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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. This method involves finding the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. This method involves finding the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1206, we need to group it as 06 and 12.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1206, we need to group it as 06 and 12.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 12. We can say n is 3 because 3 x 3 = 9, which is<a>less than</a>or equal to 12. Now the<a>quotient</a>is 3, and after subtracting 9 from 12, the<a>remainder</a>is 3.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 12. We can say n is 3 because 3 x 3 = 9, which is<a>less than</a>or equal to 12. Now the<a>quotient</a>is 3, and after subtracting 9 from 12, the<a>remainder</a>is 3.</p>
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<p><strong>Step 3:</strong>Now let us bring down 06, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 06, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3 to get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be 6n, where we need to find the value of n such that 6n x n ≤ 306.</p>
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<p><strong>Step 4:</strong>The new divisor will be 6n, where we need to find the value of n such that 6n x n ≤ 306.</p>
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<p><strong>Step 5:</strong>Let us consider n as 5, now 65 x 5 = 325, which is too large, so we try n = 4.</p>
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<p><strong>Step 5:</strong>Let us consider n as 5, now 65 x 5 = 325, which is too large, so we try n = 4.</p>
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<p><strong>Step 6:</strong>Subtract 264 (64 x 4) from 306, the difference is 42, and the quotient is 34.</p>
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<p><strong>Step 6:</strong>Subtract 264 (64 x 4) from 306, the difference is 42, and the quotient is 34.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4200.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 4200.</p>
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<p><strong>Step 8:</strong>Find the new divisor, which is 689 because 689 x 6 = 4134.</p>
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<p><strong>Step 8:</strong>Find the new divisor, which is 689 because 689 x 6 = 4134.</p>
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<p><strong>Step 9:</strong>Subtracting 4134 from 4200, we get the result 66.</p>
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<p><strong>Step 9:</strong>Subtracting 4134 from 4200, we get the result 66.</p>
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<p><strong>Step 10:</strong>Now the quotient is approximately 34.7.</p>
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<p><strong>Step 10:</strong>Now the quotient is approximately 34.7.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point.</p>
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<p>So the square root of √1206 is approximately 34.74.</p>
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<p>So the square root of √1206 is approximately 34.74.</p>
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