anggota dari himpunan B berbeda dengan himpunan A, tapi kedua himpunan memiliki anggota yang sama. Jadi, dapat dikatakan himpunan A sama dengan himpunan B.</p>
<p> </p>
<h2><span style="font-size: 18pt;">4. Himpunan yang Ekuivalen</span></h2>
<p style="text-align: justify;">Oke, kita masuk ke materi terakhir untuk pembahasan kali ini, ya. Terakhir adalah himpunan yang ekuivalen. <strong>Dua buah himpunan dikatakan ekuivalen apabila banyak anggota dari kedua himpunan bernilai sama</strong>.</p>
<p style="text-align: justify;"><strong>Contoh:</strong></p>
<p style="text-align: justify;">Misalkan, terdapat dua buah himpunan, yaitu himpunan A dan himpunan B dengan masing-masing anggota sebagai berikut:</p>
<p style="text-align: center;">A = {1, 2, 3, 4, 5} dan B = {a, b, c, d, e}</p>
<p> </p>
<p style="text-align: justify;">Bisa kamu lihat dari kedua himpunan di atas, himpunan A memiliki jumlah anggota, yaitu n(A) = 5 dan himpunan B memiliki jumlah anggota, yaitu n(B) = 5. Jadi, (n(A) = n(B) = 5). Oleh karena itu, dapat dikatakan kalau himpunan A ekuivalen dengan himpunan B.</p>
<p style="text-align: justify;">Bagaimana, sejauh ini kamu paham, ya? Nah, di bawah ini ada latihan soal yang bisa kamu kerjakan, nih. Mudah, kok! Nanti, jangan lupa tulis jawabanmu di kolom komentar, ya. Ditunggu, lho!</p>
<p><img decoding="async" style="width: 600px; margin-left: auto; margin-right: auto; display: block;" src="https://cdn-web.ruangguru.com/landing-pages/assets/hs/contoh%20soal%20himpunan%20bagian.jpg" alt="contoh soal himpunan bagian" width="600" /></p>
<p><strong>Baca Juga: <a href="/blog/apa-saja-bagian-bagian-dari-properti-sudut" rel="noopener">Apa Saja Bagian-Bagian dari Properti Sudut?</a></strong></p>
<p> </p>
<p style="text-align: justify;">Wah, sekarang, kamu sudah tahu deh apa saja macam-macam hubungan antarhimpunan di dalam Matematika itu. Ternyata, nggak sesulit yang kamu kira, ya? Kalau berdasarkan cerita Rogu, Gita, dan Iqbal sebelumnya, masalah hubungan antarhimpunan ini juga ada di sekitar, ya.</p>
<p style="text-align: justify;">Nah, bagi kamu yang masih belum paham dengan materi ini, jangan khawatir! Kamu bisa gunakan aplikasi <a href="https://www.ruangguru.com/ruangbelajar" target="_blank" rel="noopener"><strong>ruangbelajar</strong> </a>untuk pahami materi pelajaran menjadi lebih mudah lewat video animasi yang menarik bersama Master Teacher yang nggak kalah asik. Penasaran? Yuk, gabung sekarang!</p>
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<p><strong>Referensi:</strong></p>
<p style="text-align: left;">As’ari A. R., dkk. (2017). <em>Matematika SMP/MTs Kelas VII Semester I</em>. Jakarta: Pusat Kurikulum dan Perbukuan, Balitbang, Kemendikbud.</p>
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<div class="d-lg-none text-center">
<nav class="footer-menu social">
<p class="title">Ikuti Kami</p>
<a target="_blank" href="https://www.instagram.com/ruangguru/">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/instagram.png?height=60&convert=webp" type="image/webp">
<source srcset="https://cdn-web-2.ruangguru.com/static/instagram.png?height=60" type="image/png">
<img src="https://cdn-web-2.ruangguru.com/static/instagram.png" loading="lazy" alt="Logo Instagram Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.facebook.com/ruanggurucom/">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/facebook.png?height=60&convert=webp" type="image/webp">
<source srcset="https://cdn-web-2.ruangguru.com/static/facebook.png?height=60" type="image/png">
<img src="https://cdn-web-2.ruangguru.com/static/facebook.png" loading="lazy" alt="Logo Facebook Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://twitter.com/ruangguru/">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/twitter.png?height=60&convert=webp" type="image/webp">
<source srcset="https://cdn-web-2.ruangguru.com/static/twitter.png?height=60" type="image/png">
<img src="https://cdn-web-2.ruangguru.com/static/twitter.png" loading=" lazy" alt="Logo Twitter Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.youtube.com/ruangguru">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/youtube.png?height=60&convert=webp" type="image/webp">
