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Original
2026-01-01
Modified
2026-02-28
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<p>This is a method used for obtaining the square root for non-<a>perfect squares</a>, mainly. It usually involves the division of the<a>dividend</a>by the<a>divisor</a>, getting a<a>quotient</a>and a remainder too sometimes.</p>
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<p>This is a method used for obtaining the square root for non-<a>perfect squares</a>, mainly. It usually involves the division of the<a>dividend</a>by the<a>divisor</a>, getting a<a>quotient</a>and a remainder too sometimes.</p>
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<p>Follow the steps to calculate the square root of 132:</p>
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<p>Follow the steps to calculate the square root of 132:</p>
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<p> <strong>Step 1 :</strong>Write the number 132, and draw a horizontal bar above the pair of digits from right to left.</p>
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<p> <strong>Step 1 :</strong>Write the number 132, and draw a horizontal bar above the pair of digits from right to left.</p>
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<p><strong>Step 2 :</strong>Now, find the greatest number whose square is<a>less than</a>or equal to 1. Here, it is 1, Because 12=1 < 1.</p>
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<p><strong>Step 2 :</strong>Now, find the greatest number whose square is<a>less than</a>or equal to 1. Here, it is 1, Because 12=1 < 1.</p>
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<p><strong>Step 3 :</strong>Now divide 1 by 1 such that we get 1 as quotient and then multiply the divisor with the quotient, we get 1</p>
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<p><strong>Step 3 :</strong>Now divide 1 by 1 such that we get 1 as quotient and then multiply the divisor with the quotient, we get 1</p>
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<p><strong>Step 4:</strong>Subtract 1 from 1. Bring down 3 and 2 and place it beside the difference 0.</p>
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<p><strong>Step 4:</strong>Subtract 1 from 1. Bring down 3 and 2 and place it beside the difference 0.</p>
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<p><strong>Step 5:</strong>Add 1 to same divisor, 1. We get 2.</p>
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<p><strong>Step 5:</strong>Add 1 to same divisor, 1. We get 2.</p>
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<p><strong>Step 6:</strong>Now choose a number such that when placed at the end of 2, a 2-digit number will be formed. Multiply that particular number by the resultant number to get a number less than 1. Here, that number is 1. 21×1=21<32.</p>
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<p><strong>Step 6:</strong>Now choose a number such that when placed at the end of 2, a 2-digit number will be formed. Multiply that particular number by the resultant number to get a number less than 1. Here, that number is 1. 21×1=21<32.</p>
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<p><strong>Step 7:</strong>Subtract 32-21=11. Add a<a>decimal</a>point after the new quotient 11, again, bring down two zeroes and make 11 as 1100. Simultaneously add the unit’s place digit of 21,<a>i</a>.e., 1 with 21. We get here, 22. Apply Step 5 again and again until you reach 0. </p>
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<p><strong>Step 7:</strong>Subtract 32-21=11. Add a<a>decimal</a>point after the new quotient 11, again, bring down two zeroes and make 11 as 1100. Simultaneously add the unit’s place digit of 21,<a>i</a>.e., 1 with 21. We get here, 22. Apply Step 5 again and again until you reach 0. </p>
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<p>We will show two places of precision here, and so, we are left with the remainder, 2879 (refer to the picture), after some iterations and keeping the division till here, at this point </p>
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<p>We will show two places of precision here, and so, we are left with the remainder, 2879 (refer to the picture), after some iterations and keeping the division till here, at this point </p>
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<p> <strong>Step 8 :</strong>The quotient obtained is the square root. In this case, it is 11.489….</p>
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<p> <strong>Step 8 :</strong>The quotient obtained is the square root. In this case, it is 11.489….</p>
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