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2026-01-01
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<p>Last updated on<strong>October 7, 2025</strong></p>
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<p>Last updated on<strong>October 7, 2025</strong></p>
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<p>The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items and schedule events. In this topic, we will learn about the GCF of 9 and 5.</p>
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<p>The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items and schedule events. In this topic, we will learn about the GCF of 9 and 5.</p>
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<h2>What is the GCF of 9 and 5?</h2>
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<h2>What is the GCF of 9 and 5?</h2>
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<p>The<a>greatest common factor</a><a>of</a>9 and 5 is 1.</p>
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<p>The<a>greatest common factor</a><a>of</a>9 and 5 is 1.</p>
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<p>The largest<a>divisor</a>of two or more<a>numbers</a>is called the GCF of the number.</p>
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<p>The largest<a>divisor</a>of two or more<a>numbers</a>is called the GCF of the number.</p>
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<p>If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.</p>
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<p>If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.</p>
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<p>The GCF of two numbers cannot be negative because divisors are always positive.</p>
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<p>The GCF of two numbers cannot be negative because divisors are always positive.</p>
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<h2>How to find the GCF of 9 and 5?</h2>
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<h2>How to find the GCF of 9 and 5?</h2>
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<p>To find the GCF of 9 and 5, a few methods are described below -</p>
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<p>To find the GCF of 9 and 5, a few methods are described below -</p>
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<p>Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm</p>
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<p>Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm</p>
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<h2>GCF of 9 and 5 by Using Listing of factors</h2>
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<h2>GCF of 9 and 5 by Using Listing of factors</h2>
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<p>Steps to find the GCF of 9 and 5 using the listing of<a>factors</a></p>
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<p>Steps to find the GCF of 9 and 5 using the listing of<a>factors</a></p>
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<p>Step 1: Firstly, list the factors of each number Factors of 9 = 1, 3, 9. Factors of 5 = 1, 5.</p>
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<p>Step 1: Firstly, list the factors of each number Factors of 9 = 1, 3, 9. Factors of 5 = 1, 5.</p>
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<p>Step 2: Now, identify the<a>common factors</a>of them Common factors of 9 and 5: 1.</p>
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<p>Step 2: Now, identify the<a>common factors</a>of them Common factors of 9 and 5: 1.</p>
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<p>Step 3: Choose the largest factor The largest factor that both numbers have is 1.</p>
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<p>Step 3: Choose the largest factor The largest factor that both numbers have is 1.</p>
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<p>The GCF of 9 and 5 is 1.</p>
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<p>The GCF of 9 and 5 is 1.</p>
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<h2>GCF of 9 and 5 Using Prime Factorization</h2>
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<h2>GCF of 9 and 5 Using Prime Factorization</h2>
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<p>To find the GCF of 9 and 5 using the Prime Factorization Method, follow these steps:</p>
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<p>To find the GCF of 9 and 5 using the Prime Factorization Method, follow these steps:</p>
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<p>Step 1: Find the<a>prime factors</a>of each number Prime Factors of 9: 9 = 3 x 3 = 3² Prime Factors of 5: 5 = 5¹.</p>
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<p>Step 1: Find the<a>prime factors</a>of each number Prime Factors of 9: 9 = 3 x 3 = 3² Prime Factors of 5: 5 = 5¹.</p>
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<p>Step 2: Now, identify the common prime factors, There are no common prime factors.</p>
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<p>Step 2: Now, identify the common prime factors, There are no common prime factors.</p>
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<p>Step 3: Since there are no common prime factors, the GCF is 1.</p>
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<p>Step 3: Since there are no common prime factors, the GCF is 1.</p>
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<h2>GCF of 9 and 5 Using Division Method or Euclidean Algorithm Method</h2>
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<h2>GCF of 9 and 5 Using Division Method or Euclidean Algorithm Method</h2>
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<p>Find the GCF of 9 and 5 using the<a>division</a>method or Euclidean Algorithm Method.</p>
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<p>Find the GCF of 9 and 5 using the<a>division</a>method or Euclidean Algorithm Method.</p>
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<p>Follow these steps:</p>
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<p>Follow these steps:</p>
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<p>Step 1: First, divide the larger number by the smaller number Here, divide 9 by 5 9 ÷ 5 = 1 (<a>quotient</a>), The<a>remainder</a>is calculated as 9 - (5×1) = 4, The remainder is 4, not zero, so continue the process.</p>
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<p>Step 1: First, divide the larger number by the smaller number Here, divide 9 by 5 9 ÷ 5 = 1 (<a>quotient</a>), The<a>remainder</a>is calculated as 9 - (5×1) = 4, The remainder is 4, not zero, so continue the process.</p>
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<p>Step 2: Now divide the previous divisor (5) by the previous remainder (4) 5 ÷ 4 = 1 (quotient), remainder = 5 - (4×1) = 1.</p>
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<p>Step 2: Now divide the previous divisor (5) by the previous remainder (4) 5 ÷ 4 = 1 (quotient), remainder = 5 - (4×1) = 1.</p>
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<p>Step 3: Now divide the previous divisor (4) by the previous remainder (1) 4 ÷ 1 = 4 (quotient), remainder = 4 - (1×4) = 0, The remainder is zero, so the divisor will become the GCF.</p>
