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2026-01-01
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<p>Last updated on<strong>October 19, 2025</strong></p>
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<p>Last updated on<strong>October 19, 2025</strong></p>
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<p>In mathematics, to find any term of a sequence, we use explicit formulas. In this article, we will be discussing the explicit formulas in detail along with real life applications and common mistakes made by students.</p>
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<p>In mathematics, to find any term of a sequence, we use explicit formulas. In this article, we will be discussing the explicit formulas in detail along with real life applications and common mistakes made by students.</p>
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<h2>What are Explicit Formulas?</h2>
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<h2>What are Explicit Formulas?</h2>
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<p>In a<a>sequence</a>to find any<a>term</a>without knowing the previous term, we use the<a>explicit formula</a>. It is a formula used to find the nth term of a sequence based on its position. Let’s learn the explicit formula for different types of sequences:</p>
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<p>In a<a>sequence</a>to find any<a>term</a>without knowing the previous term, we use the<a>explicit formula</a>. It is a formula used to find the nth term of a sequence based on its position. Let’s learn the explicit formula for different types of sequences:</p>
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<strong>Type of Sequence</strong><strong>Explicit Formula</strong><strong>Example</strong>Arithmetic Sequence<p>an = a + (n - 1)d, where a is the first term and d is the<a>common difference</a></p>
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<strong>Type of Sequence</strong><strong>Explicit Formula</strong><strong>Example</strong>Arithmetic Sequence<p>an = a + (n - 1)d, where a is the first term and d is the<a>common difference</a></p>
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<p>For the sequence: 2, 4, 6, 8,… The fifth term, a5 = a + (n - 1)d Here, n = 5 a = 2 d = 2 a5 = 2 + (5 - 1) 2 = 2 + 4 × 2 = 2 + 8 = 10</p>
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<p>For the sequence: 2, 4, 6, 8,… The fifth term, a5 = a + (n - 1)d Here, n = 5 a = 2 d = 2 a5 = 2 + (5 - 1) 2 = 2 + 4 × 2 = 2 + 8 = 10</p>
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Geometric Sequence an = arn-1, where a is the first term and ‘r’ is the common<a>ratio</a><p>For the sequence: 2, 6, 18,… The fifth term, a5 = arn - 1 Here, n = 5 a = 2 r = 3 a5 = 2 × 3(5 - 1) = 2 × 34 = 2 × 81 = 162</p>
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Geometric Sequence an = arn-1, where a is the first term and ‘r’ is the common<a>ratio</a><p>For the sequence: 2, 6, 18,… The fifth term, a5 = arn - 1 Here, n = 5 a = 2 r = 3 a5 = 2 × 3(5 - 1) = 2 × 34 = 2 × 81 = 162</p>
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Harmonic Sequence an = 1/(a + (n - 1)d), where a is the first term and d is the common difference.<p>For the sequence: 1/3, 1/7, 1/11,…</p>
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Harmonic Sequence an = 1/(a + (n - 1)d), where a is the first term and d is the common difference.<p>For the sequence: 1/3, 1/7, 1/11,…</p>
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<h2>How To Find Explicit Formulas?</h2>
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<h2>How To Find Explicit Formulas?</h2>
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<p>To find the nth term of a sequence, we use an explicit<a>formula</a>. The sequence can be<a>arithmetic</a>, geometric, or harmonic.</p>
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<p>To find the nth term of a sequence, we use an explicit<a>formula</a>. The sequence can be<a>arithmetic</a>, geometric, or harmonic.</p>
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<p>nth term of an<a>arithmetic sequence</a>- an = a + (n - 1)d, where a is the first term</p>
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<p>nth term of an<a>arithmetic sequence</a>- an = a + (n - 1)d, where a is the first term</p>
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<p>n is the position of the term in the sequence, </p>
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<p>n is the position of the term in the sequence, </p>
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<p>and d is the common difference. Steps used for finding explicit formulas are -</p>
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<p>and d is the common difference. Steps used for finding explicit formulas are -</p>
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<p><strong>Step 1:</strong>First find the first term and the common difference of the sequence</p>
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<p><strong>Step 1:</strong>First find the first term and the common difference of the sequence</p>
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<p><strong>Step 2:</strong>Substitute the value of a, n, and d in the explicit formula, an = a + (n - 1)d</p>
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<p><strong>Step 2:</strong>Substitute the value of a, n, and d in the explicit formula, an = a + (n - 1)d</p>
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<p><strong>Step 3:</strong>Simplify the formula to find the nth term</p>
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<p><strong>Step 3:</strong>Simplify the formula to find the nth term</p>
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<p>To find the 7th term of the sequence 7, 14, 21, 28, … </p>
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<p>To find the 7th term of the sequence 7, 14, 21, 28, … </p>
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<p>In the given sequence, a = 7 and d = 7(14 - 7 = 7)</p>
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<p>In the given sequence, a = 7 and d = 7(14 - 7 = 7)</p>
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<p>The nth term of an arithmetic sequence is: an = a + (n - 1)d</p>
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<p>The nth term of an arithmetic sequence is: an = a + (n - 1)d</p>
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<p>So, the 7th term is: a7 = 7 + (7 - 1)7</p>
