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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 229, we need to group it as 29 and 2.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 229, we need to group it as 29 and 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is closest to 2. We can say n is ‘1’ because 1 x 1 is lesser than or equal to 2. Now the<a>quotient</a>is 1, after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is closest to 2. We can say n is ‘1’ because 1 x 1 is lesser than or equal to 2. Now the<a>quotient</a>is 1, after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 29 which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1 to get 2 which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 29 which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1 to get 2 which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n x n ≤ 129. Let us consider n as 5, now 25 x 5 = 125.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n x n ≤ 129. Let us consider n as 5, now 25 x 5 = 125.</p>
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<p><strong>Step 6:</strong>Subtract 125 from 129, the difference is 4, and the quotient is 15.</p>
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<p><strong>Step 6:</strong>Subtract 125 from 129, the difference is 4, and the quotient is 15.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 400.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 400.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 151 because 151 x 1 = 151.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 151 because 151 x 1 = 151.</p>
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<p><strong>Step 9:</strong>Subtracting 151 from 400, we get the result 249.</p>
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<p><strong>Step 9:</strong>Subtracting 151 from 400, we get the result 249.</p>
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<p><strong>Step 10:</strong>Now the quotient is 15.1.</p>
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<p><strong>Step 10:</strong>Now the quotient is 15.1.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero. So the square root of √229 is approximately 15.13.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero. So the square root of √229 is approximately 15.13.</p>
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