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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is useful for both perfect and non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is useful for both perfect and non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 10201, we need to group it as 01, 20, and 10.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 10201, we need to group it as 01, 20, and 10.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 10. We can use n = 3 because 3 x 3 = 9, which is less than 10. The<a>quotient</a>is 3, and the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 10. We can use n = 3 because 3 x 3 = 9, which is less than 10. The<a>quotient</a>is 3, and the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Bring down the next pair 20 to make it 120. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Bring down the next pair 20 to make it 120. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be placed beside the<a>dividend</a>to make it 6n as the new divisor. We need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be placed beside the<a>dividend</a>to make it 6n as the new divisor. We need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n x n ≤ 120; let us consider n as 2, so 62 x 2 = 124, which is too large. Try n = 1, so 61 x 1 = 61.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n x n ≤ 120; let us consider n as 2, so 62 x 2 = 124, which is too large. Try n = 1, so 61 x 1 = 61.</p>
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<p><strong>Step 6:</strong>Subtract 120 - 61, and the difference is 59, and the quotient is 31.</p>
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<p><strong>Step 6:</strong>Subtract 120 - 61, and the difference is 59, and the quotient is 31.</p>
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<p><strong>Step 7:</strong>Bring down the next pair 01 to make it 5901. Add the old divisor with the same number 61 + 1 to get 62, which will be our new divisor.</p>
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<p><strong>Step 7:</strong>Bring down the next pair 01 to make it 5901. Add the old divisor with the same number 61 + 1 to get 62, which will be our new divisor.</p>
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<p><strong>Step 8:</strong>The next step is finding 62n x n ≤ 5901; let us consider n as 9, so 629 x 9 = 5661.</p>
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<p><strong>Step 8:</strong>The next step is finding 62n x n ≤ 5901; let us consider n as 9, so 629 x 9 = 5661.</p>
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<p><strong>Step 9:</strong>Subtract 5901 - 5661, and the difference is 240, and the quotient is 310.</p>
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<p><strong>Step 9:</strong>Subtract 5901 - 5661, and the difference is 240, and the quotient is 310.</p>
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<p><strong>Step 10:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 24000.</p>
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<p><strong>Step 10:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 24000.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point or until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point or until the remainder is zero.</p>
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<p>So the square root of √10201 is 101.</p>
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<p>So the square root of √10201 is 101.</p>
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