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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1180, we need to group it as 80 and 11.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1180, we need to group it as 80 and 11.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is closest to 11. We can say n is ‘3’ because 3 x 3 = 9, which is lesser than or equal to 11. Now the<a>quotient</a>is 3, and after subtracting 9 from 11, the<a>remainder</a>is 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is closest to 11. We can say n is ‘3’ because 3 x 3 = 9, which is lesser than or equal to 11. Now the<a>quotient</a>is 3, and after subtracting 9 from 11, the<a>remainder</a>is 2.</p>
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<p><strong>Step 3:</strong>Now let us bring down 80, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3 = 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 80, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3 = 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>With 6 as the new divisor, we need to find the value of n such that 6n x n ≤ 280.</p>
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<p><strong>Step 4:</strong>With 6 as the new divisor, we need to find the value of n such that 6n x n ≤ 280.</p>
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<p><strong>Step 5:</strong>The next step is finding n such that 6n x n ≤ 280. Let us consider n as 4. Now, 64 x 4 = 256.</p>
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<p><strong>Step 5:</strong>The next step is finding n such that 6n x n ≤ 280. Let us consider n as 4. Now, 64 x 4 = 256.</p>
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<p><strong>Step 6:</strong>Subtract 256 from 280; the difference is 24, and the quotient is 34.</p>
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<p><strong>Step 6:</strong>Subtract 256 from 280; the difference is 24, and the quotient is 34.</p>
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<p><strong>Step 7:</strong>Since the dividend is<a>less than</a>the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 2400.</p>
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<p><strong>Step 7:</strong>Since the dividend is<a>less than</a>the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 2400.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor. Let’s consider n as 3 because 683 x 3 = 2049.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor. Let’s consider n as 3 because 683 x 3 = 2049.</p>
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<p><strong>Step 9:</strong>Subtracting 2049 from 2400, we get the result 351.</p>
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<p><strong>Step 9:</strong>Subtracting 2049 from 2400, we get the result 351.</p>
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<p><strong>Step 10:</strong>Now the quotient is 34.3</p>
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<p><strong>Step 10:</strong>Now the quotient is 34.3</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal value, continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal value, continue till the remainder is zero.</p>
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<p>So the square root of √1180 is approximately 34.38.</p>
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<p>So the square root of √1180 is approximately 34.38.</p>
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