HTML Diff
2 added 2 removed
Original 2026-01-01
Modified 2026-02-28
1 - <p>215 Learners</p>
1 + <p>243 Learners</p>
2 <p>Last updated on<strong>August 5, 2025</strong></p>
2 <p>Last updated on<strong>August 5, 2025</strong></p>
3 <p>If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 11250.</p>
3 <p>If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 11250.</p>
4 <h2>What is the Square Root of 11250?</h2>
4 <h2>What is the Square Root of 11250?</h2>
5 <p>The<a>square</a>root is the inverse of the square of the<a>number</a>. 11250 is not a<a>perfect square</a>. The square root of 11250 is expressed in both radical and<a>exponential form</a>. In the radical form, it is expressed as √11250, whereas (11250)¹/² in the exponential form. √11250 ≈ 106.066, which is an<a>irrational number</a>because it cannot be expressed in the form of p/q, where p and q are<a>integers</a>and q ≠ 0.</p>
5 <p>The<a>square</a>root is the inverse of the square of the<a>number</a>. 11250 is not a<a>perfect square</a>. The square root of 11250 is expressed in both radical and<a>exponential form</a>. In the radical form, it is expressed as √11250, whereas (11250)¹/² in the exponential form. √11250 ≈ 106.066, which is an<a>irrational number</a>because it cannot be expressed in the form of p/q, where p and q are<a>integers</a>and q ≠ 0.</p>
6 <h2>Finding the Square Root of 11250</h2>
6 <h2>Finding the Square Root of 11250</h2>
7 <p>The<a>prime factorization</a>method is used for perfect square numbers. However, for non-perfect square numbers, the<a>long division</a>method and approximation method are used. Let us now learn the following methods:</p>
7 <p>The<a>prime factorization</a>method is used for perfect square numbers. However, for non-perfect square numbers, the<a>long division</a>method and approximation method are used. Let us now learn the following methods:</p>
8 <ul><li>Prime factorization method</li>
8 <ul><li>Prime factorization method</li>
9 <li>Long division method</li>
9 <li>Long division method</li>
10 <li>Approximation method</li>
10 <li>Approximation method</li>
11 </ul><h2>Square Root of 11250 by Prime Factorization Method</h2>
11 </ul><h2>Square Root of 11250 by Prime Factorization Method</h2>
12 <p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 11250 is broken down into its prime factors.</p>
12 <p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 11250 is broken down into its prime factors.</p>
13 <p><strong>Step 1:</strong>Finding the prime factors of 11250</p>
13 <p><strong>Step 1:</strong>Finding the prime factors of 11250</p>
14 <p>Breaking it down, we get 2 x 3 x 3 x 5 x 5 x 5 x 5: 2¹ x 3² x 5⁴</p>
14 <p>Breaking it down, we get 2 x 3 x 3 x 5 x 5 x 5 x 5: 2¹ x 3² x 5⁴</p>
15 <p><strong>Step 2:</strong>Now we found out the prime factors of 11250. The second step is to make pairs of those prime factors. Since 11250 is not a perfect square, the digits of the number can’t be grouped in pairs completely. Therefore, calculating 11250 using prime factorization directly is not possible.</p>
15 <p><strong>Step 2:</strong>Now we found out the prime factors of 11250. The second step is to make pairs of those prime factors. Since 11250 is not a perfect square, the digits of the number can’t be grouped in pairs completely. Therefore, calculating 11250 using prime factorization directly is not possible.</p>
16 <h3>Explore Our Programs</h3>
16 <h3>Explore Our Programs</h3>
17 - <p>No Courses Available</p>
 
18 <h2>Square Root of 11250 by Long Division Method</h2>
17 <h2>Square Root of 11250 by Long Division Method</h2>
19 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
18 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
20 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 11250, we need to group it as 50, 12, and 11.</p>
19 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 11250, we need to group it as 50, 12, and 11.</p>
21 <p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 11. We can say n is ‘3’ because 3 x 3 = 9, which is<a>less than</a>11. Now the<a>quotient</a>is 3, and the<a>remainder</a>is 2.</p>
20 <p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 11. We can say n is ‘3’ because 3 x 3 = 9, which is<a>less than</a>11. Now the<a>quotient</a>is 3, and the<a>remainder</a>is 2.</p>
