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Original
2026-01-01
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2026-02-28
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<p>The intersection of<a></a><a>sets</a>refers to the collection of elements common to all the given sets. For example, set A students who take German and set B students who take Japanese, the intersection of the sets of students who take German and those who take Japanese includes only students who are enrolled in both language classes.</p>
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<p>The intersection of<a></a><a>sets</a>refers to the collection of elements common to all the given sets. For example, set A students who take German and set B students who take Japanese, the intersection of the sets of students who take German and those who take Japanese includes only students who are enrolled in both language classes.</p>
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<p><strong>Properties of Intersection of Sets</strong></p>
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<p><strong>Properties of Intersection of Sets</strong></p>
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<p>The following are some properties of the intersection operation:</p>
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<p>The following are some properties of the intersection operation:</p>
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<p><strong>Commutative law: A ∩ B=B ∩ A</strong></p>
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<p><strong>Commutative law: A ∩ B=B ∩ A</strong></p>
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<p>Examine the two sets A = {5, 6, 7, 8, 9, 10} and B = {6, 7, 9, 11} Here, A ∩ B = {5, 6, 7, 8, 9, 10} ∩ {6, 7, 9, 11} = {6, 7, 9} B ∩ A = {6, 7, 9, 11} ∩ {5, 6, 7, 8, 9, 10} = {6, 7, 9} Hence, A ∩ B=B ∩ A </p>
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<p>Examine the two sets A = {5, 6, 7, 8, 9, 10} and B = {6, 7, 9, 11} Here, A ∩ B = {5, 6, 7, 8, 9, 10} ∩ {6, 7, 9, 11} = {6, 7, 9} B ∩ A = {6, 7, 9, 11} ∩ {5, 6, 7, 8, 9, 10} = {6, 7, 9} Hence, A ∩ B=B ∩ A </p>
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<p><strong>Associative law: (A ∩ B) ∩ C=A ∩ (B ∩ C)</strong></p>
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<p><strong>Associative law: (A ∩ B) ∩ C=A ∩ (B ∩ C)</strong></p>
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<p>Examine the three sets A = {5, 6, 7, 8}, B = {7, 8, 9, 10}, and C = {9, 10, 11, 12}. Now, A ∩ B={5, 6, 7, 8} ∩ {7, 8, 9, 10}={7,8} (A ∩ B) ∩ C = {7,8} ∩ {9, 10, 11, 12}={}=φ (No elements are intersecting, so it is an<a></a><a>empty set</a>.)</p>
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<p>Examine the three sets A = {5, 6, 7, 8}, B = {7, 8, 9, 10}, and C = {9, 10, 11, 12}. Now, A ∩ B={5, 6, 7, 8} ∩ {7, 8, 9, 10}={7,8} (A ∩ B) ∩ C = {7,8} ∩ {9, 10, 11, 12}={}=φ (No elements are intersecting, so it is an<a></a><a>empty set</a>.)</p>
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<p>Now, let us find A ∩ (B ∩ C) B ∩ C={7, 8, 9, 10} ∩ {9, 10, 11, 12}={9, 10} A ∩ (B ∩ C)= {5, 6, 7, 8} ∩ {9, 10}={}=φ (No elements are intersecting, so it is an empty set.)</p>
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<p>Now, let us find A ∩ (B ∩ C) B ∩ C={7, 8, 9, 10} ∩ {9, 10, 11, 12}={9, 10} A ∩ (B ∩ C)= {5, 6, 7, 8} ∩ {9, 10}={}=φ (No elements are intersecting, so it is an empty set.)</p>
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<p>Hence, (A ∩ B) ∩ C=A ∩ (B ∩ C) </p>
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<p>Hence, (A ∩ B) ∩ C=A ∩ (B ∩ C) </p>
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<p><strong>Law of φ and U:</strong><strong>φ ∩ A=φ, U ∩ A=A</strong></p>
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<p><strong>Law of φ and U:</strong><strong>φ ∩ A=φ, U ∩ A=A</strong></p>
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<p>Now examine, φ = {} and A = {12, 14, 11} φ ∩ A={} ∩ {12, 14, 11}={}=φ (The intersection with the empty set gives the empty set. Let U = {3, 5, 7, 9, 11, 15, 17, 19, 21, 25} and A = {5, 9, 15, 19, 25}. Then, U ∩ A={3, 5, 7, 9, 11, 15, 17, 19, 21, 25} ∩ {5, 9, 15, 19, 25}= {5, 9, 15, 19, 25}=A</p>
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<p>Now examine, φ = {} and A = {12, 14, 11} φ ∩ A={} ∩ {12, 14, 11}={}=φ (The intersection with the empty set gives the empty set. Let U = {3, 5, 7, 9, 11, 15, 17, 19, 21, 25} and A = {5, 9, 15, 19, 25}. Then, U ∩ A={3, 5, 7, 9, 11, 15, 17, 19, 21, 25} ∩ {5, 9, 15, 19, 25}= {5, 9, 15, 19, 25}=A</p>
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<p>The intersection with the<a>universal set</a>gives back the original set A, since all its elements are in U.</p>
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<p>The intersection with the<a>universal set</a>gives back the original set A, since all its elements are in U.</p>
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<p><strong>Idempotent law: A ∩ A=A</strong></p>
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<p><strong>Idempotent law: A ∩ A=A</strong></p>
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<p>If A={e, f, g, h, i} Therefore, A ∩ A={e, f, g, h, i} ∩ {e, f, g, h, i}={e, f, g, h, i}=A</p>
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<p>If A={e, f, g, h, i} Therefore, A ∩ A={e, f, g, h, i} ∩ {e, f, g, h, i}={e, f, g, h, i}=A</p>
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<p><strong>Distributive law: A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)</strong></p>
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<p><strong>Distributive law: A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)</strong></p>
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<p>Consider the following three sets: A = {1, 3, 5, 7}, B = {1, 2, 4, 6}, and C = {2, 7, 4, 8}. B ∪ C={1, 2, 4, 6} ∪ {2, 7, 4, 8}={1, 2, 4, 6, 7, 8}</p>
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<p>Consider the following three sets: A = {1, 3, 5, 7}, B = {1, 2, 4, 6}, and C = {2, 7, 4, 8}. B ∪ C={1, 2, 4, 6} ∪ {2, 7, 4, 8}={1, 2, 4, 6, 7, 8}</p>
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<p>Next, A ∩ (B ∪ C)={1, 3, 5, 7} ∩ {1, 2, 4, 6, 7, 8}={1, 7} A ∩ B={1} and A ∩ C={7} (A ∩ B) ∪ (A ∩ C)={1} ∪ {7}={1,7} </p>
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<p>Next, A ∩ (B ∪ C)={1, 3, 5, 7} ∩ {1, 2, 4, 6, 7, 8}={1, 7} A ∩ B={1} and A ∩ C={7} (A ∩ B) ∪ (A ∩ C)={1} ∪ {7}={1,7} </p>
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<p><strong>Intersection of Sets Venn Diagram</strong></p>
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<p><strong>Intersection of Sets Venn Diagram</strong></p>
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<p>The intersection of two sets, A and B, is shown by the shaded area in the diagram above. Likewise, as an example below, we can create a<a>Venn diagram</a>for the intersection of three sets. </p>
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<p>The intersection of two sets, A and B, is shown by the shaded area in the diagram above. Likewise, as an example below, we can create a<a>Venn diagram</a>for the intersection of three sets. </p>
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