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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 693, we need to group it as 93 and 6.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 693, we need to group it as 93 and 6.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 6. We can say n as ‘2’ because 2 x 2 is lesser than or equal to 6. Now the<a>quotient</a>is 2. After subtracting 4 from 6, the<a>remainder</a>is 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 6. We can say n as ‘2’ because 2 x 2 is lesser than or equal to 6. Now the<a>quotient</a>is 2. After subtracting 4 from 6, the<a>remainder</a>is 2.</p>
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<p><strong>Step 3:</strong>Now let us bring down 93, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number, 2 + 2, we get 4, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 93, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number, 2 + 2, we get 4, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 4n as the new divisor; we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 4n as the new divisor; we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 4n × n ≤ 293. Let us consider n as 6, now 46 x 6 = 276.</p>
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<p><strong>Step 5:</strong>The next step is finding 4n × n ≤ 293. Let us consider n as 6, now 46 x 6 = 276.</p>
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<p><strong>Step 6:</strong>Subtract 276 from 293; the difference is 17, and the quotient is 26.</p>
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<p><strong>Step 6:</strong>Subtract 276 from 293; the difference is 17, and the quotient is 26.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1700.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1700.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 263, because 2637 × 7 = 1849.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 263, because 2637 × 7 = 1849.</p>
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<p><strong>Step 9:</strong>Subtracting 1849 from 1700, we get a negative result. Adjust n to 6, so 2636 × 6 = 1572.</p>
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<p><strong>Step 9:</strong>Subtracting 1849 from 1700, we get a negative result. Adjust n to 6, so 2636 × 6 = 1572.</p>
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<p><strong>Step 10:</strong>Subtracting 1572 from 1700, we get the result 128.</p>
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<p><strong>Step 10:</strong>Subtracting 1572 from 1700, we get the result 128.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose there are no decimal values; continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose there are no decimal values; continue till the remainder is zero.</p>
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<p>So the square root of √693 is approximately 26.324.</p>
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<p>So the square root of √693 is approximately 26.324.</p>
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