Rivalry2

HTML Diff

1 added 2 removed

Original 2026-01-01

Modified 2026-02-28

1 - <p>132 Learners</p>

1 + <p>153 Learners</p>

2 <p>Last updated on<strong>September 9, 2025</strong></p>

3 <p>The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 63 and 54.</p>

4 <h2>What is the GCF of 63 and 54?</h2>

5 <p>The<a>greatest common factor</a>of 63 and 54 is 9. The largest<a>divisor</a>of two or more<a>numbers</a>is called the GCF of the number.</p>

6 <p>If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.</p>

7 <h2>How to find the GCF of 63 and 54?</h2>

8 <p>To find the GCF of 63 and 54, a few methods are described below</p>

9 <ul><li> Listing Factors </li>

10 <li>Prime Factorization </li>

11 <li>Long Division Method / by Euclidean Algorithm</li>

12 </ul><h3>GCF of 63 and 54 by Using Listing of factors</h3>

13 <p>Steps to find the GCF of 63 and 54 using the listing of<a>factors</a></p>

14 <p><strong>Step 1:</strong>Firstly, list the factors of each number Factors of 63 = 1, 3, 7, 9, 21, 63. Factors of 54 = 1, 2, 3, 6, 9, 18, 27, 54.</p>

15 <p><strong>Step 2:</strong>Now, identify the<a>common factors</a>of them Common factors of 63 and 54: 1, 3, 9.</p>

16 <p><strong>Step 3:</strong>Choose the largest factor The largest factor that both numbers have is 9. The GCF of 63 and 54 is 9.</p>

17 <h3>Explore Our Programs</h3>

18 - <p>No Courses Available</p>

19 <h3>GCF of 63 and 54 Using Prime Factorization</h3>

18 <h3>GCF of 63 and 54 Using Prime Factorization</h3>

20 <p>To find the GCF of 63 and 54 using the Prime Factorization Method, follow these steps:</p>

19 <p>To find the GCF of 63 and 54 using the Prime Factorization Method, follow these steps:</p>

21 <p><strong>Step 1:</strong>Find the<a>prime factors</a>of each number Prime Factors of 63: 63 = 3 x 3 x 7 = 3² x 7 Prime Factors of 54: 54 = 2 x 3 x 3 x 3 = 2 x 3³</p>

20 <p><strong>Step 1:</strong>Find the<a>prime factors</a>of each number Prime Factors of 63: 63 = 3 x 3 x 7 = 3² x 7 Prime Factors of 54: 54 = 2 x 3 x 3 x 3 = 2 x 3³</p>

22 <p><strong>Step 2:</strong>Now, identify the common prime factors The common prime factors are: 3 x 3 = 3²</p>

21 <p><strong>Step 2:</strong>Now, identify the common prime factors The common prime factors are: 3 x 3 = 3²</p>

23 <p><strong>Step 3:</strong>Multiply the common prime factors 3² = 9. The Greatest Common Factor of 63 and 54 is 9.</p>

22 <p><strong>Step 3:</strong>Multiply the common prime factors 3² = 9. The Greatest Common Factor of 63 and 54 is 9.</p>

24 <h3>GCF of 63 and 54 Using Division Method or Euclidean Algorithm Method</h3>

23 <h3>GCF of 63 and 54 Using Division Method or Euclidean Algorithm Method</h3>

25 <p>Find the GCF of 63 and 54 using the<a>division</a>method or Euclidean Algorithm Method. Follow these steps:</p>

24 <p>Find the GCF of 63 and 54 using the<a>division</a>method or Euclidean Algorithm Method. Follow these steps:</p>

26 <p><strong>Step 1:</strong>First, divide the larger number by the smaller number Here, divide 63 by 54 63 ÷ 54 = 1 (<a>quotient</a>), The<a>remainder</a>is calculated as 63 - (54×1) = 9 The remainder is 9, not zero, so continue the process</p>

25 <p><strong>Step 1:</strong>First, divide the larger number by the smaller number Here, divide 63 by 54 63 ÷ 54 = 1 (<a>quotient</a>), The<a>remainder</a>is calculated as 63 - (54×1) = 9 The remainder is 9, not zero, so continue the process</p>

