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Original 2026-01-01
Modified 2026-02-28
1 <p>225 can be converted easily from decimal to binary. The methods mentioned below will help us convert the number. Let’s see how it is done.</p>
1 <p>225 can be converted easily from decimal to binary. The methods mentioned below will help us convert the number. Let’s see how it is done.</p>
2 <p><strong>Expansion Method:</strong>Let us see the step-by-step process of converting 225 using the expansion method.</p>
2 <p><strong>Expansion Method:</strong>Let us see the step-by-step process of converting 225 using the expansion method.</p>
3 <p><strong>Step 1 -</strong>Figure out the place values: In the binary system, each<a>place value</a>is a<a>power</a>of 2. Therefore, in the first step, we will ascertain the powers of 2. 2^0 = 1 2^1 = 2 2^2 = 4 2^3 = 8 2^4 = 16<a>2^5</a>= 32 2^6 = 64 2^7 = 128 2^8 = 256 Since 256 is<a>greater than</a>225, we stop at 2^7 = 128.</p>
3 <p><strong>Step 1 -</strong>Figure out the place values: In the binary system, each<a>place value</a>is a<a>power</a>of 2. Therefore, in the first step, we will ascertain the powers of 2. 2^0 = 1 2^1 = 2 2^2 = 4 2^3 = 8 2^4 = 16<a>2^5</a>= 32 2^6 = 64 2^7 = 128 2^8 = 256 Since 256 is<a>greater than</a>225, we stop at 2^7 = 128.</p>
4 <p><strong>Step 2 -</strong>Identify the largest power of 2: In the previous step, we stopped at 2^7 = 128. This is because in this step, we have to identify the largest power of 2, which is<a>less than</a>or equal to the given number, 225. Since 2^7 is the number we are looking for, write 1 in the 2^7 place. Now the value of 2^7, which is 128, is subtracted from 225. 225 - 128 = 97.</p>
4 <p><strong>Step 2 -</strong>Identify the largest power of 2: In the previous step, we stopped at 2^7 = 128. This is because in this step, we have to identify the largest power of 2, which is<a>less than</a>or equal to the given number, 225. Since 2^7 is the number we are looking for, write 1 in the 2^7 place. Now the value of 2^7, which is 128, is subtracted from 225. 225 - 128 = 97.</p>
5 <p><strong>Step 3 -</strong>Identify the next largest power of 2: In this step, we need to find the largest power of 2 that fits into the result of the previous step, 97. So, the next largest power of 2 is 2^6, which is 64. Now, we have to write 1 in the 2^6 place. And then subtract 64 from 97. 97 - 64 = 33.</p>
5 <p><strong>Step 3 -</strong>Identify the next largest power of 2: In this step, we need to find the largest power of 2 that fits into the result of the previous step, 97. So, the next largest power of 2 is 2^6, which is 64. Now, we have to write 1 in the 2^6 place. And then subtract 64 from 97. 97 - 64 = 33.</p>
6 <p><strong>Step 4 -</strong>Continue the process: Find the next largest power of 2 that fits into 33, which is 2^5 = 32. Write 1 in the 2^5 place. 33 - 32 = 1.</p>
6 <p><strong>Step 4 -</strong>Continue the process: Find the next largest power of 2 that fits into 33, which is 2^5 = 32. Write 1 in the 2^5 place. 33 - 32 = 1.</p>
7 <p><strong>Step 5 -</strong>Find the next largest power of 2 for 1, which is 2^0 = 1. Write 1 in the 2^0 place. 1 - 1 = 0. We need to stop the process here since the remainder is 0.</p>
7 <p><strong>Step 5 -</strong>Find the next largest power of 2 for 1, which is 2^0 = 1. Write 1 in the 2^0 place. 1 - 1 = 0. We need to stop the process here since the remainder is 0.</p>
