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2026-01-01
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<p>1603 Learners</p>
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<p>Last updated on<strong>November 25, 2025</strong></p>
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<p>Last updated on<strong>November 25, 2025</strong></p>
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<p>Some events are called dependent events because they are influenced by the results of events that had occurred previously. If the outcome of the event A is changed, then the outcome of the event B, occurring after the first event, is likely to be changed. Here, A and B are dependent events. In this topic, we are going to learn about dependent events and why it’s important.</p>
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<p>Some events are called dependent events because they are influenced by the results of events that had occurred previously. If the outcome of the event A is changed, then the outcome of the event B, occurring after the first event, is likely to be changed. Here, A and B are dependent events. In this topic, we are going to learn about dependent events and why it’s important.</p>
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<h2>What are Dependent Events?</h2>
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<h2>What are Dependent Events?</h2>
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<p>Dependent events are<a>events in probability</a>where the outcome of one event affects or changes the probability of another event. In other words, once one event occurs, it affects the likelihood of another event happening afterward. </p>
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<p>Dependent events are<a>events in probability</a>where the outcome of one event affects or changes the probability of another event. In other words, once one event occurs, it affects the likelihood of another event happening afterward. </p>
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<p>For example, if you have a jar containing five red marbles and five blue marbles. You pick one marble and do not put it back. Then you pick another marble.</p>
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<p>For example, if you have a jar containing five red marbles and five blue marbles. You pick one marble and do not put it back. Then you pick another marble.</p>
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<p>If the first marble is red, there are now fewer red marbles left in the jar.</p>
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<p>If the first marble is red, there are now fewer red marbles left in the jar.</p>
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<p>Because the first pick affects the second pick, these are dependent events.</p>
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<p>Because the first pick affects the second pick, these are dependent events.</p>
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<h2>What are Events in Probability?</h2>
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<h2>What are Events in Probability?</h2>
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<p>In<a>probability</a>, an event is any possible outcome or a group of outcomes from a<a>random experiment</a>. It represents what we observe or measure during the experiment. Events are classified by how their outcomes relate to each other. The main types of events are: </p>
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<p>In<a>probability</a>, an event is any possible outcome or a group of outcomes from a<a>random experiment</a>. It represents what we observe or measure during the experiment. Events are classified by how their outcomes relate to each other. The main types of events are: </p>
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<ul><li>Simple Events </li>
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<ul><li>Simple Events </li>
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<li>Compound Events </li>
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<li>Compound Events </li>
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<li>Mutually Exclusive Events </li>
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<li>Mutually Exclusive Events </li>
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<li>Dependent Event </li>
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<li>Dependent Event </li>
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<li>Independent Event</li>
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<li>Independent Event</li>
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</ul><h2>Difference Between Independent and Dependent Events</h2>
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</ul><h2>Difference Between Independent and Dependent Events</h2>
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<p>Independent and dependent events differ in whether the outcome of one event influences the probability of the other-the difference between independent and dependent events. </p>
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<p>Independent and dependent events differ in whether the outcome of one event influences the probability of the other-the difference between independent and dependent events. </p>
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<strong>Dependent Event</strong><p><strong>Independent Event</strong></p>
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<strong>Dependent Event</strong><p><strong>Independent Event</strong></p>
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In a dependent event, the outcome of one event changes or influences the probability of the next event. In an<a>independent event</a>, the outcome of one event does not affect the probability of another. Dependent events occur mainly in situations where sampling is done without replacement. In an independent event, the sampling is done with replacement. The occurrence of the first event directly affects the likelihood of the second. The occurrence of one event does not impact the outcome of the other. \(P(A \text{ and } B) = P(A) \times P(B \mid A) \) \(P(A \text{ and } B) = P(A) \times P(B) \) For example, drawing cards from a deck without replacement For example, flipping a coin and<a>rolling a die</a><h3>Explore Our Programs</h3>
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In a dependent event, the outcome of one event changes or influences the probability of the next event. In an<a>independent event</a>, the outcome of one event does not affect the probability of another. Dependent events occur mainly in situations where sampling is done without replacement. In an independent event, the sampling is done with replacement. The occurrence of the first event directly affects the likelihood of the second. The occurrence of one event does not impact the outcome of the other. \(P(A \text{ and } B) = P(A) \times P(B \mid A) \) \(P(A \text{ and } B) = P(A) \times P(B) \) For example, drawing cards from a deck without replacement For example, flipping a coin and<a>rolling a die</a><h3>Explore Our Programs</h3>