27 <p><strong>Step 2:</strong>Now divide the previous divisor (54) by the previous remainder (9) Divide 54 by 9 54 ÷ 9 = 6 (quotient), remainder = 54 - (9×6) = 0 The remainder is zero, the divisor will become the GCF. The GCF of 63 and 54 is 9.</p>

26 <p><strong>Step 2:</strong>Now divide the previous divisor (54) by the previous remainder (9) Divide 54 by 9 54 ÷ 9 = 6 (quotient), remainder = 54 - (9×6) = 0 The remainder is zero, the divisor will become the GCF. The GCF of 63 and 54 is 9.</p>

28 <h2>Common Mistakes and How to Avoid Them in GCF of 63 and 54</h2>

27 <h2>Common Mistakes and How to Avoid Them in GCF of 63 and 54</h2>

29 <p>Finding the GCF of 63 and 54 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.</p>

28 <p>Finding the GCF of 63 and 54 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.</p>

30 <h3>Problem 1</h3>

29 <h3>Problem 1</h3>

31 <p>An artist has 63 paintbrushes and 54 canvases. She wants to create sets with the largest possible number of items in each set. How many items will be in each set?</p>

30 <p>An artist has 63 paintbrushes and 54 canvases. She wants to create sets with the largest possible number of items in each set. How many items will be in each set?</p>

32 <p>Okay, lets begin</p>

31 <p>Okay, lets begin</p>

33 <p>We should find the GCF of 63 and 54 GCF of 63 and 54 3² = 9. There are 9 equal sets 63 ÷ 9 = 7 54 ÷ 9 = 6 There will be 9 sets, and each set gets 7 paintbrushes and 6 canvases.</p>

32 <p>We should find the GCF of 63 and 54 GCF of 63 and 54 3² = 9. There are 9 equal sets 63 ÷ 9 = 7 54 ÷ 9 = 6 There will be 9 sets, and each set gets 7 paintbrushes and 6 canvases.</p>

34 <h3>Explanation</h3>

33 <h3>Explanation</h3>

35 <p>As the GCF of 63 and 54 is 9, the artist can make 9 sets.</p>

34 <p>As the GCF of 63 and 54 is 9, the artist can make 9 sets.</p>

36 <p>Now divide 63 and 54 by 9.</p>

35 <p>Now divide 63 and 54 by 9.</p>

37 <p>Each set gets 7 paintbrushes and 6 canvases.</p>

36 <p>Each set gets 7 paintbrushes and 6 canvases.</p>

38 <p>Well explained 👍</p>

37 <p>Well explained 👍</p>

39 <h3>Problem 2</h3>

38 <h3>Problem 2</h3>

40 <p>A gardener has 63 red tulip bulbs and 54 yellow tulip bulbs. She wants to plant them in rows with the same number of bulbs in each row, using the largest possible number of bulbs per row. How many bulbs will be in each row?</p>

39 <p>A gardener has 63 red tulip bulbs and 54 yellow tulip bulbs. She wants to plant them in rows with the same number of bulbs in each row, using the largest possible number of bulbs per row. How many bulbs will be in each row?</p>

41 <p>Okay, lets begin</p>

40 <p>Okay, lets begin</p>

42 <p>GCF of 63 and 54 3² = 9. So each row will have 9 bulbs.</p>

41 <p>GCF of 63 and 54 3² = 9. So each row will have 9 bulbs.</p>

43 <h3>Explanation</h3>

42 <h3>Explanation</h3>

44 <p>There are 63 red and 54 yellow tulip bulbs.</p>

43 <p>There are 63 red and 54 yellow tulip bulbs.</p>

45 <p>To find the total number of bulbs in each row, we should find the GCF of 63 and 54.</p>

44 <p>To find the total number of bulbs in each row, we should find the GCF of 63 and 54.</p>

