Divisibility Rule of 990
2026-02-28 13:51 Diff
https://brightchamps.com/en-us/math/numbers/divisibility-rule-of-990

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Last updated on August 5, 2025

The divisibility rule is a way to determine whether a number is divisible by another number without using the division method. In real life, we can use the divisibility rule for quick math, dividing things evenly, and sorting things. In this topic, we will learn about the divisibility rule of 990.

What is the Divisibility Rule of 990?

The divisibility rule for 990 is a method by which we can find out if a number is divisible by 990 or not without using the division method. Check whether 2970 is divisible by 990 with the divisibility rule.

Step 1: Check if the number is divisible by 2. Since 2970 is even, it is divisible by 2.


Step 2: Check if the number is divisible by 3. Add the digits of the number: 2 + 9 + 7 + 0 = 18, which is divisible by 3.


Step 3: Check if the number is divisible by 5. Since the last digit is 0, it is divisible by 5.


Step 4: Since 2970 is divisible by 2, 3, and 5, it is divisible by 990.


 

Tips and Tricks for Divisibility Rule of 990

Learning the divisibility rule will help kids master division. Let’s learn a few tips and tricks for the divisibility rule of 990.

Know the prime factors of 990:


Memorize the prime factors of 990 (2, 3, 5, 11) to quickly check divisibility. Ensure the number is divisible by all these prime factors.

Use the division method to verify:


Students can use the division method as a way to verify and crosscheck their results. This will help them to verify and also learn.

Check divisibility in parts:


For large numbers, check divisibility by 2, then 3, then 5, and finally 11 to confirm divisibility by 990.
 

Common Mistakes and How to Avoid Them in Divisibility Rule of 990

The divisibility rule of 990 helps us to quickly check if a given number is divisible by 990, but common mistakes like calculation errors lead to incorrect calculations. Here we will understand some common mistakes that will help you.

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Problem 1

Can a shipment of 5940 products be evenly divided into boxes of 990 products each?

Okay, lets begin

Yes, 5940 is divisible by 990.
 

Explanation

To determine if 5940 can be divided evenly into boxes of 990, we need to check if 5940 is divisible by 990. 


1) Check divisibility by 9: The sum of the digits of 5940 is 5 + 9 + 4 + 0 = 18, which is divisible by 9.


2) Check divisibility by 11: Alternating sum of the digits is (5 - 9 + 4 - 0) = 0, which is divisible by 11.


3) Check divisibility by 5: The last digit is 0, which is divisible by 5.


Since 5940 is divisible by 9, 11, and 5, it is divisible by 990.
 

Well explained 👍

Problem 2

A batch of 2970 cookies needs to be packed in boxes of 990 cookies. Is this possible without leaving any cookies out?

Okay, lets begin

 Yes, 2970 is divisible by 990.
 

Explanation

To verify if 2970 can be packed into boxes of 990:


1) Check divisibility by 9: The sum of the digits of 2970 is 2 + 9 + 7 + 0 = 18, which is divisible by 9.


2) Check divisibility by 11: Alternating sum of the digits is (2 - 9 + 7 - 0) = 0, which is divisible by 11.


3) Check divisibility by 5: The last digit is 0, which is divisible by 5.


Since 2970 is divisible by 9, 11, and 5, it is divisible by 990.
 

Well explained 👍

Problem 3

Is a payment of 7920 dollars divisible into 8 installments of 990 dollars each?

Okay, lets begin

Yes, 7920 is divisible by 990.
 

Explanation

To check if 7920 can be divided into 8 installments of 990:


1) Check divisibility by 9: The sum of the digits of 7920 is 7 + 9 + 2 + 0 = 18, which is divisible by 9.


2) Check divisibility by 11: Alternating sum of the digits is (7 - 9 + 2 - 0) = 0, which is divisible by 11.


3) Check divisibility by 5: The last digit is 0, which is divisible by 5.


Since 7920 is divisible by 9, 11, and 5, it is divisible by 990.
 

Well explained 👍

Problem 4

A company needs to distribute 4550 flyers evenly using packets of 990 each. Can this be done without any flyers left over?

Okay, lets begin

No, 4550 is not divisible by 990.

Explanation

To determine if 4550 can be evenly distributed:


1) Check divisibility by 9: The sum of the digits of 4550 is 4 + 5 + 5 + 0 = 14, which is not divisible by 9.


Since 4550 is not divisible by 9, it is not divisible by 990.
 

Well explained 👍

Problem 5

A theater wants to sell 8910 tickets in batches of 990. Is this possible?

Okay, lets begin

Yes, 8910 is divisible by 990.
 

Explanation

To verify if 8910 can be sold in batches of 990:


1) Check divisibility by 9: The sum of the digits of 8910 is 8 + 9 + 1 + 0 = 18, which is divisible by 9.


2) Check divisibility by 11: Alternating sum of the digits is (8 - 9 + 1 - 0) = 0, which is divisible by 11.


3) Check divisibility by 5: The last digit is 0, which is divisible by 5.


Since 8910 is divisible by 9, 11, and 5, it is divisible by 990.
 

Well explained 👍

FAQs on Divisibility Rule of 990

1.What is the divisibility rule for 990?

The divisibility rule for 990 involves checking if the number is divisible by 2, 3, 5, and 11.
 

2.How many numbers are there between 1 and 1000 that are divisible by 990?

There is 1 number between 1 and 1000 that is divisible by 990: the number 990 itself.
 

3. Is 1980 divisible by 990?

 Yes, because 1980 is divisible by 2, 3, 5, and 11

4.What if I get 0 after checking all factors?

 If you confirm divisibility by all prime factors of 990, then the number is divisible by 990.
 

5. Does the divisibility rule of 990 apply to all integers?

Yes, the divisibility rule of 990 applies to all integers.
 

Important Glossaries for Divisibility Rule of 990

  • Divisibility rule: The set of rules used to find out whether a number is divisible by another number or not.
  • Prime factors: The prime numbers that multiply together to give a specific number, such as 2, 3, 5, and 11 for 990.
  • Multiple: A number that can be divided by another number without a remainder.
  • Even number: A number divisible by 2.
  • Sum of digits: The total obtained by adding all the digits of a number, used to check divisibility by 3.
     

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Hiralee Lalitkumar Makwana

About the Author

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.

Fun Fact

: She loves to read number jokes and games.