22 <p><strong>Step 3:</strong>Now let us bring down 1250, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3, we get 6, which will be our new divisor's starting digit.</p>
21 <p><strong>Step 3:</strong>Now let us bring down 1250, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3, we get 6, which will be our new divisor's starting digit.</p>
23 <p><strong>Step 4:</strong>The new divisor will be 60n. We need to find the value of n.</p>
22 <p><strong>Step 4:</strong>The new divisor will be 60n. We need to find the value of n.</p>
24 <p><strong>Step 5:</strong>The next step is finding the largest digit n such that 60n x n ≤ 225. Let us consider n as 3, now 63 x 3 = 189.</p>
23 <p><strong>Step 5:</strong>The next step is finding the largest digit n such that 60n x n ≤ 225. Let us consider n as 3, now 63 x 3 = 189.</p>
25 <p><strong>Step 6:</strong>Subtract 189 from 225, the difference is 36. Bring down the next pair of zeros to make it 3600.</p>
24 <p><strong>Step 6:</strong>Subtract 189 from 225, the difference is 36. Bring down the next pair of zeros to make it 3600.</p>
26 <p><strong>Step 7:</strong>The process continues, finding n for 606n ≤ 3600, which would be n = 5, making the next number 65.</p>
25 <p><strong>Step 7:</strong>The process continues, finding n for 606n ≤ 3600, which would be n = 5, making the next number 65.</p>
27 <p><strong>Step 8:</strong>Repeat these steps to find the decimal places.</p>
26 <p><strong>Step 8:</strong>Repeat these steps to find the decimal places.</p>
28 <p>So the square root of √11250 ≈ 106.066.</p>
27 <p>So the square root of √11250 ≈ 106.066.</p>
29 <h2>Square Root of 11250 by Approximation Method</h2>
28 <h2>Square Root of 11250 by Approximation Method</h2>
30 <p>The approximation method is another method for finding the square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 11250 using the approximation method.</p>
29 <p>The approximation method is another method for finding the square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 11250 using the approximation method.</p>
31 <p><strong>Step 1:</strong>Now we have to find the closest perfect square of √11250. The smallest perfect square less than 11250 is 11025, and the largest perfect square more than 11250 is 11664. √11250 falls between 105 and 108.</p>
30 <p><strong>Step 1:</strong>Now we have to find the closest perfect square of √11250. The smallest perfect square less than 11250 is 11025, and the largest perfect square more than 11250 is 11664. √11250 falls between 105 and 108.</p>
32 <p><strong>Step 2:</strong>Now we need to apply the<a>formula</a>that is (Given number - smallest perfect square) ÷ (Greater perfect square - smallest perfect square). Using the formula (11250 - 11025) ÷ (11664 - 11025) = 0.225.</p>
31 <p><strong>Step 2:</strong>Now we need to apply the<a>formula</a>that is (Given number - smallest perfect square) ÷ (Greater perfect square - smallest perfect square). Using the formula (11250 - 11025) ÷ (11664 - 11025) = 0.225.</p>
33 <p>Using the formula, we identified the<a>decimal</a>point of our square root. The next step is adding the value we got initially to the decimal number which is 105 + 0.225 = 105.225. Therefore, the square root of 11250 is approximately 106.066, after further refinement.</p>
32 <p>Using the formula, we identified the<a>decimal</a>point of our square root. The next step is adding the value we got initially to the decimal number which is 105 + 0.225 = 105.225. Therefore, the square root of 11250 is approximately 106.066, after further refinement.</p>
34 <h2>Common Mistakes and How to Avoid Them in the Square Root of 11250</h2>
33 <h2>Common Mistakes and How to Avoid Them in the Square Root of 11250</h2>
35 <p>Students do make mistakes while finding the square root, like forgetting about the negative square root, skipping long division methods, etc. Now let us look at a few of those mistakes that students tend to make in detail.</p>
34 <p>Students do make mistakes while finding the square root, like forgetting about the negative square root, skipping long division methods, etc. Now let us look at a few of those mistakes that students tend to make in detail.</p>
 
35 + <h2>Download Worksheets</h2>
36 <h3>Problem 1</h3>
36 <h3>Problem 1</h3>
37 <p>Can you help Max find the area of a square box if its side length is given as √112?</p>