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<p>So, the 7th term is: a7 = 7 + (7 - 1)7</p>
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<p>= 7+ (6 × 7)</p>
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<p>= 7+ (6 × 7)</p>
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<p>= 7 + 42 = 49</p>
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<p>= 7 + 42 = 49</p>
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<p>Therefore, the 7th term of the sequence is 49.</p>
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<p>Therefore, the 7th term of the sequence is 49.</p>
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<h2>Explicit Formula For Arithmetic Sequence</h2>
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<h2>Explicit Formula For Arithmetic Sequence</h2>
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<p>In an arithmetic sequence, the difference between consecutive terms is<a>constant</a>and is called the common difference (d). To find the nth term of an arithmetic sequence, we use the explicit formula: an = a + (n - 1)d. Where, </p>
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<p>In an arithmetic sequence, the difference between consecutive terms is<a>constant</a>and is called the common difference (d). To find the nth term of an arithmetic sequence, we use the explicit formula: an = a + (n - 1)d. Where, </p>
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<ul><li>an is the nth term</li>
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<ul><li>an is the nth term</li>
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</ul><ul><li>a is the first term</li>
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</ul><ul><li>a is the first term</li>
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</ul><ul><li>d is the common difference</li>
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</ul><ul><li>d is the common difference</li>
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</ul><p>For example, for the arithmetic sequence 2, 5, 8, 11, 14, …, finding the explicit formula</p>
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</ul><p>For example, for the arithmetic sequence 2, 5, 8, 11, 14, …, finding the explicit formula</p>
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<p> Here, a = 2</p>
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<p> Here, a = 2</p>
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<p>d = 3</p>
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<p>d = 3</p>
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<p>The explicit formula of an arithmetic sequence is: an = a + (n - 1)d Substituting the value of a and d:</p>
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<p>The explicit formula of an arithmetic sequence is: an = a + (n - 1)d Substituting the value of a and d:</p>
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<p>an = 2 + (n - 1)3</p>
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<p>an = 2 + (n - 1)3</p>
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<p>= 2 + 3n - 3 </p>
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<p>= 2 + 3n - 3 </p>
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<p>an = 3n - 1 </p>
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<p>an = 3n - 1 </p>
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<p>Find the 25th term of the sequence. </p>
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<p>Find the 25th term of the sequence. </p>
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<p>a25 = 3 × 25 - 1 </p>
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<p>a25 = 3 × 25 - 1 </p>
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<p>= 75 - 1</p>
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<p>= 75 - 1</p>
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<p>= 74</p>
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<p>= 74</p>
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<p>Therefore, the 25th term of the sequence is 74. </p>
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<p>Therefore, the 25th term of the sequence is 74. </p>
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<h2>Explicit Formula For Geometric Sequence</h2>
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<h2>Explicit Formula For Geometric Sequence</h2>
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<p>The<a>geometric sequence</a>is any sequence where the ratio of any two consecutive terms is the same. The ratio is known as the common ratio (r). The general form of a geometric sequence can be represented as a, ar, ar2, ar3, … arn - 1. For the geometric sequence, the explicit formula is an = arn - 1. </p>
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<p>The<a>geometric sequence</a>is any sequence where the ratio of any two consecutive terms is the same. The ratio is known as the common ratio (r). The general form of a geometric sequence can be represented as a, ar, ar2, ar3, … arn - 1. For the geometric sequence, the explicit formula is an = arn - 1. </p>
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<p>Where, </p>
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<p>Where, </p>
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<ul><li>a is the first term</li>
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<ul><li>a is the first term</li>
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</ul><ul><li>an is the nth term </li>
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</ul><ul><li>an is the nth term </li>
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</ul><ul><li>r is the common ratio</li>
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</ul><ul><li>r is the common ratio</li>
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</ul><p>For example, for the sequence: 1, 2, 4, 8, …, finding the explicit formula</p>
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</ul><p>For example, for the sequence: 1, 2, 4, 8, …, finding the explicit formula</p>
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<p>Here, a = 1</p>
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<p>Here, a = 1</p>
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<p>r = 2</p>
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<p>r = 2</p>
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<p>The explicit formula for geometric sequences is: an = arn - 1 Substituting the value of a and r:</p>
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<p>The explicit formula for geometric sequences is: an = arn - 1 Substituting the value of a and r:</p>