8 <p><strong>Step 6 -</strong>Identify the unused place values: In previous steps, we wrote 1 in the 2^7, 2^6, 2^5, and 2^0 places. Now, we can just write 0s in the remaining places, which are 2^4, 2^3, 2^2, and 2^1. Now, by substituting the values, we get, 1 in the 2^7 place 1 in the 2^6 place 1 in the 2^5 place 0 in the 2^4 place 0 in the 2^3 place 0 in the 2^2 place 0 in the 2^1 place 1 in the 2^0 place</p>
8 <p><strong>Step 6 -</strong>Identify the unused place values: In previous steps, we wrote 1 in the 2^7, 2^6, 2^5, and 2^0 places. Now, we can just write 0s in the remaining places, which are 2^4, 2^3, 2^2, and 2^1. Now, by substituting the values, we get, 1 in the 2^7 place 1 in the 2^6 place 1 in the 2^5 place 0 in the 2^4 place 0 in the 2^3 place 0 in the 2^2 place 0 in the 2^1 place 1 in the 2^0 place</p>
9 <p><strong>Step 7 -</strong>Write the values in reverse order: We now write the numbers upside down to represent 225 in binary. Therefore, 11100001 is 225 in binary.</p>
9 <p><strong>Step 7 -</strong>Write the values in reverse order: We now write the numbers upside down to represent 225 in binary. Therefore, 11100001 is 225 in binary.</p>
10 <p><strong>Grouping Method:</strong>In this method, we divide the number 225 by 2. Let us see the step-by-step conversion.</p>
10 <p><strong>Grouping Method:</strong>In this method, we divide the number 225 by 2. Let us see the step-by-step conversion.</p>
11 <p><strong>Step 1 -</strong>Divide the given number 225 by 2. 225 / 2 = 112. Here, 112 is the quotient and 1 is the remainder.</p>
11 <p><strong>Step 1 -</strong>Divide the given number 225 by 2. 225 / 2 = 112. Here, 112 is the quotient and 1 is the remainder.</p>
12 <p><strong>Step 2 -</strong>Divide the previous quotient (112) by 2. 112 / 2 = 56. Here, the quotient is 56 and the remainder is 0.</p>
12 <p><strong>Step 2 -</strong>Divide the previous quotient (112) by 2. 112 / 2 = 56. Here, the quotient is 56 and the remainder is 0.</p>
13 <p><strong>Step 3 -</strong>Repeat the previous step. 56 / 2 = 28. Now, the quotient is 28, and 0 is the remainder.</p>
13 <p><strong>Step 3 -</strong>Repeat the previous step. 56 / 2 = 28. Now, the quotient is 28, and 0 is the remainder.</p>
14 <p><strong>Step 4 -</strong>Repeat the previous step. 28 / 2 = 14. Here, the quotient is 14, and 0 is the remainder.</p>
14 <p><strong>Step 4 -</strong>Repeat the previous step. 28 / 2 = 14. Here, the quotient is 14, and 0 is the remainder.</p>
15 <p><strong>Step 5 -</strong>Repeat the previous step. 14 / 2 = 7. Here, the quotient is 7, and 0 is the remainder.</p>
15 <p><strong>Step 5 -</strong>Repeat the previous step. 14 / 2 = 7. Here, the quotient is 7, and 0 is the remainder.</p>
16 <p><strong>Step 6 -</strong>Repeat the previous step. 7 / 2 = 3. Here, the quotient is 3, and 1 is the remainder.</p>
16 <p><strong>Step 6 -</strong>Repeat the previous step. 7 / 2 = 3. Here, the quotient is 3, and 1 is the remainder.</p>
17 <p><strong>Step 7 -</strong>Repeat the previous step. 3 / 2 = 1. Here, the quotient is 1, and 1 is the remainder.</p>
17 <p><strong>Step 7 -</strong>Repeat the previous step. 3 / 2 = 1. Here, the quotient is 1, and 1 is the remainder.</p>
18 <p><strong>Step 8 -</strong>Repeat the previous step. 1 / 2 = 0.</p>
18 <p><strong>Step 8 -</strong>Repeat the previous step. 1 / 2 = 0.</p>
19 <p>Here, the remainder is 1. And we stop the<a>division</a>here because the quotient is 0.</p>
19 <p>Here, the remainder is 1. And we stop the<a>division</a>here because the quotient is 0.</p>
20 <p><strong>Step 9 -</strong>Write down the remainders from bottom to top. Therefore, 225 (decimal) = 11100001 (binary).</p>
20 <p><strong>Step 9 -</strong>Write down the remainders from bottom to top. Therefore, 225 (decimal) = 11100001 (binary).</p>
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