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1 - <p>265 Learners</p>
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2 <p>Last updated on<strong>August 5, 2025</strong></p>
2 <p>Last updated on<strong>August 5, 2025</strong></p>
3 <p>If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 1682.</p>
3 <p>If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 1682.</p>
4 <h2>What is the Square Root of 1682?</h2>
4 <h2>What is the Square Root of 1682?</h2>
5 <p>The<a>square</a>root is the inverse of the square of the<a>number</a>. 1682 is not a<a>perfect square</a>. The square root of 1682 is expressed in both radical and<a>exponential form</a>. In the radical form, it is expressed as √1682, whereas (1682)^(1/2) in the exponential form. √1682 ≈ 41.011, which is an<a>irrational number</a>because it cannot be expressed in the form of p/q, where p and q are<a>integers</a>and q ≠ 0.</p>
5 <p>The<a>square</a>root is the inverse of the square of the<a>number</a>. 1682 is not a<a>perfect square</a>. The square root of 1682 is expressed in both radical and<a>exponential form</a>. In the radical form, it is expressed as √1682, whereas (1682)^(1/2) in the exponential form. √1682 ≈ 41.011, which is an<a>irrational number</a>because it cannot be expressed in the form of p/q, where p and q are<a>integers</a>and q ≠ 0.</p>
6 <h2>Finding the Square Root of 1682</h2>
6 <h2>Finding the Square Root of 1682</h2>
7 <p>The<a>prime factorization</a>method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where the long-<a>division</a>method and approximation method are used. Let us now learn the following methods:</p>
7 <p>The<a>prime factorization</a>method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where the long-<a>division</a>method and approximation method are used. Let us now learn the following methods:</p>
8 <ul><li>Prime factorization method</li>
8 <ul><li>Prime factorization method</li>
9 <li>Long division method</li>
9 <li>Long division method</li>
10 <li>Approximation method</li>
10 <li>Approximation method</li>
11 </ul><h2>Square Root of 1682 by Prime Factorization Method</h2>
11 </ul><h2>Square Root of 1682 by Prime Factorization Method</h2>
12 <p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 1682 is broken down into its prime factors:</p>
12 <p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 1682 is broken down into its prime factors:</p>
13 <p><strong>Step 1:</strong>Finding the prime factors of 1682 Breaking it down, we get 2 × 3 × 281: 2¹ × 3¹ × 281¹</p>
13 <p><strong>Step 1:</strong>Finding the prime factors of 1682 Breaking it down, we get 2 × 3 × 281: 2¹ × 3¹ × 281¹</p>
14 <p><strong>Step 2:</strong>Now we found out the prime factors of 1682. The second step is to make pairs of those prime factors. Since 1682 is not a perfect square, the digits of the number can’t be grouped in pairs.</p>
14 <p><strong>Step 2:</strong>Now we found out the prime factors of 1682. The second step is to make pairs of those prime factors. Since 1682 is not a perfect square, the digits of the number can’t be grouped in pairs.</p>
15 <p>Therefore, calculating 1682 using prime factorization is impossible.</p>
15 <p>Therefore, calculating 1682 using prime factorization is impossible.</p>
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18 <h2>Square Root of 1682 by Long Division Method</h2>
17 <h2>Square Root of 1682 by Long Division Method</h2>
19 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
18 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
20 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1682, we need to group it as 16 and 82.</p>
19 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1682, we need to group it as 16 and 82.</p>
21 <p><strong>Step 2:</strong>Now we need to find n whose square is closest to 16. We can say n as ‘4’ because 4 × 4 = 16. Now the<a>quotient</a>is 4 and after subtracting 16 - 16 the<a>remainder</a>is 0.</p>
20 <p><strong>Step 2:</strong>Now we need to find n whose square is closest to 16. We can say n as ‘4’ because 4 × 4 = 16. Now the<a>quotient</a>is 4 and after subtracting 16 - 16 the<a>remainder</a>is 0.</p>
22 <p><strong>Step 3:</strong>Now let us bring down 82 which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 4 + 4, we get 8 which will be our new divisor.</p>
