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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 235, we need to group it as 35 and 2.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 235, we need to group it as 35 and 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 2. We can say n is ‘1’ because 1 x 1 is lesser than or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 2. We can say n is ‘1’ because 1 x 1 is lesser than or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 35, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1; we get 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 35, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 1 + 1; we get 2, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 135. Let us consider n as 5; now 25 x 5 = 125.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 135. Let us consider n as 5; now 25 x 5 = 125.</p>
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<p><strong>Step 6:</strong>Subtract 125 from 135; the difference is 10, and the quotient is 15.</p>
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<p><strong>Step 6:</strong>Subtract 125 from 135; the difference is 10, and the quotient is 15.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1000.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1000.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 305 because 305 x 3 = 915.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor that is 305 because 305 x 3 = 915.</p>
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<p><strong>Step 9:</strong>Subtracting 915 from 1000, we get the result 85.</p>
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<p><strong>Step 9:</strong>Subtracting 915 from 1000, we get the result 85.</p>
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<p><strong>Step 10:</strong>Now the quotient is 15.3.</p>
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<p><strong>Step 10:</strong>Now the quotient is 15.3.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values continue till the remainder is zero. So the square root of √235 is approximately 15.33.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values continue till the remainder is zero. So the square root of √235 is approximately 15.33.</p>
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