37 <p>Can you help Max find the area of a square box if its side length is given as √112?</p>
38 <p>Okay, lets begin</p>
38 <p>Okay, lets begin</p>
39 <p>The area of the square is approximately 1254.24 square units.</p>
39 <p>The area of the square is approximately 1254.24 square units.</p>
40 <h3>Explanation</h3>
40 <h3>Explanation</h3>
41 <p>The area of the square = side².</p>
41 <p>The area of the square = side².</p>
42 <p>The side length is given as √112.</p>
42 <p>The side length is given as √112.</p>
43 <p>Area of the square = side² = √112 x √112 ≈ 10.583 x 10.583 = 1254.24</p>
43 <p>Area of the square = side² = √112 x √112 ≈ 10.583 x 10.583 = 1254.24</p>
44 <p>Therefore, the area of the square box is approximately 1254.24 square units.</p>
44 <p>Therefore, the area of the square box is approximately 1254.24 square units.</p>
45 <p>Well explained 👍</p>
45 <p>Well explained 👍</p>
46 <h3>Problem 2</h3>
46 <h3>Problem 2</h3>
47 <p>A square-shaped building measuring 11250 square feet is built; if each of the sides is √11250, what will be the square feet of half of the building?</p>
47 <p>A square-shaped building measuring 11250 square feet is built; if each of the sides is √11250, what will be the square feet of half of the building?</p>
48 <p>Okay, lets begin</p>
48 <p>Okay, lets begin</p>
49 <p>5625 square feet</p>
49 <p>5625 square feet</p>
50 <h3>Explanation</h3>
50 <h3>Explanation</h3>
51 <p>We can just divide the given area by 2 as the building is square-shaped.</p>
51 <p>We can just divide the given area by 2 as the building is square-shaped.</p>
52 <p>Dividing 11250 by 2 = we get 5625.</p>
52 <p>Dividing 11250 by 2 = we get 5625.</p>
53 <p>So half of the building measures 5625 square feet.</p>
53 <p>So half of the building measures 5625 square feet.</p>
54 <p>Well explained 👍</p>
54 <p>Well explained 👍</p>
55 <h3>Problem 3</h3>
55 <h3>Problem 3</h3>
56 <p>Calculate √11250 x 5.</p>
56 <p>Calculate √11250 x 5.</p>
57 <p>Okay, lets begin</p>
57 <p>Okay, lets begin</p>
58 <p>530.33</p>
58 <p>530.33</p>
59 <h3>Explanation</h3>
59 <h3>Explanation</h3>
60 <p>The first step is to find the square root of 11250, which is approximately 106.066.</p>
60 <p>The first step is to find the square root of 11250, which is approximately 106.066.</p>
61 <p>The second step is to multiply 106.066 by 5.</p>
61 <p>The second step is to multiply 106.066 by 5.</p>
62 <p>So 106.066 x 5 ≈ 530.33.</p>
62 <p>So 106.066 x 5 ≈ 530.33.</p>
63 <p>Well explained 👍</p>
63 <p>Well explained 👍</p>
64 <h3>Problem 4</h3>
64 <h3>Problem 4</h3>
65 <p>What will be the square root of (11025 + 225)?</p>
65 <p>What will be the square root of (11025 + 225)?</p>
66 <p>Okay, lets begin</p>
66 <p>Okay, lets begin</p>
67 <p>The square root is 108.</p>
67 <p>The square root is 108.</p>
68 <h3>Explanation</h3>
68 <h3>Explanation</h3>
69 <p>To find the square root, we need to find the sum of (11025 + 225). 11025 + 225 = 11250, and then √11250 ≈ 106.066.</p>
69 <p>To find the square root, we need to find the sum of (11025 + 225). 11025 + 225 = 11250, and then √11250 ≈ 106.066.</p>
70 <p>Therefore, the square root of (11025 + 225) is approximately 106.066.</p>
70 <p>Therefore, the square root of (11025 + 225) is approximately 106.066.</p>
71 <p>Well explained 👍</p>
71 <p>Well explained 👍</p>
72 <h3>Problem 5</h3>
72 <h3>Problem 5</h3>
73 <p>Find the perimeter of the rectangle if its length ‘l’ is √112 units and the width ‘w’ is 38 units.</p>
73 <p>Find the perimeter of the rectangle if its length ‘l’ is √112 units and the width ‘w’ is 38 units.</p>
74 <p>Okay, lets begin</p>
74 <p>Okay, lets begin</p>
75 <p>We find the perimeter of the rectangle as approximately 97.166 units.</p>
75 <p>We find the perimeter of the rectangle as approximately 97.166 units.</p>
76 <h3>Explanation</h3>
76 <h3>Explanation</h3>
77 <p>Perimeter of the rectangle = 2 × (length + width).</p>
77 <p>Perimeter of the rectangle = 2 × (length + width).</p>
78 <p>Perimeter = 2 × (√112 + 38) ≈ 2 × (10.583 + 38) = 2 × 48.583 = 97.166 units.</p>
78 <p>Perimeter = 2 × (√112 + 38) ≈ 2 × (10.583 + 38) = 2 × 48.583 = 97.166 units.</p>
79 <p>Well explained 👍</p>
79 <p>Well explained 👍</p>
80 <h2>FAQ on Square Root of 11250</h2>
80 <h2>FAQ on Square Root of 11250</h2>
81 <h3>1.What is √11250 in its simplest form?</h3>
81 <h3>1.What is √11250 in its simplest form?</h3>