46 <p>There will be 9 bulbs in each row.</p>

45 <p>There will be 9 bulbs in each row.</p>

47 <p>Well explained 👍</p>

46 <p>Well explained 👍</p>

48 <h3>Problem 3</h3>

47 <h3>Problem 3</h3>

49 <p>A chef has 63 kilograms of apples and 54 kilograms of oranges. She wants to divide both fruits into portions of equal weight, using the heaviest possible weight. What should be the weight of each portion?</p>

48 <p>A chef has 63 kilograms of apples and 54 kilograms of oranges. She wants to divide both fruits into portions of equal weight, using the heaviest possible weight. What should be the weight of each portion?</p>

50 <p>Okay, lets begin</p>

49 <p>Okay, lets begin</p>

51 <p>For calculating the heaviest equal weight, we have to calculate the GCF of 63 and 54 The GCF of 63 and 54 3² = 9. The portion is 9 kilograms.</p>

50 <p>For calculating the heaviest equal weight, we have to calculate the GCF of 63 and 54 The GCF of 63 and 54 3² = 9. The portion is 9 kilograms.</p>

52 <h3>Explanation</h3>

51 <h3>Explanation</h3>

53 <p>For calculating the heaviest weight of the fruits, first, we need to calculate the GCF of 63 and 54, which is 9.</p>

52 <p>For calculating the heaviest weight of the fruits, first, we need to calculate the GCF of 63 and 54, which is 9.</p>

54 <p>The weight of each portion will be 9 kilograms.</p>

53 <p>The weight of each portion will be 9 kilograms.</p>

55 <p>Well explained 👍</p>

54 <p>Well explained 👍</p>

56 <h3>Problem 4</h3>

55 <h3>Problem 4</h3>

57 <p>A carpenter has two wooden boards, one 63 cm long and the other 54 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?</p>

56 <p>A carpenter has two wooden boards, one 63 cm long and the other 54 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?</p>

58 <p>Okay, lets begin</p>

57 <p>Okay, lets begin</p>

59 <p>The carpenter needs the longest piece of wood GCF of 63 and 54 3² = 9. The longest length of each piece is 9 cm.</p>

58 <p>The carpenter needs the longest piece of wood GCF of 63 and 54 3² = 9. The longest length of each piece is 9 cm.</p>

60 <h3>Explanation</h3>

59 <h3>Explanation</h3>

61 <p>To find the longest length of each piece of the two wooden boards, 63 cm and 54 cm, respectively.</p>

60 <p>To find the longest length of each piece of the two wooden boards, 63 cm and 54 cm, respectively.</p>

