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1 - <p>124 Learners</p>

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2 <p>Last updated on<strong>September 11, 2025</strong></p>

3 <p>The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 63 and 81.</p>

4 <h2>What is the GCF of 63 and 81?</h2>

5 <p>The<a>greatest common factor</a>of 63 and 81 is 9. The largest<a>divisor</a>of two or more<a>numbers</a>is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.</p>

6 <h2>How to find the GCF of 63 and 81?</h2>

7 <p>To find the GCF of 63 and 81, a few methods are described below -</p>

8 <ol><li>Listing Factors</li>

9 <li>Prime Factorization</li>

10 <li>Long Division Method / by Euclidean Algorithm</li>

11 </ol><h2>GCF of 63 and 81 by Using Listing of factors</h2>

12 <p>Steps to find the GCF of 63 and 81 using the listing of<a>factors</a>:</p>

13 <p><strong>Step 1:</strong>Firstly, list the factors of each number Factors of 63 = 1, 3, 7, 9, 21, 63. Factors of 81 = 1, 3, 9, 27, 81.</p>

14 <p><strong>Step 2:</strong>Now, identify the<a>common factors</a>of them Common factors of 63 and 81: 1, 3, 9.</p>

15 <p><strong>Step 3:</strong>Choose the largest factor The largest factor that both numbers have is 9. The GCF of 63 and 81 is 9.</p>

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18 <h2>GCF of 63 and 81 Using Prime Factorization</h2>

17 <h2>GCF of 63 and 81 Using Prime Factorization</h2>

19 <p>To find the GCF of 63 and 81 using the Prime Factorization Method, follow these steps:</p>

18 <p>To find the GCF of 63 and 81 using the Prime Factorization Method, follow these steps:</p>

20 <p><strong>Step 1:</strong>Find the<a>prime factors</a>of each number Prime Factors of 63: 63 = 3 x 3 x 7 = 3² x 7 Prime Factors of 81: 81 = 3 x 3 x 3 x 3 = 3⁴</p>

19 <p><strong>Step 1:</strong>Find the<a>prime factors</a>of each number Prime Factors of 63: 63 = 3 x 3 x 7 = 3² x 7 Prime Factors of 81: 81 = 3 x 3 x 3 x 3 = 3⁴</p>

21 <p><strong>Step 2:</strong>Now, identify the common prime factors The common prime factors are: 3 x 3 = 3²</p>

20 <p><strong>Step 2:</strong>Now, identify the common prime factors The common prime factors are: 3 x 3 = 3²</p>

22 <p><strong>Step 3:</strong>Multiply the common prime factors 3² = 9. The Greatest Common Factor of 63 and 81 is 9.</p>

21 <p><strong>Step 3:</strong>Multiply the common prime factors 3² = 9. The Greatest Common Factor of 63 and 81 is 9.</p>

23 <h2>GCF of 63 and 81 Using Division Method or Euclidean Algorithm Method</h2>

22 <h2>GCF of 63 and 81 Using Division Method or Euclidean Algorithm Method</h2>

24 <p>Find the GCF of 63 and 81 using the<a>division</a>method or Euclidean Algorithm Method. Follow these steps:</p>

23 <p>Find the GCF of 63 and 81 using the<a>division</a>method or Euclidean Algorithm Method. Follow these steps:</p>

25 <p><strong>Step 1:</strong>First, divide the larger number by the smaller number Here, divide 81 by 63 81 ÷ 63 = 1 (<a>quotient</a>), The<a>remainder</a>is calculated as 81 - (63×1) = 18 The remainder is 18, not zero, so continue the process</p>

24 <p><strong>Step 1:</strong>First, divide the larger number by the smaller number Here, divide 81 by 63 81 ÷ 63 = 1 (<a>quotient</a>), The<a>remainder</a>is calculated as 81 - (63×1) = 18 The remainder is 18, not zero, so continue the process</p>

