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2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 187, we need to group it as 87 and 1.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 187, we need to group it as 87 and 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 1. We can say n is 1 because \(1 \times 1\) is lesser than or equal to 1. Now the<a>quotient</a>is 1. After subtracting 1-1, the<a>remainder</a>is 0.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 1. We can say n is 1 because \(1 \times 1\) is lesser than or equal to 1. Now the<a>quotient</a>is 1. After subtracting 1-1, the<a>remainder</a>is 0.</p>
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<p><strong>Step 3:</strong>Now let us bring down 87, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 87, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding \(2 \cdot n \cdot n \leq 87\). Let us consider n as 3, now \(2 \times 3 \times 3 = 18\).</p>
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<p><strong>Step 5:</strong>The next step is finding \(2 \cdot n \cdot n \leq 87\). Let us consider n as 3, now \(2 \times 3 \times 3 = 18\).</p>
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<p><strong>Step 6:</strong>Subtract 87 from 18, the difference is 69, and the quotient is 13.</p>
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<p><strong>Step 6:</strong>Subtract 87 from 18, the difference is 69, and the quotient is 13.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 6900.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 6900.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 136 because \(273 \times 3 = 819\).</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 136 because \(273 \times 3 = 819\).</p>
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<p><strong>Step 9:</strong>Subtracting 819 from 6900, we get the result 6081.</p>
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<p><strong>Step 9:</strong>Subtracting 819 from 6900, we get the result 6081.</p>
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<p><strong>Step 10:</strong>Now the quotient is 13.6.</p>
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<p><strong>Step 10:</strong>Now the quotient is 13.6.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero. So the square root of √187 is approximately 13.67.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero. So the square root of √187 is approximately 13.67.</p>
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