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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1014, we need to group it as 14 and 10.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1014, we need to group it as 14 and 10.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is closest to 10. We can say n as ‘3’ because 3 × 3 = 9 is<a>less than</a>or equal to 10. Now the<a>quotient</a>is 3, and after subtracting 10 - 9, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is closest to 10. We can say n as ‘3’ because 3 × 3 = 9 is<a>less than</a>or equal to 10. Now the<a>quotient</a>is 3, and after subtracting 10 - 9, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 14, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3, we get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 14, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3, we get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 6n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 6n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 114. Let us consider n as 1; now 6 × 1 × 1 = 6.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 114. Let us consider n as 1; now 6 × 1 × 1 = 6.</p>
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<p><strong>Step 6:</strong>Subtract 114 from 6, the difference is 108, and the quotient is 31.</p>
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<p><strong>Step 6:</strong>Subtract 114 from 6, the difference is 108, and the quotient is 31.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 10800.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 10800.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 317 because 317 × 3 = 951.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 317 because 317 × 3 = 951.</p>
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<p><strong>Step 9:</strong>Subtracting 951 from 10800, we get the result 10849.</p>
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<p><strong>Step 9:</strong>Subtracting 951 from 10800, we get the result 10849.</p>
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<p><strong>Step 10:</strong>Now the quotient is 31.8.</p>
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<p><strong>Step 10:</strong>Now the quotient is 31.8.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose there are no more decimal values; continue until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose there are no more decimal values; continue until the remainder is zero.</p>
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<p>So the square root of √1014 ≈ 31.84</p>
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<p>So the square root of √1014 ≈ 31.84</p>
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