62 <p>We have to find the GCF of 63 and 54, which is 9 cm.</p>

61 <p>We have to find the GCF of 63 and 54, which is 9 cm.</p>

63 <p>The longest length of each piece is 9 cm.</p>

62 <p>The longest length of each piece is 9 cm.</p>

64 <p>Well explained 👍</p>

63 <p>Well explained 👍</p>

65 <h3>Problem 5</h3>

64 <h3>Problem 5</h3>

66 <p>If the GCF of 63 and ‘b’ is 9, and the LCM is 378. Find ‘b’.</p>

65 <p>If the GCF of 63 and ‘b’ is 9, and the LCM is 378. Find ‘b’.</p>

67 <p>Okay, lets begin</p>

66 <p>Okay, lets begin</p>

68 <p>The value of ‘b’ is 54.</p>

67 <p>The value of ‘b’ is 54.</p>

69 <h3>Explanation</h3>

68 <h3>Explanation</h3>

70 <p>GCF x LCM = product of the numbers</p>

69 <p>GCF x LCM = product of the numbers</p>

71 <p>9 × 378</p>

70 <p>9 × 378</p>

72 <p>= 63 × b 3402</p>

71 <p>= 63 × b 3402</p>

73 <p>= 63b b</p>

72 <p>= 63b b</p>

74 <p>= 3402 ÷ 63 = 54</p>

73 <p>= 3402 ÷ 63 = 54</p>

75 <p>Well explained 👍</p>

74 <p>Well explained 👍</p>

76 <h2>FAQs on the Greatest Common Factor of 63 and 54</h2>

75 <h2>FAQs on the Greatest Common Factor of 63 and 54</h2>

77 <h3>1.What is the LCM of 63 and 54?</h3>

76 <h3>1.What is the LCM of 63 and 54?</h3>

78 <p>The LCM of 63 and 54 is 378.</p>

77 <p>The LCM of 63 and 54 is 378.</p>

79 <h3>2.Is 63 divisible by 3?</h3>

78 <h3>2.Is 63 divisible by 3?</h3>

80 <p>Yes, 63 is divisible by 3 because the<a>sum</a>of its digits (6 + 3 = 9) is divisible by 3.</p>

79 <p>Yes, 63 is divisible by 3 because the<a>sum</a>of its digits (6 + 3 = 9) is divisible by 3.</p>

81 <h3>3.What will be the GCF of any two prime numbers?</h3>

80 <h3>3.What will be the GCF of any two prime numbers?</h3>

82 <p>The common factor of<a>prime numbers</a>is 1 and the number itself. Since 1 is the only common factor of any two prime numbers, it is said to be the GCF of any two prime numbers.</p>

81 <p>The common factor of<a>prime numbers</a>is 1 and the number itself. Since 1 is the only common factor of any two prime numbers, it is said to be the GCF of any two prime numbers.</p>

83 <h3>4.What is the prime factorization of 54?</h3>

82 <h3>4.What is the prime factorization of 54?</h3>

84 <p>The prime factorization of 54 is 2 x 3³.</p>

83 <p>The prime factorization of 54 is 2 x 3³.</p>

85 <h3>5.Are 63 and 54 prime numbers?</h3>

84 <h3>5.Are 63 and 54 prime numbers?</h3>

86 <p>No, 63 and 54 are not prime numbers because both of them have more than two factors.</p>

85 <p>No, 63 and 54 are not prime numbers because both of them have more than two factors.</p>

87 <h2>Important Glossaries for GCF of 63 and 54</h2>

86 <h2>Important Glossaries for GCF of 63 and 54</h2>

88 <ul><li><strong>Factors:</strong>Factors are numbers that divide the target number completely. For example, the factors of 18 are 1, 2, 3, 6, 9, and 18.</li>

87 <ul><li><strong>Factors:</strong>Factors are numbers that divide the target number completely. For example, the factors of 18 are 1, 2, 3, 6, 9, and 18.</li>

89 </ul><ul><li><strong>Multiple:</strong>Multiples are the products we get by multiplying a given number by another. For example, the multiples of 7 are 7, 14, 21, 28, and so on.</li>

88 </ul><ul><li><strong>Multiple:</strong>Multiples are the products we get by multiplying a given number by another. For example, the multiples of 7 are 7, 14, 21, 28, and so on.</li>

90 </ul><ul><li><strong>Prime Factors:</strong>These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 21 are 3 and 7.</li>

89 </ul><ul><li><strong>Prime Factors:</strong>These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 21 are 3 and 7.</li>

91 </ul><ul><li><strong>Remainder:</strong>The value left after division when the number cannot be divided evenly. For example, when 10 is divided by 3, the remainder is 1 and the quotient is 3.</li>

90 </ul><ul><li><strong>Remainder:</strong>The value left after division when the number cannot be divided evenly. For example, when 10 is divided by 3, the remainder is 1 and the quotient is 3.</li>

92 </ul><ul><li><strong>LCM:</strong>The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 63 and 54 is 378.</li>

91 </ul><ul><li><strong>LCM:</strong>The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 63 and 54 is 378.</li>

93 </ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>

92 </ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>

94 <p>▶</p>

93 <p>▶</p>

95 <h2>Hiralee Lalitkumar Makwana</h2>

94 <h2>Hiralee Lalitkumar Makwana</h2>

96 <h3>About the Author</h3>

95 <h3>About the Author</h3>

97 <p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>

96 <p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>

98 <h3>Fun Fact</h3>

97 <h3>Fun Fact</h3>

99 <p>: She loves to read number jokes and games.</p>

98 <p>: She loves to read number jokes and games.</p>