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Original
2026-01-01
Modified
2026-02-28
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<p>71 can be converted easily from decimal to binary. The methods mentioned below will help us convert the number. Let’s see how it is done.</p>
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<p>71 can be converted easily from decimal to binary. The methods mentioned below will help us convert the number. Let’s see how it is done.</p>
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<p>Expansion Method: Let us see the step-by-step process of converting 71 using the expansion method.</p>
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<p>Expansion Method: Let us see the step-by-step process of converting 71 using the expansion method.</p>
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<p><strong>Step 1</strong>- Figure out the place values: In the binary system, each<a>place value</a>is a<a>power</a>of 2. Therefore, in the first step, we will ascertain the powers of 2.</p>
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<p><strong>Step 1</strong>- Figure out the place values: In the binary system, each<a>place value</a>is a<a>power</a>of 2. Therefore, in the first step, we will ascertain the powers of 2.</p>
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<p>20 = 1</p>
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<p>20 = 1</p>
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<p>21 = 2</p>
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<p>21 = 2</p>
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<p>22 = 4</p>
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<p>22 = 4</p>
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<p>23 = 8</p>
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<p>23 = 8</p>
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<p>24 = 16</p>
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<p>24 = 16</p>
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<p>25 = 32</p>
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<p>25 = 32</p>
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<p>26 = 64</p>
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<p>26 = 64</p>
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<p>27 = 128</p>
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<p>27 = 128</p>
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<p>Since 128 is<a>greater than</a>71, we stop at 2^6 = 64.</p>
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<p>Since 128 is<a>greater than</a>71, we stop at 2^6 = 64.</p>
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<p><strong>Step 2</strong>- Identify the largest power of 2: In the previous step, we stopped at 26 = 64. This is because, in this step, we have to identify the largest power of 2, which is<a>less than</a>or equal to the given number, 71. Since 26 is the number we are looking for, write 1 in the 26 place. Now the value of 26, which is 64, is subtracted from 71. 71 - 64 = 7.</p>
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<p><strong>Step 2</strong>- Identify the largest power of 2: In the previous step, we stopped at 26 = 64. This is because, in this step, we have to identify the largest power of 2, which is<a>less than</a>or equal to the given number, 71. Since 26 is the number we are looking for, write 1 in the 26 place. Now the value of 26, which is 64, is subtracted from 71. 71 - 64 = 7.</p>
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<p><strong>Step 3</strong>- Identify the next largest power of 2: In this step, we need to find the largest power of 2 that fits into the result of the previous step, 7. So, the next largest power of 2 is 22, which is less than or equal to 7. Now, we have to write 1 in the 22 place. And then subtract 4 from 7. 7 - 4 = 3.</p>
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<p><strong>Step 3</strong>- Identify the next largest power of 2: In this step, we need to find the largest power of 2 that fits into the result of the previous step, 7. So, the next largest power of 2 is 22, which is less than or equal to 7. Now, we have to write 1 in the 22 place. And then subtract 4 from 7. 7 - 4 = 3.</p>
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<p><strong>Step 4</strong>- Continue with the next largest power of 2: Now, we find the largest power of 2 that fits into 3, which is 21. Write 1 in the 21 place and subtract 2. 3 - 2 = 1.</p>
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<p><strong>Step 4</strong>- Continue with the next largest power of 2: Now, we find the largest power of 2 that fits into 3, which is 21. Write 1 in the 21 place and subtract 2. 3 - 2 = 1.</p>
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<p><strong>Step 5</strong>- Write the final 1: The remaining number is 1, which is 20, so write 1 in the 20 place. Now, by substituting the values, we get, 1 in the 20 place 1 in the 21 place 1 in the 22 place 0 in the 23 place 0 in the 24 place 0 in the 25 place 1 in the 26 place</p>
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<p><strong>Step 5</strong>- Write the final 1: The remaining number is 1, which is 20, so write 1 in the 20 place. Now, by substituting the values, we get, 1 in the 20 place 1 in the 21 place 1 in the 22 place 0 in the 23 place 0 in the 24 place 0 in the 25 place 1 in the 26 place</p>
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<p><strong>Step 6</strong>- Write the values in reverse order: We now write the numbers upside down to represent 71 in binary. Therefore, 1000111 is 71 in binary.</p>
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<p><strong>Step 6</strong>- Write the values in reverse order: We now write the numbers upside down to represent 71 in binary. Therefore, 1000111 is 71 in binary.</p>
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<p>Grouping Method: In this method, we divide the number 71 by 2. Let us see the step-by-step conversion.</p>
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<p>Grouping Method: In this method, we divide the number 71 by 2. Let us see the step-by-step conversion.</p>
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<p><strong>Step 1</strong>- Divide the given number 71 by 2. 71 / 2 = 35. Here, 35 is the quotient and 1 is the remainder.</p>
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<p><strong>Step 1</strong>- Divide the given number 71 by 2. 71 / 2 = 35. Here, 35 is the quotient and 1 is the remainder.</p>
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<p><strong>Step 2</strong>- Divide the previous quotient (35) by 2. 35 / 2 = 17. Here, the quotient is 17 and the remainder is 1.</p>
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<p><strong>Step 2</strong>- Divide the previous quotient (35) by 2. 35 / 2 = 17. Here, the quotient is 17 and the remainder is 1.</p>
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<p><strong>Step 3</strong>- Repeat the previous step. 17 / 2 = 8. Now, the quotient is 8, and 1 is the remainder.</p>
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<p><strong>Step 3</strong>- Repeat the previous step. 17 / 2 = 8. Now, the quotient is 8, and 1 is the remainder.</p>
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<p><strong>Step 4</strong>- Repeat the previous step. 8 / 2 = 4. Here, the remainder is 0.</p>
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<p><strong>Step 4</strong>- Repeat the previous step. 8 / 2 = 4. Here, the remainder is 0.</p>
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<p><strong>Step 5</strong>- Repeat the previous step. 4 / 2 = 2. Here, the remainder is 0.</p>
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<p><strong>Step 5</strong>- Repeat the previous step. 4 / 2 = 2. Here, the remainder is 0.</p>
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<p><strong>Step 6</strong>- Repeat the previous step. 2 / 2 = 1. Here, the remainder is 0.</p>
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<p><strong>Step 6</strong>- Repeat the previous step. 2 / 2 = 1. Here, the remainder is 0.</p>
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<p><strong>Step 7</strong>- Repeat the previous step. 1 / 2 = 0. Here, the remainder is 1. And we stop the<a>division</a>here because the quotient is 0.</p>
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<p><strong>Step 7</strong>- Repeat the previous step. 1 / 2 = 0. Here, the remainder is 1. And we stop the<a>division</a>here because the quotient is 0.</p>
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<p><strong>Step 8</strong>- Write down the remainders from bottom to top. Therefore, 71 (decimal) = 1000111 (binary).</p>
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<p><strong>Step 8</strong>- Write down the remainders from bottom to top. Therefore, 71 (decimal) = 1000111 (binary).</p>
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