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2026-01-01
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2026-02-28
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<p>305 Learners</p>
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<p>Last updated on<strong>September 30, 2025</strong></p>
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<p>Last updated on<strong>September 30, 2025</strong></p>
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<p>If a number is multiplied by itself, the result is a square. The inverse operation of squaring a number is finding its square root. The square root is used in fields such as vehicle design and finance. Here, we will discuss the square root of 525.</p>
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<p>If a number is multiplied by itself, the result is a square. The inverse operation of squaring a number is finding its square root. The square root is used in fields such as vehicle design and finance. Here, we will discuss the square root of 525.</p>
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<h2>What is the Square Root of 525?</h2>
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<h2>What is the Square Root of 525?</h2>
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<p>The<a>square</a>root is the inverse<a>of</a>squaring a<a>number</a>. 525 is not a<a>perfect square</a>. The square root of 525 can be expressed in both radical and exponential forms. In radical form, it is expressed as √525, whereas in<a>exponential form</a>, it is (525)(1/2). √525 ≈ 22.91288, which is an<a>irrational number</a>because it cannot be expressed as a<a>fraction</a>p/q, where p and q are integers and q ≠ 0.</p>
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<p>The<a>square</a>root is the inverse<a>of</a>squaring a<a>number</a>. 525 is not a<a>perfect square</a>. The square root of 525 can be expressed in both radical and exponential forms. In radical form, it is expressed as √525, whereas in<a>exponential form</a>, it is (525)(1/2). √525 ≈ 22.91288, which is an<a>irrational number</a>because it cannot be expressed as a<a>fraction</a>p/q, where p and q are integers and q ≠ 0.</p>
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<h2>Finding the Square Root of 525</h2>
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<h2>Finding the Square Root of 525</h2>
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<p>The<a>prime factorization</a>method is used for perfect squares. However, for non-perfect squares, methods like the<a>long division</a>method and approximation method are used. Let us explore these methods: -</p>
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<p>The<a>prime factorization</a>method is used for perfect squares. However, for non-perfect squares, methods like the<a>long division</a>method and approximation method are used. Let us explore these methods: -</p>
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<ol><li>Prime factorization method </li>
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<ol><li>Prime factorization method </li>
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<li>Long division method </li>
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<li>Long division method </li>
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<li>Approximation method</li>
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<li>Approximation method</li>
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</ol><h2>Square Root of 525 by Prime Factorization Method</h2>
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</ol><h2>Square Root of 525 by Prime Factorization Method</h2>
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<p>Prime factorization involves expressing a number as a<a>product</a>of its prime<a>factors</a>. Let us break down 525 into its prime factors:</p>
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<p>Prime factorization involves expressing a number as a<a>product</a>of its prime<a>factors</a>. Let us break down 525 into its prime factors:</p>
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<p><strong>Step 1:</strong>Find the prime factors of 525 Breaking it down, we get 3 × 5 × 5 × 7: 31 × 52 × 71</p>
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<p><strong>Step 1:</strong>Find the prime factors of 525 Breaking it down, we get 3 × 5 × 5 × 7: 31 × 52 × 71</p>
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<p><strong>Step 2:</strong>Since 525 is not a perfect square, the digits cannot be grouped into pairs.</p>
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<p><strong>Step 2:</strong>Since 525 is not a perfect square, the digits cannot be grouped into pairs.</p>
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<p>Therefore, calculating the<a>square root</a>of 525 using prime factorization alone is not feasible.</p>
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<p>Therefore, calculating the<a>square root</a>of 525 using prime factorization alone is not feasible.</p>
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<h2>Square Root of 525 by Long Division Method</h2>
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<h2>Square Root of 525 by Long Division Method</h2>
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<p>The long<a>division</a>method is useful for finding the square root of non-perfect squares. Let's find the square root of 525 using this method, step by step:</p>
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<p>The long<a>division</a>method is useful for finding the square root of non-perfect squares. Let's find the square root of 525 using this method, step by step:</p>
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<p><strong>Step 1:</strong>Group the digits of 525 from right to left as 25 and 5.</p>
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<p><strong>Step 1:</strong>Group the digits of 525 from right to left as 25 and 5.</p>
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<p><strong>Step 2:</strong>Find the largest<a>integer</a>n whose square is<a>less than</a>or equal to 5. Here, n is 2 because 2 × 2 = 4. The<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Find the largest<a>integer</a>n whose square is<a>less than</a>or equal to 5. Here, n is 2 because 2 × 2 = 4. The<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Bring down the next pair, 25, making the new<a>dividend</a>125. Add the previous<a>divisor</a>to itself to get 4, making the new divisor.</p>
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<p><strong>Step 3:</strong>Bring down the next pair, 25, making the new<a>dividend</a>125. Add the previous<a>divisor</a>to itself to get 4, making the new divisor.</p>
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<p><strong>Step 4:</strong>Determine n such that 4n × n ≤ 125. If n is 2, then 42 × 2 = 84.</p>
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<p><strong>Step 4:</strong>Determine n such that 4n × n ≤ 125. If n is 2, then 42 × 2 = 84.</p>
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<p><strong>Step 5:</strong>Subtract 84 from 125, giving a remainder of 41. The<a>quotient</a>so far is 22. Step 6: Bring down two zeros, making the new dividend 4100.</p>
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<p><strong>Step 5:</strong>Subtract 84 from 125, giving a remainder of 41. The<a>quotient</a>so far is 22. Step 6: Bring down two zeros, making the new dividend 4100.</p>
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<p><strong>Step 7:</strong>Find the new divisor, which is 229, because 229 × 9 = 2061.</p>
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<p><strong>Step 7:</strong>Find the new divisor, which is 229, because 229 × 9 = 2061.</p>
