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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 2533, we need to group it as 25 and 33.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 2533, we need to group it as 25 and 33.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 25. We can say n is '5' because 5 × 5 = 25. Now the<a>quotient</a>is 5, after subtracting 25 from 25, the<a>remainder</a>is 0.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 25. We can say n is '5' because 5 × 5 = 25. Now the<a>quotient</a>is 5, after subtracting 25 from 25, the<a>remainder</a>is 0.</p>
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<p><strong>Step 3:</strong>Now let us bring down 33, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number, 5 + 5, we get 10, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 33, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number, 5 + 5, we get 10, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 10n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 10n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 10n × n ≤ 33. Let's consider n as 3, now 10 × 3 × 3 = 90. But 90 is greater than 33, so we use n = 2.</p>
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<p><strong>Step 5:</strong>The next step is finding 10n × n ≤ 33. Let's consider n as 3, now 10 × 3 × 3 = 90. But 90 is greater than 33, so we use n = 2.</p>
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<p><strong>Step 6:</strong>Subtract 33 from 20 (10 × 2), the difference is 13, and the quotient is 52.</p>
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<p><strong>Step 6:</strong>Subtract 33 from 20 (10 × 2), the difference is 13, and the quotient is 52.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1300.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1300.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 504 (1048 × 4 = 4192).</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 504 (1048 × 4 = 4192).</p>
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<p><strong>Step 9:</strong>Subtracting 4192 from 1300 we get the result 882.</p>
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<p><strong>Step 9:</strong>Subtracting 4192 from 1300 we get the result 882.</p>
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<p><strong>Step 10:</strong>Now the quotient is 50.4.</p>
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<p><strong>Step 10:</strong>Now the quotient is 50.4.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
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<p>So the square root of √2533 is approximately 50.33.</p>
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<p>So the square root of √2533 is approximately 50.33.</p>
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