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<h2>Properties of Dependent Events</h2>
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<h2>Properties of Dependent Events</h2>
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<p>Dependent events are events in which the outcome of one event influences or changes the result of another. These events play an important role in probability, decision-making, and real-world predictions. Below are the key properties of dependent events: </p>
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<p>Dependent events are events in which the outcome of one event influences or changes the result of another. These events play an important role in probability, decision-making, and real-world predictions. Below are the key properties of dependent events: </p>
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<ul><li>In dependent events, the outcome of one event affects the likelihood of the next. Once an event occurs, the information gained from it changes the conditions for the following event. </li>
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<ul><li>In dependent events, the outcome of one event affects the likelihood of the next. Once an event occurs, the information gained from it changes the conditions for the following event. </li>
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<li>The probability of dependent events changes after each event. So, after the first event changes the situation, the probabilities for the next event are different.The probability of dependent events changes after each event. So, after the first event changes the situation, the probabilities for the next event are different. </li>
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<li>The probability of dependent events changes after each event. So, after the first event changes the situation, the probabilities for the next event are different.The probability of dependent events changes after each event. So, after the first event changes the situation, the probabilities for the next event are different. </li>
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<li><p>When one event occurs, it can alter the<a>number</a>of remaining possible outcomes. For example, drawing a card from a deck without replacing it reduces the total number of cards for the next draw. </p>
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<li><p>When one event occurs, it can alter the<a>number</a>of remaining possible outcomes. For example, drawing a card from a deck without replacing it reduces the total number of cards for the next draw. </p>
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</li>
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</li>
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<li><p>Dependent events do not always have a direct or obvious connection. For example, bad weather might increase the number of car accidents. Weather and accidents are different, but they affect each other. </p>
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<li><p>Dependent events do not always have a direct or obvious connection. For example, bad weather might increase the number of car accidents. Weather and accidents are different, but they affect each other. </p>
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</li>
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</li>
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<li><p>The<a>sequence</a>in which events happen can affect the probabilities of dependent events. For example, drawing cards one after another without replacement is different from drawing with replacement.</p>
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<li><p>The<a>sequence</a>in which events happen can affect the probabilities of dependent events. For example, drawing cards one after another without replacement is different from drawing with replacement.</p>
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</li>
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</li>
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</ul><h2>Probability of Dependent Events</h2>
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</ul><h2>Probability of Dependent Events</h2>
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<p>The probability of dependent events is based on<a>conditional probability</a>, which tells us how likely one event is to occur given that another has already happened. In dependent events, the outcome of the first event changes the probability of the second event. </p>
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<p>The probability of dependent events is based on<a>conditional probability</a>, which tells us how likely one event is to occur given that another has already happened. In dependent events, the outcome of the first event changes the probability of the second event. </p>
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<p>For example, a box has three red balls and two blue balls. You pick one ball and do not put it back. Then you pick a second ball. Since the first ball is not replaced, the number of balls changes. This means the probability of the second pick depends on what was picked first, so the events are dependent.</p>
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<p>For example, a box has three red balls and two blue balls. You pick one ball and do not put it back. Then you pick a second ball. Since the first ball is not replaced, the number of balls changes. This means the probability of the second pick depends on what was picked first, so the events are dependent.</p>
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<h2>Dependent Events Formula</h2>
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<h2>Dependent Events Formula</h2>
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<p>The probability of dependent events is the chance that one event occurs after another. The<a>formula</a>for finding the probability of dependent events uses conditional probability. It is written as: </p>
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<p>The probability of dependent events is the chance that one event occurs after another. The<a>formula</a>for finding the probability of dependent events uses conditional probability. It is written as: </p>
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<p>\(P(B | A) = {{P (A ∩ B) \over P (A)}}\) </p>
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<p>\(P(B | A) = {{P (A ∩ B) \over P (A)}}\) </p>
