Rivalry2

HTML Diff

1 added 2 removed

Original 2026-01-01

Modified 2026-02-28

1 - <p>184 Learners</p>

1 + <p>209 Learners</p>

2 <p>Last updated on<strong>August 5, 2025</strong></p>

3 <p>The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, group or arrange items, and schedule events. In this topic, we will learn about the GCF of 15 and 25.</p>

4 <h2>What is the GCF of 15 and 25?</h2>

5 <p>The<a>greatest common factor</a><a>of</a>15 and 25 is 5. The largest<a>divisor</a>of two or more<a>numbers</a>is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.</p>

6 <h2>How to find the GCF of 15 and 25?</h2>

7 <p>To find the GCF of 15 and 25, a few methods are described below -</p>

8 <ul><li>Listing Factors</li>

9 <li>Prime Factorization</li>

10 <li>Long Division Method / by Euclidean Algorithm</li>

11 </ul><h2>GCF of 15 and 25 by Using Listing of factors</h2>

12 <p>Steps to find the GCF of 15 and 25 using the listing of<a>factors</a></p>

13 <p><strong>Step 1:</strong>Firstly, list the factors of each number</p>

14 <p>Factors of 15 = 1, 3, 5, 15.</p>

15 <p>Factors of 25 = 1, 5, 25.</p>

16 <p><strong>Step 2:</strong>Now, identify the<a>common factors</a>of them Common factors of 15 and 25: 1, 5.</p>

17 <p><strong>Step 3:</strong>Choose the largest factor</p>

18 <p>The largest factor that both numbers have is 5.</p>

19 <p>The GCF of 15 and 25 is 5.</p>

20 <h3>Explore Our Programs</h3>

21 - <p>No Courses Available</p>

22 <h2>GCF of 15 and 25 Using Prime Factorization</h2>

21 <h2>GCF of 15 and 25 Using Prime Factorization</h2>

23 <p>To find the GCF of 15 and 25 using the Prime Factorization Method, follow these steps:</p>

22 <p>To find the GCF of 15 and 25 using the Prime Factorization Method, follow these steps:</p>

24 <p><strong>Step 1:</strong>Find the<a>prime factors</a>of each number</p>

23 <p><strong>Step 1:</strong>Find the<a>prime factors</a>of each number</p>

25 <p>Prime Factors of 15: 15 = 3 x 5</p>

24 <p>Prime Factors of 15: 15 = 3 x 5</p>

26 <p>Prime Factors of 25: 25 = 5 x 5 = 5²</p>

25 <p>Prime Factors of 25: 25 = 5 x 5 = 5²</p>

27 <p><strong>Step 2:</strong>Now, identify the common prime factors</p>

26 <p><strong>Step 2:</strong>Now, identify the common prime factors</p>

28 <p>The common prime factor is: 5</p>

27 <p>The common prime factor is: 5</p>

29 <p><strong>Step 3:</strong>Multiply the common prime factors</p>

28 <p><strong>Step 3:</strong>Multiply the common prime factors</p>

30 <p>The Greatest Common Factor of 15 and 25 is 5.</p>

29 <p>The Greatest Common Factor of 15 and 25 is 5.</p>

31 <h2>GCF of 15 and 25 Using Division Method or Euclidean Algorithm Method</h2>

30 <h2>GCF of 15 and 25 Using Division Method or Euclidean Algorithm Method</h2>

32 <p>Find the GCF of 15 and 25 using the<a>division</a>method or Euclidean Algorithm Method. Follow these steps:</p>

31 <p>Find the GCF of 15 and 25 using the<a>division</a>method or Euclidean Algorithm Method. Follow these steps:</p>

33 <p><strong>Step 1:</strong>First, divide the larger number by the smaller number</p>

32 <p><strong>Step 1:</strong>First, divide the larger number by the smaller number</p>

34 <p>Here, divide 25 by 15 25 ÷ 15 = 1 (<a>quotient</a>),</p>

33 <p>Here, divide 25 by 15 25 ÷ 15 = 1 (<a>quotient</a>),</p>

35 <p>The<a>remainder</a>is calculated as 25 - (15×1) = 10</p>

34 <p>The<a>remainder</a>is calculated as 25 - (15×1) = 10</p>

36 <p>The remainder is 10, not zero, so continue the process</p>

35 <p>The remainder is 10, not zero, so continue the process</p>

37 <p><strong>Step 2:</strong>Now divide the previous divisor (15) by the previous remainder (10)</p>