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<p><strong>Step 8:</strong>Subtract 2061 from 4100, giving a remainder of 2039.</p>
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<p><strong>Step 8:</strong>Subtract 2061 from 4100, giving a remainder of 2039.</p>
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<p><strong>Step 9:</strong>The quotient so far is 22.9. Repeat these steps until you have sufficient decimal places.</p>
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<p><strong>Step 9:</strong>The quotient so far is 22.9. Repeat these steps until you have sufficient decimal places.</p>
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<p>Thus, √525 ≈ 22.91.</p>
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<p>Thus, √525 ≈ 22.91.</p>
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<h2>Square Root of 525 by Approximation Method</h2>
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<h2>Square Root of 525 by Approximation Method</h2>
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<p>The approximation method is another approach to find square roots. Let's approximate the square root of 525:</p>
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<p>The approximation method is another approach to find square roots. Let's approximate the square root of 525:</p>
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<p><strong>Step 1:</strong>Identify the perfect squares closest to 525. 484 and 529 are the nearest perfect squares, with square roots 22 and 23, respectively.</p>
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<p><strong>Step 1:</strong>Identify the perfect squares closest to 525. 484 and 529 are the nearest perfect squares, with square roots 22 and 23, respectively.</p>
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<p><strong>Step 2:</strong>Apply the<a>formula</a>:</p>
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<p><strong>Step 2:</strong>Apply the<a>formula</a>:</p>
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<p>(Given number - smaller perfect square) / (Larger perfect square - smaller perfect square)</p>
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<p>(Given number - smaller perfect square) / (Larger perfect square - smaller perfect square)</p>
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<p>(525 - 484) / (529 - 484) = 41 / 45 ≈ 0.9111</p>
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<p>(525 - 484) / (529 - 484) = 41 / 45 ≈ 0.9111</p>
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<p>Add this<a>decimal</a>to the smaller root: 22 + 0.9111 = 22.9111</p>
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<p>Add this<a>decimal</a>to the smaller root: 22 + 0.9111 = 22.9111</p>
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<p>Therefore, √525 ≈ 22.9111.</p>
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<p>Therefore, √525 ≈ 22.9111.</p>
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<h2>Common Mistakes and How to Avoid Them in the Square Root of 525</h2>
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<h2>Common Mistakes and How to Avoid Them in the Square Root of 525</h2>
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<p>Mistakes are common when calculating square roots, such as forgetting negative roots or misapplying methods. Let's examine some common errors and how to avoid them.</p>
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<p>Mistakes are common when calculating square roots, such as forgetting negative roots or misapplying methods. Let's examine some common errors and how to avoid them.</p>
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<h2>Download Worksheets</h2>
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<h3>Problem 1</h3>
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<h3>Problem 1</h3>
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<p>Can you help Max find the area of a square box if its side length is given as √525?</p>
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<p>Can you help Max find the area of a square box if its side length is given as √525?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The area of the square is 525 square units.</p>
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<p>The area of the square is 525 square units.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>The area of a square = side².</p>
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<p>The area of a square = side².</p>
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<p>The side length is given as √525.</p>
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<p>The side length is given as √525.</p>
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<p>Area = (√525)² = 525.</p>
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<p>Area = (√525)² = 525.</p>
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<p>Therefore, the area of the square box is 525 square units.</p>
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<p>Therefore, the area of the square box is 525 square units.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 2</h3>
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<h3>Problem 2</h3>
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<p>A square-shaped building measuring 525 square feet is built; if each side is √525, what will be the square feet of half of the building?</p>
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<p>A square-shaped building measuring 525 square feet is built; if each side is √525, what will be the square feet of half of the building?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>262.5 square feet</p>
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<p>262.5 square feet</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>Divide the total area by 2 for half of the building: 525 / 2 = 262.5</p>
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<p>Divide the total area by 2 for half of the building: 525 / 2 = 262.5</p>
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<p>So half of the building measures 262.5 square feet.</p>
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<p>So half of the building measures 262.5 square feet.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 3</h3>
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<h3>Problem 3</h3>
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<p>Calculate √525 × 5.</p>
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<p>Calculate √525 × 5.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>114.56</p>
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<p>114.56</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>First, find the square root of 525, which is approximately 22.91288.</p>
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<p>First, find the square root of 525, which is approximately 22.91288.</p>
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<p>Then multiply 22.91288 by 5:</p>
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<p>Then multiply 22.91288 by 5:</p>
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<p>22.91288 × 5 ≈ 114.56</p>
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<p>22.91288 × 5 ≈ 114.56</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 4</h3>
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<h3>Problem 4</h3>
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<p>What will be the square root of (525 + 100)?</p>
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<p>What will be the square root of (525 + 100)?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The square root is approximately 25.</p>
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<p>The square root is approximately 25.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>First, find the sum of (525 + 100): 525 + 100 = 625.</p>