26 <p><strong>Step 2:</strong>Now divide the previous divisor (63) by the previous remainder (18) Divide 63 by 18 63 ÷ 18 = 3 (quotient), remainder = 63 - (18×3) = 9 The remainder is not zero, so continue the process</p>

25 <p><strong>Step 2:</strong>Now divide the previous divisor (63) by the previous remainder (18) Divide 63 by 18 63 ÷ 18 = 3 (quotient), remainder = 63 - (18×3) = 9 The remainder is not zero, so continue the process</p>

27 <p><strong>Step 3:</strong>Now divide the previous divisor (18) by the previous remainder (9) Divide 18 by 9 18 ÷ 9 = 2 (quotient), remainder = 18 - (9×2) = 0</p>

26 <p><strong>Step 3:</strong>Now divide the previous divisor (18) by the previous remainder (9) Divide 18 by 9 18 ÷ 9 = 2 (quotient), remainder = 18 - (9×2) = 0</p>

28 <p>The remainder is zero, the divisor will become the GCF. The GCF of 63 and 81 is 9.</p>

27 <p>The remainder is zero, the divisor will become the GCF. The GCF of 63 and 81 is 9.</p>

29 <h2>Common Mistakes and How to Avoid Them in GCF of 63 and 81</h2>

28 <h2>Common Mistakes and How to Avoid Them in GCF of 63 and 81</h2>

30 <p>Finding the GCF of 63 and 81 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.</p>

29 <p>Finding the GCF of 63 and 81 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.</p>

31 <h3>Problem 1</h3>

30 <h3>Problem 1</h3>

32 <p>A teacher has 63 pencils and 81 erasers. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?</p>

31 <p>A teacher has 63 pencils and 81 erasers. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?</p>

33 <p>Okay, lets begin</p>

32 <p>Okay, lets begin</p>

34 <p>We should find the GCF of 63 and 81. GCF of 63 and 81 3² = 9.</p>

33 <p>We should find the GCF of 63 and 81. GCF of 63 and 81 3² = 9.</p>

35 <p>There are 9 equal groups. 63 ÷ 9 = 7 81 ÷ 9 = 9</p>

34 <p>There are 9 equal groups. 63 ÷ 9 = 7 81 ÷ 9 = 9</p>

36 <p>There will be 9 groups, and each group gets 7 pencils and 9 erasers.</p>

35 <p>There will be 9 groups, and each group gets 7 pencils and 9 erasers.</p>

37 <h3>Explanation</h3>

36 <h3>Explanation</h3>

38 <p>As the GCF of 63 and 81 is 9, the teacher can make 9 groups. Now divide 63 and 81 by 9. Each group gets 7 pencils and 9 erasers.</p>

37 <p>As the GCF of 63 and 81 is 9, the teacher can make 9 groups. Now divide 63 and 81 by 9. Each group gets 7 pencils and 9 erasers.</p>

39 <p>Well explained 👍</p>

38 <p>Well explained 👍</p>

40 <h3>Problem 2</h3>

39 <h3>Problem 2</h3>

41 <p>A school has 63 red chairs and 81 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?</p>

40 <p>A school has 63 red chairs and 81 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?</p>

42 <p>Okay, lets begin</p>

41 <p>Okay, lets begin</p>

43 <p>GCF of 63 and 81 3² = 9. So each row will have 9 chairs.</p>

42 <p>GCF of 63 and 81 3² = 9. So each row will have 9 chairs.</p>

44 <h3>Explanation</h3>

43 <h3>Explanation</h3>

45 <p>There are 63 red and 81 blue chairs. To find the total number of chairs in each row, we should find the GCF of 63 and 81. There will be 9 chairs in each row.</p>

44 <p>There are 63 red and 81 blue chairs. To find the total number of chairs in each row, we should find the GCF of 63 and 81. There will be 9 chairs in each row.</p>