36 <p><strong>Step 2:</strong>Now divide the previous divisor (15) by the previous remainder (10)</p>

38 <p>Divide 15 by 10 15 ÷ 10 = 1 (quotient), remainder = 15 - (10×1) = 5</p>

37 <p>Divide 15 by 10 15 ÷ 10 = 1 (quotient), remainder = 15 - (10×1) = 5</p>

39 <p>The remainder is 5, so continue the process</p>

38 <p>The remainder is 5, so continue the process</p>

40 <p><strong>Step 3:</strong>Now divide the previous divisor (10) by the previous remainder (5)</p>

39 <p><strong>Step 3:</strong>Now divide the previous divisor (10) by the previous remainder (5)</p>

41 <p>Divide 10 by 5 10 ÷ 5 = 2 (quotient), remainder = 0</p>

40 <p>Divide 10 by 5 10 ÷ 5 = 2 (quotient), remainder = 0</p>

42 <p>The remainder is zero, the divisor will become the GCF.</p>

41 <p>The remainder is zero, the divisor will become the GCF.</p>

43 <p>The GCF of 15 and 25 is 5.</p>

42 <p>The GCF of 15 and 25 is 5.</p>

44 <h2>Common Mistakes and How to Avoid Them in GCF of 15 and 25</h2>

43 <h2>Common Mistakes and How to Avoid Them in GCF of 15 and 25</h2>

45 <p>Finding GCF of 15 and 25 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.</p>

44 <p>Finding GCF of 15 and 25 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.</p>

46 <h3>Problem 1</h3>

45 <h3>Problem 1</h3>

47 <p>A gardener has 15 rose bushes and 25 tulip bulbs. She wants to plant them in equal rows, with the largest number of plants in each row. How many plants will be in each row?</p>

46 <p>A gardener has 15 rose bushes and 25 tulip bulbs. She wants to plant them in equal rows, with the largest number of plants in each row. How many plants will be in each row?</p>

48 <p>Okay, lets begin</p>

47 <p>Okay, lets begin</p>

49 <p>We should find the GCF of 15 and 25 GCF of 15 and 25 is 5.</p>

48 <p>We should find the GCF of 15 and 25 GCF of 15 and 25 is 5.</p>

50 <p>There are 5 equal groups.</p>

49 <p>There are 5 equal groups.</p>

51 <p>15 ÷ 5 = 3 25 ÷ 5 = 5</p>

50 <p>15 ÷ 5 = 3 25 ÷ 5 = 5</p>

52 <p>There will be 5 rows, and each row gets 3 rose bushes and 5 tulip bulbs.</p>

51 <p>There will be 5 rows, and each row gets 3 rose bushes and 5 tulip bulbs.</p>

53 <h3>Explanation</h3>

52 <h3>Explanation</h3>

54 <p>As the GCF of 15 and 25 is 5, the gardener can make 5 rows.</p>

53 <p>As the GCF of 15 and 25 is 5, the gardener can make 5 rows.</p>

55 <p>Now divide 15 and 25 by 5.</p>

54 <p>Now divide 15 and 25 by 5.</p>

56 <p>Each row gets 3 rose bushes and 5 tulip bulbs.</p>

55 <p>Each row gets 3 rose bushes and 5 tulip bulbs.</p>

57 <p>Well explained 👍</p>

56 <p>Well explained 👍</p>

58 <h3>Problem 2</h3>

57 <h3>Problem 2</h3>

59 <p>A chef has 15 kilograms of flour and 25 kilograms of sugar. She wants to package them into bags with the same weight, using the largest possible weight per bag. How much will each bag weigh?</p>

58 <p>A chef has 15 kilograms of flour and 25 kilograms of sugar. She wants to package them into bags with the same weight, using the largest possible weight per bag. How much will each bag weigh?</p>

