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Original
2026-01-01
Modified
2026-02-28
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<p>Let us take the following example of a right skewed histogram to calculate the mean, median, and mode from the given dataset:</p>
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<p>Let us take the following example of a right skewed histogram to calculate the mean, median, and mode from the given dataset:</p>
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<p>3, 3, 3, 6, 3, 9, 3, 3, 4, 8, 7, 6, 5, 4, 6, 7</p>
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<p>3, 3, 3, 6, 3, 9, 3, 3, 4, 8, 7, 6, 5, 4, 6, 7</p>
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<p><strong>Solution: </strong></p>
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<p><strong>Solution: </strong></p>
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<p><strong>Mean</strong>= 3 + 3 + 3 + 6 + 3 + 9 + 3 + 3 + 4 + 8 + 7 + 6 + 5 + 4 + 6 + 7 = 80</p>
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<p><strong>Mean</strong>= 3 + 3 + 3 + 6 + 3 + 9 + 3 + 3 + 4 + 8 + 7 + 6 + 5 + 4 + 6 + 7 = 80</p>
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<p>= \({80 \over 16}\) = 5.</p>
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<p>= \({80 \over 16}\) = 5.</p>
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<p><strong>Median:</strong>Arrange the data in<a>ascending order</a>:</p>
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<p><strong>Median:</strong>Arrange the data in<a>ascending order</a>:</p>
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<p>3, 3, 3, 3, 3, 3, 4, 4, 5, 6, 6, 6, 7, 7, 8, 9.</p>
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<p>3, 3, 3, 3, 3, 3, 4, 4, 5, 6, 6, 6, 7, 7, 8, 9.</p>
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<p>Since there are 16 values, the 8th and 9th are the middle values; so the<a>average</a>is: \({{4 + 5} \over 2} = {9 \over 2} = 4.5\)</p>
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<p>Since there are 16 values, the 8th and 9th are the middle values; so the<a>average</a>is: \({{4 + 5} \over 2} = {9 \over 2} = 4.5\)</p>
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<p><strong>Mode:</strong>The mode is the most frequently occurring value. In the data<a>set</a>given above, the mode is 3 because 3 is the most frequently occurring value.</p>
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<p><strong>Mode:</strong>The mode is the most frequently occurring value. In the data<a>set</a>given above, the mode is 3 because 3 is the most frequently occurring value.</p>
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<p><strong>Verification:</strong>In a right-skewed histogram, the relationship between the mean, median, and mode follows this pattern: Mean > Median > Mode. In the above example, the mean = 5, median = 4.5 and mode = 3. Hence, this proves that the above data is a right skewed histogram. </p>
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<p><strong>Verification:</strong>In a right-skewed histogram, the relationship between the mean, median, and mode follows this pattern: Mean > Median > Mode. In the above example, the mean = 5, median = 4.5 and mode = 3. Hence, this proves that the above data is a right skewed histogram. </p>
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