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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 2756, we need to group it as 56 and 27.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 2756, we need to group it as 56 and 27.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 27. We can say n as ‘5’ because 5 x 5 = 25, which is less than 27. Now the<a>quotient</a>is 5 after subtracting 25 from 27, the<a>remainder</a>is 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 27. We can say n as ‘5’ because 5 x 5 = 25, which is less than 27. Now the<a>quotient</a>is 5 after subtracting 25 from 27, the<a>remainder</a>is 2.</p>
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<p><strong>Step 3:</strong>Now let us bring down 56 to the right of 2, making the new<a>dividend</a>256. Add the old<a>divisor</a>with the same number 5 + 5, we get 10, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 56 to the right of 2, making the new<a>dividend</a>256. Add the old<a>divisor</a>with the same number 5 + 5, we get 10, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be 10n. We need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be 10n. We need to find the value of n.</p>
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<p><strong>Step 5:</strong>We find 10n x n ≤ 256. Let us consider n as 2, now 10 x 2 = 20, and 20 x 2 = 40, which is too low. Try n = 5, yielding 105 x 5 = 525, which is too high, so try n = 2, to get 102 x 2 = 204.</p>
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<p><strong>Step 5:</strong>We find 10n x n ≤ 256. Let us consider n as 2, now 10 x 2 = 20, and 20 x 2 = 40, which is too low. Try n = 5, yielding 105 x 5 = 525, which is too high, so try n = 2, to get 102 x 2 = 204.</p>
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<p><strong>Step 6:</strong>Subtract 204 from 256, the difference is 52, and the quotient is 52.</p>
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<p><strong>Step 6:</strong>Subtract 204 from 256, the difference is 52, and the quotient is 52.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 5200.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 5200.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 520 because 520 x 10 = 5200.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 520 because 520 x 10 = 5200.</p>
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<p><strong>Step 9:</strong>Subtracting 5200 from 5200, we get the remainder 0.</p>
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<p><strong>Step 9:</strong>Subtracting 5200 from 5200, we get the remainder 0.</p>
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<p><strong>Step 10:</strong>Now the quotient is 52.0</p>
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<p><strong>Step 10:</strong>Now the quotient is 52.0</p>
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<p><strong>Step 11:</strong>Continue doing these steps until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until the remainder is zero.</p>
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<p>So the square root of √2756 is approximately 52.52.</p>
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<p>So the square root of √2756 is approximately 52.52.</p>
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