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3 In mathematics, there are different methods to solve linear equations. One such method is cross multiplication, which is used to compare fractions or solve linear equations involving two variables. In this article, we will learn how to apply this method effectively.

4 <h2>What is Cross-Multiplication?</h2>

5 What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math

6 ▶

7 Cross<a>multiplication</a>is a common method of multiplying<a>numbers</a>in<a>fraction</a>form. Cross multiplication involves multiplying the<a>numerators</a>of one fraction by the<a>denominator</a>of the other across an<a>equation</a>. This method can be easily applied when<a>solving linear equations</a>with two variables. For example:

8 $a_1 x + b_1 y + c_1 = 0 $

9 $a_2 x + b_2 y + c_2 = 0 $

10 If cross-multiplication is performed correctly, we can quickly obtain the values of x and y by simplifying the equation.

11 <h2>How to Cross Multiply Fractions?</h2>

12 Cross multiplication is primarily used with fractions to compare them or check their equality. This method can help solve equations when dealing with<a>complex fractions</a>. Given below are the different steps involved in this process:

13 For example: $\frac{5}{8} = \frac{10}{16} $

14 Step 1:To begin, multiply the fraction's<a>numerator</a>on the right by the fraction's denominator on the left. Multiplying $10 \times 8 = 80 $.

15 Step 2: Now, we multiply the fraction's denominator on the right by the fraction's numerator on the left. We can represent $\frac{10}{16} $ as $\frac{5}{8} $ (since they are<a>equivalent fractions</a>).

16 Step 3:After the<a>cross multiplication</a>, always compare the LHS and RHS. If they are equal, we can conclude that the fractions are equivalent. Here, in this 80 = 80, the fractions are equivalent.

17 <h2>What is the Formula for Cross-Multiplication?</h2>

18 The cross-multiplication<a>formula</a>is used for solving<a>linear equations</a>with two<a>variables</a>, as given below:

19 $a_1 x + b_1 y + c_1 = 0 $

20 $a_2 x + b_2 y + c_2 = 0 $

21 The cross-multiplication formula used to solve linear equations is:

22 ${x \over b_1c_2 \space -\space b_2c_1} = {y \over c_1a_2 \space- \space c_2a_1} = {1 \over b_2a_1 \space-\space b_1a_2}$

23 How to derive cross-multiplication formula?

24 In linear equations with two variables, we derive the cross-multiplication formula by eliminating one variable, often by making the<a>coefficients</a>of that variable equal.

25 For example: Let’s consider two linear equations as

26 $a_1 x + b_1 y + c_1 = 0 $

27 $a_2 x + b_2 y + c_2 = 0 $

28 We solve these equations by making the coefficients of y equal in both equations:

29 <ul><li>We first multiply all terms of equation (1) by b2 and all terms of equation (2) by b1:$b_2 \times (a_1 x + b_1 y + c_1) = 0 $

30 ⇒ $b_2 a_1 x + b_2 b_1 y + c_1 $....(3)

31 $b_1 \times (a_2 x + b_2 y + c_2) = 0 $

32 ⇒ $b_1 a_2 x + b_1 b_2 y + b_1 c_2 $…(4)

33 </li>

34 <li>Then, subtract equation (4) from equation (3), $(b_2 a_1 - b_1 a_2)x + (b_2 c_1 - b_1 c_2) = 0$

35 </li>

36 <li>Isolating x,$x = \frac{b_1 c_2 - b_2 c_1}{b_2 a_1 - b_1 a_2}$…(a)

37 where $(b_2 a_1 - b_1 a_2) \neq 0$

38 </li>

39 <li>Similarly, solve (1) and (2) for y:$y = \frac{c_1 a_2 - c_2 a_1}{b_2 a_1 - b_1 a_2}$…(b)

40 where $(b_2 a_1 - b_1 a_2) \neq 0$

41 </li>

42 <li>We now combine (a) and (b),${x \over b_1c_2 \space -\space b_2c_1} = {y \over c_1a_2 \space- \space c_2a_1} = {1 \over b_2a_1 \space-\space b_1a_2}$

43 </li>

44 </ul>Thus, we derived the required cross-multiplication formula.

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47 <h2>Comparing Fractions by Cross Multiply</h2>

46 <h2>Comparing Fractions by Cross Multiply</h2>

48 To compare two fractions using cross-multiplication, start by writing the fractions you want to compare, like $\frac{a}{b} \ and \ \frac{c}{d}.$ Then, cross-multiply by multiplying the numerator of the first fraction (a) with the denominator of the second fraction (d),and multiplying the numerator of the second fraction (c) with the denominator of the first fraction (b). This gives you two products: a × d and b × c.