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<p>an = 1 × 2n - 1 = 2n - 1</p>
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<p>an = 1 × 2n - 1 = 2n - 1</p>
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<p>Finding the 5th term:</p>
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<p>Finding the 5th term:</p>
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<p>a5 = 2(5 - 1)</p>
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<p>a5 = 2(5 - 1)</p>
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<p>= 24 = 16</p>
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<p>= 24 = 16</p>
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<p>So, the 5th term is 16 </p>
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<p>So, the 5th term is 16 </p>
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<h2>Explicit Formula For Harmonic Sequence</h2>
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<h2>Explicit Formula For Harmonic Sequence</h2>
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<p>A harmonic sequence is a type of sequence where the reciprocals of the terms form an arithmetic sequence. For instance, the harmonic sequence of 2, 4, 6, 8, … is 1/2, 1/4, 1/6, 1/8, …. The general form of a harmonic sequence can be represented as 1/a, 1/(a +d), 1/(a + 2d), …, 1/(a + (n - 1)d). For a harmonic sequence, the explicit formula: an = 1/(a + (n - 1)d)</p>
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<p>A harmonic sequence is a type of sequence where the reciprocals of the terms form an arithmetic sequence. For instance, the harmonic sequence of 2, 4, 6, 8, … is 1/2, 1/4, 1/6, 1/8, …. The general form of a harmonic sequence can be represented as 1/a, 1/(a +d), 1/(a + 2d), …, 1/(a + (n - 1)d). For a harmonic sequence, the explicit formula: an = 1/(a + (n - 1)d)</p>
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<ul><li>Where a is the first term</li>
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<ul><li>Where a is the first term</li>
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</ul><ul><li>an is the nth term</li>
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</ul><ul><li>an is the nth term</li>
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</ul><ul><li>d is the common difference</li>
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</ul><ul><li>d is the common difference</li>
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</ul><p>For example, find the explicit formula for the harmonic sequence: 1/3, 1/6, 1/9, 1/12. </p>
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</ul><p>For example, find the explicit formula for the harmonic sequence: 1/3, 1/6, 1/9, 1/12. </p>
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<p>We take the reciprocals of the terms: 3, 6, 9, 12, …, to find a and d. Here, a = 3</p>
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<p>We take the reciprocals of the terms: 3, 6, 9, 12, …, to find a and d. Here, a = 3</p>
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<p>d = 3</p>
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<p>d = 3</p>
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<p>an = 1/(a + (n - 1)d)</p>
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<p>an = 1/(a + (n - 1)d)</p>
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<p>Substituting the value of a and d</p>
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<p>Substituting the value of a and d</p>
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<p>an = 1/(3 + (n - 1)3)</p>
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<p>an = 1/(3 + (n - 1)3)</p>
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<p>= 1/(3 + 3n - 3)</p>
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<p>= 1/(3 + 3n - 3)</p>
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<p>= 1/(3n)</p>
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<p>= 1/(3n)</p>
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<p>Finding the 5th term </p>
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<p>Finding the 5th term </p>
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<p>an = 1/(3n)</p>
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<p>an = 1/(3n)</p>
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<p>a5 = 1/(3 × 5)</p>
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<p>a5 = 1/(3 × 5)</p>
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<p>= 1/15</p>
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<p>= 1/15</p>
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<p>So, the 5th term of the sequence is 1/15</p>
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<p>So, the 5th term of the sequence is 1/15</p>
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<h2>Step-by-Step Use of an Explicit Formula</h2>
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<h2>Step-by-Step Use of an Explicit Formula</h2>
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<p>The use of explicit formula can be understood by the example mentioned below.</p>
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<p>The use of explicit formula can be understood by the example mentioned below.</p>
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<p>Find the 5th term of the sequence where an=3n+2.</p>
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<p>Find the 5th term of the sequence where an=3n+2.</p>
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<p><strong>Step 1:</strong>Identify the formula and substitute n = 5n </p>
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<p><strong>Step 1:</strong>Identify the formula and substitute n = 5n </p>
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<p>a5 = 3(5)+2</p>
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<p>a5 = 3(5)+2</p>
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<p><strong>Step 2:</strong>Simplify the<a>expression</a>.</p>
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<p><strong>Step 2:</strong>Simplify the<a>expression</a>.</p>
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<p>a5 = 15 + 2 = 17.</p>
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<p>a5 = 15 + 2 = 17.</p>
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<p>The fifth term of the sequence is 17.</p>
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<p>The fifth term of the sequence is 17.</p>
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<h2>Tips and Tricks to Master Explicit Formulas</h2>
