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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1460, we need to group it as 60 and 14.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1460, we need to group it as 60 and 14.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 14. We can say n as ‘3’ because 3 × 3 = 9, which is<a>less than</a>14. Now the<a>quotient</a>is 3, and after subtracting 9 from 14, the<a>remainder</a>is 5.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 14. We can say n as ‘3’ because 3 × 3 = 9, which is<a>less than</a>14. Now the<a>quotient</a>is 3, and after subtracting 9 from 14, the<a>remainder</a>is 5.</p>
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<p><strong>Step 3:</strong>Now let us bring down 60, making the new<a>dividend</a>560. Add the old<a>divisor</a>with the same number, 3 + 3, to get 6, which will be part of our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 60, making the new<a>dividend</a>560. Add the old<a>divisor</a>with the same number, 3 + 3, to get 6, which will be part of our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we have 6n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we have 6n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 560. Let us consider n as 9, now 6 × 9 = 54, and 549 is the closest product.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 560. Let us consider n as 9, now 6 × 9 = 54, and 549 is the closest product.</p>
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<p><strong>Step 6:</strong>Subtract 549 from 560; the difference is 11, and the quotient is 39.</p>
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<p><strong>Step 6:</strong>Subtract 549 from 560; the difference is 11, and the quotient is 39.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeros to the dividend. Now the new dividend is 1100.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeros to the dividend. Now the new dividend is 1100.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 78, because 789 × 1 = 789.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 78, because 789 × 1 = 789.</p>
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<p><strong>Step 9:</strong>Subtracting 789 from 1100, we get the result 311.</p>
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<p><strong>Step 9:</strong>Subtracting 789 from 1100, we get the result 311.</p>
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<p><strong>Step 10:</strong>Now the quotient is 38.2.</p>
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<p><strong>Step 10:</strong>Now the quotient is 38.2.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p>So the square root of √1460 is approximately 38.21.</p>
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<p>So the square root of √1460 is approximately 38.21.</p>
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