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<img src="https://cdn-web-2.ruangguru.com/static/youtube.png" loading=" lazy" alt="Logo Youtube Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.linkedin.com/company/ruangguru-com">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/linkedin.png?height=60&convert=webp" type="image/webp">
<source srcset="https://cdn-web-2.ruangguru.com/static/linkedin.png?height=60" type="image/png">
<img src="https://cdn-web-2.ruangguru.com/static/linkedin.png" loading=" lazy" alt="Logo LinkedIn Footer" width="32px" height="32px" />
</picture>
</a>
<a target="_blank" href="https://www.tiktok.com/@ruangguru">
<picture>
<source srcset="https://cdn-web-2.ruangguru.com/static/tiktok.png?height=60&convert=webp" type="image/webp">
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<img src="https://cdn-web-2.ruangguru.com/static/tiktok.png" loading=" lazy" alt="Logo TikTok Footer" width="32px" height="32px" />
</picture>
</a>
</nav>
</div>
<p class="footer-copyright">
© 2026 All Rights Reserved PT. Ruang Raya Indonesia
</p>
</div>
<style>
.bantuan-container {
position: relative;
}
.bantuan-element {
position: fixed;
z-index: 999;
display: flex;
align-items: flex-end;
justify-content: flex-end;
cursor: pointer;
transition: all 0.6s ease;
}
.bantuan-top {
bottom: 11rem;
right: 2rem;
}
.bantuan-bottom {
bottom: 2rem;
right: 2rem;
}
.bantuan-top-2 {
bottom: 15rem;
right: 2rem;
}
.bantuan-top-3 {
bottom: 19rem;
right: 2rem;
}
.bantuan-bottom-2 {
bottom: 5rem;
right: 2rem;
}
.bantuan-bottom-3 {
bottom: 8rem;
right: 2rem;
}
@media (min-width: 768px) {
.bantuan-element img {
width: auto;
transition: all 0.4s ease;
}
.bantuan-top img {
width: 140px;
}
.bantuan-bottom img {
width: 140px;
}
.bantuan-top-2 img,
.bantuan-top-3 img {
width: 140px;
}
.bantuan-bottom-2 img,
.bantuan-bottom-3 img {
width: 140px;
}
.bantuan-element.clicked {
bottom: 9rem;
right: 2.5rem;
}
.bantuan-element.clicked img {
width: auto;
height: 64px;
}
}
@media (max-width: 767px) {
.bantuan-top {
bottom: 8rem;
right: 1rem;
align-items: center;
}
.bantuan-bottom {
bottom: 2rem;
right: 1.25rem;
align-items: center;
}
.bantuan-top-2 {
bottom: 12rem;
right: 1rem;
align-items: center;
}
.bantuan-top-3 {
bottom: 16rem;
right: 1rem;
align-items: center;
}
.bantuan-bottom-2 {
bottom: 5rem;
right: 1.25rem;
align-items: center;
}
.bantuan-bottom-3 {
bottom: 8rem;
right: 1.25rem;
align-items: center;
}
.bantuan-element img {
width: auto;
}
.bantuan-top img,
.bantuan-top-2 img,
.bantuan-top-3 img {
width: 96px;
}
.bantuan-bottom img,
.bantuan-bottom-2 img,
.bantuan-bottom-3 img {
width: 96px;
}
}
.bantuan-element:hover {
transform: scale(1.05);
}
.bantuan-element img {
max-width: 100%;
height: auto;
}
</style>
<div id="bantuan-divs-container" style="position: relative" data-product="ruangguru" data-table="rg_floating_icon"></div>
<script>
class FloatingDivsComponent {
constructor(product = 'ruangguru', table = 'rg_floating_icon') {
this.container = document.getElementById('bantuan-divs-container');
this.floatingElements = [];
this.product = product;
this.table = table;
// Configuration
this.config = {
baseApiUrl: 'https://gw.ruangguru.com/api/v3/rdb/p_ddgy8hjx5dxsqx/rg_banner/views/',
apiKey: 'vLyK3dJrDBRmOwueX2OJXibMkgsUbBk0WS4ua2p1',
maxElements: 2,
zIndexBase: 100,
};
// Build dynamic API URL based on table parameter
this.config.apiUrl = this.buildApiUrl();
this.init();
}
buildApiUrl() {
const baseUrl = this.config.baseApiUrl;
const tableName = this.table || 'rg_floating_icon';
const queryParams =
'offset=0&limit=99999&sort=rankPosition&where=(type,eq,floating)~and(showIn,anyof,blog)~and(hide,is,false)~and(product,eq,' +
this.product +
')&nested%5Bcta%5D%5Bfields%5D=Id,name,ctaId,imageUrl,ctaLink,targetUrl';
return `${baseUrl}${tableName}?${queryParams}`;
}
async init() {
try {
await this.fetchFloatingElements();
this.renderFloatingElements();
} catch (error) {
console.error('Failed to initialize floating divs component:', error);
}
}