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<p>Where P(A ∩B) is the probability that both events A and B occur P(A) is the probability that event A happens.</p>
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<p>Where P(A ∩B) is the probability that both events A and B occur P(A) is the probability that event A happens.</p>
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<h2>How to Find the Probability of Dependent Event?</h2>
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<h2>How to Find the Probability of Dependent Event?</h2>
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<p>To find the probability of a dependent event, we use the concept of conditional probability. This helps us determine how likely an event is to occur after another event has already occurred. </p>
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<p>To find the probability of a dependent event, we use the concept of conditional probability. This helps us determine how likely an event is to occur after another event has already occurred. </p>
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<p>If event A happens first and event B occurs next, the probability of event B after A is written as P(B | A). The formula is: </p>
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<p>If event A happens first and event B occurs next, the probability of event B after A is written as P(B | A). The formula is: </p>
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<p>\(P(B | A) = {P (A ∩ B) \over P (A)}\)</p>
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<p>\(P(B | A) = {P (A ∩ B) \over P (A)}\)</p>
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<p>For example, a jar contains three red candies and two blue candies. You pick one candy and do not put it back. Then you pick another candy. If you like a red candy first, what is the probability that you will enjoy a blue candy second?</p>
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<p>For example, a jar contains three red candies and two blue candies. You pick one candy and do not put it back. Then you pick another candy. If you like a red candy first, what is the probability that you will enjoy a blue candy second?</p>
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<p>To find the probability of picking blue candy, we use the formula: </p>
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<p>To find the probability of picking blue candy, we use the formula: </p>
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<p> \(P(B | A) = {P (A ∩ B) \over P (A)}\)</p>
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<p> \(P(B | A) = {P (A ∩ B) \over P (A)}\)</p>
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<p>Let, the probability of picking a red candy be event A and the probability of picking a blue candy be B. </p>
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<p>Let, the probability of picking a red candy be event A and the probability of picking a blue candy be B. </p>
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<p>Finding P(A):</p>
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<p>Finding P(A):</p>
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<p>There are 3 red and 2 blue candies, so the total is 5</p>
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<p>There are 3 red and 2 blue candies, so the total is 5</p>
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<p>P(A) = \(3\over 5\)</p>
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<p>P(A) = \(3\over 5\)</p>
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<p>After picking a red, the total candies left = 4</p>
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<p>After picking a red, the total candies left = 4</p>
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<p>So, the remaining blue candies = 2</p>
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<p>So, the remaining blue candies = 2</p>
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<p>So, \(P(B|A) = {{2\over 4}} = {{1\over 2}}\)</p>
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<p>So, \(P(B|A) = {{2\over 4}} = {{1\over 2}}\)</p>
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<p>So, the probability of picking a blue candy second after picking a red candy first is \(1 \over 2\).</p>
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<p>So, the probability of picking a blue candy second after picking a red candy first is \(1 \over 2\).</p>
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<h2>Tips and Tricks to Master Dependent Events</h2>
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<h2>Tips and Tricks to Master Dependent Events</h2>
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<p>Helping children understand dependent events becomes much easier when learning is grounded in simple examples and hands-on activities. Here are a few tips and tricks to master dependent events. </p>
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<p>Helping children understand dependent events becomes much easier when learning is grounded in simple examples and hands-on activities. Here are a few tips and tricks to master dependent events. </p>
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<ul><li>Memorize the key formula for a dependent event: \(P(B | A) = {{P (A ∩ B)) \over (P (A) }} \). </li>
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<ul><li>Memorize the key formula for a dependent event: \(P(B | A) = {{P (A ∩ B)) \over (P (A) }} \). </li>
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<li> Adjust the sample size after the first Event, since the total number of outcomes changes. </li>
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<li> Adjust the sample size after the first Event, since the total number of outcomes changes. </li>
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<li>Parents can ask the child to explain how one Event affects the next. This helps them slow down, think clearly, and avoid mistakes in probability calculations. </li>
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<li>Parents can ask the child to explain how one Event affects the next. This helps them slow down, think clearly, and avoid mistakes in probability calculations. </li>
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<li>Teachers can use visual models like diagrams, probability trees, or colored counters to explain how outcomes change after each Event. </li>
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<li>Teachers can use visual models like diagrams, probability trees, or colored counters to explain how outcomes change after each Event. </li>
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<li>Check whether the second Event depends on the first Event. If the result of Event B changes after Event A happens, then the events are dependent.</li>