60 <p>Okay, lets begin</p>

59 <p>Okay, lets begin</p>

61 <p>GCF of 15 and 25 is 5. So each bag will weigh 5 kilograms.</p>

60 <p>GCF of 15 and 25 is 5. So each bag will weigh 5 kilograms.</p>

62 <h3>Explanation</h3>

61 <h3>Explanation</h3>

63 <p>There are 15 kilograms of flour and 25 kilograms of sugar.</p>

62 <p>There are 15 kilograms of flour and 25 kilograms of sugar.</p>

64 <p>To find the total weight in each bag, we should find the GCF of 15 and 25.</p>

63 <p>To find the total weight in each bag, we should find the GCF of 15 and 25.</p>

65 <p>There will be 5 kilograms in each bag.</p>

64 <p>There will be 5 kilograms in each bag.</p>

66 <p>Well explained 👍</p>

65 <p>Well explained 👍</p>

67 <h3>Problem 3</h3>

66 <h3>Problem 3</h3>

68 <p>A cyclist has a 15-kilometer route and a 25-kilometer route. He wants to divide both routes into equal segments, using the longest possible segment length. How long should each segment be?</p>

67 <p>A cyclist has a 15-kilometer route and a 25-kilometer route. He wants to divide both routes into equal segments, using the longest possible segment length. How long should each segment be?</p>

69 <p>Okay, lets begin</p>

68 <p>Okay, lets begin</p>

70 <p>For calculating the longest equal segment length, we have to calculate the GCF of 15 and 25</p>

69 <p>For calculating the longest equal segment length, we have to calculate the GCF of 15 and 25</p>

71 <p>The GCF of 15 and 25 is 5.</p>

70 <p>The GCF of 15 and 25 is 5.</p>

72 <p>Each segment is 5 kilometers long.</p>

71 <p>Each segment is 5 kilometers long.</p>

73 <h3>Explanation</h3>

72 <h3>Explanation</h3>

74 <p>For calculating the longest segment length of the route, first, we need to calculate the GCF of 15 and 25, which is 5.</p>

73 <p>For calculating the longest segment length of the route, first, we need to calculate the GCF of 15 and 25, which is 5.</p>

75 <p>The length of each segment of the route will be 5 kilometers.</p>

74 <p>The length of each segment of the route will be 5 kilometers.</p>

76 <p>Well explained 👍</p>

75 <p>Well explained 👍</p>

77 <h3>Problem 4</h3>

76 <h3>Problem 4</h3>

78 <p>A musician has two pieces of wire for instruments, one 15 cm long and the other 25 cm long. He wants to cut them into the longest possible equal pieces, without any wire left over. What should be the length of each piece?</p>

77 <p>A musician has two pieces of wire for instruments, one 15 cm long and the other 25 cm long. He wants to cut them into the longest possible equal pieces, without any wire left over. What should be the length of each piece?</p>

79 <p>Okay, lets begin</p>

78 <p>Okay, lets begin</p>

80 <p>The musician needs the longest piece of wire GCF of 15 and 25 is 5.</p>

79 <p>The musician needs the longest piece of wire GCF of 15 and 25 is 5.</p>

81 <p>The longest length of each piece is 5 cm.</p>

80 <p>The longest length of each piece is 5 cm.</p>

82 <h3>Explanation</h3>

81 <h3>Explanation</h3>

83 <p>To find the longest length of each piece of the two pieces of wire, 15 cm and 25 cm, respectively, we have to find the GCF of 15 and 25, which is 5 cm.</p>

82 <p>To find the longest length of each piece of the two pieces of wire, 15 cm and 25 cm, respectively, we have to find the GCF of 15 and 25, which is 5 cm.</p>