async fetchFloatingElements() {
try {
const options = {
method: 'GET',
headers: {
'xc-token': this.config.apiKey || 'vLyK3dJrDBRmOwueX2OJXibMkgsUbBk0WS4ua2p1',
},
};
const urlNoco = this.config.apiUrl;
const response = await fetch(urlNoco, options);
if (!response.ok) {
throw new Error(`HTTP error! status: ${response.status}`);
}
const data = await response.json();
this.floatingElements = this.processApiResponse(data);
} catch (error) {
console.error('Error fetching floating elements:', error);
throw error;
}
}
processApiResponse(data) {
if (!data || !data.list || !Array.isArray(data.list)) {
return [];
}
console.log(data.list);
// Ensure we only get maximum 2 elements
const limitedElements = data.list.slice(0, this.config.maxElements);
return limitedElements;
}
renderFloatingElements() {
if (!this.container || this.floatingElements.length === 0) {
return;
}
// Additional safeguard: ensure we never render more than maxElements
const elementsToRender = this.floatingElements.slice(0, this.config.maxElements);
// Clean up existing elements and their event listeners
this.cleanupExistingElements();
// Clear existing content
this.container.innerHTML = '';
elementsToRender.forEach((element, index) => {
const floatingDiv = this.createFloatingDiv(element, index);
this.container.appendChild(floatingDiv);
});
}
cleanupExistingElements() {
// Clear existing elements (no need for event listener cleanup with CSS approach)
const existingElements = this.container.querySelectorAll('[data-floating-element]');
existingElements.forEach(element => {
element.remove();
});
}
createFloatingDiv(element, index) {
const div = document.createElement('div');
const cta = element.cta[0]; // Use the first CTA
// Add data attribute for cleanup tracking
div.setAttribute('data-floating-element', 'true');
// Apply CSS classes based on rankPosition
const positionClass = this.getPositionClass(element.rankPosition, index);
div.className = `bantuan-element ${positionClass}`;
div.style.zIndex = this.config.zIndexBase + index;
// Create the link and image
const link = document.createElement('a');
link.href = 'https://cta.ruangguru.com/' + cta.ctaId || '#';
link.target = '_blank';
// Add tracking attributes
link.setAttribute('data-tracking-event-type', 'landing_page__core__item_click');
link.setAttribute(
'data-tracking-context',
JSON.stringify({
product_name: this.product,
cta_action: 'redirection',
cta_action_detail: link.href,
item_type: 'floating',
item_name: element.name || 'Floating element',
item_category: 'payment',
item_position: index,
item_serial: null,
section_type: 'floating_item',
section_position: 'body',
section_name: 'floating_item',
})
);
const img = document.createElement('img');
img.src = element.imageUrl + '?h=200&convert=webp';
img.alt = element.name || 'Floating element';
img.loading = 'lazy';
// Add click tracking
link.addEventListener('click', () => {
this.trackClick(element, cta);
});
link.appendChild(img);
div.appendChild(link);
return div;
}
getPositionClass(rankPosition, index) {
// Define positioning classes based on rankPosition
if (rankPosition === 1) {
return 'bantuan-top'; // Top position
} else if (rankPosition === 2) {
return 'bantuan-bottom'; // Bottom position
} else {
// For additional elements, distribute them evenly
return `bantuan-${index % 2 === 0 ? 'top' : 'bottom'}-${Math.floor(index / 2) + 1}`;
}
}
trackClick(element, cta) {
// Implement click tracking logic here
console.log('Floating element clicked:', {
elementId: element.Id,
elementName: cta.name,
ctaId: cta.ctaId,
targetUrl: cta.targetUrl,
});
}
// Public method to manually refresh
async refresh() {
try {
await this.fetchFloatingElements();
this.renderFloatingElements();
} catch (error) {
console.error('Failed to refresh floating elements:', error);
throw error;
}
}
// Public method to get current floating elements
getFloatingElements() {
return [...this.floatingElements];
}
}
// Initialize the component when DOM is ready
document.addEventListener('DOMContentLoaded', () => {
// Get product and table parameters from data attributes
const container = document.getElementById('bantuan-divs-container');