21 <p><strong>Step 3:</strong>Now let us bring down 82 which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 4 + 4, we get 8 which will be our new divisor.</p>
23 <p><strong>Step 4:</strong>We need to find a number that when multiplied by the new divisor gives a product<a>less than</a>or equal to 82. Let us consider n as 1, now 81 × 1 = 81.</p>
22 <p><strong>Step 4:</strong>We need to find a number that when multiplied by the new divisor gives a product<a>less than</a>or equal to 82. Let us consider n as 1, now 81 × 1 = 81.</p>
24 <p><strong>Step 5:</strong>Subtract 82 from 81 and the difference is 1, and the quotient is 41.</p>
23 <p><strong>Step 5:</strong>Subtract 82 from 81 and the difference is 1, and the quotient is 41.</p>
25 <p><strong>Step 6:</strong>Since the remainder is not zero, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 100.</p>
24 <p><strong>Step 6:</strong>Since the remainder is not zero, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 100.</p>
26 <p><strong>Step 7:</strong>Now we need to find the new divisor, which will be 82. We need to find a number that when multiplied by 82 gives a product less than or equal to 100. The closest we can use is 1.</p>
25 <p><strong>Step 7:</strong>Now we need to find the new divisor, which will be 82. We need to find a number that when multiplied by 82 gives a product less than or equal to 100. The closest we can use is 1.</p>
27 <p><strong>Step 8:</strong>Subtracting 82 from 100 we get the result 18.</p>
26 <p><strong>Step 8:</strong>Subtracting 82 from 100 we get the result 18.</p>
28 <p><strong>Step 9:</strong>The quotient is now 41.0 and we continue with additional decimal places to get a more precise value.</p>
27 <p><strong>Step 9:</strong>The quotient is now 41.0 and we continue with additional decimal places to get a more precise value.</p>
29 <p>So the square root of √1682 is approximately 41.011.</p>
28 <p>So the square root of √1682 is approximately 41.011.</p>
30 <h2>Square Root of 1682 by Approximation Method</h2>
29 <h2>Square Root of 1682 by Approximation Method</h2>
31 <p>The approximation method is another method for finding square roots; it is an easy method to find the square root of a given number. Now let us learn how to find the square root of 1682 using the approximation method.</p>
30 <p>The approximation method is another method for finding square roots; it is an easy method to find the square root of a given number. Now let us learn how to find the square root of 1682 using the approximation method.</p>
32 <p><strong>Step 1:</strong>Now we have to find the closest perfect squares of √1682.</p>
31 <p><strong>Step 1:</strong>Now we have to find the closest perfect squares of √1682.</p>
33 <p>The smallest perfect square less than 1682 is 1600 and the largest perfect square<a>greater than</a>1682 is 1764.</p>
32 <p>The smallest perfect square less than 1682 is 1600 and the largest perfect square<a>greater than</a>1682 is 1764.</p>
34 <p>√1682 falls somewhere between 40 and 42.</p>
33 <p>√1682 falls somewhere between 40 and 42.</p>
35 <p><strong>Step 2:</strong>Now we need to apply the<a>formula</a>:</p>
34 <p><strong>Step 2:</strong>Now we need to apply the<a>formula</a>:</p>
36 <p>(Given number - smallest perfect square) / (Greater perfect square - smallest perfect square).</p>
35 <p>(Given number - smallest perfect square) / (Greater perfect square - smallest perfect square).</p>
37 <p>Using the formula, (1682 - 1600) ÷ (1764 - 1600) ≈ 0.511</p>
36 <p>Using the formula, (1682 - 1600) ÷ (1764 - 1600) ≈ 0.511</p>
38 <p>Using the formula, we identified the<a>decimal</a>point of our square root.</p>
37 <p>Using the formula, we identified the<a>decimal</a>point of our square root.</p>
39 <p>The next step is adding the value we got initially to the decimal number which is 41 + 0.011 = 41.011, so the square root of 1682 is approximately 41.011.</p>
38 <p>The next step is adding the value we got initially to the decimal number which is 41 + 0.011 = 41.011, so the square root of 1682 is approximately 41.011.</p>
40 <h2>Common Mistakes and How to Avoid Them in the Square Root of 1682</h2>
39 <h2>Common Mistakes and How to Avoid Them in the Square Root of 1682</h2>
