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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 141, we need to group it as 41 and 1.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 141, we need to group it as 41 and 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 1. We can say n is ‘1’ because 1 x 1 is<a>less than</a>or equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1-1, the<a>remainder</a>is 0.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 1. We can say n is ‘1’ because 1 x 1 is<a>less than</a>or equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1-1, the<a>remainder</a>is 0.</p>
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<p><strong>Step 3:</strong>Now let us bring down 41, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1; we get 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 41, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1; we get 2, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 41. Let us consider n as 1, now 2 x 1 x 1 = 21</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 41. Let us consider n as 1, now 2 x 1 x 1 = 21</p>
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<p><strong>Step 6:</strong>Subtract 41 from 21; the difference is 20, and the quotient is 11.</p>
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<p><strong>Step 6:</strong>Subtract 41 from 21; the difference is 20, and the quotient is 11.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 2000.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 2000.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, that is 109, because 219 x 9 = 1971</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, that is 109, because 219 x 9 = 1971</p>
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<p><strong>Step 9:</strong>Subtracting 1971 from 2000, we get the result 29.</p>
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<p><strong>Step 9:</strong>Subtracting 1971 from 2000, we get the result 29.</p>
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<p><strong>Step 10:</strong>Now the quotient is 11.9</p>
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<p><strong>Step 10:</strong>Now the quotient is 11.9</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. If there are no decimal values, continue until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. If there are no decimal values, continue until the remainder is zero.</p>
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<p>So the square root of √141 is approximately 11.87</p>
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<p>So the square root of √141 is approximately 11.87</p>
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