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<p>Step 3: Now divide the previous divisor (4) by the previous remainder (1) 4 ÷ 1 = 4 (quotient), remainder = 4 - (1×4) = 0, The remainder is zero, so the divisor will become the GCF.</p>
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<p>The GCF of 9 and 5 is 1.</p>
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<p>The GCF of 9 and 5 is 1.</p>
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<h2>Common Mistakes and How to Avoid Them in GCF of 9 and 5</h2>
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<h2>Common Mistakes and How to Avoid Them in GCF of 9 and 5</h2>
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<p>Finding the GCF of 9 and 5 looks simple, but students often make mistakes while calculating the GCF.</p>
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<p>Finding the GCF of 9 and 5 looks simple, but students often make mistakes while calculating the GCF.</p>
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<p>Here are some common mistakes to be avoided by the students.</p>
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<p>Here are some common mistakes to be avoided by the students.</p>
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<h3>Problem 1</h3>
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<h3>Problem 1</h3>
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<p>A teacher has 9 apples and 5 oranges. She wants to group them into equal sets, with the largest number of fruits in each group. How many fruits will be in each group?</p>
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<p>A teacher has 9 apples and 5 oranges. She wants to group them into equal sets, with the largest number of fruits in each group. How many fruits will be in each group?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>We should find the GCF of 9 and 5 GCF of 9 and 5 is 1.</p>
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<p>We should find the GCF of 9 and 5 GCF of 9 and 5 is 1.</p>
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<p>There are 1 equal group 9 ÷ 1 = 9 5 ÷ 1 = 5.</p>
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<p>There are 1 equal group 9 ÷ 1 = 9 5 ÷ 1 = 5.</p>
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<p>There will be 1 group, and each group gets 9 apples and 5 oranges.</p>
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<p>There will be 1 group, and each group gets 9 apples and 5 oranges.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>Since the GCF of 9 and 5 is 1, the teacher can make 1 group.</p>
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<p>Since the GCF of 9 and 5 is 1, the teacher can make 1 group.</p>
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<p>Now divide 9 and 5 by 1.</p>
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<p>Now divide 9 and 5 by 1.</p>
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<p>Each group gets 9 apples and 5 oranges.</p>
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<p>Each group gets 9 apples and 5 oranges.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 2</h3>
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<h3>Problem 2</h3>
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<p>A school has 9 red chairs and 5 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?</p>
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<p>A school has 9 red chairs and 5 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>GCF of 9 and 5 is 1.</p>
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<p>GCF of 9 and 5 is 1.</p>
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<p>So each row will have 1 chair.</p>
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<p>So each row will have 1 chair.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>There are 9 red and 5 blue chairs.</p>
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<p>There are 9 red and 5 blue chairs.</p>
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<p>To find the total number of chairs in each row, we should find the GCF of 9 and 5.</p>
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<p>To find the total number of chairs in each row, we should find the GCF of 9 and 5.</p>
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<p>There will be 1 chair in each row.</p>
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<p>There will be 1 chair in each row.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 3</h3>
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<h3>Problem 3</h3>
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<p>A tailor has 9 meters of red ribbon and 5 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?</p>
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<p>A tailor has 9 meters of red ribbon and 5 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>For calculating the longest equal length, we have to calculate the GCF of 9 and 5.</p>
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<p>For calculating the longest equal length, we have to calculate the GCF of 9 and 5.</p>
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<p>The GCF of 9 and 5 is 1.</p>
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<p>The GCF of 9 and 5 is 1.</p>
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<p>The ribbon is 1 meter long.</p>
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<p>The ribbon is 1 meter long.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>For calculating the longest length of the ribbon, first, we need to calculate the GCF of 9 and 5, which is 1.</p>
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<p>For calculating the longest length of the ribbon, first, we need to calculate the GCF of 9 and 5, which is 1.</p>
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<p>The length of each piece of the ribbon will be 1 meter.</p>
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<p>The length of each piece of the ribbon will be 1 meter.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 4</h3>
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<h3>Problem 4</h3>
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<p>A carpenter has two wooden planks, one 9 cm long and the other 5 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?</p>
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<p>A carpenter has two wooden planks, one 9 cm long and the other 5 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The carpenter needs the longest piece of wood GCF of 9 and 5 is 1.</p>
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<p>The carpenter needs the longest piece of wood GCF of 9 and 5 is 1.</p>
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<p>The longest length of each piece is 1 cm.</p>
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<p>The longest length of each piece is 1 cm.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>To find the longest length of each piece of the two wooden planks, 9 cm and 5 cm, respectively, we have to find the GCF of 9 and 5, which is 1 cm.</p>
