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Original
2026-01-01
Modified
2026-02-28
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<p>The properties of intersection of sets are:</p>
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<p>The properties of intersection of sets are:</p>
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<ul><li><strong>Commutative Law</strong></li>
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<ul><li><strong>Commutative Law</strong></li>
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</ul><ul><li><strong>Associative Law</strong></li>
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</ul><ul><li><strong>Associative Law</strong></li>
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</ul><ul><li><strong>Distributive Law</strong></li>
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</ul><ul><li><strong>Distributive Law</strong></li>
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</ul><ul><li><strong>Law of Empty Set</strong></li>
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</ul><ul><li><strong>Law of Empty Set</strong></li>
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</ul><ul><li><strong>Law of Universal Set</strong></li>
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</ul><ul><li><strong>Law of Universal Set</strong></li>
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</ul><ul><li><strong>Idempotent Law</strong></li>
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</ul><ul><li><strong>Idempotent Law</strong></li>
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</ul><p><strong>Commutative Law</strong>: Commutative law states that the order of the intersection doesn’t matter. The order of the sets does not affect the result.</p>
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</ul><p><strong>Commutative Law</strong>: Commutative law states that the order of the intersection doesn’t matter. The order of the sets does not affect the result.</p>
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<p>Rule: A ∩ B = B ∩ A</p>
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<p>Rule: A ∩ B = B ∩ A</p>
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<p>Example: Let A = {cat, dog} and B = {cat, rabbit}. </p>
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<p>Example: Let A = {cat, dog} and B = {cat, rabbit}. </p>
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<p>A ∩ B = {cat} - (1)</p>
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<p>A ∩ B = {cat} - (1)</p>
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<p>B ∩ A = {cat} - (2)</p>
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<p>B ∩ A = {cat} - (2)</p>
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<p>From (1) and (2), we get that A ∩ B = B ∩ A</p>
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<p>From (1) and (2), we get that A ∩ B = B ∩ A</p>
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<p><strong>Associative Law</strong>: While finding the<a>intersection of three sets</a>, we can group any two sets first. If the resultant is grouped with the remaining set, the result will be the same. </p>
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<p><strong>Associative Law</strong>: While finding the<a>intersection of three sets</a>, we can group any two sets first. If the resultant is grouped with the remaining set, the result will be the same. </p>
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<p>Rule: (A ∩ B) ∩ C = A ∩ (B ∩ C)</p>
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<p>Rule: (A ∩ B) ∩ C = A ∩ (B ∩ C)</p>
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<p>Example: Let A = {1, 2}, B = {2, 3}, C = {2, 4}</p>
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<p>Example: Let A = {1, 2}, B = {2, 3}, C = {2, 4}</p>
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<p>A ∩ B = {2}</p>
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<p>A ∩ B = {2}</p>
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<p>(A ∩ B) ∩ C = {2} - (1)</p>
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<p>(A ∩ B) ∩ C = {2} - (1)</p>
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<p>B ∩ C = {2}</p>
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<p>B ∩ C = {2}</p>
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<p>A ∩ (B ∩ C) = {2} - (2)</p>
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<p>A ∩ (B ∩ C) = {2} - (2)</p>
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<p>From (1) and (2), (A ∩ B) ∩ C = A ∩ (B ∩ C)</p>
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<p>From (1) and (2), (A ∩ B) ∩ C = A ∩ (B ∩ C)</p>
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<p><strong>Distributive Law</strong>: If we intersect one set with the union of two other sets, it is equivalent to finding the intersection with each set separately and then taking their union.</p>
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<p><strong>Distributive Law</strong>: If we intersect one set with the union of two other sets, it is equivalent to finding the intersection with each set separately and then taking their union.</p>
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<p> Rule: A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)</p>
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<p> Rule: A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)</p>
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<p>Example: A = {red, blue}, B ={blue, green}, C = {blue, yellow}</p>
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<p>Example: A = {red, blue}, B ={blue, green}, C = {blue, yellow}</p>
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<p>B ∪ C = {blue, green, yellow}</p>
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<p>B ∪ C = {blue, green, yellow}</p>
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<p>A ∩ (B ∪ C) = {blue} - (1)</p>
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<p>A ∩ (B ∪ C) = {blue} - (1)</p>
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<p>A ∩ B = {blue}</p>
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<p>A ∩ B = {blue}</p>
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<p>A ∩ C = {blue}</p>
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<p>A ∩ C = {blue}</p>
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<p>(A ∩ B) ∪ (A ∩ C) = {blue} - (2)</p>
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<p>(A ∩ B) ∪ (A ∩ C) = {blue} - (2)</p>
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<p>From (1) and (2), A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)</p>
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<p>From (1) and (2), A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)</p>
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<p>Therefore, the distributive law is true.</p>
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<p>Therefore, the distributive law is true.</p>
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<p><strong>Law of Empty Set</strong>: If we take the intersection of any set with an empty set, the result will always be an empty set. </p>
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<p><strong>Law of Empty Set</strong>: If we take the intersection of any set with an empty set, the result will always be an empty set. </p>
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<p>Rule: A ∩ ∅ = ∅</p>
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<p>Rule: A ∩ ∅ = ∅</p>
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<p>Example: A = {1, 2, 3} and ∅ = {}</p>
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<p>Example: A = {1, 2, 3} and ∅ = {}</p>
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<p>A ∩ ∅ = ∅, because the empty set has no elements to share with set A.</p>
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<p>A ∩ ∅ = ∅, because the empty set has no elements to share with set A.</p>
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<p><strong>Law of Universal Set</strong>: If we intersect any set with a<a></a><a>universal set</a>, the result is the original set, because the universal set has all the elements in it. </p>
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<p><strong>Law of Universal Set</strong>: If we intersect any set with a<a></a><a>universal set</a>, the result is the original set, because the universal set has all the elements in it. </p>
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<p>Rule: A ∩ U = A</p>
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<p>Rule: A ∩ U = A</p>
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<p>Example: A = {sun, moon}, U = {sun, moon, stars, sky}</p>
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<p>Example: A = {sun, moon}, U = {sun, moon, stars, sky}</p>
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<p>A ∩ U = {sun, moon}</p>
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<p>A ∩ U = {sun, moon}</p>
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<p>The intersection of set A with the universal set U gives back set A. </p>
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<p>The intersection of set A with the universal set U gives back set A. </p>
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<p><strong>Idempotent Set</strong>: Intersecting a<a>set</a>with itself results in the same set.</p>
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<p><strong>Idempotent Set</strong>: Intersecting a<a>set</a>with itself results in the same set.</p>
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<p>Rule: A ∩ A = A</p>
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<p>Rule: A ∩ A = A</p>
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<p>Example: A = {10, 20}</p>
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<p>Example: A = {10, 20}</p>
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<p>A ∩ A = {10, 20}</p>
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<p>A ∩ A = {10, 20}</p>
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<p>Intersecting a set with itself results in the same set, therefore the idempotent law is true.</p>
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<p>Intersecting a set with itself results in the same set, therefore the idempotent law is true.</p>
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