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Original 2026-01-01
Modified 2026-02-28
1 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
1 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 386, we need to group it as 86 and 3.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 386, we need to group it as 86 and 3.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 3. We can say n as ‘1’ because 1 x 1 is lesser than or equal to 3. Now the<a>quotient</a>is 1, and after subtracting 1 from 3, the<a>remainder</a>is 2.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 3. We can say n as ‘1’ because 1 x 1 is lesser than or equal to 3. Now the<a>quotient</a>is 1, and after subtracting 1 from 3, the<a>remainder</a>is 2.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 86, making the new<a>dividend</a>286. Add the old<a>divisor</a>with the same number, 1 + 1, giving us 2, which will be our new divisor.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 86, making the new<a>dividend</a>286. Add the old<a>divisor</a>with the same number, 1 + 1, giving us 2, which will be our new divisor.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
6 <p><strong>Step 5:</strong>Finding 2n × n ≤ 286, let us consider n as 9, then 2 x 9 x 9 = 261.</p>
6 <p><strong>Step 5:</strong>Finding 2n × n ≤ 286, let us consider n as 9, then 2 x 9 x 9 = 261.</p>
7 <p><strong>Step 6:</strong>Subtract 261 from 286, the difference is 25, and the quotient becomes 19.</p>
7 <p><strong>Step 6:</strong>Subtract 261 from 286, the difference is 25, and the quotient becomes 19.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. The new dividend is 2500.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. The new dividend is 2500.</p>
9 <p><strong>Step 8:</strong>Find the new divisor, which is 193 because 1939 x 9 = 17451.</p>
9 <p><strong>Step 8:</strong>Find the new divisor, which is 193 because 1939 x 9 = 17451.</p>
10 <p><strong>Step 9:</strong>Subtracting 17451 from 25000, we get the result 7549.</p>
10 <p><strong>Step 9:</strong>Subtracting 17451 from 25000, we get the result 7549.</p>
11 <p><strong>Step 10:</strong>Now the quotient is approximately 19.6.</p>
11 <p><strong>Step 10:</strong>Now the quotient is approximately 19.6.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
13 <p>So the square root of √386 is approximately 19.65.</p>
13 <p>So the square root of √386 is approximately 19.65.</p>
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