84 <p>The longest length of each piece is 5 cm.</p>

83 <p>The longest length of each piece is 5 cm.</p>

85 <p>Well explained 👍</p>

84 <p>Well explained 👍</p>

86 <h3>Problem 5</h3>

85 <h3>Problem 5</h3>

87 <p>If the GCF of 15 and ‘a’ is 5, and the LCM is 75. Find ‘a’.</p>

86 <p>If the GCF of 15 and ‘a’ is 5, and the LCM is 75. Find ‘a’.</p>

88 <p>Okay, lets begin</p>

87 <p>Okay, lets begin</p>

89 <p>The value of ‘a’ is 25.</p>

88 <p>The value of ‘a’ is 25.</p>

90 <h3>Explanation</h3>

89 <h3>Explanation</h3>

91 <p>GCF x LCM = product of the numbers 5 × 75 = 15 × a</p>

90 <p>GCF x LCM = product of the numbers 5 × 75 = 15 × a</p>

92 <p>375 = 15a</p>

91 <p>375 = 15a</p>

93 <p>a = 375 ÷ 15 = 25</p>

92 <p>a = 375 ÷ 15 = 25</p>

94 <p>Well explained 👍</p>

93 <p>Well explained 👍</p>

95 <h2>FAQs on the Greatest Common Factor of 15 and 25</h2>

94 <h2>FAQs on the Greatest Common Factor of 15 and 25</h2>

96 <h3>1.What is the LCM of 15 and 25?</h3>

95 <h3>1.What is the LCM of 15 and 25?</h3>

97 <p>The LCM of 15 and 25 is 75.</p>

96 <p>The LCM of 15 and 25 is 75.</p>

98 <h3>2.Is 15 divisible by 3?</h3>

97 <h3>2.Is 15 divisible by 3?</h3>

99 <p>Yes, 15 is divisible by 3 because 15 ÷ 3 = 5, which is an<a>integer</a>.</p>

98 <p>Yes, 15 is divisible by 3 because 15 ÷ 3 = 5, which is an<a>integer</a>.</p>

100 <h3>3.What will be the GCF of any two prime numbers?</h3>

99 <h3>3.What will be the GCF of any two prime numbers?</h3>

101 <p>The common factor of<a>prime numbers</a>is 1 and the number itself. Since 1 is the only common factor of any two prime numbers, it is said to be the GCF of any two prime numbers.</p>

100 <p>The common factor of<a>prime numbers</a>is 1 and the number itself. Since 1 is the only common factor of any two prime numbers, it is said to be the GCF of any two prime numbers.</p>

102 <h3>4.What is the prime factorization of 25?</h3>

101 <h3>4.What is the prime factorization of 25?</h3>

103 <p>The prime factorization of 25 is 5².</p>

102 <p>The prime factorization of 25 is 5².</p>

104 <h3>5.Are 15 and 25 prime numbers?</h3>

103 <h3>5.Are 15 and 25 prime numbers?</h3>

105 <p>No, 15 and 25 are not prime numbers because both of them have more than two factors.</p>

104 <p>No, 15 and 25 are not prime numbers because both of them have more than two factors.</p>

106 <h2>Important Glossaries for GCF of 15 and 25</h2>

105 <h2>Important Glossaries for GCF of 15 and 25</h2>

107 <ul><li><strong>Factors:</strong>Factors are numbers that divide the target number completely. For example, the factors of 10 are 1, 2, 5, and 10.</li>

106 <ul><li><strong>Factors:</strong>Factors are numbers that divide the target number completely. For example, the factors of 10 are 1, 2, 5, and 10.</li>

108 <li><strong>Multiple:</strong>Multiples are the products we get by multiplying a given number by another. For example, the multiples of 3 are 3, 6, 9, 12, and so on.</li>

107 <li><strong>Multiple:</strong>Multiples are the products we get by multiplying a given number by another. For example, the multiples of 3 are 3, 6, 9, 12, and so on.</li>

109 <li><strong>Prime Factors:</strong>These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 25 are 5 and 5.</li>

108 <li><strong>Prime Factors:</strong>These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 25 are 5 and 5.</li>

110 <li><strong>Remainder:</strong>The value left after division when the number cannot be divided evenly. For example, when 10 is divided by 3, the remainder is 1, and the quotient is 3.</li>

109 <li><strong>Remainder:</strong>The value left after division when the number cannot be divided evenly. For example, when 10 is divided by 3, the remainder is 1, and the quotient is 3.</li>

111 <li><strong>LCM:</strong>The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 15 and 25 is 75.</li>

110 <li><strong>LCM:</strong>The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 15 and 25 is 75.</li>

112 </ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>

111 </ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>

113 <p>▶</p>

112 <p>▶</p>

114 <h2>Hiralee Lalitkumar Makwana</h2>

113 <h2>Hiralee Lalitkumar Makwana</h2>

115 <h3>About the Author</h3>

114 <h3>About the Author</h3>

116 <p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>

115 <p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>

117 <h3>Fun Fact</h3>

116 <h3>Fun Fact</h3>

118 <p>: She loves to read number jokes and games.</p>

117 <p>: She loves to read number jokes and games.</p>