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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1083, we need to group it as 83 and 10.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1083, we need to group it as 83 and 10.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 10. We can say n as ‘3’ because 3 × 3 = 9 is lesser than 10. Now the<a>quotient</a>is 3, and after subtracting 9 from 10, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 10. We can say n as ‘3’ because 3 × 3 = 9 is lesser than 10. Now the<a>quotient</a>is 3, and after subtracting 9 from 10, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 83, making the new<a>dividend</a>183. Add the previous<a>divisor</a>(3) with the same number to get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 83, making the new<a>dividend</a>183. Add the previous<a>divisor</a>(3) with the same number to get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the previous divisor and quotient. Now we use 6n as the new divisor and need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the previous divisor and quotient. Now we use 6n as the new divisor and need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 183. Let us consider n as 3; now, 63 × 3 = 189, which is too large. Trying n as 2, we get 62 × 2 = 124.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 183. Let us consider n as 3; now, 63 × 3 = 189, which is too large. Trying n as 2, we get 62 × 2 = 124.</p>
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<p><strong>Step 6:</strong>Subtract 124 from 183; the difference is 59, and the quotient is 32.</p>
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<p><strong>Step 6:</strong>Subtract 124 from 183; the difference is 59, and the quotient is 32.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 5900.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 5900.</p>
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<p><strong>Step 8:</strong>Find the new divisor, which is 649, because 649 × 9 = 5841. Step 9: Subtracting 5841 from 5900, we get the result 59.</p>
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<p><strong>Step 8:</strong>Find the new divisor, which is 649, because 649 × 9 = 5841. Step 9: Subtracting 5841 from 5900, we get the result 59.</p>
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<p><strong>Step 10:</strong>Now the quotient is 32.9.</p>
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<p><strong>Step 10:</strong>Now the quotient is 32.9.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p>So the square root of √1083 is approximately 32.89.</p>
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<p>So the square root of √1083 is approximately 32.89.</p>
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