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Original 2026-01-01
Modified 2026-02-28
1 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
1 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 152, we need to group it as 52 and 1.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 152, we need to group it as 52 and 1.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 1. We can say n is ‘1’ because 1 x 1 is equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1-1, the<a>remainder</a>is 0.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 1. We can say n is ‘1’ because 1 x 1 is equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1-1, the<a>remainder</a>is 0.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 52, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number, 1 + 1, to get 2, which will be our new divisor.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 52, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number, 1 + 1, to get 2, which will be our new divisor.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor; we need to find the value of n.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor; we need to find the value of n.</p>
6 <p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 52. Let us consider n as 2; now 2 x 2 x 2 = 8</p>
6 <p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 52. Let us consider n as 2; now 2 x 2 x 2 = 8</p>
7 <p><strong>Step 6:</strong>Subtract 52 from 8; the difference is 44, and the quotient is 12.</p>
7 <p><strong>Step 6:</strong>Subtract 52 from 8; the difference is 44, and the quotient is 12.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4400.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4400.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that is 246 because 246 x 18 = 4428, which is close to 4400.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that is 246 because 246 x 18 = 4428, which is close to 4400.</p>
10 <p><strong>Step 9:</strong>Subtracting 4428 from 4400, we get the result -28.</p>
10 <p><strong>Step 9:</strong>Subtracting 4428 from 4400, we get the result -28.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 12.3</p>
11 <p><strong>Step 10:</strong>Now the quotient is 12.3</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
13 <p>So the square root of √152 is approximately 12.32.</p>
13 <p>So the square root of √152 is approximately 12.32.</p>
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