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Original
2026-01-01
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2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 715, we need to group it as 15 and 7.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 715, we need to group it as 15 and 7.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 7. We can say n is ‘2’ because 2 × 2 = 4, which is lesser than or equal to 7. Now the<a>quotient</a>is 2, after subtracting 4 from 7, the<a>remainder</a>is 3.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 7. We can say n is ‘2’ because 2 × 2 = 4, which is lesser than or equal to 7. Now the<a>quotient</a>is 2, after subtracting 4 from 7, the<a>remainder</a>is 3.</p>
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<p><strong>Step 3:</strong>Bring down 15, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 2 + 2, we get 4, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Bring down 15, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 2 + 2, we get 4, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the previous divisor and the quotient. Now we get 4n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the previous divisor and the quotient. Now we get 4n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 4n × n ≤ 315. Let us consider n as 7, now 47 × 7 = 329, which is greater than 315. So, we try n as 6: 46 × 6 = 276.</p>
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<p><strong>Step 5:</strong>The next step is finding 4n × n ≤ 315. Let us consider n as 7, now 47 × 7 = 329, which is greater than 315. So, we try n as 6: 46 × 6 = 276.</p>
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<p><strong>Step 6:</strong>Subtract 276 from 315, the difference is 39, and the quotient is 26.</p>
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<p><strong>Step 6:</strong>Subtract 276 from 315, the difference is 39, and the quotient is 26.</p>
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<p><strong>Step 7:</strong>Since the new dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 3900.</p>
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<p><strong>Step 7:</strong>Since the new dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 3900.</p>
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<p><strong>Step 8:</strong>The new divisor is 532 because 532 × 7 = 3724, which is less than 3900.</p>
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<p><strong>Step 8:</strong>The new divisor is 532 because 532 × 7 = 3724, which is less than 3900.</p>
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<p><strong>Step 9:</strong>Subtracting 3724 from 3900, we get the remainder 176.</p>
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<p><strong>Step 9:</strong>Subtracting 3724 from 3900, we get the remainder 176.</p>
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<p><strong>Step 10:</strong>Now the quotient is 26.7</p>
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<p><strong>Step 10:</strong>Now the quotient is 26.7</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point or until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point or until the remainder is zero.</p>
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<p>So the square root of √715 is approximately 26.73.</p>
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<p>So the square root of √715 is approximately 26.73.</p>
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