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Original 2026-01-01

Modified 2026-02-28

1 1984 can be converted easily from decimal to binary. The methods mentioned below will help us convert the number. Let’s see how it is done.

2 Expansion Method:Let us see the step-by-step process of converting 1984 using the expansion method.

3 Step 1 -Figure out the place values: In the binary system, each<a>place value</a>is a<a>power</a>of 2. Therefore, in the first step, we will ascertain the powers of 2.

4 20 = 1

5 21 = 2

6 22 = 4

7 23 = 8

8 24 = 16

9 25 = 32

10 26 = 64

11 27 = 128

12 28 = 256

13 29 = 512

14 210 = 1024

15 211 = 2048

16 Since 2048 is<a>greater than</a>1984, we stop at 2^10 = 1024.

17 Step 2 -Identify the largest power of 2: In the previous step, we stopped at 210 = 1024. This is because, in this step, we have to identify the largest power of 2, which is<a>less than</a>or equal to the given number, 1984. Since 2^10 is the number we are looking for, write 1 in the 2^10 place. Now the value of 2^10, which is 1024, is subtracted from 1984. 1984 - 1024 = 960.

18 Step 3 -Identify the next largest power of 2: In this step, we need to find the largest power of 2 that fits into the result of the previous step, 960. So, the next largest power of 2 is 2^9 = 512. Now, we have to write 1 in the 2^9 place. And then subtract 512 from 960. 960 - 512 = 448.

19 Step 4 -Continue the process: Repeat the process for 448, using the next largest power of 2, which is 2^8 = 256. 448 - 256 = 192. Next, use 27 = 128. 192 - 128 = 64. Finally, use 26 = 64. 64 - 64 = 0. We need to stop the process here since the remainder is 0.

20 Step 5 -Identify the unused place values: We wrote 1 in the 2^10, 2^9, 2^8, 2^7, and 2^6 places. Now, we can just write 0s in the remaining places, which are<a>2^5</a>, 2^4, 2^3, 2^2, 2^1, and 2^0. Now, by substituting the values, we get, 0 in the 2^0 place 0 in the 2^1 place 0 in the 2^2 place 0 in the 2^3 place 0 in the 2^4 place 0 in the 2^5 place 1 in the 2^6 place 1 in the 2^7 place 1 in the 2^8 place 1 in the 2^9 place 1 in the 2^10 place

21 Step 6 -Write the values in reverse order: We now write the numbers upside down to represent 1984 in binary. Therefore, 11111000000 is 1984 in binary.

22 Grouping Method:In this method, we divide the number 1984 by 2. Let us see the step-by-step conversion.

23 Step 1 -Divide the given number 1984 by 2. 1984 / 2 = 992. Here, 992 is the quotient and 0 is the remainder.

24 Step 2 -Divide the previous quotient (992) by 2. 992 / 2 = 496. Here, the quotient is 496 and the remainder is 0.

25 Step 3 -Repeat the previous step. 496 / 2 = 248. Now, the quotient is 248 and 0 is the remainder.

26 Step 4 -Repeat the previous step. 248 / 2 = 124. Here, the quotient is 124 and the remainder is 0.

27 Step 5 -Repeat the previous step. 124 / 2 = 62. Here, the quotient is 62 and the remainder is 0.

28 Step 6 -Repeat the previous step. 62 / 2 = 31. Now, the quotient is 31 and the remainder is 0.

29 Step 7 -Repeat the previous step. 31 / 2 = 15. Now, the quotient is 15 and the remainder is 1.

30 Step 8 -Repeat the previous step. 15 / 2 = 7. Here, the quotient is 7 and the remainder is 1.

31 Step 9 -Repeat the previous step. 7 / 2 = 3. Now, the quotient is 3 and the remainder is 1.

32 Step 10 -Repeat the previous step. 3 / 2 = 1. Here, the quotient is 1 and the remainder is 1.

33 Step 11 -Repeat the previous step. 1 / 2 = 0. Here, the remainder is 1. And we stop the<a>division</a>here because the quotient is 0.

34 Step 12 -Write down the remainders from bottom to top. Therefore, 1984 (decimal) = 11111000000 (binary).