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Original 2026-01-01
Modified 2026-02-28
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1.43, we treat it as 1.43.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1.43, we treat it as 1.43.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is closest to 1. We can say n as ‘1’ because 1 × 1 is lesser than or equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1 - 1, the<a>remainder</a>is 0.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is closest to 1. We can say n as ‘1’ because 1 × 1 is lesser than or equal to 1. Now the<a>quotient</a>is 1, and after subtracting 1 - 1, the<a>remainder</a>is 0.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 43, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1 to get 2, which will be our new divisor.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 43, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1 to get 2, which will be our new divisor.</p>
5 <p><strong>Step 4:</strong>The new divisor will be 2n, and we need to find the value of n.</p>
5 <p><strong>Step 4:</strong>The new divisor will be 2n, and we need to find the value of n.</p>
6 <p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 43. Let us consider n as 1, now 2 × 1 × 1 = 2.</p>
6 <p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 43. Let us consider n as 1, now 2 × 1 × 1 = 2.</p>
7 <p><strong>Step 6:</strong>Subtract 2 from 43; the difference is 41, and the quotient is 1.</p>
7 <p><strong>Step 6:</strong>Subtract 2 from 43; the difference is 41, and the quotient is 1.</p>
8 <p><strong>Step 7:</strong>Since the dividend has no more digits, we need to add a<a>decimal</a>point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4100.</p>
8 <p><strong>Step 7:</strong>Since the dividend has no more digits, we need to add a<a>decimal</a>point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4100.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that fits. Let us consider 21.9 because 219 × 9 = 1971.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that fits. Let us consider 21.9 because 219 × 9 = 1971.</p>
10 <p><strong>Step 9:</strong>Subtracting 1971 from 4100, we get the result 2129.</p>
10 <p><strong>Step 9:</strong>Subtracting 1971 from 4100, we get the result 2129.</p>
11 <p><strong>Step 10:</strong>Continue this process until we have the desired precision.</p>
11 <p><strong>Step 10:</strong>Continue this process until we have the desired precision.</p>
12 <p>The quotient so far is approximately 1.19.</p>
12 <p>The quotient so far is approximately 1.19.</p>
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