const product = container.getAttribute('data-product') || 'ruangguru';
const table = container.getAttribute('data-table') || 'rg_floating_icon';
new FloatingDivsComponent(product, table);
});
// Export for use in other modules if needed
if (typeof module !== 'undefined' && module.exports) {
module.exports = FloatingDivsComponent;
}
</script> <div id="wp-install-nudge" style="
position: fixed;
bottom: 0rem;
right: 0;
z-index: 999;
cursor: pointer;
"></div>
<script>
(function (w, d, s, o, f, js, fjs) {
w['Sales-Nudge-Widget'] = o; w[o] = w[o] || function () { (w[o].q = w[o].q || []).push(arguments) };
js = d.createElement(s), fjs = d.getElementsByTagName(s)[0];
js.id = o; js.src = f; js.async = 1; fjs.parentNode.insertBefore(js, fjs);
}(window, document, 'script', 'wpInstallNudge', 'https://cdn-web-2.ruangguru.com/sales-nudge/6198a95130/dist/widget.js'));
wpInstallNudge('init', { targetElementId: 'wp-install-nudge', clientTarget: 'ruangguru_blog' });
</script>
<script>
// note: disabled due to auto reload page
// var lastScrollTop = 0;
// $(window).scroll(function(event){
// var st = $(this).scrollTop();
// if (st > lastScrollTop){
// $('#wp-install-nudge').slideDown( "slow", function() {});
// } else {
// $('#wp-install-nudge').slideUp( "slow", function() {});
// }
// lastScrollTop = st;
// });
// $(document).ready(function () {
// $("#wp-install-nudge").hide();
// });
$('#wp-install-nudge').click(function(){
Analytics.track("promotion__install_nudge__click",
{
user_email: "ruangguru@blog.com",
cta_link: widgetData.dataConfig.target_link
}).catch((err) => {
console.log("tracker error", err);
});
});
</script>
</footer>
<div id="__next"></div>
<script type="speculationrules">
{"prefetch":[{"source":"document","where":{"and":[{"href_matches":"\/blog\/*"},{"not":{"href_matches":["\/blog\/wp-*.php","\/blog\/wp-admin\/*","\/blog\/wp-content\/uploads\/*","\/blog\/wp-content\/*","\/blog\/wp-content\/plugins\/*","\/blog\/wp-content\/themes\/ruangguru\/*","\/blog\/*\\?(.+)"]}},{"not":{"selector_matches":"a[rel~=\"nofollow\"]"}},{"not":{"selector_matches":".no-prefetch, .no-prefetch a"}}]},"eagerness":"conservative"}]}
</script>
<script>
async function getCtaDetails(ctaIds) {
const endpoint =
" https://gw.ruangguru.com/api/v3/rdb/p_ddgy8hjx5dxsqx/CTA/views/CTA?offset=0&limit=10&where=(ctaId,in," + ctaIds.toString() + ")";
try {
const response = await fetch(endpoint, {
headers: {
"xc-token": "-hG2nBDJzSj0agSgNtcJx97M4F02y54nUMoY6plJ",
},
});
const data = await response.json();
const ctaList = data?.list || [];
const ctaMap = new Map();
for (const ctaData of ctaList) {
ctaMap.set(ctaData.ctaId, ctaData);
}
return ctaMap;
} catch (error) {
console.error("Error fetching CTA details:", error);
return new Map();
}
}
async function replaceCTA() {
const regex = /{{cta\((‘(.*?)’|“(.*?)”)\)}}/g;
const bodyHTML = document.body.innerHTML;
const matches = Array.from(bodyHTML.matchAll(regex));
const ctaIds = matches.map((match) => {
let ctaId = match[2] ?? match[3];
return ctaId;
});
const ctaMap = await getCtaDetails(ctaIds);
const replacedHTML = bodyHTML.replace(regex, (match, _inner, ctaId1, ctaId2) => {
const ctaId = ctaId1 ?? ctaId2;
const ctaData = ctaMap.get(ctaId);
if (ctaData) {
return `<a href="https://cta.ruangguru.com/${ctaData.ctaId}" target="_${ctaData.targetType}" style="position:relative;display:inline-block;">
<img src="${ctaData.imageUrl}" loading="lazy" alt="${ctaData.altText}" />
</a>`;
} else {
return match;
}
});
document.body.innerHTML = replacedHTML;
}
</script>
<meta name="author" content="Ruangguru Tech Team">
<!-- Google Tag Manager (noscript) -->
<noscript><iframe src="https://www.googletagmanager.com/ns.html?id=GTM-PVNLZFT" height="0" width="0" style="display:none;visibility:hidden"></iframe></noscript>
<!-- Tracker -->
<script type="text/javascript" src="https://cdn-web-2.ruangguru.com/landing-page-web/public/staticpages/global-assets/js/cta.js"></script>
<script src="https://unpkg.com/@dotlottie/player-component@latest/dist/dotlottie-player.mjs" type="module"></script>
</body>
</html>