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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 239, we group it as 39 and 2.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 239, we group it as 39 and 2.</p>
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<p><strong>Step 2:</strong>Now we need to find a number n whose square is 2 or less. We can say n as ‘1’ because 1 × 1 is<a>less than</a>or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find a number n whose square is 2 or less. We can say n as ‘1’ because 1 × 1 is<a>less than</a>or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 39, making the new<a>dividend</a>139. Add the old<a>divisor</a>with the same number 1 + 1 to get 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 39, making the new<a>dividend</a>139. Add the old<a>divisor</a>with the same number 1 + 1 to get 2, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be 2n, and we need to find the value of n such that 2n × n ≤ 139. Let us consider n as 6, now 26 × 6 = 156, which is<a>greater than</a>139, so try n as 5, 25 × 5 = 125.</p>
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<p><strong>Step 4:</strong>The new divisor will be 2n, and we need to find the value of n such that 2n × n ≤ 139. Let us consider n as 6, now 26 × 6 = 156, which is<a>greater than</a>139, so try n as 5, 25 × 5 = 125.</p>
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<p><strong>Step 5:</strong>Subtract 125 from 139; the difference is 14, and the quotient is 15.</p>
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<p><strong>Step 5:</strong>Subtract 125 from 139; the difference is 14, and the quotient is 15.</p>
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<p><strong>Step 6:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1400.</p>
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<p><strong>Step 6:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1400.</p>
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<p><strong>Step 7:</strong>Now we need to find the new divisor that is 310 because 310 × 4 = 1240.</p>
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<p><strong>Step 7:</strong>Now we need to find the new divisor that is 310 because 310 × 4 = 1240.</p>
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<p><strong>Step 8:</strong>Subtracting 1240 from 1400, we get 160.</p>
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<p><strong>Step 8:</strong>Subtracting 1240 from 1400, we get 160.</p>
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<p><strong>Step 9:</strong>Now the quotient is 15.4.</p>
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<p><strong>Step 9:</strong>Now the quotient is 15.4.</p>
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<p><strong>Step 10:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal value, continue till the remainder is zero.</p>
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<p><strong>Step 10:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal value, continue till the remainder is zero.</p>
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<p>So the square root of √239 ≈ 15.459.</p>
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<p>So the square root of √239 ≈ 15.459.</p>
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