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Original 2026-01-01
Modified 2026-02-28
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1269, we need to group it as 69 and 12.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1269, we need to group it as 69 and 12.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is 12. We can say n as ‘3’ because 3 x 3 = 9, which is lesser than or equal to 12. Now the<a>quotient</a>is 3, and after subtracting 12 - 9, the<a>remainder</a>is 3.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is 12. We can say n as ‘3’ because 3 x 3 = 9, which is lesser than or equal to 12. Now the<a>quotient</a>is 3, and after subtracting 12 - 9, the<a>remainder</a>is 3.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 69, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number: 3 + 3 = 6, which will be our new divisor.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 69, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number: 3 + 3 = 6, which will be our new divisor.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 6n as the new divisor; we need to find the value of n.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 6n as the new divisor; we need to find the value of n.</p>
6 <p><strong>Step 5:</strong>The next step is finding 6n x n ≤ 369; let us consider n as 5, now 65 x 5 = 325.</p>
6 <p><strong>Step 5:</strong>The next step is finding 6n x n ≤ 369; let us consider n as 5, now 65 x 5 = 325.</p>
7 <p><strong>Step 6:</strong>Subtract 369 from 325; the difference is 44, and the quotient is 35.</p>
7 <p><strong>Step 6:</strong>Subtract 369 from 325; the difference is 44, and the quotient is 35.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4400.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4400.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor, which is 9, because 359 x 9 = 3231.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor, which is 9, because 359 x 9 = 3231.</p>
10 <p><strong>Step 9:</strong>Subtracting 3231 from 4400, we get the result 1169.</p>
10 <p><strong>Step 9:</strong>Subtracting 3231 from 4400, we get the result 1169.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 35.6.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 35.6.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
13 <p>So the square root of √1269 is approximately 35.61.</p>
13 <p>So the square root of √1269 is approximately 35.61.</p>
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