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<h2>Tips and Tricks to Master Explicit Formulas</h2>
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<p>Explicit formulas in<a>math</a>are a difficult topic to comprehend, therefore some tips and tricks are useful to master the topic.</p>
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<p>Explicit formulas in<a>math</a>are a difficult topic to comprehend, therefore some tips and tricks are useful to master the topic.</p>
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<p><strong>Always Identify the Type of Sequence First:</strong> Before using any formula, check if it’s arithmetic, geometric, or harmonic.</p>
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<p><strong>Always Identify the Type of Sequence First:</strong> Before using any formula, check if it’s arithmetic, geometric, or harmonic.</p>
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<p><strong>Write Down the Given Data Clearly:</strong> Always list what is given, a1, n, d, or r.</p>
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<p><strong>Write Down the Given Data Clearly:</strong> Always list what is given, a1, n, d, or r.</p>
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<p><strong>Substitute Carefully:</strong> When substituting into the formula, use parentheses to avoid sign or order errors.</p>
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<p><strong>Substitute Carefully:</strong> When substituting into the formula, use parentheses to avoid sign or order errors.</p>
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<p><strong>Don’t Forget the Order of Operations:</strong> Follow BODMAS/PEDMAS rules while simplifying.</p>
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<p><strong>Don’t Forget the Order of Operations:</strong> Follow BODMAS/PEDMAS rules while simplifying.</p>
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<p><strong>Watch for Negative or Fractional Values: </strong>If r<0 or d<0 o, terms may alternate signs.</p>
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<p><strong>Watch for Negative or Fractional Values: </strong>If r<0 or d<0 o, terms may alternate signs.</p>
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<h2>Common Mistakes and How to Avoid Them in Explicit Formulas</h2>
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<h2>Common Mistakes and How to Avoid Them in Explicit Formulas</h2>
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<p>The explicit formula is used to find the nth term of a sequence. Students tend to make mistakes when using the explicit formula. Here are some common mistakes and the ways to avoid them.</p>
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<p>The explicit formula is used to find the nth term of a sequence. Students tend to make mistakes when using the explicit formula. Here are some common mistakes and the ways to avoid them.</p>
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<h2>Real-world Applications of Explicit Formulas</h2>
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<h2>Real-world Applications of Explicit Formulas</h2>
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<p>To calculate or predict a specific term in a sequence, we use the explicit formulas. Here are some real-life applications of the explicit formulas.</p>
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<p>To calculate or predict a specific term in a sequence, we use the explicit formulas. Here are some real-life applications of the explicit formulas.</p>
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<ul><li>In sports, we use the arithmetic sequence to design a workout routine to plan a steady increase in the repetitions. At any point in training to determine the<a>number</a>of repetitions, we use the explicit formula. </li>
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<ul><li>In sports, we use the arithmetic sequence to design a workout routine to plan a steady increase in the repetitions. At any point in training to determine the<a>number</a>of repetitions, we use the explicit formula. </li>
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</ul><ul><li>In finance, to calculate the savings, loans, and investments, where the amount forms a geometric sequence, we can use the explicit formula to predict the amount at a particular time. </li>
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</ul><ul><li>In finance, to calculate the savings, loans, and investments, where the amount forms a geometric sequence, we can use the explicit formula to predict the amount at a particular time. </li>
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</ul><ul><li>For linear population growth models, the explicit formula can predict the population at a specific time. </li>
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</ul><ul><li>For linear population growth models, the explicit formula can predict the population at a specific time. </li>
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</ul><ul><li>In computer algorithms, we can use explicit formulas to directly calculate the value in the sequence, which helps in improving efficiency. </li>
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</ul><ul><li>In computer algorithms, we can use explicit formulas to directly calculate the value in the sequence, which helps in improving efficiency. </li>
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</ul><ul><li>In environmental studies, explicit formulas can be applied to model patterns such as temperature changes or rainfall distribution over time, helping predict future trends based on previous<a>data</a>.</li>
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</ul><ul><li>In environmental studies, explicit formulas can be applied to model patterns such as temperature changes or rainfall distribution over time, helping predict future trends based on previous<a>data</a>.</li>
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</ul><h3>Problem 1</h3>
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</ul><h3>Problem 1</h3>
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<p>Find the explicit formula for an arithmetic sequence, where the first term is 5 and the common difference is 3.</p>
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<p>Find the explicit formula for an arithmetic sequence, where the first term is 5 and the common difference is 3.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>an = 3n + 2</p>
