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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 2521, we need to group it as 21 and 25.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 2521, we need to group it as 21 and 25.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 25. We can say n is ‘5’ because 5 x 5 = 25. Now the<a>quotient</a>is 5, and after subtracting 25 - 25, the<a>remainder</a>is 0.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 25. We can say n is ‘5’ because 5 x 5 = 25. Now the<a>quotient</a>is 5, and after subtracting 25 - 25, the<a>remainder</a>is 0.</p>
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<p><strong>Step 3:</strong>Bring down 21, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 5 + 5 = 10, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Bring down 21, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 5 + 5 = 10, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 10n as the new divisor; we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 10n as the new divisor; we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 10n x n ≤ 21. Let us consider n as 2, now 10 x 2 x 2 = 40, which is greater than 21, so n should be 1.</p>
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<p><strong>Step 5:</strong>The next step is finding 10n x n ≤ 21. Let us consider n as 2, now 10 x 2 x 2 = 40, which is greater than 21, so n should be 1.</p>
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<p><strong>Step 6:</strong>Multiply 10 x 1 = 10, and subtract 21 - 10, the difference is 11, and the quotient is 51.</p>
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<p><strong>Step 6:</strong>Multiply 10 x 1 = 10, and subtract 21 - 10, the difference is 11, and the quotient is 51.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1100.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1100.</p>
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<p><strong>Step 8:</strong>Now, the new divisor becomes 102. Find n such that 102n x n ≤ 1100. We find n = 9 works because 102 x 9 = 918.</p>
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<p><strong>Step 8:</strong>Now, the new divisor becomes 102. Find n such that 102n x n ≤ 1100. We find n = 9 works because 102 x 9 = 918.</p>
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<p><strong>Step 9:</strong>Subtract 918 from 1100, and we get the result 182.</p>
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<p><strong>Step 9:</strong>Subtract 918 from 1100, and we get the result 182.</p>
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<p><strong>Step 10:</strong>Now, the quotient is 50.9.</p>
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<p><strong>Step 10:</strong>Now, the quotient is 50.9.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
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<p>So the square root of √2521 is approximately 50.21.</p>
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<p>So the square root of √2521 is approximately 50.21.</p>
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