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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 275, we need to group it as 75 and 2.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 275, we need to group it as 75 and 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 2. We can say n is ‘1’ because 1 x 1 is less than or equal to 2. Now the<a>quotient</a>is 1; after subtracting 1, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 2. We can say n is ‘1’ because 1 x 1 is less than or equal to 2. Now the<a>quotient</a>is 1; after subtracting 1, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 75, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number: 1 + 1 = 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 75, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number: 1 + 1 = 2, which will be our new divisor.</p>
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<p><strong>Step 4</strong>: The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4</strong>: The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n x n ≤ 175. Let us consider n as 6; now 26 x 6 = 156.</p>
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<p><strong>Step 5:</strong>The next step is finding 2n x n ≤ 175. Let us consider n as 6; now 26 x 6 = 156.</p>
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<p><strong>Step 6:</strong>Subtract 156 from 175; the difference is 19, and the quotient is 16.</p>
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<p><strong>Step 6:</strong>Subtract 156 from 175; the difference is 19, and the quotient is 16.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1900.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1900.</p>
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<p><strong>Step 8:</strong>Now we need to find a new divisor. Let's consider n as 7, because 327 x 7 = 2289, which is close to 1900.</p>
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<p><strong>Step 8:</strong>Now we need to find a new divisor. Let's consider n as 7, because 327 x 7 = 2289, which is close to 1900.</p>
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<p><strong>Step 9:</strong>Subtracting 2289 from 1900 is not feasible, so we adjust n accordingly.</p>
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<p><strong>Step 9:</strong>Subtracting 2289 from 1900 is not feasible, so we adjust n accordingly.</p>
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<p><strong>Step 10:</strong>The quotient is approximately 16.58. Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
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<p><strong>Step 10:</strong>The quotient is approximately 16.58. Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
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<p>So the square root of √275 is approximately 16.58.</p>
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<p>So the square root of √275 is approximately 16.58.</p>
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