41 <p>Students do make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in the long division method. Now let us look at a few of those mistakes that students tend to make in detail.</p>
40 <p>Students do make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in the long division method. Now let us look at a few of those mistakes that students tend to make in detail.</p>
 
41 + <h2>Download Worksheets</h2>
42 <h3>Problem 1</h3>
42 <h3>Problem 1</h3>
43 <p>Can you help Max find the area of a square box if its side length is given as √1382?</p>
43 <p>Can you help Max find the area of a square box if its side length is given as √1382?</p>
44 <p>Okay, lets begin</p>
44 <p>Okay, lets begin</p>
45 <p>The area of the square is approximately 1382 square units.</p>
45 <p>The area of the square is approximately 1382 square units.</p>
46 <h3>Explanation</h3>
46 <h3>Explanation</h3>
47 <p>The area of the square = side². The side length is given as √1382. Area of the square = side² = √1382 × √1382 = 1382. Therefore, the area of the square box is approximately 1382 square units.</p>
47 <p>The area of the square = side². The side length is given as √1382. Area of the square = side² = √1382 × √1382 = 1382. Therefore, the area of the square box is approximately 1382 square units.</p>
48 <p>Well explained 👍</p>
48 <p>Well explained 👍</p>
49 <h3>Problem 2</h3>
49 <h3>Problem 2</h3>
50 <p>A square-shaped building measuring 1682 square feet is built; if each of the sides is √1682, what will be the square feet of half of the building?</p>
50 <p>A square-shaped building measuring 1682 square feet is built; if each of the sides is √1682, what will be the square feet of half of the building?</p>
51 <p>Okay, lets begin</p>
51 <p>Okay, lets begin</p>
52 <p>841 square feet.</p>
52 <p>841 square feet.</p>
53 <h3>Explanation</h3>
53 <h3>Explanation</h3>
54 <p>We can just divide the given area by 2 as the building is square-shaped. Dividing 1682 by 2 = 841. So half of the building measures 841 square feet.</p>
54 <p>We can just divide the given area by 2 as the building is square-shaped. Dividing 1682 by 2 = 841. So half of the building measures 841 square feet.</p>
55 <p>Well explained 👍</p>
55 <p>Well explained 👍</p>
56 <h3>Problem 3</h3>
56 <h3>Problem 3</h3>
57 <p>Calculate √1682 × 5.</p>
57 <p>Calculate √1682 × 5.</p>
58 <p>Okay, lets begin</p>
58 <p>Okay, lets begin</p>
59 <p>205.055</p>
59 <p>205.055</p>
60 <h3>Explanation</h3>
60 <h3>Explanation</h3>
61 <p>The first step is to find the square root of 1682 which is approximately 41.011, the second step is to multiply 41.011 by 5. So 41.011 × 5 ≈ 205.055.</p>
61 <p>The first step is to find the square root of 1682 which is approximately 41.011, the second step is to multiply 41.011 by 5. So 41.011 × 5 ≈ 205.055.</p>
62 <p>Well explained 👍</p>
62 <p>Well explained 👍</p>
63 <h3>Problem 4</h3>
63 <h3>Problem 4</h3>
64 <p>What will be the square root of (1382 + 6)?</p>
64 <p>What will be the square root of (1382 + 6)?</p>
65 <p>Okay, lets begin</p>
65 <p>Okay, lets begin</p>
66 <p>The square root is approximately 37.0135.</p>
66 <p>The square root is approximately 37.0135.</p>
67 <h3>Explanation</h3>
67 <h3>Explanation</h3>
68 <p>To find the square root, we need to find the sum of (1382 + 6). 1382 + 6 = 1388, and then √1388 ≈ 37.0135. Therefore, the square root of (1382 + 6) is approximately ±37.0135.</p>
68 <p>To find the square root, we need to find the sum of (1382 + 6). 1382 + 6 = 1388, and then √1388 ≈ 37.0135. Therefore, the square root of (1382 + 6) is approximately ±37.0135.</p>
69 <p>Well explained 👍</p>
69 <p>Well explained 👍</p>
70 <h3>Problem 5</h3>
70 <h3>Problem 5</h3>
71 <p>Find the perimeter of a rectangle if its length ‘l’ is √1382 units and the width ‘w’ is 38 units.</p>
71 <p>Find the perimeter of a rectangle if its length ‘l’ is √1382 units and the width ‘w’ is 38 units.</p>
72 <p>Okay, lets begin</p>
72 <p>Okay, lets begin</p>
73 <p>We find the perimeter of the rectangle as approximately 156.027 units.</p>
73 <p>We find the perimeter of the rectangle as approximately 156.027 units.</p>
74 <h3>Explanation</h3>
74 <h3>Explanation</h3>
75 <p>Perimeter of the rectangle = 2 × (length + width). Perimeter = 2 × (√1382 + 38) = 2 × (37.162 + 38) = 2 × 75.162 = 150.324 units.</p>
