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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 17.7, treat it as 1770 by considering it in the hundredths place.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 17.7, treat it as 1770 by considering it in the hundredths place.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 1. We can say n is '1' because 1 × 1 is less than or equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1 - 1, the<a>remainder</a>is 0.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 1. We can say n is '1' because 1 × 1 is less than or equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1 - 1, the<a>remainder</a>is 0.</p>
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<p><strong>Step 3:</strong>Now let us bring down 77, making the new<a>dividend</a>170. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 77, making the new<a>dividend</a>170. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 170. Let us consider n as 8; now 28 × 8 = 224, which exceeds 170. Try n as 6; 26 × 6 = 156, which fits.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 170. Let us consider n as 8; now 28 × 8 = 224, which exceeds 170. Try n as 6; 26 × 6 = 156, which fits.</p>
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<p><strong>Step 6:</strong>Subtract 156 from 170; the difference is 14, and the quotient is 16.</p>
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<p><strong>Step 6:</strong>Subtract 156 from 170; the difference is 14, and the quotient is 16.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to bring down two zeroes, making the new dividend 1400.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to bring down two zeroes, making the new dividend 1400.</p>
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<p><strong>Step 8:</strong>Now, the new divisor is 32 because 326 × 4 = 1304.</p>
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<p><strong>Step 8:</strong>Now, the new divisor is 32 because 326 × 4 = 1304.</p>
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<p><strong>Step 9:</strong>Subtracting 1304 from 1400 results in 96.</p>
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<p><strong>Step 9:</strong>Subtracting 1304 from 1400 results in 96.</p>
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<p><strong>Step 10:</strong>Now the quotient is 4.2.</p>
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<p><strong>Step 10:</strong>Now the quotient is 4.2.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until you have two numbers after the decimal point or the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until you have two numbers after the decimal point or the remainder is zero.</p>
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<p>So, the square root of √17.7 is approximately 4.21.</p>
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<p>So, the square root of √17.7 is approximately 4.21.</p>
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