47 To compare two fractions using cross-multiplication, start by writing the fractions you want to compare, like $\frac{a}{b} \ and \ \frac{c}{d}.$ Then, cross-multiply by multiplying the numerator of the first fraction (a) with the denominator of the second fraction (d),and multiplying the numerator of the second fraction (c) with the denominator of the first fraction (b). This gives you two products: a × d and b × c.

49 After that, compare the two products:

48 After that, compare the two products:

50 If a × d > b × c, then $\frac{a}{b}$ is<a>greater than</a> $\frac{c}{d}$

49 If a × d > b × c, then $\frac{a}{b}$ is<a>greater than</a> $\frac{c}{d}$

51 If a × d

50 If a × d

52 If a × d = b × c, then the two fractions are equal.

51 If a × d = b × c, then the two fractions are equal.

53 This method is useful because it allows you to directly compare the fractions without needing to find a<a>common denominator</a>.

52 This method is useful because it allows you to directly compare the fractions without needing to find a<a>common denominator</a>.

54 <h2>Comparing Ratios by Cross Multiply</h2>

53 <h2>Comparing Ratios by Cross Multiply</h2>

55 To compare two<a>ratios</a>using cross-multiplication, follow these simple steps:

54 To compare two<a>ratios</a>using cross-multiplication, follow these simple steps:

56 Write down the two ratios you want to compare. For example, you have: $\frac{a}{b}\ and \ \frac{c}{d}$ Cross-multiply:Multiply the numerator of the first<a>ratio</a>(a) by the denominator of the second ratio (d), and multiply the numerator of the second ratio (c) by the denominator of the first ratio (b). This gives you: $a×d$ $b×c$

55 Write down the two ratios you want to compare. For example, you have: $\frac{a}{b}\ and \ \frac{c}{d}$ Cross-multiply:Multiply the numerator of the first<a>ratio</a>(a) by the denominator of the second ratio (d), and multiply the numerator of the second ratio (c) by the denominator of the first ratio (b). This gives you: $a×d$ $b×c$

57 Compare the products:

56 Compare the products:

58 If a×d>b×c, then the first ratio is larger.

57 If a×d>b×c, then the first ratio is larger.

59 If a×d<b×c, then the second ratio is larger.

58 If a×d<b×c, then the second ratio is larger.

60 If a×d=b×c, the ratios are equal.

59 If a×d=b×c, the ratios are equal.

61 Example: Let’s compare the ratios 34 and 56.

60 Example: Let’s compare the ratios 34 and 56.

62 Cross-multiply:Multiply 3 by 6: 3×6=18

61 Cross-multiply:Multiply 3 by 6: 3×6=18

63 Multiply 4 by 5: 4×5=20

62 Multiply 4 by 5: 4×5=20

64 Compare: Since 18 is<a>less than</a>20, we know that 34 is smaller than 56.

63 Compare: Since 18 is<a>less than</a>20, we know that 34 is smaller than 56.

65 <h2>Cross Multiply With One Variable</h2>

64 <h2>Cross Multiply With One Variable</h2>

66 Set up the equation:You’ll start with two fractions, and one of them will have a variable (like x). For example:$\frac{a}{b}\ =\ \frac{c}{x}$

65 Set up the equation:You’ll start with two fractions, and one of them will have a variable (like x). For example:$\frac{a}{b}\ =\ \frac{c}{x}$

67 Cross-multiply:This means you multiply the top number of the first fraction by the bottom number of the second fraction, and multiply the top number of the second fraction by the bottom number of the first fraction. This gives you: $ a×x=b×c$

66 Cross-multiply:This means you multiply the top number of the first fraction by the bottom number of the second fraction, and multiply the top number of the second fraction by the bottom number of the first fraction. This gives you: $ a×x=b×c$