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<li>Check whether the second Event depends on the first Event. If the result of Event B changes after Event A happens, then the events are dependent.</li>
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</ul><h2>Common Mistakes and How to Avoid Them in Dependent Events</h2>
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</ul><h2>Common Mistakes and How to Avoid Them in Dependent Events</h2>
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<p>When dealing with dependent events, students can make mistakes. Learning about the following common mistakes can help us avoid them: </p>
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<p>When dealing with dependent events, students can make mistakes. Learning about the following common mistakes can help us avoid them: </p>
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<h2>Real-life Applications of Dependent Events</h2>
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<h2>Real-life Applications of Dependent Events</h2>
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<p>We use the concept of dependent events on a daily basis. It is widely used in environmental sciences and various other fields.</p>
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<p>We use the concept of dependent events on a daily basis. It is widely used in environmental sciences and various other fields.</p>
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<ul><li><strong> Weather Prediction:</strong>Meteorologists use dependent events to accurately predict the weather conditions and to find the probability that the weather tomorrow depends on today's weather conditions. </li>
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<ul><li><strong> Weather Prediction:</strong>Meteorologists use dependent events to accurately predict the weather conditions and to find the probability that the weather tomorrow depends on today's weather conditions. </li>
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</ul><ul><li><strong>Sports Strategies:</strong>Sports analysts use dependent events to predict whether the team is going to win or lose based on their previous performance and their score in the current game.</li>
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</ul><ul><li><strong>Sports Strategies:</strong>Sports analysts use dependent events to predict whether the team is going to win or lose based on their previous performance and their score in the current game.</li>
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</ul><ul><li><strong>Education:</strong>Educational institutes use dependent events to determine whether a student is going to pass based on the students’ previous performance in earlier exams.</li>
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</ul><ul><li><strong>Education:</strong>Educational institutes use dependent events to determine whether a student is going to pass based on the students’ previous performance in earlier exams.</li>
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</ul><ul><li><strong>Finance:</strong>dependent events are used to assess credit risk, where the likelihood of loan default depends on prior payment history. </li>
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</ul><ul><li><strong>Finance:</strong>dependent events are used to assess credit risk, where the likelihood of loan default depends on prior payment history. </li>
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<li><strong>Medical Diagnosis</strong>: Doctors use dependent events when diagnosing patients - for example, the probability of having a certain disease may depend on family history, lifestyle, or previous test results. </li>
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<li><strong>Medical Diagnosis</strong>: Doctors use dependent events when diagnosing patients - for example, the probability of having a certain disease may depend on family history, lifestyle, or previous test results. </li>
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<li><strong>Marketing and Customer Behavior:</strong>Businesses analyze dependent events to predict future purchases. A customer’s likelihood of buying a<a>product</a>depends on their previous buying history or interaction with similar items.</li>
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<li><strong>Marketing and Customer Behavior:</strong>Businesses analyze dependent events to predict future purchases. A customer’s likelihood of buying a<a>product</a>depends on their previous buying history or interaction with similar items.</li>
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</ul><h3>Problem 1</h3>
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</ul><h3>Problem 1</h3>
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<p>A bottle contains 5 red balls and 3 blue balls. Two balls are drawn without replacement. What is the probability that both balls are red?</p>
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<p>A bottle contains 5 red balls and 3 blue balls. Two balls are drawn without replacement. What is the probability that both balls are red?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The probability that both balls are red is \(5\over14\). </p>
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<p>The probability that both balls are red is \(5\over14\). </p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>We use the formula, \(P{{(A {\text { and }} B)}} = {{P(A) × P(B | A)}}\).</p>
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<p>We use the formula, \(P{{(A {\text { and }} B)}} = {{P(A) × P(B | A)}}\).</p>
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<p>P(Red1 and Red2) \(= {{5\over8} × {4\over 7}} = {20\over 56} = {5\over 14}\)</p>
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<p>P(Red1 and Red2) \(= {{5\over8} × {4\over 7}} = {20\over 56} = {5\over 14}\)</p>
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<p><strong>Step 1</strong>: Probability of first red \(= {{5\over 8}}\)</p>
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<p><strong>Step 1</strong>: Probability of first red \(= {{5\over 8}}\)</p>
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<p>Since a ball is taken and not replaced, there will be 4 red balls and a total of 7 balls remaining.</p>
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<p>Since a ball is taken and not replaced, there will be 4 red balls and a total of 7 balls remaining.</p>
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<p><strong>Step 2</strong>: Probability of second red (without replacement) \(= {{4\over 7}} \)</p>
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<p><strong>Step 2</strong>: Probability of second red (without replacement) \(= {{4\over 7}} \)</p>
