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2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1027, we need to group it as 27 and 10.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1027, we need to group it as 27 and 10.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 10. We can say n as ‘3’ because 3 x 3 = 9, which is less than 10. Now the<a>quotient</a>is 3; after subtracting 10 - 9, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 10. We can say n as ‘3’ because 3 x 3 = 9, which is less than 10. Now the<a>quotient</a>is 3; after subtracting 10 - 9, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 27, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 27, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 6n as the new divisor; we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 6n as the new divisor; we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n x n ≤ 127. Let's consider n as 2, now 6 x 2 x 2 = 24.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n x n ≤ 127. Let's consider n as 2, now 6 x 2 x 2 = 24.</p>
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<p><strong>Step 6:</strong>Subtract 127 from 124; the difference is 3, and the quotient is 32.</p>
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<p><strong>Step 6:</strong>Subtract 127 from 124; the difference is 3, and the quotient is 32.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 300.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 300.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 64 because 642 x 4 = 256.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 64 because 642 x 4 = 256.</p>
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<p><strong>Step 9:</strong>Subtracting 256 from 300, we get the result 44.</p>
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<p><strong>Step 9:</strong>Subtracting 256 from 300, we get the result 44.</p>
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<p><strong>Step 10:</strong>Now the quotient is 32.0.</p>
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<p><strong>Step 10:</strong>Now the quotient is 32.0.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p>So the square root of √1027 is approximately 32.05.</p>
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<p>So the square root of √1027 is approximately 32.05.</p>
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