68 Solve for x:To find x, just divide both sides of the equation by a $x = \frac{b \times c}{a}$

67 Solve for x:To find x, just divide both sides of the equation by a $x = \frac{b \times c}{a}$

69 Example:Let’s say you have this equation: $\frac{3}{4} \ =\ \frac{6}{x}$

68 Example:Let’s say you have this equation: $\frac{3}{4} \ =\ \frac{6}{x}$

70 Cross-multiply:

69 Cross-multiply:

71 Multiply 3 by x to get 3x.

70 Multiply 3 by x to get 3x.

72 Multiply 4 by 6 to get 24.

71 Multiply 4 by 6 to get 24.

73 So, now you 3x = 24.

72 So, now you 3x = 24.

74 Solve for x:To isolate x, divide both sides by 3:

73 Solve for x:To isolate x, divide both sides by 3:

75 $x=\frac{24}{3}$

74 $x=\frac{24}{3}$

76 So, x = 8.

75 So, x = 8.

77 <h2>Cross Multiply With Two Variables</h2>

76 <h2>Cross Multiply With Two Variables</h2>

78 Write down the equation:You’ll start with two fractions, each containing a variable (like x and y). For example: $\frac{x}{a} \ = \ \frac{y}{b}$

77 Write down the equation:You’ll start with two fractions, each containing a variable (like x and y). For example: $\frac{x}{a} \ = \ \frac{y}{b}$

79 Cross-multiply:This means you multiply the top of the first fraction by the bottom of the second fraction, and the top of the second fraction by the bottom of the first fraction. You get:

78 Cross-multiply:This means you multiply the top of the first fraction by the bottom of the second fraction, and the top of the second fraction by the bottom of the first fraction. You get:

80 $ x×b=y×a$

79 $ x×b=y×a$

81 Simplify:Now, you have an equation without fractions, which is easier to work with. You can solve for one variable.

80 Simplify:Now, you have an equation without fractions, which is easier to work with. You can solve for one variable.

82 Example:Let’s say you have the equation:

81 Example:Let’s say you have the equation:

83 $\frac{x}{3} \ = \ \frac{y}{4}$

82 $\frac{x}{3} \ = \ \frac{y}{4}$

84 Cross-multiply:

83 Cross-multiply:

85 Multiply x by y: $ x \times y.$

84 Multiply x by y: $ x \times y.$

86 Multiply three by 4:$ 3×4=12.$

85 Multiply three by 4:$ 3×4=12.$

87 So now the equation looks like this:

86 So now the equation looks like this:

88 $x×y=12$

87 $x×y=12$

89 Solve for one variable: If you want to find x, you can divide both sides of the equation by y

88 Solve for one variable: If you want to find x, you can divide both sides of the equation by y

90 x = 12y

89 x = 12y

91 Now, you can solve for x once you know the value of 𝑦

90 Now, you can solve for x once you know the value of 𝑦

92 <h2>How to Solve Linear Equations by Cross Multiplication Method?</h2>

91 <h2>How to Solve Linear Equations by Cross Multiplication Method?</h2>

93 Cross-multiplication is a quick and effective method for solving linear equations with two variables. Solving linear equations with two variables, we apply the cross-multiplication method as given below:

92 Cross-multiplication is a quick and effective method for solving linear equations with two variables. Solving linear equations with two variables, we apply the cross-multiplication method as given below:

94 Use the cross-multiplication formula:

93 Use the cross-multiplication formula:

95 ${x \over b_1c_2 \space -\space b_2c_1} = {y \over c_1a_2 \space- \space c_2a_1} = {1 \over b_2a_1 \space-\space b_1a_2}$

94 ${x \over b_1c_2 \space -\space b_2c_1} = {y \over c_1a_2 \space- \space c_2a_1} = {1 \over b_2a_1 \space-\space b_1a_2}$

96 Solve the linear equations:

95 Solve the linear equations:

97 $3x + 4y = 8$

96 $3x + 4y = 8$

98 $2x + y = 5$

97 $2x + y = 5$

99 <ul><li>First, we convert the equations into<a>standard form</a>: Since the general form of a linear equation is:$ax + by + c = 0 $

98 <ul><li>First, we convert the equations into<a>standard form</a>: Since the general form of a linear equation is:$ax + by + c = 0 $

100 We rewrite the given equation as:

99 We rewrite the given equation as:

101 $3x + 4y - 8 = 0$

100 $3x + 4y - 8 = 0$

102 $2x + y - 5 = 0$

101 $2x + y - 5 = 0$

103 </li>

102 </li>

104 <li>When<a>comparing</a>the general form: $a_1 x + b_1 y = -c_1$ and $a_2 x + b_2 y = -c_2$:$a_1 = 3, \quad b_1 = 4, \quad c_1 = -8$

103 <li>When<a>comparing</a>the general form: $a_1 x + b_1 y = -c_1$ and $a_2 x + b_2 y = -c_2$:$a_1 = 3, \quad b_1 = 4, \quad c_1 = -8$