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<p>Now we multiply the probabilities to get the final answer. So, \({5\over 8} × {4\over 7} = {20\over 56} = {{5\over 14}}\)</p>
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<p>Now we multiply the probabilities to get the final answer. So, \({5\over 8} × {4\over 7} = {20\over 56} = {{5\over 14}}\)</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 2</h3>
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<h3>Problem 2</h3>
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<p>In a deck, there are 52 cards. What is the probability of drawing a King followed by a Queen without replacement?</p>
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<p>In a deck, there are 52 cards. What is the probability of drawing a King followed by a Queen without replacement?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>\(4\over 663\). </p>
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<p>\(4\over 663\). </p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>We use the formula, \(P(A {\text {and }}B) = P(A) × P(B | A)\).</p>
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<p>We use the formula, \(P(A {\text {and }}B) = P(A) × P(B | A)\).</p>
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<ul><li>P(King and Queen) \(= {4\over 52} × {4\over 51} = {16\over 2652} = {4\over 663}\)</li>
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<ul><li>P(King and Queen) \(= {4\over 52} × {4\over 51} = {16\over 2652} = {4\over 663}\)</li>
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</ul><ul><li>The probability of drawing a King first = \(4\over52\)</li>
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</ul><ul><li>The probability of drawing a King first = \(4\over52\)</li>
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</ul><ul><li>One card is gone, so only 51 remain and 4 Queens are left.</li>
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</ul><ul><li>One card is gone, so only 51 remain and 4 Queens are left.</li>
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</ul><ul><li>The probability of drawing a Queen is \(4\over 51\)</li>
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</ul><ul><li>The probability of drawing a Queen is \(4\over 51\)</li>
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</ul><ul><li>Multiply both the probabilities to get the final answer.</li>
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</ul><ul><li>Multiply both the probabilities to get the final answer.</li>
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</ul><p>Well explained 👍</p>
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</ul><p>Well explained 👍</p>
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<h3>Problem 3</h3>
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<h3>Problem 3</h3>
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<p>If a class has 12 boys and 8 girls. Two students are chosen randomly, what is the probability that both students chosen are girls?</p>
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<p>If a class has 12 boys and 8 girls. Two students are chosen randomly, what is the probability that both students chosen are girls?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>\(14\over 95\) </p>
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<p>\(14\over 95\) </p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>We use the formula, \(P(A {\text { and }}B) = P(A) × P(B | A)\).</p>
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<p>We use the formula, \(P(A {\text { and }}B) = P(A) × P(B | A)\).</p>
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<p>P(Girl1 and Girl2) = \({8\over20} × {7\over19} = {56\over380} = {14\over95}\)</p>
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<p>P(Girl1 and Girl2) = \({8\over20} × {7\over19} = {56\over380} = {14\over95}\)</p>
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<ul><li>The probability of choosing a girl first is \(8\over20\)</li>
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<ul><li>The probability of choosing a girl first is \(8\over20\)</li>
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</ul><ul><li>One girl is chosen so, leaving a total of 7 girls out of 19 students.</li>
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</ul><ul><li>One girl is chosen so, leaving a total of 7 girls out of 19 students.</li>
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</ul><ul><li>The probability of choosing another girl is \(7 \over 19\)</li>
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</ul><ul><li>The probability of choosing another girl is \(7 \over 19\)</li>
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</ul><ul><li>Multiply the probabilities to get the final probability</li>
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</ul><ul><li>Multiply the probabilities to get the final probability</li>
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</ul><p>Well explained 👍</p>
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</ul><p>Well explained 👍</p>
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<h3>Problem 4</h3>
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<h3>Problem 4</h3>
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<p>A box contains 3 dark chocolates and 5 milk chocolates. What is the probability of picking a dark chocolate first and then a milk chocolate, if the chocolates aren’t replaced?</p>
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<p>A box contains 3 dark chocolates and 5 milk chocolates. What is the probability of picking a dark chocolate first and then a milk chocolate, if the chocolates aren’t replaced?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>\(15\over 56\). </p>
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<p>\(15\over 56\). </p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>We use the formula, \(P( A {\text { and }}B) = P(A) × P(B | A)\).</p>
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<p>We use the formula, \(P( A {\text { and }}B) = P(A) × P(B | A)\).</p>
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<p>P(Dark and Milk) \(= 38 × 57 = 1556\)</p>
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<p>P(Dark and Milk) \(= 38 × 57 = 1556\)</p>
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<ul><li>The probability of picking a dark chocolate first = 38</li>
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<ul><li>The probability of picking a dark chocolate first = 38</li>
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</ul><ul><li>If one chocolate is removed, that leaves 5 milk chocolates for a total of 7.</li>
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</ul><ul><li>If one chocolate is removed, that leaves 5 milk chocolates for a total of 7.</li>