46 <p>Well explained 👍</p>

45 <p>Well explained 👍</p>

47 <h3>Problem 3</h3>

46 <h3>Problem 3</h3>

48 <p>A tailor has 63 meters of red ribbon and 81 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?</p>

47 <p>A tailor has 63 meters of red ribbon and 81 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?</p>

49 <p>Okay, lets begin</p>

48 <p>Okay, lets begin</p>

50 <p>For calculating the longest equal length, we have to calculate the GCF of 63 and 81.</p>

49 <p>For calculating the longest equal length, we have to calculate the GCF of 63 and 81.</p>

51 <p>The GCF of 63 and 81 3² = 9.</p>

50 <p>The GCF of 63 and 81 3² = 9.</p>

52 <p>The ribbon is 9 meters long.</p>

51 <p>The ribbon is 9 meters long.</p>

53 <h3>Explanation</h3>

52 <h3>Explanation</h3>

54 <p>For calculating the longest length of the ribbon, first, we need to calculate the GCF of 63 and 81, which is 9. The length of each piece of the ribbon will be 9 meters.</p>

53 <p>For calculating the longest length of the ribbon, first, we need to calculate the GCF of 63 and 81, which is 9. The length of each piece of the ribbon will be 9 meters.</p>

55 <p>Well explained 👍</p>

54 <p>Well explained 👍</p>

56 <h3>Problem 4</h3>

55 <h3>Problem 4</h3>

57 <p>A carpenter has two wooden planks, one 63 cm long and the other 81 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?</p>

56 <p>A carpenter has two wooden planks, one 63 cm long and the other 81 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?</p>

58 <p>Okay, lets begin</p>

57 <p>Okay, lets begin</p>

59 <p>The carpenter needs the longest piece of wood.</p>

58 <p>The carpenter needs the longest piece of wood.</p>

60 <p>GCF of 63 and 81 3² = 9.</p>

59 <p>GCF of 63 and 81 3² = 9.</p>

61 <p>The longest length of each piece is 9 cm.</p>

60 <p>The longest length of each piece is 9 cm.</p>

62 <h3>Explanation</h3>

61 <h3>Explanation</h3>

63 <p>To find the longest length of each piece of the two wooden planks, 63 cm and 81 cm, respectively, we have to find the GCF of 63 and 81, which is 9 cm. The longest length of each piece is 9 cm.</p>

62 <p>To find the longest length of each piece of the two wooden planks, 63 cm and 81 cm, respectively, we have to find the GCF of 63 and 81, which is 9 cm. The longest length of each piece is 9 cm.</p>

64 <p>Well explained 👍</p>

63 <p>Well explained 👍</p>

65 <h3>Problem 5</h3>

64 <h3>Problem 5</h3>

66 <p>If the GCF of 63 and ‘a’ is 9, and the LCM is 567. Find ‘a’.</p>

65 <p>If the GCF of 63 and ‘a’ is 9, and the LCM is 567. Find ‘a’.</p>

67 <p>Okay, lets begin</p>

66 <p>Okay, lets begin</p>

68 <p>The value of ‘a’ is 81.</p>

67 <p>The value of ‘a’ is 81.</p>

69 <h3>Explanation</h3>

68 <h3>Explanation</h3>

70 <p>GCF × LCM = product of the numbers</p>

69 <p>GCF × LCM = product of the numbers</p>

71 <p>9 × 567 = 63 × a</p>

70 <p>9 × 567 = 63 × a</p>

72 <p>5103 = 63a</p>

71 <p>5103 = 63a</p>

73 <p>a = 5103 ÷ 63 = 81</p>

72 <p>a = 5103 ÷ 63 = 81</p>

74 <p>Well explained 👍</p>

73 <p>Well explained 👍</p>

75 <h2>FAQs on the Greatest Common Factor of 63 and 81</h2>

74 <h2>FAQs on the Greatest Common Factor of 63 and 81</h2>

76 <h3>1.What is the LCM of 63 and 81?</h3>

75 <h3>1.What is the LCM of 63 and 81?</h3>

77 <p>The LCM of 63 and 81 is 567.</p>

76 <p>The LCM of 63 and 81 is 567.</p>

78 <h3>2.Is 63 divisible by 3?</h3>

77 <h3>2.Is 63 divisible by 3?</h3>

79 <p>Yes, 63 is divisible by 3 because the<a>sum</a>of its digits (6 + 3) is 9, which is divisible by 3.</p>