105 $a_2 = 2, \quad b_2 = 1, \quad c_2 = -5$

104 $a_2 = 2, \quad b_2 = 1, \quad c_2 = -5$

106 </li>

105 </li>

107 <li>Now, apply the cross-multiplication formula:${x \over b_1c_2 \space -\space b_2c_1} = {y \over c_1a_2 \space- \space c_2a_1} = {1 \over b_2a_1 \space-\space b_1a_2}$

106 <li>Now, apply the cross-multiplication formula:${x \over b_1c_2 \space -\space b_2c_1} = {y \over c_1a_2 \space- \space c_2a_1} = {1 \over b_2a_1 \space-\space b_1a_2}$

108 </li>

107 </li>

109 <li>Substituting the values:${x \over (4\times-5) \space -\space (1\times-8)} = {y \over (-8\times2) \space- \space (-5\times3)} = {1 \over (1\times 3) \space-\space (4\times2)}$

108 <li>Substituting the values:${x \over (4\times-5) \space -\space (1\times-8)} = {y \over (-8\times2) \space- \space (-5\times3)} = {1 \over (1\times 3) \space-\space (4\times2)}$

110 </li>

109 </li>

111 <li>Simplifying the fractions:${x \over (-20) \space -\space (-8)} = {y \over (-16) \space- \space (-15)} = {1 \over 3 \space-\space 8}$${x \over (-12)} = {y \over (-1)} = {1 \over (-5)}$

110 <li>Simplifying the fractions:${x \over (-20) \space -\space (-8)} = {y \over (-16) \space- \space (-15)} = {1 \over 3 \space-\space 8}$${x \over (-12)} = {y \over (-1)} = {1 \over (-5)}$

112 </li>

111 </li>

113 <li>Isolating x: Comparing the first and third fractions:${x \over (-12)} = {1 \over (-5)}$

112 <li>Isolating x: Comparing the first and third fractions:${x \over (-12)} = {1 \over (-5)}$

114 ${x } = {{-12 \times 1} \over (-5) } = {12 \over 5}$

113 ${x } = {{-12 \times 1} \over (-5) } = {12 \over 5}$

115 </li>

114 </li>

116 <li>Isolating y: Compare the second and third fractions:${y \over (-1)} = {1 \over (-5)}$

115 <li>Isolating y: Compare the second and third fractions:${y \over (-1)} = {1 \over (-5)}$

117 ${y } = {1 \times -1 \over (-5)} = {1 \over 5}$

116 ${y } = {1 \times -1 \over (-5)} = {1 \over 5}$

118 ⇒ $x = \frac{12}{5}, \quad y = \frac{1}{5}$

117 ⇒ $x = \frac{12}{5}, \quad y = \frac{1}{5}$

119 </li>

118 </li>

120 </ul><h2>Tips and Tricks to Master Cross Multiplication</h2>

119 </ul><h2>Tips and Tricks to Master Cross Multiplication</h2>

121 Cross multiplication can help learners to find many values in real life on a daily basis. It is one of the important topics of mathematics. Here are some tips and tricks to be a master in cross multiplying.

120 Cross multiplication can help learners to find many values in real life on a daily basis. It is one of the important topics of mathematics. Here are some tips and tricks to be a master in cross multiplying.

122 <ul><li>Understand the concept very well. Learn the equation and always remember it. </li>

121 <ul><li>Understand the concept very well. Learn the equation and always remember it. </li>

123 <li>Before cross-multiplying, always remember to check if the fraction is in its simplest form or not. If not, simplify it. </li>

122 <li>Before cross-multiplying, always remember to check if the fraction is in its simplest form or not. If not, simplify it. </li>

124 <li>After solving, estimate to see if the answer is making an equivalent. </li>

123 <li>After solving, estimate to see if the answer is making an equivalent. </li>

125 <li>Try to solve problems by using diagonal arrow marks for easier identification. </li>

124 <li>Try to solve problems by using diagonal arrow marks for easier identification. </li>

126 <li>Practice more with some real-life examples such as finding cooking recipes, shopping<a>discounts</a>, etc.</li>

125 <li>Practice more with some real-life examples such as finding cooking recipes, shopping<a>discounts</a>, etc.</li>

127 </ul><h2>Common Mistakes and How to Avoid Them in Cross Multiplication</h2>

126 </ul><h2>Common Mistakes and How to Avoid Them in Cross Multiplication</h2>

128 Solving linear equations using cross multiplication is a quick way to obtain results. However, students often make mistakes when solving equations using this method. Here are a few common mistakes and tips to avoid them:

127 Solving linear equations using cross multiplication is a quick way to obtain results. However, students often make mistakes when solving equations using this method. Here are a few common mistakes and tips to avoid them:

129 <h2>Real-Life Applications of Cross-Multiplication</h2>

128 <h2>Real-Life Applications of Cross-Multiplication</h2>

130 Cross-multiplication in equations helps students determine the value of unknown numbers easily. This technique can be applied to various real-life situations. Here are a few examples of its applications:

129 Cross-multiplication in equations helps students determine the value of unknown numbers easily. This technique can be applied to various real-life situations. Here are a few examples of its applications:

131 <ul><li>Cross-multiplication is used to compare the prices of different items for choosing the cheaper option when the quantity remains the same. </li>

130 <ul><li>Cross-multiplication is used to compare the prices of different items for choosing the cheaper option when the quantity remains the same. </li>

132 <li>This method helps adjust the quantities of ingredients required for a recipe without changing the proportions. </li>

131 <li>This method helps adjust the quantities of ingredients required for a recipe without changing the proportions. </li>

133 <li>Cross-multiplication is utilized in calculating the time required for a journey at a<a>constant</a>speed. Suppose a car travels 180 km in 3 hours, then we can calculate how far it can travel in 5 hours at the same speed using cross multiplication. Which on the other hand, will give us the distance as 300 km. </li>

132 <li>Cross-multiplication is utilized in calculating the time required for a journey at a<a>constant</a>speed. Suppose a car travels 180 km in 3 hours, then we can calculate how far it can travel in 5 hours at the same speed using cross multiplication. Which on the other hand, will give us the distance as 300 km. </li>

134 <li>We apply cross-multiplication to convert currencies accurately on the basis of their exchange rates. If 1 USD values up to 75 rupees in India, We can calculate the value of 50 USD by cross multiplying them. </li>

133 <li>We apply cross-multiplication to convert currencies accurately on the basis of their exchange rates. If 1 USD values up to 75 rupees in India, We can calculate the value of 50 USD by cross multiplying them. </li>

135 <li>While shopping a<a>product</a>with discount, we can calculate the amount we need to pay by cross multiplying the discounted<a>percentage</a>and the product's cost.</li>

134 <li>While shopping a<a>product</a>with discount, we can calculate the amount we need to pay by cross multiplying the discounted<a>percentage</a>and the product's cost.</li>

136 - </ul><h3>Problem 1</h3>

135 + </ul><h2>Download Worksheets</h2>

136 + <h3>Problem 1</h3>

137 Solve the following linear equations using the cross-multiplication method: 6x - 3y = 9 8x + 6y = 11

138 Okay, lets begin

139 $x = \frac{29}{20}, \quad y = -\frac{1}{10}$

140 <h3>Explanation</h3>

141 <ul><li>Rewrite the equations in the form $ax + by + c = 0$ (standard form):$6x - 3y - 9 = 0$

142 $8x + 6y- 11 = 0$

143 </li>

144 <li>Now, we compare $a_1 x + b_1 y + c_1 = 0 $ and $a_2 x + b_2 y + c_2 = 0 $:$ a_1 = 6, \quad b_1 = -3, \quad c_1 = -9, \quad$

145 $a_2 = 8, \quad b_2 = 6, \quad c_2 = -11$

146 </li>

147 <li>Apply the cross-multiplication formula: ${x \over b_1c_2 \space -\space b_2c_1} = {y \over c_1a_2 \space- \space c_2a_1} = {1 \over b_2a_1 \space-\space b_1a_2}$

148 </li>

149 <li>Substituting the values:${x \over (-3\times-11) \space -\space 6\times-9)} = {y \over (-9\times8) \space- \space (-11\times 6)} = {1 \over (6\times 6) \space-\space (-8\times-3)}$