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</ul><ul><li>The probability of picking milk chocolate is 57.</li>
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</ul><ul><li>The probability of picking milk chocolate is 57.</li>
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</ul><ul><li>Multiply both probabilities to get the answer.</li>
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</ul><ul><li>Multiply both probabilities to get the answer.</li>
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</ul><p>Well explained 👍</p>
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</ul><p>Well explained 👍</p>
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<h3>Problem 5</h3>
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<h3>Problem 5</h3>
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<p>In a lottery with 10 tickets, 3 are winners. If 2 tickets are purchased without replacement, what is the probability that both are winners?</p>
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<p>In a lottery with 10 tickets, 3 are winners. If 2 tickets are purchased without replacement, what is the probability that both are winners?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>\(1\over15\). </p>
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<p>\(1\over15\). </p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>\(P( A {\text { and }}B) = P(A) × P(B | A)\)</p>
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<p>\(P( A {\text { and }}B) = P(A) × P(B | A)\)</p>
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<p>P(T1 and T2) = \({3\over10} × {2\over9} = {6\over90} = {1\over15} \)</p>
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<p>P(T1 and T2) = \({3\over10} × {2\over9} = {6\over90} = {1\over15} \)</p>
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<ul><li>First ticket probability \(= {{3\over10}}\)</li>
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<ul><li>First ticket probability \(= {{3\over10}}\)</li>
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</ul><ul><li>Second ticket probability \(= {2\over9}\)</li>
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</ul><ul><li>Second ticket probability \(= {2\over9}\)</li>
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</ul><ul><li>Multiply the two probabilities to get the final answer.</li>
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</ul><ul><li>Multiply the two probabilities to get the final answer.</li>
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</ul><p>Well explained 👍</p>
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</ul><p>Well explained 👍</p>
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<h2>FAQs on Dependent Events</h2>
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<h2>FAQs on Dependent Events</h2>
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<h3>1.How do I know if events are dependent on each other?</h3>
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<h3>1.How do I know if events are dependent on each other?</h3>
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<p>If the outcome of the first event changes the sample space for the second event, then we know that the events are dependent on each other. </p>
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<p>If the outcome of the first event changes the sample space for the second event, then we know that the events are dependent on each other. </p>
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<h3>2.Why do dependent events change the probabilities chance?</h3>
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<h3>2.Why do dependent events change the probabilities chance?</h3>
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<p>The first event changes the sample space, so this would affect the likelihood of the second event’s outcome.</p>
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<p>The first event changes the sample space, so this would affect the likelihood of the second event’s outcome.</p>
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<h3>3.Can a dependent event become an independent event?</h3>
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<h3>3.Can a dependent event become an independent event?</h3>
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<p>No, if events are dependent on each other, then it will remain dependent on each other. But, if the first event’s outcome is ever reset, there is a chance of the event becoming independent. </p>
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<p>No, if events are dependent on each other, then it will remain dependent on each other. But, if the first event’s outcome is ever reset, there is a chance of the event becoming independent. </p>
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<h3>4.What is the formula for dependent events?</h3>
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<h3>4.What is the formula for dependent events?</h3>
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<p>The formula we use for dependent events is: P(A and B) = P(A) × P(B | A).</p>
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<p>The formula we use for dependent events is: P(A and B) = P(A) × P(B | A).</p>
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<h3>5.How to solve for multi-step dependent event problems?</h3>
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<h3>5.How to solve for multi-step dependent event problems?</h3>
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<p>Break the problem into smaller steps. First, calculate for P(A) and then calculate for P(B|A) and multiply them together. </p>
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<p>Break the problem into smaller steps. First, calculate for P(A) and then calculate for P(B|A) and multiply them together. </p>
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<h2>Jaipreet Kour Wazir</h2>
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<h2>Jaipreet Kour Wazir</h2>
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<h3>About the Author</h3>
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<h3>About the Author</h3>
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<p>Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref</p>
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<p>Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref</p>
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<h3>Fun Fact</h3>
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<h3>Fun Fact</h3>
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<p>: She compares datasets to puzzle games-the more you play with them, the clearer the picture becomes!</p>
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<p>: She compares datasets to puzzle games-the more you play with them, the clearer the picture becomes!</p>