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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 11.6, we need to consider it as 11.60.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 11.6, we need to consider it as 11.60.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 11. We can say n as ‘3’ because 3 x 3 = 9 is less than 11. Now the<a>quotient</a>is 3, and after subtracting 9 from 11, the<a>remainder</a>is 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 11. We can say n as ‘3’ because 3 x 3 = 9 is less than 11. Now the<a>quotient</a>is 3, and after subtracting 9 from 11, the<a>remainder</a>is 2.</p>
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<p><strong>Step 3:</strong>Now let us bring down 60, making the new<a>dividend</a>260. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 60, making the new<a>dividend</a>260. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be 6n. We need to find the value of n such that 6n x n ≤ 260.</p>
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<p><strong>Step 4:</strong>The new divisor will be 6n. We need to find the value of n such that 6n x n ≤ 260.</p>
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<p><strong>Step 5:</strong>Let us consider n as 4, now 64 x 4 = 256.</p>
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<p><strong>Step 5:</strong>Let us consider n as 4, now 64 x 4 = 256.</p>
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<p><strong>Step 6:</strong>Subtract 256 from 260, the difference is 4, and the quotient is 3.4.</p>
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<p><strong>Step 6:</strong>Subtract 256 from 260, the difference is 4, and the quotient is 3.4.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 400.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 400.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor. It will be 68 because 684 x 4 = 2736, and 68 x 5 = 340, which is less than 400.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor. It will be 68 because 684 x 4 = 2736, and 68 x 5 = 340, which is less than 400.</p>
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<p><strong>Step 9:</strong>Subtracting 340 from 400 gives the result 60.</p>
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<p><strong>Step 9:</strong>Subtracting 340 from 400 gives the result 60.</p>
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<p><strong>Step 10:</strong>Now the quotient is approximately 3.40.</p>
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<p><strong>Step 10:</strong>Now the quotient is approximately 3.40.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
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<p>So the square root of √11.6 ≈ 3.405877.</p>
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<p>So the square root of √11.6 ≈ 3.405877.</p>
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