82 <p>The prime factorization of 11250 is 2 x 3 x 3 x 5 x 5 x 5 x 5, so the simplest form of √11250 = √(2 x 3² x 5⁴).</p>
82 <p>The prime factorization of 11250 is 2 x 3 x 3 x 5 x 5 x 5 x 5, so the simplest form of √11250 = √(2 x 3² x 5⁴).</p>
83 <h3>2.Mention the factors of 11250.</h3>
83 <h3>2.Mention the factors of 11250.</h3>
84 <p>Factors of 11250 include 1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 30, 45, 50, 75, 90, 150, 225, 250, 375, 450, 750, 1125, 2250, 3750, 5625, and 11250.</p>
84 <p>Factors of 11250 include 1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 30, 45, 50, 75, 90, 150, 225, 250, 375, 450, 750, 1125, 2250, 3750, 5625, and 11250.</p>
85 <h3>3.Calculate the square of 11250.</h3>
85 <h3>3.Calculate the square of 11250.</h3>
86 <p>We get the square of 11250 by multiplying the number by itself, that is 11250 x 11250 = 126562500.</p>
86 <p>We get the square of 11250 by multiplying the number by itself, that is 11250 x 11250 = 126562500.</p>
87 <h3>4.Is 11250 a prime number?</h3>
87 <h3>4.Is 11250 a prime number?</h3>
88 <p>11250 is not a<a>prime number</a>, as it has more than two factors.</p>
88 <p>11250 is not a<a>prime number</a>, as it has more than two factors.</p>
89 <h3>5.11250 is divisible by?</h3>
89 <h3>5.11250 is divisible by?</h3>
90 <p>11250 has many factors; those are 1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 30, 45, 50, 75, 90, 150, 225, 250, 375, 450, 750, 1125, 2250, 3750, 5625, and 11250.</p>
90 <p>11250 has many factors; those are 1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 30, 45, 50, 75, 90, 150, 225, 250, 375, 450, 750, 1125, 2250, 3750, 5625, and 11250.</p>
91 <h2>Important Glossaries for the Square Root of 11250</h2>
91 <h2>Important Glossaries for the Square Root of 11250</h2>
92 <ul><li><strong>Square root:</strong>A square root is the inverse of a square. Example: 4² = 16 and the inverse of the square is the square root, that is √16 = 4. </li>
92 <ul><li><strong>Square root:</strong>A square root is the inverse of a square. Example: 4² = 16 and the inverse of the square is the square root, that is √16 = 4. </li>
93 <li><strong>Irrational number:</strong>An irrational number is a number that cannot be written in the form of p/q, where q is not equal to zero and p and q are integers. </li>
93 <li><strong>Irrational number:</strong>An irrational number is a number that cannot be written in the form of p/q, where q is not equal to zero and p and q are integers. </li>
94 <li><strong>Principal square root:</strong>A number has both positive and negative square roots; however, it is always the positive square root that has more prominence due to its uses in the real world. That is the reason it is also known as a principal square root. </li>
94 <li><strong>Principal square root:</strong>A number has both positive and negative square roots; however, it is always the positive square root that has more prominence due to its uses in the real world. That is the reason it is also known as a principal square root. </li>
95 <li><strong>Prime factorization:</strong>The process of breaking down a composite number into its prime factors. For example, the prime factorization of 11250 is 2 x 3² x 5⁴. </li>
95 <li><strong>Prime factorization:</strong>The process of breaking down a composite number into its prime factors. For example, the prime factorization of 11250 is 2 x 3² x 5⁴. </li>
96 <li><strong>Approximation:</strong>The method of finding a value that is close enough to the correct value, usually within an acceptable error margin.</li>
96 <li><strong>Approximation:</strong>The method of finding a value that is close enough to the correct value, usually within an acceptable error margin.</li>
97 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
97 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
98 <p>▶</p>
98 <p>▶</p>
99 <h2>Jaskaran Singh Saluja</h2>
99 <h2>Jaskaran Singh Saluja</h2>
100 <h3>About the Author</h3>
100 <h3>About the Author</h3>
101 <p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
101 <p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
102 <h3>Fun Fact</h3>
102 <h3>Fun Fact</h3>
103 <p>: He loves to play the quiz with kids through algebra to make kids love it.</p>
103 <p>: He loves to play the quiz with kids through algebra to make kids love it.</p>