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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 261, we group it as 61 and 2.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 261, we group it as 61 and 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 2. We can say n as ‘1’ because 1 x 1 is lesser than or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 2. We can say n as ‘1’ because 1 x 1 is lesser than or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Bring down 61, making it the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Bring down 61, making it the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 161. Let us consider n as 8, now 28 x 8 = 224</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 161. Let us consider n as 8, now 28 x 8 = 224</p>
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<p><strong>Step 6:</strong>Subtract 161 from 224, the difference is 63, and the quotient is 16</p>
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<p><strong>Step 6:</strong>Subtract 161 from 224, the difference is 63, and the quotient is 16</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 6300.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 6300.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor. Let us consider n as 2, 322 x 2 = 644</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor. Let us consider n as 2, 322 x 2 = 644</p>
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<p><strong>Step 9:</strong>Subtracting 644 from 6300, we get the result 5656.</p>
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<p><strong>Step 9:</strong>Subtracting 644 from 6300, we get the result 5656.</p>
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<p><strong>Step 10:</strong>Now the quotient is 16.1</p>
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<p><strong>Step 10:</strong>Now the quotient is 16.1</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal value, continue until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal value, continue until the remainder is zero.</p>
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<p>So the square root of √261 is approximately 16.15.</p>
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<p>So the square root of √261 is approximately 16.15.</p>
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