75 <p>Perimeter of the rectangle = 2 × (length + width). Perimeter = 2 × (√1382 + 38) = 2 × (37.162 + 38) = 2 × 75.162 = 150.324 units.</p>
76 <p>Well explained 👍</p>
76 <p>Well explained 👍</p>
77 <h2>FAQ on Square Root of 1682</h2>
77 <h2>FAQ on Square Root of 1682</h2>
78 <h3>1.What is √1682 in its simplest form?</h3>
78 <h3>1.What is √1682 in its simplest form?</h3>
79 <p>The prime factorization of 1682 is 2 × 3 × 281 so the simplest form of √1682 = √(2 × 3 × 281).</p>
79 <p>The prime factorization of 1682 is 2 × 3 × 281 so the simplest form of √1682 = √(2 × 3 × 281).</p>
80 <h3>2.Mention the factors of 1682.</h3>
80 <h3>2.Mention the factors of 1682.</h3>
81 <p>Factors of 1682 are 1, 2, 3, 6, 281, 562, 843, and 1682.</p>
81 <p>Factors of 1682 are 1, 2, 3, 6, 281, 562, 843, and 1682.</p>
82 <h3>3.Calculate the square of 1682.</h3>
82 <h3>3.Calculate the square of 1682.</h3>
83 <p>We get the square of 1682 by multiplying the number by itself, that is 1682 × 1682 = 2,829,124.</p>
83 <p>We get the square of 1682 by multiplying the number by itself, that is 1682 × 1682 = 2,829,124.</p>
84 <h3>4.Is 1682 a prime number?</h3>
84 <h3>4.Is 1682 a prime number?</h3>
85 <p>1682 is not a<a>prime number</a>, as it has more than two factors.</p>
85 <p>1682 is not a<a>prime number</a>, as it has more than two factors.</p>
86 <h3>5.1682 is divisible by?</h3>
86 <h3>5.1682 is divisible by?</h3>
87 <p>1682 has several factors; those are 1, 2, 3, 6, 281, 562, 843, and 1682.</p>
87 <p>1682 has several factors; those are 1, 2, 3, 6, 281, 562, 843, and 1682.</p>
88 <h2>Important Glossaries for the Square Root of 1682</h2>
88 <h2>Important Glossaries for the Square Root of 1682</h2>
89 <ul><li><strong>Square root:</strong>A square root is the inverse of a square. Example: 4² = 16 and the inverse of the square is the square root that is √16 = 4. </li>
89 <ul><li><strong>Square root:</strong>A square root is the inverse of a square. Example: 4² = 16 and the inverse of the square is the square root that is √16 = 4. </li>
90 <li><strong>Irrational number:</strong>An irrational number is a number that cannot be written in the form of p/q, where q is not equal to zero and p and q are integers. </li>
90 <li><strong>Irrational number:</strong>An irrational number is a number that cannot be written in the form of p/q, where q is not equal to zero and p and q are integers. </li>
91 <li><strong>Principal square root:</strong>A number has both positive and negative square roots, however, it is always the positive square root that has more prominence due to its uses in the real world. This is the reason it is also known as the principal square root. </li>
91 <li><strong>Principal square root:</strong>A number has both positive and negative square roots, however, it is always the positive square root that has more prominence due to its uses in the real world. This is the reason it is also known as the principal square root. </li>
92 <li><strong>Prime factorization:</strong>The process of expressing a number as a product of its prime factors. For example, the prime factorization of 1682 is 2 × 3 × 281. </li>
92 <li><strong>Prime factorization:</strong>The process of expressing a number as a product of its prime factors. For example, the prime factorization of 1682 is 2 × 3 × 281. </li>
93 <li><strong>Approximation:</strong>The process of finding a value that is close enough to the right answer, usually within a specified range. For example, the approximate value of √1682 is 41.011.</li>
93 <li><strong>Approximation:</strong>The process of finding a value that is close enough to the right answer, usually within a specified range. For example, the approximate value of √1682 is 41.011.</li>
94 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
94 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
95 <p>▶</p>
95 <p>▶</p>
96 <h2>Jaskaran Singh Saluja</h2>
96 <h2>Jaskaran Singh Saluja</h2>
97 <h3>About the Author</h3>
97 <h3>About the Author</h3>
98 <p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
98 <p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
99 <h3>Fun Fact</h3>
99 <h3>Fun Fact</h3>
100 <p>: He loves to play the quiz with kids through algebra to make kids love it.</p>
100 <p>: He loves to play the quiz with kids through algebra to make kids love it.</p>