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<p>an = 3n + 2</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>To find the explicit formula of an arithmetic sequence, we use the formula, an = a + (n - 1)d</p>
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<p>To find the explicit formula of an arithmetic sequence, we use the formula, an = a + (n - 1)d</p>
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<p>Here, a = 5</p>
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<p>Here, a = 5</p>
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<p>d = 3</p>
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<p>d = 3</p>
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<p>Therefore, an = 5 + (n - 1)3</p>
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<p>Therefore, an = 5 + (n - 1)3</p>
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<p>= 5 + 3n - 3</p>
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<p>= 5 + 3n - 3</p>
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<p>= 3n + 2</p>
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<p>= 3n + 2</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 2</h3>
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<h3>Problem 2</h3>
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<p>If the first term and the common ratio of a geometric sequence are 3 and 2, find the explicit formula.</p>
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<p>If the first term and the common ratio of a geometric sequence are 3 and 2, find the explicit formula.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>an = 3 × 2n -1</p>
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<p>an = 3 × 2n -1</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>The explicit formula of a geometric sequence is: an = arn - 1</p>
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<p>The explicit formula of a geometric sequence is: an = arn - 1</p>
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<p>Here, a = 3</p>
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<p>Here, a = 3</p>
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<p>r = 2</p>
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<p>r = 2</p>
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<p>So, an = 3 × 2n - 1</p>
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<p>So, an = 3 × 2n - 1</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 3</h3>
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<h3>Problem 3</h3>
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<p>Find the 25th term of a harmonic sequence where the first term is 1/2 and the common difference is 3?</p>
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<p>Find the 25th term of a harmonic sequence where the first term is 1/2 and the common difference is 3?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The 25th term is 1/74</p>
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<p>The 25th term is 1/74</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>The explicit formula for a harmonic sequence is: an = 1/(a + (n - 1)d)</p>
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<p>The explicit formula for a harmonic sequence is: an = 1/(a + (n - 1)d)</p>
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<p>Given the first term is 1/2</p>
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<p>Given the first term is 1/2</p>
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<p>So, a = 2</p>
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<p>So, a = 2</p>
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<p>d = 3</p>
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<p>d = 3</p>
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<p>So, an = 1/(2 + (n - 1)3)</p>
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<p>So, an = 1/(2 + (n - 1)3)</p>
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<p>= 1/(2 + 3n - 3)</p>
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<p>= 1/(2 + 3n - 3)</p>
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<p>= 1/(3n -1)</p>
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<p>= 1/(3n -1)</p>
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<p>So, the 25th term = a25 = 1/(3 × 25 - 1)</p>
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<p>So, the 25th term = a25 = 1/(3 × 25 - 1)</p>
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<p>= 1/(75 - 1)</p>
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<p>= 1/(75 - 1)</p>
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<p>= 1/74</p>
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<p>= 1/74</p>
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<p>So, the 25th term is 1/74</p>
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<p>So, the 25th term is 1/74</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 4</h3>
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<h3>Problem 4</h3>
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<p>For an arithmetic sequence with a = 3 and d = 5, find the 12th term.</p>
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<p>For an arithmetic sequence with a = 3 and d = 5, find the 12th term.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The 12th term is 58</p>
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<p>The 12th term is 58</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>If a = 3 and d = 5</p>
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<p>If a = 3 and d = 5</p>
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<p>The explicit formula of the arithmetic sequence is: an = a + (n - 1)d</p>
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<p>The explicit formula of the arithmetic sequence is: an = a + (n - 1)d</p>
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<p>a12 = 3 + (12 - 1)5</p>
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<p>a12 = 3 + (12 - 1)5</p>
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<p>= 3 + 11 × 5</p>
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<p>= 3 + 11 × 5</p>
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<p>= 3 + 55 </p>
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<p>= 3 + 55 </p>
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<p>= 58 </p>
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<p>= 58 </p>
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<p>So, here the 12th term is 58</p>
