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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 3625, we need to group it as 36 and 25.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 3625, we need to group it as 36 and 25.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 36. We can say n as ‘6’ because 6 × 6 is lesser than or equal to 36. Now the<a>quotient</a>is 6, and after subtracting 36 - 36, the<a>remainder</a>is 0.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 36. We can say n as ‘6’ because 6 × 6 is lesser than or equal to 36. Now the<a>quotient</a>is 6, and after subtracting 36 - 36, the<a>remainder</a>is 0.</p>
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<p><strong>Step 3:</strong>Now let us bring down 25, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 6 + 6, we get 12, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 25, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 6 + 6, we get 12, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 12n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 12n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 12n × n ≤ 25. Let us consider n as 2, now 12 × 2 × 2 = 48.</p>
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<p><strong>Step 5:</strong>The next step is finding 12n × n ≤ 25. Let us consider n as 2, now 12 × 2 × 2 = 48.</p>
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<p><strong>Step 6:</strong>Subtract 25 from 48; the difference is -23, which means n should be 1. Now 12 × 1 = 12.</p>
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<p><strong>Step 6:</strong>Subtract 25 from 48; the difference is -23, which means n should be 1. Now 12 × 1 = 12.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1300.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1300.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 121 because 1211 × 1 = 1211.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 121 because 1211 × 1 = 1211.</p>
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<p><strong>Step 9:</strong>Subtracting 1211 from 1300, we get the result 89.</p>
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<p><strong>Step 9:</strong>Subtracting 1211 from 1300, we get the result 89.</p>
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<p><strong>Step 10:</strong>Now the quotient is 60.2.</p>
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<p><strong>Step 10:</strong>Now the quotient is 60.2.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p>So the square root of √3625 ≈ 60.21.</p>
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<p>So the square root of √3625 ≈ 60.21.</p>
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