78 <p>Yes, 63 is divisible by 3 because the<a>sum</a>of its digits (6 + 3) is 9, which is divisible by 3.</p>

80 <h3>3.What will be the GCF of any two co-prime numbers?</h3>

79 <h3>3.What will be the GCF of any two co-prime numbers?</h3>

81 <p>The common factor of<a>co-prime numbers</a>is 1. Since 1 is the only common factor of any two co-prime numbers, it is said to be the GCF of any two co-prime numbers.</p>

80 <p>The common factor of<a>co-prime numbers</a>is 1. Since 1 is the only common factor of any two co-prime numbers, it is said to be the GCF of any two co-prime numbers.</p>

82 <h3>4.What is the prime factorization of 81?</h3>

81 <h3>4.What is the prime factorization of 81?</h3>

83 <p>The prime factorization of 81 is 3⁴.</p>

82 <p>The prime factorization of 81 is 3⁴.</p>

84 <h3>5.Are 63 and 81 prime numbers?</h3>

83 <h3>5.Are 63 and 81 prime numbers?</h3>

85 <p>No, 63 and 81 are not<a>prime numbers</a>because both of them have more than two factors.</p>

84 <p>No, 63 and 81 are not<a>prime numbers</a>because both of them have more than two factors.</p>

86 <h2>Important Glossaries for GCF of 63 and 81</h2>

85 <h2>Important Glossaries for GCF of 63 and 81</h2>

87 <ul><li><strong>Factors:</strong>Factors are numbers that divide the target number completely. For example, the factors of 18 are 1, 2, 3, 6, 9, and 18.</li>

86 <ul><li><strong>Factors:</strong>Factors are numbers that divide the target number completely. For example, the factors of 18 are 1, 2, 3, 6, 9, and 18.</li>

88 </ul><ul><li><strong>Multiple:</strong>Multiples are the products we get by multiplying a given number by another. For example, the multiples of 3 are 3, 6, 9, 12, and so on.</li>

87 </ul><ul><li><strong>Multiple:</strong>Multiples are the products we get by multiplying a given number by another. For example, the multiples of 3 are 3, 6, 9, 12, and so on.</li>

89 </ul><ul><li><strong>Prime Factors:</strong>These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 28 are 2 and 7.</li>

88 </ul><ul><li><strong>Prime Factors:</strong>These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 28 are 2 and 7.</li>

90 </ul><ul><li><strong>Remainder:</strong>The value left after division when the number cannot be divided evenly. For example, when 14 is divided by 4, the remainder is 2 and the quotient is 3.</li>

89 </ul><ul><li><strong>Remainder:</strong>The value left after division when the number cannot be divided evenly. For example, when 14 is divided by 4, the remainder is 2 and the quotient is 3.</li>

91 </ul><ul><li><strong>LCM:</strong>The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 12 and 15 is 60.</li>

90 </ul><ul><li><strong>LCM:</strong>The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 12 and 15 is 60.</li>

92 </ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>

91 </ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>

93 <p>▶</p>

92 <p>▶</p>

94 <h2>Hiralee Lalitkumar Makwana</h2>

93 <h2>Hiralee Lalitkumar Makwana</h2>

95 <h3>About the Author</h3>

94 <h3>About the Author</h3>

96 <p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>

95 <p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>

97 <h3>Fun Fact</h3>

96 <h3>Fun Fact</h3>

98 <p>: She loves to read number jokes and games.</p>

97 <p>: She loves to read number jokes and games.</p>