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<p>So, here the 12th term is 58</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 5</h3>
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<h3>Problem 5</h3>
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<p>What is the common difference of the sequence if the explicit formula is a_n = 7n - 2?</p>
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<p>What is the common difference of the sequence if the explicit formula is a_n = 7n - 2?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The common difference is 7</p>
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<p>The common difference is 7</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>Here, the explicit formula is: an = 7n - 2</p>
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<p>Here, the explicit formula is: an = 7n - 2</p>
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<p>To find the common difference, let’s find the 2nd and 1st terms</p>
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<p>To find the common difference, let’s find the 2nd and 1st terms</p>
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<p>a1 = 7 × 1 - 2</p>
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<p>a1 = 7 × 1 - 2</p>
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<p>= 7 - 2 </p>
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<p>= 7 - 2 </p>
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<p>= 5</p>
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<p>= 5</p>
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<p>a2 = 7 × 2 - 2</p>
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<p>a2 = 7 × 2 - 2</p>
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<p>= 14 - 2 </p>
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<p>= 14 - 2 </p>
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<p>= 12</p>
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<p>= 12</p>
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<p>The difference between any two consecutive terms in a sequence is the common difference.</p>
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<p>The difference between any two consecutive terms in a sequence is the common difference.</p>
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<p>So, d = a2 - a1</p>
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<p>So, d = a2 - a1</p>
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<p>= 12 - 5 </p>
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<p>= 12 - 5 </p>
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<p>= 7</p>
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<p>= 7</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h2>FAQs on Explicit Formulas</h2>
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<h2>FAQs on Explicit Formulas</h2>
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<h3>1.What is an explicit formula?</h3>
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<h3>1.What is an explicit formula?</h3>
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<p>The formula used to find the nth term of a sequence when the previous term is unknown is the explicit formula.</p>
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<p>The formula used to find the nth term of a sequence when the previous term is unknown is the explicit formula.</p>
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<h3>2.What is the explicit formula for an arithmetic sequence?</h3>
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<h3>2.What is the explicit formula for an arithmetic sequence?</h3>
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<p>For an arithmetic sequence, the explicit formula is an = a + (n - 1)d, where a is the first term and d is the common difference.</p>
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<p>For an arithmetic sequence, the explicit formula is an = a + (n - 1)d, where a is the first term and d is the common difference.</p>
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<h3>3.What is the explicit formula for a geometric sequence?</h3>
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<h3>3.What is the explicit formula for a geometric sequence?</h3>
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<p>The explicit formula for geometric sequences is an = arn - 1, where a is the first term and r is the common difference.</p>
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<p>The explicit formula for geometric sequences is an = arn - 1, where a is the first term and r is the common difference.</p>
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<h3>4.What is the explicit formula for a harmonic sequence?</h3>
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<h3>4.What is the explicit formula for a harmonic sequence?</h3>
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<p>The formula for harmonic sequence is: an = 1/(a + (n - 1)d).</p>
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<p>The formula for harmonic sequence is: an = 1/(a + (n - 1)d).</p>
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<h3>5.What is the explicit formula for 2, 4, 6, 8, ….?</h3>
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<h3>5.What is the explicit formula for 2, 4, 6, 8, ….?</h3>
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<p>an = a + (n - 1)d is the explicit formula for the arithmetic sequence. Here a = 2 and d = 2, so an = 2 + (n - 1)2 = 2 + 2n - 2, so an = 2n. </p>
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<p>an = a + (n - 1)d is the explicit formula for the arithmetic sequence. Here a = 2 and d = 2, so an = 2 + (n - 1)2 = 2 + 2n - 2, so an = 2n. </p>
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<h2>Jaskaran Singh Saluja</h2>
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<h2>Jaskaran Singh Saluja</h2>
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<h3>About the Author</h3>
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<h3>About the Author</h3>
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<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
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<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
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<h3>Fun Fact</h3>
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<h3>Fun Fact</h3>
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<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>
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<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>