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Original
2026-01-01
Modified
2026-02-28
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<p>The formula (a+b)3(a + b)^3(a+b)3 is a<a>binomial</a>formula for finding the cube of a number. It expands as:</p>
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<p>The formula (a+b)3(a + b)^3(a+b)3 is a<a>binomial</a>formula for finding the cube of a number. It expands as:</p>
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<p>(a+b)3=a3+3a2b+3ab2+b3(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3(a+b)3=a3+3a2b+3ab2+b3</p>
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<p>(a+b)3=a3+3a2b+3ab2+b3(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3(a+b)3=a3+3a2b+3ab2+b3</p>
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<p><strong>Step 1:</strong>Split the number 1373 into two parts: a=1300a = 1300a=1300 and b=73b = 73b=73, so a+b=1373a + b = 1373a+b=1373.</p>
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<p><strong>Step 1:</strong>Split the number 1373 into two parts: a=1300a = 1300a=1300 and b=73b = 73b=73, so a+b=1373a + b = 1373a+b=1373.</p>
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<p><strong>Step 2:</strong>Now, apply the formula:</p>
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<p><strong>Step 2:</strong>Now, apply the formula:</p>
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<p>(a+b)3=a3+3a2b+3ab2+b3(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3(a+b)3=a3+3a2b+3ab2+b3</p>
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<p>(a+b)3=a3+3a2b+3ab2+b3(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3(a+b)3=a3+3a2b+3ab2+b3</p>
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<p><strong>Step 3:</strong>Calculate each<a>term</a>:</p>
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<p><strong>Step 3:</strong>Calculate each<a>term</a>:</p>
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<p>a³ = 1300³ = 2,197,000,000 3a²b = 3 × 1300² × 73 = 370,530,000 3ab² = 3 × 1300 × 73² = 20,803,500 b³ = 73³ = 389,017</p>
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<p>a³ = 1300³ = 2,197,000,000 3a²b = 3 × 1300² × 73 = 370,530,000 3ab² = 3 × 1300 × 73² = 20,803,500 b³ = 73³ = 389,017</p>
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<p><strong>Step 4:</strong>Add all the terms together:</p>
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<p><strong>Step 4:</strong>Add all the terms together:</p>
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<p>(1300 + 73)³ = 1300³ + 3 × 1300² × 73 + 3 × 1300 × 73² + 73³ = 2,197,000,000 + 370,530,000 + 20,803,500 + 389,017 = 2,586,967,717</p>
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<p>(1300 + 73)³ = 1300³ + 3 × 1300² × 73 + 3 × 1300 × 73² + 73³ = 2,197,000,000 + 370,530,000 + 20,803,500 + 389,017 = 2,586,967,717</p>
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<p>So: 1373³ = 2,586,967,717</p>
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<p>So: 1373³ = 2,586,967,717</p>
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<p><strong>Step 5:</strong>Hence, the cube of 1373 is<strong>2,586,967,717</strong>.</p>
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<p><strong>Step 5:</strong>Hence, the cube of 1373 is<strong>2,586,967,717</strong>.</p>
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