150 </li>

151 <li>Simplify each term:$(-3 × -11) - (6 × -9) = 33 + 54 = 87$

152 $(-9 × 8) - (- 11 × 6) = -72 + 66 = - 6$

153 $(6 × 6) - (8 × -3) = 36 + 24 = 60$

154 Thus, the equation simplifies to:

155 ${x \over 87} = {y\over -6} = {1\over 60}$

156 </li>

157 <li>Solve for x and y:$x = {87 \times 1\over 60} = {87 \over 60}$

158 $ {y = {-6 \times 1\over 60}} = -{1 \over 10}$

159 </li>

160 <li>So, $x = \frac{29}{20}, \quad y = -\frac{1}{10}$</li>

161 </ul>Well explained 👍

162 <h3>Problem 2</h3>

163 Solve the equation: 2/5 = x/10

164 Okay, lets begin

165 x = 4

166 <h3>Explanation</h3>

167 <ul><li>Apply the cross-multiplication method:$2 × 10 = 5 × x$

168 $20 = 5x$

169 </li>

170 <li>Solve for x by dividing both sides by 5:$x = \frac{20}{5}$

171 x = 4

172 </li>

173 </ul>Well explained 👍

174 <h3>Problem 3</h3>

175 Check if the fractions 3/12 and 5/20 are proportional.

176 Okay, lets begin

177 $\frac{3}{12} $ and $\frac{5}{20} $ are proportional (since both sides are equal).

178 <h3>Explanation</h3>

179 We use cross-multiplication to check if the given fractions are proportional:

180 <ul><li>Set up the proportion as:$\frac{3}{12} $ = $\frac{5}{20} $

181 </li>

182 </ul><ul><li>Now apply cross-multiplication,$3 × 20 = 12 × 5 $ 60 = 60

183 </li>

184 </ul>Since both sides are equal, we can confirm that $\frac{3}{12} $ and $\frac{5}{20} $ are proportional.

185 Well explained 👍

186 <h3>Problem 4</h3>

187 Anna needs 6 cups of flour to make 12 pancakes. How many cups of flour are needed to make 18 pancakes?

188 Okay, lets begin

189 9 cups of flour.

190 <h3>Explanation</h3>

191 Let the number of cups of flour required to make 18 pancakes be x

192 <ul><li>Set up the proportion to maintain the ratio: $\frac{6}{12} = \frac{x}{18} $ </li>

193 <li>Now, apply cross multiplication:$6 × 18 = 12 × x $ $108 = 12x$

194 </li>

195 <li>Solve for x:We divide both sides by 12:

196 $x = \frac{108}{12} = 9 $

197 So, Anna needs 9 cups of flour to make 18 pancakes.

198 </li>

199 </ul>Well explained 👍

200 <h3>Problem 5</h3>

201 A store sells 9 apples for $7. How much would 20 apples cost?

202 Okay, lets begin

203 The cost of 20 apples is approximately $15.56.

204 <h3>Explanation</h3>

205 Let y be the cost of 20 apples, and set up the proportion: $\frac{9}{7} = \frac{20}{y}$

206 <ul><li>Apply cross multiplication:$9 × y = 7 × 20$ $9y = 140$ $y = \frac{140}{9} = 15.556$

207 </li>

208 </ul>So, the cost of 20 apples is approximately $15.56.

209 Well explained 👍

210 <h2>FAQs on Cross Multiplication</h2>

211 <h3>1.What do you mean by cross-multiplication?</h3>

212 Cross-multiplication is a method used to solve equations that have two fractions<a>set</a>equal to each other.

213 <h3>2.How can we perform cross-multiplication?</h3>

214 We solve an equation that is in the form of fractions like $\frac{a}{b} = \frac{c}{d} $ as: $a × d = b × c$, then solve for the unknown variable.

215 <h3>3.Cite one real-life example of cross-multiplication.</h3>

216 Cross-multiplication can be easily applied to determine the unknown values in proportional relationships. For example, to adjust ingredients in a recipe by keeping them proportional.

217 <h3>4.Does the cross-multiplication apply to all fraction equations?</h3>

218 No, cross-multiplication applies only to fractions that can be set up as proportions.

219 <h3>5.How can we verify the solution?</h3>

220 To verify the solution:

221 <ul><li>Substitute the obtained values of x and y into the original equation.</li>

222 <li>Check if both sides of the equation are equal.</li>

223 <li>If they are equal, we confirm that the solution is correct.</li>

224 </ul><h3>6.How can I make it easy for my child to understand cross-multiplication?</h3>

225 Use some visual aids like drawing arrow marks diagonally between the fractions to make it interactive. Start with basic examples.

226 <h3>7.How do I help my child practice?</h3>

227 Give them daily life problems to solve, like traveling, shopping discount, etc. Start with smaller numbers and then increase gradually.

228 <h2>Hiralee Lalitkumar Makwana</h2>

229 <h3>About the Author</h3>

230 Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.

231 <h3>Fun Fact</h3>

232 : She loves to read number jokes and games.