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<p>First, find the sum of (525 + 100): 525 + 100 = 625.</p>
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<p>Then find the square root: √625 = 25.</p>
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<p>Then find the square root: √625 = 25.</p>
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<p>Therefore, the square root of (525 + 100) is ±25.</p>
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<p>Therefore, the square root of (525 + 100) is ±25.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 5</h3>
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<h3>Problem 5</h3>
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<p>Find the perimeter of a rectangle if its length ‘l’ is √525 units and the width ‘w’ is 50 units.</p>
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<p>Find the perimeter of a rectangle if its length ‘l’ is √525 units and the width ‘w’ is 50 units.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The perimeter of the rectangle is approximately 145.83 units.</p>
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<p>The perimeter of the rectangle is approximately 145.83 units.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>Perimeter of a rectangle = 2 × (length + width).</p>
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<p>Perimeter of a rectangle = 2 × (length + width).</p>
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<p>Perimeter = 2 × (√525 + 50)</p>
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<p>Perimeter = 2 × (√525 + 50)</p>
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<p>= 2 × (22.91288 + 50) ≈ 145.83 units.</p>
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<p>= 2 × (22.91288 + 50) ≈ 145.83 units.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h2>FAQ on Square Root of 525</h2>
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<h2>FAQ on Square Root of 525</h2>
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<h3>1.What is √525 in its simplest form?</h3>
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<h3>1.What is √525 in its simplest form?</h3>
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<p>The prime factorization of 525 is 3 × 5^2 × 7, so √525 = √(3 × 5^2 × 7) = 5√(3 × 7) = 5√21.</p>
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<p>The prime factorization of 525 is 3 × 5^2 × 7, so √525 = √(3 × 5^2 × 7) = 5√(3 × 7) = 5√21.</p>
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<h3>2.Mention the factors of 525.</h3>
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<h3>2.Mention the factors of 525.</h3>
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<p>Factors of 525 are 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, and 525.</p>
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<p>Factors of 525 are 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, and 525.</p>
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<h3>3.Calculate the square of 525.</h3>
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<h3>3.Calculate the square of 525.</h3>
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<p>The square of 525 is 275625, calculated by multiplying 525 by itself: 525 × 525 = 275625.</p>
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<p>The square of 525 is 275625, calculated by multiplying 525 by itself: 525 × 525 = 275625.</p>
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<h3>4.Is 525 a prime number?</h3>
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<h3>4.Is 525 a prime number?</h3>
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<h3>5.525 is divisible by?</h3>
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<h3>5.525 is divisible by?</h3>
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<p>525 is divisible by 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, and 525.</p>
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<p>525 is divisible by 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, and 525.</p>
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<h2>Important Glossaries for the Square Root of 525</h2>
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<h2>Important Glossaries for the Square Root of 525</h2>
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<ul><li><strong>Square root:</strong>The square root is the inverse of squaring a number. For example, 42 = 16, so the square root is √16 = 4.</li>
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<ul><li><strong>Square root:</strong>The square root is the inverse of squaring a number. For example, 42 = 16, so the square root is √16 = 4.</li>
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</ul><ul><li><strong>Irrational number:</strong>An irrational number cannot be expressed as a fraction of two integers, with a non-zero denominator. √525 is an example.</li>
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</ul><ul><li><strong>Irrational number:</strong>An irrational number cannot be expressed as a fraction of two integers, with a non-zero denominator. √525 is an example.</li>
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</ul><ul><li><strong>Principal square root:</strong>The positive square root, often used in practical applications, is known as the principal square root. For example, the principal square root of 16 is 4.</li>
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</ul><ul><li><strong>Principal square root:</strong>The positive square root, often used in practical applications, is known as the principal square root. For example, the principal square root of 16 is 4.</li>
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</ul><ul><li><strong>Prime factorization:</strong>This is the expression of a number as a product of its prime factors. For example, the prime factorization of 525 is 3 × 52 × 7.</li>
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</ul><ul><li><strong>Prime factorization:</strong>This is the expression of a number as a product of its prime factors. For example, the prime factorization of 525 is 3 × 52 × 7.</li>
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</ul><ul><li><strong>Long division method:</strong>A method for finding square roots of non-perfect squares by dividing in steps, offering a precise decimal value.</li>
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</ul><ul><li><strong>Long division method:</strong>A method for finding square roots of non-perfect squares by dividing in steps, offering a precise decimal value.</li>
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</ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
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</ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
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<h2>Jaskaran Singh Saluja</h2>
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<h2>Jaskaran Singh Saluja</h2>
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<h3>About the Author</h3>
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<h3>About the Author</h3>
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<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
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<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
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<h3>Fun Fact</h3>
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<h3>Fun Fact</h3>
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<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>
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<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>