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<p>To find the longest length of each piece of the two wooden planks, 9 cm and 5 cm, respectively, we have to find the GCF of 9 and 5, which is 1 cm.</p>
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<p>The longest length of each piece is 1 cm.</p>
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<p>The longest length of each piece is 1 cm.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 5</h3>
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<h3>Problem 5</h3>
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<p>If the GCF of 9 and ‘a’ is 1, and the LCM is 45. Find ‘a’.</p>
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<p>If the GCF of 9 and ‘a’ is 1, and the LCM is 45. Find ‘a’.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>The value of ‘a’ is 5.</p>
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<p>The value of ‘a’ is 5.</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>GCF x LCM = product of the numbers 1 × 45 = 9 × a 45 = 9a a = 45 ÷ 9 = 5</p>
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<p>GCF x LCM = product of the numbers 1 × 45 = 9 × a 45 = 9a a = 45 ÷ 9 = 5</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h2>FAQs on the Greatest Common Factor of 9 and 5</h2>
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<h2>FAQs on the Greatest Common Factor of 9 and 5</h2>
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<h3>1.What is the LCM of 9 and 5?</h3>
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<h3>1.What is the LCM of 9 and 5?</h3>
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<p>The LCM of 9 and 5 is 45.</p>
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<p>The LCM of 9 and 5 is 45.</p>
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<h3>2.Is 9 divisible by 2?</h3>
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<h3>2.Is 9 divisible by 2?</h3>
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<p>No, 9 is not divisible by 2 because it is an odd number.</p>
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<p>No, 9 is not divisible by 2 because it is an odd number.</p>
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<h3>3.What will be the GCF of any two prime numbers?</h3>
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<h3>3.What will be the GCF of any two prime numbers?</h3>
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<p>The common factor of<a>prime numbers</a>is 1 and the number itself.</p>
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<p>The common factor of<a>prime numbers</a>is 1 and the number itself.</p>
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<p>Since 1 is the only common factor of any two prime numbers, it is said to be the GCF of any two prime numbers.</p>
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<p>Since 1 is the only common factor of any two prime numbers, it is said to be the GCF of any two prime numbers.</p>
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<h3>4.What is the prime factorization of 5?</h3>
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<h3>4.What is the prime factorization of 5?</h3>
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<p>The prime factorization of 5 is 5¹.</p>
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<p>The prime factorization of 5 is 5¹.</p>
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<h3>5.Are 9 and 5 prime numbers?</h3>
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<h3>5.Are 9 and 5 prime numbers?</h3>
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<p>No, 9 and 5 are not both prime numbers because 9 has more than two factors, while 5 is a prime number.</p>
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<p>No, 9 and 5 are not both prime numbers because 9 has more than two factors, while 5 is a prime number.</p>
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<h2>Important Glossaries for GCF of 9 and 5</h2>
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<h2>Important Glossaries for GCF of 9 and 5</h2>
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<ul><li><strong>Factors</strong>: Factors are numbers that divide the target number completely. For example, the factors of 6 are 1, 2, 3, and 6.</li>
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<ul><li><strong>Factors</strong>: Factors are numbers that divide the target number completely. For example, the factors of 6 are 1, 2, 3, and 6.</li>
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</ul><ul><li><strong>Multiple</strong>: Multiples are the products we get by multiplying a given number by another. For example, the multiples of 3 are 3, 6, 9, 12, and so on.</li>
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</ul><ul><li><strong>Multiple</strong>: Multiples are the products we get by multiplying a given number by another. For example, the multiples of 3 are 3, 6, 9, 12, and so on.</li>
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</ul><ul><li><strong>Prime Factors</strong>: These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 9 are 3 and 3.</li>
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</ul><ul><li><strong>Prime Factors</strong>: These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 9 are 3 and 3.</li>
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</ul><ul><li><strong>Remainder</strong>: The value left after division when the number cannot be divided evenly. For example, when 10 is divided by 4, the remainder is 2.</li>
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</ul><ul><li><strong>Remainder</strong>: The value left after division when the number cannot be divided evenly. For example, when 10 is divided by 4, the remainder is 2.</li>
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</ul><ul><li><strong>LCM</strong>: The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 9 and 5 is 45.</li>
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</ul><ul><li><strong>LCM</strong>: The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 9 and 5 is 45.</li>
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</ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>
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</ul><p>What Are Numbers? 🔢 | Fun Explanation with 🎯 Real-Life Examples for Kids | ✨BrightCHAMPS Math</p>
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<h2>Hiralee Lalitkumar Makwana</h2>
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<h2>Hiralee Lalitkumar Makwana</h2>
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<h3>About the Author</h3>
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<h3>About the Author</h3>
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<p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>
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<p>Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.</p>
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<h3>Fun Fact</h3>
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<h3>Fun Fact</h3>
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<p>: She loves to read number jokes and games.</p>
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<p>: She loves to read number jokes and games.</p>