HTML Diff
0 added 0 removed
Original 2026-01-01
Modified 2026-02-28
1 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
1 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 332, we need to group it as 32 and 3.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 332, we need to group it as 32 and 3.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is &lt;= 3. We can say n is ‘1’ because 1 x 1 = 1, which is<a>less than</a>3. Now the<a>quotient</a>is 1, and after subtracting 1 from 3, the<a>remainder</a>is 2.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is &lt;= 3. We can say n is ‘1’ because 1 x 1 = 1, which is<a>less than</a>3. Now the<a>quotient</a>is 1, and after subtracting 1 from 3, the<a>remainder</a>is 2.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 32, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number: 1 + 1 = 2, which will be our new divisor.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 32, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number: 1 + 1 = 2, which will be our new divisor.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, we need to find the value of n.</p>
6 <p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 232. Let us consider n as 9, now 2 x 9 x 9 = 162.</p>
6 <p><strong>Step 5:</strong>The next step is finding 2n × n ≤ 232. Let us consider n as 9, now 2 x 9 x 9 = 162.</p>
7 <p><strong>Step 6:</strong>Subtract 162 from 232, the difference is 70, and the quotient is 19.</p>
7 <p><strong>Step 6:</strong>Subtract 162 from 232, the difference is 70, and the quotient is 19.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 7000.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 7000.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that is 389 because 389 x 9 = 3501.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that is 389 because 389 x 9 = 3501.</p>
10 <p><strong>Step 9:</strong>Subtracting 3501 from 7000 we get the result 3499.</p>
10 <p><strong>Step 9:</strong>Subtracting 3501 from 7000 we get the result 3499.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 18.9.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 18.9.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
13 <p>So the square root of √332 ≈ 18.22</p>
13 <p>So the square root of √332 ≈ 18.22</p>
14  
14